How to define the slug of another model in myListView - django

Question

I sort of need help understanding my own code specifically the views.py. I'm trying to change url pattern for my TitleUpdateListView from using my Update models title field and instead using the slug field instead.
If someone could help explain line by line whats going in in my TitleUpdateListView so I could better understand whats specifically going on that would be great.
urls.py
urlpatterns = [
# Update view for each game
path('<str:title>/updates/', TitleUpdateListView.as_view(), name='title-updates'),
# Adds the ability to sort by platform
path('<str:title>/updates/<int:platform_id>/', TitleUpdateAjaxListView.as_view(), name='title-updates-ajax'),
]
views.py
class TitleUpdateListView(ListView):
model = Update
context_object_name = 'updates'
template_name = 'updates/title_updates.html'
def get_queryset(self):
title = get_object_or_404(Game, title=self.kwargs.get('title'))
return Update.objects.filter(game=title).order_by('-date_published')
def get_context_data(self, **kwargs):
context = super(TitleUpdateListView, self).get_context_data(**kwargs)
context['game'] = get_object_or_404(Game, title=self.kwargs.get('title'))
return context
class TitleUpdateAjaxListView(ListView):
model = Update
template_name = 'updates/updates_ajax.html'
context_object_name = 'updates'
paginate_by = 5
def get_queryset(self):
title = get_object_or_404(Game, title=self.kwargs.get('title'))
return Update.objects.filter(game=title, platform=Platform.objects.filter(
id=self.kwargs.get('platform_id')).first()).order_by('-date_published')
def get_context_data(self, **kwargs):
context = super(TitleUpdateAjaxListView, self).get_context_data(**kwargs)
context['game'] = get_object_or_404(Game, title=self.kwargs.get('title'))
return context
def get(self, request, *args, **kwargs):
self.object_list = self.get_queryset()
context = self.get_context_data()
return render(request, self.template_name, context)

Answer 1

Not sure what you meant by "I'm trying to change url pattern for my TitleUpdateListView from using my Update models title field and instead using the slug field instead.". In the urls.py, you can change the name of the parameter (the xxxx in <str:xxxx>) to whatever you want, as long as you also look for this same name in the view. You can change it to <str:slug> and in your view you'd fetch it like self.kwargs.get('slug'). Just remember to also change which parameter are you using to filter the Game table (slug instead of title).
As for explaining what your view does, you should probably take a look at Django's docs on Class Based Views, but I'll try to give an overview:
The get_queryset method is searching the Game table to find the games whose title matches the title passed in the URL parameter. It then returns a list of all Update objects whose game field points to the game just found.
The get_context_data method is adding the same Game object found in the get_queryset method to the view's context under the 'game' key. This means that you can access the Game object inside the template that this view renders.

Answer 2

You just need to change the get_queryset method of your view:
# change url variable name from title to slug
path('<str:slug>/updates/', TitleUpdateListView.as_view(), name='title-updates'),
def get_queryset(self):
# the url variables are stored in the dictionary self.kwargs
slug = self.kwargs.get('slug')
game = get_object_or_404(Game, slug=slug)
return Update.objects.filter(game=game).order_by('-date_published')
The same applies for get_context_data:
def get_context_data(self, **kwargs):
context = super(TitleUpdateListView, self).get_context_data(**kwargs)
context['game'] = get_object_or_404(Game, slug=self.kwargs.get('slug'))
return context