from django.contrib import admin
from django.conf.urls import include, url
from rest_slack.views import DRSEventView, DRSCommandView
from django.urls import path
api_patterns = ([
path('web/', DRSEventView.as_view()),
path('events/', DRSCommandView.as_view()),
], 'api')
urlpatterns = [
url(r'^admin/', admin.site.urls),
path('api/v1/', include(api_patterns)),]
Now what's happening is I'm using django 1.9 which doesn't let me include django.urls. Second thing If I use any other version of djangorestframework it doesn't let me use path object in this.
Related
from django.contrib import admin
from django.urls import path,include
from Users.urls import *
from django.contrib import admin
urlpatterns = [
path('admin/', admin.site.urls),
path("",include("Users.urls")),
path('api/v1/rest-auth/', include('rest_auth.urls')),
]
Error:-ImportError: cannot import name 'url' from 'django.conf.urls'
In rest_auth.urls do this:
from rest_framework.routers import DefaultRouter
router = DefaultRouter()
app_name = 'recipe'
urlpatterns = [
path('',include(router.urls)),
]
Hope your problem will solve now.
In my Django project I have 2 apps: core and books. In my core/urls.py, I use python include('books.url') to import the urls from books/urls.py, but I keep getting this error
I have been having this issue now that's bugging me. I had a workaround for it, though I really want to fix this.
core/urls.py
from django.contrib import admin
from django.urls import path
from django.conf.urls import include
# local
urlpatterns = [
path('/', include('books.urls')),
path('admin/', admin.site.urls),
]
books/urls.py
from django.contrib import admin
from django.urls import path
# local
from graphene_django.views import GraphQLView
from books.schema import schema
urlpatterns = [
path('graphql/', GraphQLView.as_view(graphiql=True, schema=schema)),
]
As suggested by SO, I have:
put books.urls inside the single quotes ' '
placed the path('/', include('books.urls')) on top
switch from from django.urls import include to
from django.conf.urls import include
The only workaround I have is place all urls into the core/urls.py, but that seems too chunky in the long run. I don't get why include works for everyone but not me!
Could you help me with this issue? Thank you!
Now GraphQLView is called with the URL 127.0.0.1:8000/graphql/, if you want to call it with the URL 127.0.0.1:8000/, you need to change your code:
core/urls.py
from django.contrib import admin
from django.urls import path
from django.conf.urls import include
# local
urlpatterns = [
path('/', include('books.urls')),
path('admin/', admin.site.urls),
]
books/urls.py
from django.contrib import admin
from django.urls import path
# local
from graphene_django.views import GraphQLView
from books.schema import schema
urlpatterns = [
path('/', GraphQLView.as_view(graphiql=True, schema=schema)),
]
I created a password reset view following this tutorial.
I used the urls for class based views since django uses CBVs in the version 2.1 and above. It seemed to work fine, but today I am getting the above stated error. I have commented the admin url, on uncommenting it the password_reset view works, but through the django registration and uses it's own template regardless of the templates I have created. Why am I getting this problem suddenly when it worked fine earlier?
urls.py
from django.conf.urls import url,include
from django.contrib import admin
from NewApp import views
from django.conf import settings
from django.conf.urls.static import serve
from django.urls import path
urlpatterns = [
url(r'^$', views.user_login , name='user_login'),
url(r'^NewApp/', include('NewApp.urls', namespace="NewApp")),
path('', include('django.contrib.auth.urls')),
]
NewApp/urls.py
from django.conf.urls import url,include
from django.urls import path
from . import views
from django.conf import settings
from django.conf.urls.static import static
from django.contrib.auth import views as auth_views
app_name = 'NewApp'
urlpatterns = [
path('password_reset/', auth_views.PasswordResetView.as_view(), name='password_reset'),
path('password_reset/done/', auth_views.PasswordResetDoneView.as_view(), name='password_reset_done'),
path('reset/<uidb64>/<token>/', auth_views.PasswordResetConfirmView.as_view(), name='password_reset_confirm'),
path('reset/done/', auth_views.PasswordResetCompleteView.as_view(), name='password_reset_complete'),
]
Apart from these, I have only used templates which are just copied from the link I have mentioned.
views for password reset need to access the admin by default. So you have to include the admin site to urls.py:
from django.urls import path
from django.contrib import admin
urlpatterns = [
...
path('admin/', admin.site.urls),
...
]
[A similar question was asked, but not marked as answered, here. I considered continuing that thread but the website told me I'm only supposed to post an answer, so it seems I have to start a new topic.] I'm trying to follow this tutorial and I'm having problems with the URL mapping. Specifically with the part described as "So best practice is to create an “url.py” per application and to include it in our main projects url.py file". The relevant, I hope, part of the folder structure, which arose by following steps of the tutorial to the letter (if possible; usage of the 'patterns' module was impossible for example) and using Django 1.10 is the following:
myproject/
myapp/
urls.py
views.py
myproject/
urls.py
The myproject/urls.py is as follows:
from django.conf.urls import include, url
from django.contrib import admin
admin.autodiscover()
from myapp.views import hello
urlpatterns = [
url(r'^admin/', include(admin.site.urls)),
url(r'^myapp/', include(myapp.urls)),
]
The myapp/urls.py is as follows:
from django.conf.urls import include, url
urlpatterns = [
url(r'^hello/', myapp.views.hello),
]
The myapp/views.py is as follows:
from django.shortcuts import render
def hello(request):
return render(request, "hello.html", {})
However, running 'python manage.py runserver' results in the following error:
url(r'^myapp/', include(myapp.urls)),
NameError: name 'myapp' is not defined
INSTALLED_APPS in settings.py contains 'myapp'.
I'd be greatful for any tips on how to deal with the NameError! [Or any tips whatsoever that anyone might consider to be helpful!]
You have the NameError because you are referencing myapp in myproject/urls.py but haven't imported it.
The typical approach in Django is to use a string with include, which means that the import is not required.
url(r'^myapp/', include('myapp.urls')),
Since you have move the hello URL pattern into myapp/urls.py, you can remove from myapp.views import hello from myproject/urls.py.
Once you've made that change, you will get another NameError in myapp/urls.py. In this case, a common approach is to use a relative import for the app's views.
from django.conf.urls import url
from . import views
urlpatterns = [
url(r'^hello/$', views.hello),
]
Make sure you have imported following modules to urls.py.
from django.conf.urls import url
from django.contrib import admin
in django 2.0
use these
from django.contrib import admin
from django.urls import path
from first_app import views
urlpatterns = [
path('',views.index, name="index"),
path('admin/', admin.site.urls),
]
your app URL has to be a string
so, here is how the code should look like.
from django.conf.urls import include, url
from django.contrib import admin
admin.autodiscover()
from myapp.views import hello
urlpatterns = [
url(r'^admin/', include(admin.site.urls)),
url(r'^myapp/', include('myapp.urls')),
]
also, note that from python 2 upward the regular expression is not needed.
change URL to path
from django.conf.URLs import include path
from Django.contrib import admin
admin.autodiscover()
from myapp.views import hello
urlpatterns = [
path('^admin/', include(admin.site.urls)),
path('^myapp/', include('myapp.urls')),
]
In Django 2.1.7 here is the default urls .py file
from django.contrib import admin
from django.urls import path
urlpatterns = [
path('admin/', admin.site.urls),
]
so we need to add this line as well
from django.conf.urls import url
I have followed #Alasdair answers
You have the NameError because you are referencing myapp in myproject/urls.py but haven't imported it.
The typical approach in Django is to use a string with include, which
means that the import is not required.
Unfortunately, it didn't work out(I still got the name X is not defined error). Here is how I do it.
from django.contrib import admin
from django.urls import include
from django.conf.urls import url
from article import urls as article_users
from article import urls as user_urls
urlpatterns = [
path('admin/', admin.site.urls),
path('api/article/', include(article_users)),
path('api/user/', include(user_urls)),
]
Before using the URL command be sure to first import the url from the module Urls. Then try using the runserver.
from django.conf.urls import url
from django.contrib import admin
from django.urls import path
I am new to django and python. During url mapping to views i am getting following error:
TypeError: view must be a callable or a list/tuple in the case of include().
Urls. py code:-
from django.conf.urls import url
from django.contrib import admin
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^posts/$', "posts.views.post_home"), #posts is module and post_home
] # is a function in view.
views.py code:-
from django.shortcuts import render
from django.http import HttpResponse
# Create your views here.
#function based views
def post_home(request):
response = "<h1>Success</h1>"
return HttpResponse(response)
Traceback
In 1.10, you can no longer pass import paths to url(), you need to pass the actual view function:
from posts.views import post_home
urlpatterns = [
...
url(r'^posts/$', post_home),
]
Replace your admin url pattern with this
url(r'^admin/', include(admin.site.urls))
So your urls.py becomes :
from django.conf.urls import url, include
from django.contrib import admin
urlpatterns = [
url(r'^admin/', include(admin.site.urls)),
url(r'^posts/$', "posts.views.post_home"), #posts is module and post_home
]
admin urls are callable by include (before 1.9).
For Django 1.11.2
In the main urls.py write :
from django.conf.urls import include,url
from django.contrib import admin
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^posts/', include("Post.urls")),
]
And in the appname/urls.py file write:
from django.conf.urls import url
from . import views
urlpatterns = [
url(r'^$',views.post_home),
]
Answer is in project-dir/urls.py
Including another URLconf
1. Import the include() function: from django.conf.urls import url, include
2. Add a URL to urlpatterns: url(r'^blog/', include('blog.urls'))
Just to complement the answer from #knbk, we could use the template below:
as is in 1.9:
from django.conf.urls import url, include
urlpatterns = [
url(r'^admin/', admin.site.urls), #it's not allowed to use the include() in the admin.urls
url(r'^posts/$', include(posts.views.post_home),
]
as should be in 1.10:
from your_project_django.your_app_django.view import name_of_your_view
urlpatterns = [
...
url(r'^name_of_the_view/$', name_of_the_view),
]
Remember to create in your_app_django >> views.py the function to render your view.
You need to pass actual view function
from posts.views import post_home
urlpatterns = [
...
url(r'^posts/$', post_home),
]
This works fine!
You can have a read at URL Dispatcher Django
and here Common Reguler Expressions Django URLs