I want to write a template function that writes tables to HDF5 files.
The signature should look similar to
template<typename record> void writeTable(const std::vector<record>& data);
where record is a struct, or
template<typename... elements>
void writeTable(const std::vector<std::tuple<elements...>>& data);
The actual implementation would have more parameters to determine the destionation, etc.
To write the data I need to define a HDF5 compound type, which contains the name and the offset of the members. Usually you would use the HOFFSET macro the get the field offset, but as I don't know the struct fields beforehand I can't do that.
What I tried so far was constructing a struct type from the typename pack. The naive implementation did not have standard layout, but the implementation here does. All that's left is get the offsets of the members. I would like to expand the parameter pack into an initializer list with the offsets:
#include <vector>
template<typename... members> struct record {};
template<typename member, typename... members> struct record<member, members...> :
record<members...> {
record(member m, members... ms) : record<members...>(ms...), tail(m) {}
member tail;
};
template<typename... Args> void
make_table(const std::string& name, const std::vector<record<Args...>>& data) {
using record_type = record<Args...>;
std::vector<size_t> offsets = { get_offset(record_type,Args)... };
}
int main() {
std::vector<record<int, float>> table = { {1, 1.0}, {2, 2.0} };
make_table("table", table);
}
Is there a possible implementation for get_offset? I would think not, because in the case of record<int, int> it would be ambiguous. Is there another way to do it?
Or is there any other way I could approach this problem?
Calculating offsets is quite simple. Given a tuple with types T0, T1 ... TN. The offset of T0 is 0 (as long as you use alignas(T0) on your char array. The offset of T1 is the sizeof(T0) rounded up to alignof(T1).
In general, the offset of TB (which comes after TA) is round_up(offset_of<TA>() + sizeof(TA), alignof(TB)).
Calculating the offsets of elements in a std::tuple could be done like this:
constexpr size_t roundup(size_t num, size_t multiple) {
const size_t mod = num % multiple;
return mod == 0 ? num : num + multiple - mod;
}
template <size_t I, typename Tuple>
struct offset_of {
static constexpr size_t value = roundup(
offset_of<I - 1, Tuple>::value + sizeof(std::tuple_element_t<I - 1, Tuple>),
alignof(std::tuple_element_t<I, Tuple>)
);
};
template <typename Tuple>
struct offset_of<0, Tuple> {
static constexpr size_t value = 0;
};
template <size_t I, typename Tuple>
constexpr size_t offset_of_v = offset_of<I, Tuple>::value;
Here's a test suite. As you can see from the first test, the alignment of elements is taken into account.
static_assert(offset_of_v<1, std::tuple<char, long double>> == 16);
static_assert(offset_of_v<2, std::tuple<char, char, long double>> == 16);
static_assert(offset_of_v<3, std::tuple<char, char, char, long double>> == 16);
static_assert(offset_of_v<4, std::tuple<char, char, char, char, long double>> == 16);
static_assert(offset_of_v<0, std::tuple<int, double, int, char, short, long double>> == 0);
static_assert(offset_of_v<1, std::tuple<int, double, int, char, short, long double>> == 8);
static_assert(offset_of_v<2, std::tuple<int, double, int, char, short, long double>> == 16);
static_assert(offset_of_v<3, std::tuple<int, double, int, char, short, long double>> == 20);
static_assert(offset_of_v<4, std::tuple<int, double, int, char, short, long double>> == 22);
static_assert(offset_of_v<5, std::tuple<int, double, int, char, short, long double>> == 32);
I hardcoded the offsets in the above tests. The offsets are correct if the following tests succeed.
static_assert(sizeof(char) == 1 && alignof(char) == 1);
static_assert(sizeof(short) == 2 && alignof(short) == 2);
static_assert(sizeof(int) == 4 && alignof(int) == 4);
static_assert(sizeof(double) == 8 && alignof(double) == 8);
static_assert(sizeof(long double) == 16 && alignof(long double) == 16);
std::tuple seems to store it's elements sequentially (without sorting them to optimize padding). That's proven by the following tests. I don't think the standard requires std::tuple to be implemented this way so I don't think the following tests are guaranteed to succeed.
template <size_t I, typename Tuple>
size_t real_offset(const Tuple &tup) {
const char *base = reinterpret_cast<const char *>(&tup);
return reinterpret_cast<const char *>(&std::get<I>(tup)) - base;
}
int main(int argc, char **argv) {
using Tuple = std::tuple<int, double, int, char, short, long double>;
Tuple tup;
assert((offset_of_v<0, Tuple> == real_offset<0>(tup)));
assert((offset_of_v<1, Tuple> == real_offset<1>(tup)));
assert((offset_of_v<2, Tuple> == real_offset<2>(tup)));
assert((offset_of_v<3, Tuple> == real_offset<3>(tup)));
assert((offset_of_v<4, Tuple> == real_offset<4>(tup)));
assert((offset_of_v<5, Tuple> == real_offset<5>(tup)));
}
Now that I've gone to all of this effort, would that real_offset function suit your needs?
This is a minimal implementation of a tuple that accesses a char[] with offset_of. This is undefined behavior though because of the reinterpret_cast. Even though I'm constructing the object in the same bytes and accessing the object in the same bytes, it's still UB. See this answer for all the standardese. It will work on every compiler you can find but it's UB so just use it anyway. This tuple is standard layout (unlike std::tuple). If the elements of your tuple are all trivially copyable, you can remove the copy and move constructors and replace them with memcpy.
template <typename... Elems>
class tuple;
template <size_t I, typename Tuple>
struct tuple_element;
template <size_t I, typename... Elems>
struct tuple_element<I, tuple<Elems...>> {
using type = std::tuple_element_t<I, std::tuple<Elems...>>;
};
template <size_t I, typename Tuple>
using tuple_element_t = typename tuple_element<I, Tuple>::type;
template <typename Tuple>
struct tuple_size;
template <typename... Elems>
struct tuple_size<tuple<Elems...>> {
static constexpr size_t value = sizeof...(Elems);
};
template <typename Tuple>
constexpr size_t tuple_size_v = tuple_size<Tuple>::value;
constexpr size_t roundup(size_t num, size_t multiple) {
const size_t mod = num % multiple;
return mod == 0 ? num : num + multiple - mod;
}
template <size_t I, typename Tuple>
struct offset_of {
static constexpr size_t value = roundup(
offset_of<I - 1, Tuple>::value + sizeof(tuple_element_t<I - 1, Tuple>),
alignof(tuple_element_t<I, Tuple>)
);
};
template <typename Tuple>
struct offset_of<0, Tuple> {
static constexpr size_t value = 0;
};
template <size_t I, typename Tuple>
constexpr size_t offset_of_v = offset_of<I, Tuple>::value;
template <size_t I, typename Tuple>
auto &get(Tuple &tuple) noexcept {
return *reinterpret_cast<tuple_element_t<I, Tuple> *>(tuple.template addr<I>());
}
template <size_t I, typename Tuple>
const auto &get(const Tuple &tuple) noexcept {
return *reinterpret_cast<tuple_element_t<I, Tuple> *>(tuple.template addr<I>());
}
template <typename... Elems>
class tuple {
alignas(tuple_element_t<0, tuple>) char storage[offset_of_v<sizeof...(Elems), tuple<Elems..., char>>];
using idx_seq = std::make_index_sequence<sizeof...(Elems)>;
template <size_t I>
void *addr() {
return static_cast<void *>(&storage + offset_of_v<I, tuple>);
}
template <size_t I, typename Tuple>
friend auto &get(const Tuple &) noexcept;
template <size_t I, typename Tuple>
friend const auto &get(Tuple &) noexcept;
template <size_t... I>
void default_construct(std::index_sequence<I...>) {
(new (addr<I>()) Elems{}, ...);
}
template <size_t... I>
void destroy(std::index_sequence<I...>) {
(get<I>(*this).~Elems(), ...);
}
template <size_t... I>
void move_construct(tuple &&other, std::index_sequence<I...>) {
(new (addr<I>()) Elems{std::move(get<I>(other))}, ...);
}
template <size_t... I>
void copy_construct(const tuple &other, std::index_sequence<I...>) {
(new (addr<I>()) Elems{get<I>(other)}, ...);
}
template <size_t... I>
void move_assign(tuple &&other, std::index_sequence<I...>) {
(static_cast<void>(get<I>(*this) = std::move(get<I>(other))), ...);
}
template <size_t... I>
void copy_assign(const tuple &other, std::index_sequence<I...>) {
(static_cast<void>(get<I>(*this) = get<I>(other)), ...);
}
public:
tuple() noexcept((std::is_nothrow_default_constructible_v<Elems> && ...)) {
default_construct(idx_seq{});
}
~tuple() {
destroy(idx_seq{});
}
tuple(tuple &&other) noexcept((std::is_nothrow_move_constructible_v<Elems> && ...)) {
move_construct(other, idx_seq{});
}
tuple(const tuple &other) noexcept((std::is_nothrow_copy_constructible_v<Elems> && ...)) {
copy_construct(other, idx_seq{});
}
tuple &operator=(tuple &&other) noexcept((std::is_nothrow_move_assignable_v<Elems> && ...)) {
move_assign(other, idx_seq{});
return *this;
}
tuple &operator=(const tuple &other) noexcept((std::is_nothrow_copy_assignable_v<Elems> && ...)) {
copy_assign(other, idx_seq{});
return *this;
}
};
Alternatively, you could use this function:
template <size_t I, typename Tuple>
size_t member_offset() {
return reinterpret_cast<size_t>(&std::get<I>(*static_cast<Tuple *>(nullptr)));
}
template <typename Member, typename Class>
size_t member_offset(Member (Class::*ptr)) {
return reinterpret_cast<size_t>(&(static_cast<Class *>(nullptr)->*ptr));
}
template <auto MemPtr>
size_t member_offset() {
return member_offset(MemPtr);
}
Once again, this is undefined behavior (because of the nullptr dereference and the reinterpret_cast) but it will work as expected with every major compiler. The function cannot be constexpr (even though member offset is a compile-time calculation).
Not sure to understand what do you exactly want but... what about using recursion based on a index sequence (starting from C++14) something as follows?
#include <vector>
#include <utility>
#include <iostream>
template <typename... members>
struct record
{ };
template <typename member, typename... members>
struct record<member, members...> : record<members...>
{
record (member m, members... ms) : record<members...>(ms...), tail(m)
{ }
member tail;
};
template <std::size_t, typename, std::size_t = 0u>
struct get_offset;
template <std::size_t N, typename A0, typename ... As, std::size_t Off>
struct get_offset<N, record<A0, As...>, Off>
: public get_offset<N-1u, record<As...>, Off+sizeof(A0)>
{ };
template <typename A0, typename ... As, std::size_t Off>
struct get_offset<0u, record<A0, As...>, Off>
: public std::integral_constant<std::size_t, Off>
{ };
template <typename... Args, std::size_t ... Is>
auto make_table_helper (std::string const & name,
std::vector<record<Args...>> const & data,
std::index_sequence<Is...> const &)
{ return std::vector<std::size_t>{ get_offset<Is, record<Args...>>::value... }; }
template <typename... Args>
auto make_table (std::string const & name,
std::vector<record<Args...>> const & data)
{ return make_table_helper(name, data, std::index_sequence_for<Args...>{}); }
int main ()
{
std::vector<record<int, float>> table = { {1, 1.0}, {2, 2.0} };
auto v = make_table("table", table);
for ( auto const & o : v )
std::cout << o << ' ';
std::cout << std::endl;
}
Unfortunately isn't an efficient solution because the last value is calculated n-times.
Related
I have a function that computes a certain object from a given parameter (say, an important node from a graph). Now, when calculating such an object, the function might allocate some memory. Sometimes I want the function to just return the result, and sometimes to return the result plus the memory used to compute it.
I typically solve this binary case like this:
enum class what {
what1, // return, e.g., just an int
what2 // return, e.g., a std::pair<int, std::vector<int>>
};
template <what w>
std::conditional_t<w == what::what1, int, std::pair<int, std::vector<int>>>
calculate_something(const param& p) { ... }
I would like to generalize the solution above to longer enumerations
enum class list_whats {
what1,
what2,
what3,
what4,
what5
};
One possible solution is to nest as many std::conditional_t as needed
template <list_whats what>
std::conditional_t<
what == list_whats::what1,
int,
std::conditional_t<
what == list_whats::what2,
float,
....
>
>
>
calculate_something(const param& p) { ... }
But this is cumbersome and perhaps not too elegant.
Does anyone know how to do this in C++ 17?
EDIT
To make the question perfectly clear: how do I implement the function return_something so as to be able to run the following main?
int main() {
int s1 = return_something<list_whats::what1>();
s1 = 3;
float s2 = return_something<list_whats::what2>();
s2 = 4.0f;
double s3 = return_something<list_whats::what3>();
s3 = 9.0;
std::string s4 = return_something<list_whats::what4>();
s4 = "qwer";
std::vector<int> s5 = return_something<list_whats::what5>();
s5[3] = 25;
}
I don't think you should use std::conditional at all to solve your problem. If I get this right, you want to use a template parameter to tell your function what to return. The elegant way to do this could look something like this:
#include <vector>
enum class what { what1, what2 };
template <what W>
auto compute() {
if constexpr (W == what::what1) {
return 100;
}
if constexpr (W == what::what2) {
return std::pair{100, std::vector<int>{}};
}
}
auto main() -> int {
[[maybe_unused]] const auto as_int = compute<what::what1>();
[[maybe_unused]] const auto as_pair = compute<what::what2>();
}
You can also use template specialization if you prefer another syntax:
template <what W>
auto compute();
template <>
auto compute<what::what1>() {
return 100;
}
template <>
auto compute<what::what2>() {
return std::pair{100, std::vector<int>{}};
}
Here's my approach:
what_pair is a pair that corresponds one enum to one type.
what_type_index accepts a enum and a std::tuple<what_pair<...>...> and searches the tuple map where the enums are equal and returns index. It returns maximum std::size_t value, if no match was found.
what_type is the final type, it is the tuple element at the found position. The program won't compile when the index is std::size_t max value because of invalid std::tuple access.
template<what W, typename T>
struct what_pair {
constexpr static what w = W;
using type = T;
};
template<what w, typename tuple_map>
constexpr auto what_type_index() {
std::size_t index = std::numeric_limits<std::size_t>::max();
auto search_map = [&]<std::size_t... Ints>(std::index_sequence<Ints...>) {
((std::tuple_element_t<Ints, tuple_map>::w == w ? (index = Ints) : 0), ...);
};
search_map(std::make_index_sequence<std::tuple_size_v<tuple_map>>());
return index;
}
template<what w, typename tuple_map>
using what_type = typename
std::tuple_element_t<what_type_index<w, tuple_map>(), tuple_map>::type;
and this is the example usage:
int main() {
using what_map = std::tuple<
what_pair<what::what1, int>,
what_pair<what::what2, float>,
what_pair<what::what3, double>,
what_pair<what::what4, std::string>,
what_pair<what::what5, std::vector<int>>>;
static_assert(std::is_same_v<what_type<what::what1, what_map>, int>);
static_assert(std::is_same_v<what_type<what::what2, what_map>, float>);
static_assert(std::is_same_v<what_type<what::what3, what_map>, double>);
static_assert(std::is_same_v<what_type<what::what4, what_map>, std::string>);
static_assert(std::is_same_v<what_type<what::what5, what_map>, std::vector<int>>);
//compilation error, because 'what6' wasn't specified in the 'what_map'
using error = what_type<what::what6, what_map>;
}
try it out on godbolt.
I found a possible solution that nests two structs: the first takes a list of Boolean values to indicate which type should be used, and the nested struct takes the list of possible types (see conditional_list in the example code below -- the nested structs were inspired by this answer). But perhaps it's not elegant enough. I'm wondering if there is a possible solution of the form
std::conditional_list<
..., // list of Boolean values, (of any length!)
... // list of types (list that should be as long as the first)
>::type
My proposal
#include <type_traits>
#include <iostream>
#include <vector>
// -----------------------------------------------------------------------------
template<auto A, auto... ARGS>
constexpr auto sum = A + sum<ARGS...>;
template<auto A>
constexpr auto sum<A> = A;
// -----------------------------------------------------------------------------
template <bool... values>
static constexpr bool exactly_one_v = sum<values...> == 1;
// -----------------------------------------------------------------------------
template <bool... values>
struct which {
static_assert(exactly_one_v<values...>);
template <std::size_t idx, bool v1, bool... vs>
struct _which_impl {
static constexpr std::size_t value =
(v1 ? idx : _which_impl<idx + 1, vs...>::value);
};
template <std::size_t idx, bool v>
struct _which_impl<idx, v> {
static constexpr std::size_t value = (v ? idx : idx + 1);
};
static constexpr std::size_t value = _which_impl<0, values...>::value;
};
template <bool... conds>
static constexpr std::size_t which_v = which<conds...>::value;
// -----------------------------------------------------------------------------
template <std::size_t ith_idx, typename... Ts>
struct ith_type {
template <std::size_t cur_idx, typename t1, typename... ts>
struct _ith_type_impl {
typedef
std::conditional_t<
ith_idx == cur_idx,
t1,
typename _ith_type_impl<cur_idx + 1, ts...>::type
>
type;
};
template <std::size_t cur_idx, typename t1>
struct _ith_type_impl<cur_idx, t1> {
typedef
std::conditional_t<ith_idx == cur_idx, t1, std::nullptr_t>
type;
};
static_assert(ith_idx < sizeof...(Ts));
typedef typename _ith_type_impl<0, Ts...>::type type;
};
template <std::size_t ith_idx, typename... ts>
using ith_type_t = typename ith_type<ith_idx, ts...>::type;
// -----------------------------------------------------------------------------
template <bool... conds>
struct conditional_list {
template <typename... ts>
struct good_type {
static_assert(sizeof...(conds) == sizeof...(ts));
typedef ith_type_t<which_v<conds...>, ts...> type;
};
};
// -----------------------------------------------------------------------------
enum class list_whats {
what1,
what2,
what3,
what4,
what5,
};
template <list_whats what>
typename conditional_list<
what == list_whats::what1,
what == list_whats::what2,
what == list_whats::what3,
what == list_whats::what4,
what == list_whats::what5
>::template good_type<
int,
float,
double,
std::string,
std::vector<int>
>::type
return_something() noexcept {
if constexpr (what == list_whats::what1) { return 1; }
if constexpr (what == list_whats::what2) { return 2.0f; }
if constexpr (what == list_whats::what3) { return 3.0; }
if constexpr (what == list_whats::what4) { return "42"; }
if constexpr (what == list_whats::what5) { return {1,2,3,4,5}; }
}
int main() {
auto s1 = return_something<list_whats::what1>();
s1 = 3;
auto s2 = return_something<list_whats::what2>();
s2 = 4.0f;
auto s3 = return_something<list_whats::what3>();
s3 = 9.0;
auto s4 = return_something<list_whats::what4>();
s4 = "qwer";
auto s5 = return_something<list_whats::what5>();
s5[3] = 25;
}
An alternative to working only with types is to write a function that returns the specific type, or an identity<type>. It's sometimes more readable. Here is an example:
// if you don't have it in std
template<typename T>
struct identity {
using type = T;
};
enum class what {
what1,
what2,
what3
};
template<what w>
auto return_type_for_calc() {
if constexpr (w == what::what1) {
return identity<int>();
} else if constexpr (w==what::what2) {
return identity<double>();
} else {
return identity<float>();
}
}
template<what w>
decltype(return_type_for_calc<w>())
calculate_something()
{
return {};
}
int main() {
calculate_something<what::what1>();
calculate_something<what::what2>();
return 0;
}
Although I already posted an answer to my own question, and I accepted an answer from another user, I thought I could post another possibility in tackling this problem using the following struct
template <typename... Ts> struct type_sequence { };
which I learnt about in this talk by Andrei Alexandrescu. Since I learnt quite a bit by using it and the result is a bit simpler than the original answer that used two nested structs I thought I would share it here. However, the solution I would actually implement is the one that was accepted.
This is the full code with a main function included. Notice the change in the specification of function return_something. Now this function indicates the return type (which I like very much, perhaps I'm old fashioned) in a more readable way than in my first answer. You can try it out here.
#include <type_traits>
#include <iostream>
#include <vector>
template <bool... values>
struct which {
template <std::size_t idx, bool v1, bool... vs>
struct _which_impl {
static constexpr std::size_t value =
(v1 ? idx : _which_impl<idx + 1, vs...>::value);
};
template <std::size_t idx, bool v>
struct _which_impl<idx, v> {
static constexpr std::size_t value = (v ? idx : idx + 1);
};
static constexpr std::size_t value = _which_impl<0, values...>::value;
};
template <std::size_t ith_idx, typename... Ts>
struct ith_type {
template <std::size_t cur_idx, typename t1, typename... ts>
struct _ith_type_impl {
using type =
std::conditional_t<
ith_idx == cur_idx,
t1,
typename _ith_type_impl<cur_idx + 1, ts...>::type
>;
};
template <std::size_t cur_idx, typename t1>
struct _ith_type_impl<cur_idx, t1> {
using type = std::conditional_t<ith_idx == cur_idx, t1, std::nullptr_t>;
};
using type = typename _ith_type_impl<0, Ts...>::type;
};
template <std::size_t ith_idx, typename... ts>
using ith_type_t = typename ith_type<ith_idx, ts...>::type;
template <bool... conds>
static constexpr std::size_t which_v = which<conds...>::value;
template <typename... Ts> struct type_sequence { };
template <bool... values> struct bool_sequence {
static constexpr std::size_t which = which_v<values...>;
};
template <std::size_t ith_idx, typename... Ts>
struct ith_type<ith_idx, type_sequence<Ts...>> : ith_type<ith_idx, Ts...>
{ };
template <typename bool_sequence, typename type_sequence>
struct conditional_list {
using type = ith_type_t<bool_sequence::which, type_sequence>;
};
template <typename bool_sequence, typename type_sequence>
using conditional_list_t =
typename conditional_list<bool_sequence, type_sequence>::type;
enum class list_whats {
what1,
what2,
what3,
what4,
what5,
};
template <list_whats what>
conditional_list_t<
bool_sequence<
what == list_whats::what1,
what == list_whats::what2,
what == list_whats::what3,
what == list_whats::what4,
what == list_whats::what5
>,
type_sequence<
int,
float,
double,
std::string,
std::vector<int>
>
>
return_something() noexcept {
if constexpr (what == list_whats::what1) { return 1; }
if constexpr (what == list_whats::what2) { return 2.0f; }
if constexpr (what == list_whats::what3) { return 3.0; }
if constexpr (what == list_whats::what4) { return "42"; }
if constexpr (what == list_whats::what5) { return {1,2,3,4,5}; }
}
int main() {
[[maybe_unused]] auto s1 = return_something<list_whats::what1>();
[[maybe_unused]] auto s2 = return_something<list_whats::what2>();
[[maybe_unused]] auto s3 = return_something<list_whats::what3>();
[[maybe_unused]] auto s4 = return_something<list_whats::what4>();
[[maybe_unused]] auto s5 = return_something<list_whats::what5>();
}
I know that I can use SFINAE to disable generation of templated functions based on a condition, but that doesn't really work in this case. I want to initialize an array at compile-time that should contain values that matches a condition. Something like this:
template <std::size_t i, class ... Types, class ... Group>
constexpr auto fetch_match(const std::tuple<Group...>& candidates)
{
if constexpr (is_match<std::tuple<Group...>, i, Types...>())
{
auto& group = std::get<i>(candidates);
return group.template get<Types...>();
}
}
template <class ... Types, class ... Group, std::size_t ... indices>
constexpr auto get_matches(const std::tuple<Group...>& candidates, std::index_sequence<indices...>)
{
constexpr std::array views {
(fetch_match<indices, Types...>(candidates), ...),
};
return views;
}
I know the code above is wrong and doesn't compile. If the condition isn't filled, then I want the fold expression to not generate that function call. How would I do that?
This question might be an XY-problem, so here's a the problem in more detail.
I have a Registry that contains Groups of heterogeneous data. I want to be able to query all groups that contains the specified sub list of types. For example, for (const auto& view : registry.get<char, short, int>()) should yield an array with views of the groups that contain char, short and int. I've created a mcve below. The problem with the current code is that I have to first create the array and then copy the views, which I'd like to avoid.
#include <tuple>
#include <array>
#include <utility>
#include <type_traits>
#include <iostream>
template <typename T, typename... Ts>
constexpr bool contains = (std::is_same<T, Ts>{} || ...);
template <typename Subset, typename Set>
constexpr bool is_subset_of = false;
template <typename... Ts, typename... Us>
constexpr bool is_subset_of<std::tuple<Ts...>, std::tuple<Us...>> = (contains<Ts, Us...> && ...);
template <typename ... T>
struct View
{
const char* name_of_group; // For debugging.
std::tuple<T...> data;
};
template <typename ... Ts>
struct Group
{
using type_set = std::tuple<Ts...>;
static const char* name; // For debugging.
std::tuple<Ts...> data;
explicit Group(Ts... values) : data(values...) {}
template <typename ... Us>
[[nodiscard]] View<Us...> get() const noexcept
{
return { this->name, std::make_tuple(std::get<Us>(this->data)...) };
}
};
template <class Groups, std::size_t i, class ... Types>
constexpr bool is_match()
{
using group_type = std::tuple_element_t<i, Groups>;
bool match = is_subset_of<std::tuple<Types...>, typename group_type::type_set>;
return match;
}
template <std::size_t i, class ... Types, class ... Group, class Array>
constexpr void add_matches(const std::tuple<Group...>& candidates, Array& matches, std::size_t& index)
{
if constexpr (is_match<std::tuple<Group...>, i, Types...>())
{
auto& group = std::get<i>(candidates);
matches[index++] = group.template get<Types...>();
}
}
template <class ... Types, class ... Group, std::size_t ... indices>
constexpr auto get_matches(const std::tuple<Group...>& candidates, std::index_sequence<indices...>)
{
constexpr std::size_t size = (is_match<std::tuple<Group...>, indices, Types...>() + ... + 0);
std::array<View<Types...>, size> views {};
std::size_t index = 0;
(add_matches<indices, Types...>(candidates, views, index), ...);
return views;
}
template <typename ... Group>
class Registry
{
public:
explicit Registry(Group... groups) : groups(groups...) {}
template <typename ... T>
auto get()
{
constexpr auto indices = std::index_sequence_for<Group...>{};
return get_matches<T...>(this->groups, indices);
}
private:
std::tuple<Group...> groups;
};
using A = Group<char>;
using B = Group<char, short>;
using C = Group<char, short, int>;
using D = Group<char, short, int, long long>;
// Giving the classes names for debugging purposes.
template<> const char* A::name = "A";
template<> const char* B::name = "B";
template<> const char* C::name = "C";
template<> const char* D::name = "D";
int main()
{
auto registry = Registry(A{0}, B{1,1}, C{2,2,2}, D{3,3,3,3});
// Should yield an array of size 2 with View<char, short, int>,
// one from group C and one from Group D.
for (const auto& view : registry.get<char, short, int>())
{
std::cout << "View of group: " << view.name_of_group << std::endl;
std::cout << "char: " << int(std::get<char>(view.data)) << std::endl;
std::cout << "short: " << std::get<short>(view.data) << std::endl;
std::cout << "int: " << std::get<int>(view.data) << std::endl;
}
}
Trying the suggestion in the comments, the following code is as far as I got.
template <class Groups, std::size_t i, class ... Types>
constexpr bool is_match()
{
using group_type = std::tuple_element_t<i, Groups>;
bool match = is_subset_of<std::tuple<Types...>, typename group_type::type_set>;
return match;
}
template <class ... Types, class ... Group, std::size_t ... indices>
constexpr auto build_view_array(const std::tuple<Group...>& candidates, std::index_sequence<indices...>)
{
std::array views {
std::get<indices>(candidates).template get<Types...>()...
};
return views;
}
template <std::size_t i, class Groups, class TypeSet, std::size_t ... x>
constexpr auto get_matching_indices()
{
if constexpr (is_match<Groups, i, TypeSet>())
return std::index_sequence<x..., i>{};
else
return std::index_sequence<x...>{};
}
template <std::size_t i, std::size_t j, std::size_t ... rest, class Groups, class TypeSet, std::size_t ... x>
constexpr auto get_matching_indices()
{
if constexpr (is_match<Groups, i, TypeSet>())
return get_matching_indices<j, rest..., Groups, TypeSet, i, x...>();
else
return get_matching_indices<j, rest..., Groups, TypeSet, x...>();
}
template <class ... Types, class ... Group, std::size_t ... indices>
constexpr auto get_matches(const std::tuple<Group...>& candidates, std::index_sequence<indices...>)
{
constexpr auto matching_indices = get_matching_indices<indices..., std::tuple<Group...>, std::tuple<Types...>>();
constexpr auto views = build_view_array<Types...>(candidates, matching_indices);
return views;
}
It feels like it should work, but it won't compile due to the following error:
/Users/tedkleinbergman/Programming/ECS/temp.cpp:76:39: error: no matching function for call to 'get_matching_indices'
constexpr auto matching_indices = get_matching_indices<indices..., std::tuple<Group...>, std::tuple<Types...>>();
^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
/Users/tedkleinbergman/Programming/ECS/temp.cpp:92:16: note: in instantiation of function template specialization 'get_matches<char, short, int, Group<char>, Group<char, short>, Group<char, short, int>, Group<char, short, int, long long> , 0, 1, 2, 3>' requested here
return get_matches<T...>(this->groups, indices);
^
/Users/tedkleinbergman/Programming/ECS/temp.cpp:118:38: note: in instantiation of function template specialization 'Registry<Group<char>, Group<char, short>, Group<char, short, int>, Group<char, short, int, long long> >::get<char, short, int>' requested here
for (const auto& view : registry.get<char, short, int>())
^
/Users/tedkleinbergman/Programming/ECS/temp.cpp:57:16: note: candidate template ignored: invalid explicitly-specified argument for template parameter 'Groups'
constexpr auto get_matching_indices()
^
/Users/tedkleinbergman/Programming/ECS/temp.cpp:65:16: note: candidate template ignored: invalid explicitly-specified argument for template parameter 'rest'
constexpr auto get_matching_indices()
^
1 error generated.
First, start with an index_sequence filter:
template<std::size_t I>
using index_t = std::integral_constant<std::size_t, I>;
template<std::size_t I>
constexpr index_t<I> index = {};
template<std::size_t...Is, std::size_t...Js>
constexpr std::index_sequence<Is...,Js...> concatenate( std::index_sequence<Is...>, std::index_sequence<Js...> ) {
return {};
}
template <class Test>
constexpr auto filter_sequence(std::index_sequence<> sequence, Test test) {
return sequence;
}
template<std::size_t I0, std::size_t...Is, class Test>
constexpr auto filter_sequence( std::index_sequence<I0, Is...>, Test test )
{
constexpr auto tail = filter_sequence( std::index_sequence<Is...>{}, test );
if constexpr ( test(index<I0>) ) {
return concatenate( std::index_sequence<I0>{}, tail );
} else {
return tail;
}
}
we then use these primitives.
template <class Group, class ... Types>
constexpr auto get_match_indexes()
{
constexpr auto test = [](auto I){ return is_match<Group, I, Types...>(); };
constexpr auto indexes = std::make_index_sequence< std::tuple_size_v<Group> >{};
constexpr auto retval = filter_sequence( indexes, test );
return retval;
}
template<class ... Types, class Group, std::size_t...Is>
std::array<sizeof...Is, View<Types...>> get_matches(const Group& candidates, std::index_sequence<Is...> ) {
return {{
std::get<Is>(candidates).template get<Types...>(), ...
}};
}
template<class ... Types, class Group>
std::array<sizeof...Is, View<Types...>> get_matches(const Group& candidates ) {
return get_matches<Types...>( candidates, get_match_indexes<Group, Types...>() );
}
or something like that.
Note that some compilers may need to replace is_match<Group, I, Types...>() with is_match<Group, decltype(I)::value, Types...>().
There may be typos. This uses c++17 at the least.
filter_sequence uses O(n^2) template symbol length and O(n) recursive template instantiation depth. It can be improved to O(n lg n) length and O(lg n) depth with a tricky code; basically, you need to split Is... into As... and Bs... down the middle and recurse that way.
Here is a log-depth split of an index sequence:
template<class A, class B>
struct two_things {
A a;
B b;
};
template<class A, class B>
two_things(A,B)->two_things<A,B>;
template<class Seq>
constexpr auto split_sequence( index_t<0>, Seq seq ) {
return two_things{ std::index_sequence<>{}, seq };
}
template<std::size_t I0, std::size_t...Is>
constexpr auto split_sequence( index_t<1>, std::index_sequence<I0, Is...> seq ) {
return two_things{ std::index_sequence<I0>{}, std::index_sequence<Is...>{} };
}
template<std::size_t N, class Seq>
constexpr auto split_sequence( index_t<N>, Seq seq ) {
constexpr auto step1 = split_sequence( constexpr_index<N/2>, seq );
constexpr auto step2 = split_sequence( constexpr_index<N-N/2>, step1.b );
return two_things{ concatenate(step1.a, step2.a), step2.b };
}
template<std::size_t...Is>
constexpr auto halve_sequence( std::index_sequence<Is...> seq ) {
return split( index< (sizeof...(Is)) / 2u >, seq );
}
(two_things exists as a many-many-many times lighter tuple or pair than the std one).
That in turn lets you improve filter sequence.
template<std::size_t I, class Test>
constexpr auto filter_sequence( std::index_sequence<I> seq, Test test )
{
if constexpr ( test(constexpr_index<I>) ) {
return seq;
} else {
return std::index_sequence<>{};
}
}
template<std::size_t...Is, class Test>
constexpr auto filter_sequence( std::index_sequence<Is...> seq, Test test )
{
constexpr auto split = halve_sequence( seq );
constexpr auto head = filter_sequence( split.a, test );
constexpr auto tail = filter_sequence( split.b, test );
return concatenate(head, tail);
}
this version should compile faster and use less memory, especially for large numbers of elements. But you should start with the simpler one above, because (as I noted) there are probably plenty of tpyos.
Live example.
I am trying to write a function in order to generate arbitrarily nested vectors and initialize with the given specific value in C++. For example, auto test_vector = n_dim_vector_generator<2, long double>(static_cast<long double>(1), 1); is expected to create a "test_vector" object which type is std::vector<std::vector<long double>>. The content of this test_vector should as same as the following code.
std::vector<long double> vector1;
vector1.push_back(1);
std::vector<std::vector<long double>> test_vector;
test_vector.push_back(vector1);
The more complex usage of the n_dim_vector_generator function:
auto test_vector2 = n_dim_vector_generator<15, long double>(static_cast<long double>(2), 3);
In this case, the parameter static_cast<long double>(2) is as the data in vectors and the number 3 is as the push times. So, the content of this test_vector2 should as same as the following code.
std::vector<long double> vector1;
vector1.push_back(static_cast<long double>(2));
vector1.push_back(static_cast<long double>(2));
vector1.push_back(static_cast<long double>(2));
std::vector<std::vector<long double>> vector2;
vector2.push_back(vector1);
vector2.push_back(vector1);
vector2.push_back(vector1);
std::vector<std::vector<std::vector<long double>>> vector3;
vector3.push_back(vector2);
vector3.push_back(vector2);
vector3.push_back(vector2);
//...Totally repeat 15 times in order to create test_vector2
std::vector<...std::vector<long double>> test_vector2;
test_vector2.push_back(vector14);
test_vector2.push_back(vector14);
test_vector2.push_back(vector14);
The detail to implement n_dim_vector_generator function is as follows.
#include <iostream>
#include <vector>
template <typename T, std::size_t N>
struct n_dim_vector_type;
template <typename T>
struct n_dim_vector_type<T, 0> {
using type = T;
};
template <typename T, std::size_t N>
struct n_dim_vector_type {
using type = std::vector<typename n_dim_vector_type<T, N - 1>::type>;
};
template<std::size_t N, typename T>
typename n_dim_vector_type<T,N>::type n_dim_vector_generator(T t, unsigned int);
template <std::size_t N, typename T>
typename n_dim_vector_type<T, N>::type n_dim_vector_generator<N, T>(T input_data, unsigned int push_back_times) {
if (N == 0)
{
return std::move(input_data);
}
typename n_dim_vector_type<T, N>::type return_data;
for (size_t loop_number = 0; loop_number < push_back_times; loop_number++)
{
return_data.push_back(n_dim_vector_generator<N - 1, T>(input_data, push_back_times));
}
return return_data;
}
As a result, I got an error 'return': cannot convert from 'long double' to 'std::vector<std::vector<long double,std::allocator<long double>>,std::allocator<std::vector<long double,std::allocator<long double>>>>' I know that it caused by if (N == 0) block which is as the terminate condition to recursive structure. However, if I tried to edit the terminate condition into separate form.
template <typename T>
inline T n_dim_vector_generator<0, T>(T input_data, unsigned int push_back_times) {
return std::move(input_data);
}
template <std::size_t N, typename T>
typename n_dim_vector_type<T, N>::type n_dim_vector_generator<N, T>(T input_data, unsigned int push_back_times) {
typename n_dim_vector_type<T, N>::type return_data;
for (size_t loop_number = 0; loop_number < push_back_times; loop_number++)
{
return_data.push_back(n_dim_vector_generator<N - 1, T>(input_data, push_back_times));
}
return return_data;
}
The error 'n_dim_vector_generator': illegal use of explicit template arguments happened. Is there any better solution to this problem?
The develop environment is in Windows 10 1909 with Microsoft Visual Studio Enterprise 2019 Version 16.4.3
To achieve your specific mapping of:
auto test_vector = n_dim_vector_generator<2, long double>(2, 3)
to a 3x3 vector filled with 2's, your template can be a bit simpler if you take advantage of this vector constructor:
std::vector<std::vector<T>>(COUNT, std::vector<T>(...))
Since vector is copyable, this will fill COUNT slots with a different copy of the vector. So...
template <size_t N, typename T>
struct n_dim_vector_generator {
using type = std::vector<typename n_dim_vector_generator<N-1, T>::type>;
type operator()(T value, size_t size) {
return type(size, n_dim_vector_generator<N-1, T>{}(value, size));
}
};
template <typename T>
struct n_dim_vector_generator<0, T> {
using type = T;
type operator()(T value, size_t size) {
return value;
}
};
usage:
auto test_vector = n_dim_vector_generator<2, long double>{}(2, 3);
Demo: https://godbolt.org/z/eiDAUG
For the record, to address some concerns from the comments, C++ has an idiomatic, initializable, contiguous-memory class equivalent of a multi-dimension C array: a nested std::array:
std::array<std::array<long double, COLUMNS>, ROWS> test_array = { /*...*/ };
for (auto& row : test_array)
for (auto cell : row)
std::cout << cell << std::endl;
If you wanted to reduce the boilerplate to declare one, you can use a struct for that:
template <typename T, size_t... N>
struct multi_array;
template <typename T, size_t NFirst, size_t... N>
struct multi_array<T, NFirst, N...> {
using type = std::array<typename multi_array<T, N...>::type, NFirst>;
};
template <typename T, size_t NLast>
struct multi_array<T, NLast> {
using type = std::array<T, NLast>;
};
template <typename T, size_t... N>
using multi_array_t = typename multi_array<T, N...>::type;
Then to use:
multi_array_t<long double, ROWS, COLUMNS> test_array = { /*...*/ };
for (auto& row : test_array)
for (auto cell : row)
std::cout << cell << std::endl;
This is allocated on the stack, like a C array. That will eat up your stack space for a big array of course. But you can make a decorator range around std::unique_ptr to make a pointer to one a bit easier to access:
template <typename T, size_t... N>
struct dynamic_multi_array : std::unique_ptr<multi_array_t<T, N...>> {
using std::unique_ptr<multi_array_t<T, N...>>::unique_ptr;
constexpr typename multi_array_t<T, N...>::value_type& operator [](size_t index) { return (**this)[index]; }
constexpr const typename multi_array_t<T, N...>::value_type& operator [](size_t index) const { return (**this)[index]; }
constexpr typename multi_array_t<T, N...>::iterator begin() { return (**this).begin(); }
constexpr typename multi_array_t<T, N...>::iterator end() { return (**this).end(); }
constexpr typename multi_array_t<T, N...>::const_iterator begin() const { return (**this).begin(); }
constexpr typename multi_array_t<T, N...>::const_iterator end() const { return (**this).end(); }
constexpr typename multi_array_t<T, N...>::const_iterator cbegin() const { return (**this).cbegin(); }
constexpr typename multi_array_t<T, N...>::const_iterator cend() const { return (**this).cend(); }
constexpr typename multi_array_t<T, N...>::size_type size() const { return (**this).size(); }
constexpr bool empty() const { return (**this).empty(); }
constexpr typename multi_array_t<T, N...>::value_type* data() { return (**this).data(); }
constexpr const typename multi_array_t<T, N...>::value_type* data() const { return (**this).data(); }
};
(let the buyer beware if you use those methods with nullptr)
Then you can still brace-initialize a new expression and use it like a container:
dynamic_multi_array<long double, ROWS, COLUMNS> test_array {
new multi_array_t<long double, ROWS, COLUMNS> { /* ... */ }
};
for (auto& row : test_array)
for (auto cell : row)
std::cout << cell << std::endl;
Demo: https://godbolt.org/z/lUwVE_
I would like iterate over an tuple in some way with member function templates (for later create a new type of tuple from the given template type T).
However, the break condition (function) is not used so I get this error:
invalid use of incomplete type: 'class std::tuple_element<0ul, std::tuple<> >'
The problem seems to be, that even though N == size of the tuple, std::tuple_element_t is evaluated for N != size and not handled as SFINAE.
Both examples showing different not working solutions. What do I wrong?
Note: The function for evaluated with is_same is omitted to minimize the example.
#include <type_traits>
#include <tuple>
template<typename...Ts>
struct A
{
using tuple = std::tuple<Ts...>;
static constexpr std::size_t size = sizeof...(Ts);
template<typename T, std::size_t N = 0, typename std::enable_if_t<N == size>* = nullptr>
int get()
{
return 0;
}
template<typename T, std::size_t N = 0, typename std::enable_if_t<N != size && !std::is_same<T, std::tuple_element_t<N, tuple>>::value>* = nullptr>
int get()
{
return get<T, N + 1>() - 1;
}
};
int main()
{
A<int, float, double, float, float> a;
return a.get<char>();
}
Live Example 1
#include <type_traits>
#include <tuple>
template<typename...Ts>
struct A
{
using tuple = std::tuple<Ts...>;
static constexpr std::size_t size = sizeof...(Ts);
template<typename T, std::size_t N = 0>
std::enable_if_t<N == size, int> get()
{
return 0;
}
template<typename T, std::size_t N = 0>
std::enable_if_t<N != size && !std::is_same<T, std::tuple_element_t<N, tuple>>::value, int> get()
{
return get<T, N + 1>() - 1;
}
};
int main()
{
A<int, float, double, float, float> a;
return a.get<char>();
}
Live Example 2
One workaround would be to use a third function to evaluate until sizeof tuple - 2 and than evaluate sizeof tuple - 1, but Is this really necessary?
#include <type_traits>
#include <tuple>
template<typename...Ts>
struct A
{
using tuple = std::tuple<Ts...>;
static constexpr std::size_t size = sizeof...(Ts);
template<typename T, std::size_t N = 0, typename std::enable_if_t<(N == size - 1) && std::is_same<T, std::tuple_element_t<N, tuple>>::value>* = nullptr>
int get()
{
return 1;
}
template<typename T, std::size_t N = 0, typename std::enable_if_t<(N == size - 1) && !std::is_same<T, std::tuple_element_t<N, tuple>>::value>* = nullptr>
int get()
{
return 2;
}
template<typename T, std::size_t N = 0, typename std::enable_if_t<(N < size - 1) && !std::is_same<T, std::tuple_element_t<N, tuple>>::value>* = nullptr>
int get()
{
return get<T, N + 1>() - 1;
}
};
int main()
{
A<int, float, double, float, float> a;
return a.get<char>();
}
Live Example 3
As suggested by #PiotrSkotnicki in the comments to the question, here is your second example once fixed:
#include <type_traits>
#include <tuple>
template<typename...Ts>
struct A
{
using tuple = std::tuple<Ts...>;
static constexpr std::size_t size = sizeof...(Ts);
template<typename T, std::size_t N = 0>
std::enable_if_t<N == size-1, int>
get()
{
return std::is_same<T, std::tuple_element_t<N, tuple>>::value ? N : 0;
}
template<typename T, std::size_t N = 0>
std::enable_if_t<N != size-1 && !std::is_same<T, std::tuple_element_t<N, tuple>>::value, int>
get()
{
return get<T, N + 1>() - 1;
}
};
int main()
{
A<int, float, double, float, float> a;
return a.get<char>();
}
What was the problem?
Consider the following line:
std::enable_if_t<N != size && !std::is_same<T, std::tuple_element_t<N, tuple>>::value, int> get()
In this case, N was substituted in order to evaluate the condition of the enable_if, even when N == size (substitution is mandatory to find that N == size indeed).
Thus, the tuple_element_t (let me say) issued an out of range and that's why you got the compilation error.
I've simply updated your code to avoid reaching size while iterating over N. It was a matter of using size-1 as a value on which to switch between functions.
In a comment to this answer the OP said:
It does solve the problem but not for automatic type return type deduction based on which function is used (returning int was just an example). I should have been clearer on this.
It follows a minimal, working example that probably solves the problem also for that.
It's far easier to reason in terms of inheritance and tag dispatching in this case, so as to reduce the boilerplate due to sfinae. Moreover, one can use specializations to introduce specific behaviors for specific types if needed.
The final case, the one for the type that is not part of the types list, is easily handled in a dedicated function as well.
It follows the code:
#include <type_traits>
#include <tuple>
template<typename>
struct tag {};
template<typename...>
struct B;
template<typename T, typename... Ts>
struct B<T, Ts...>: B<Ts...> {
using B<Ts...>::get;
auto get(tag<T>) {
return T{};
}
};
template<>
struct B<> {
template<typename T>
auto get(tag<T>) {
return nullptr;
}
};
template<typename...Ts>
struct A: private B<Ts...>
{
template<typename T>
auto get() {
return B<Ts...>::get(tag<T>{});
}
};
int main()
{
A<int, float, double, float, float> a;
static_assert(std::is_same<decltype(a.get<char>()), std::nullptr_t>::value, "!");
static_assert(std::is_same<decltype(a.get<float>()), float>::value, "!");
}
What about using an additional struct that, with partial specialization, can avoid the use of std::tuple_element_t ?
I mean, something like
template <typename T, std::size_t N>
struct checkType
{ constexpr static bool value
= std::is_same<T, std::tuple_element_t<N, tuple>>::value; };
template <typename T>
struct checkType<T, size>
{ constexpr static bool value = false; };
template <typename, std::size_t N = 0>
std::enable_if_t<N == size, int> get ()
{ return 0; }
template <typename T, std::size_t N = 0>
std::enable_if_t<(N < size) && ! checkType<T, N>::value, int> get()
{ return get<T, N + 1>() - 1; }
For example:
std::tuple<int, double> t;
void* p = &std::get<1>(t);
Now I want to get p's index by some function like
template<typename... Ts>
size_t index(void* p, std::tuple<Ts...> const& t)
{
...
}
Sure the result is 1 for this example. I am interested in how to implement the function to get the index when p is obtained by ways other than the explicit index.
Something you do not need in C++14, a mini indexes library:
template<unsigned...>struct indexes{using type=indexes;};
template<unsigned Cnt,unsigned...Is>
struct make_indexes:make_indexes<Cnt-1,Cnt-1,Is...>{};
template<unsigned...Is>
struct make_indexes<0,Is...>:indexes<Is...>{};
template<unsigned Cnt>
using make_indexes_t=typename make_indexes<Cnt>::type;
Function that does actual work. Creates an array pointers-to-elements. Then searches for p. The nullptr and -1 make it work for empty tuples.
template<unsigned...Is,class Tuple>
unsigned index_of(indexes<Is...>,void const* p, Tuple const&t){
void const* r[]={ nullptr, &std::get<Is>(t)... };
auto it = std::find( std::begin(r), std::end(r), p );
if (it==std::end(r))
return -1;
else
return (it-std::begin(r))-1;
}
you can put that in a details namespace.
The final function:
template<class...Ts>
unsigned index_of( void const*p, std::tuple<Ts...> const& t ){
return index_of( make_indexes_t<sizeof...(Ts)>{}, p, t );
}
return unsigned(-1) on failure.
Logarithmic complexity in terms of comparisons is possible - under the assumption that adresses of consecutive elements are decreasing:
#include <iostream>
#include <algorithm>
#include <tuple>
// minimalistic index-list implementation
template <std::size_t...> struct index_list {using type = index_list;};
template <typename, typename> struct concat;
template <std::size_t... i, std::size_t... j>
struct concat<index_list<i...>, index_list<j...>> : index_list<i..., j...> {};
// (Inefficient) linear recursive definition of make_indices:
template <std::size_t N> struct make_indices :
concat<typename make_indices<N-1>::type, index_list<N-1>> {};
template <> struct make_indices<0> : index_list<> {};
template <> struct make_indices<1> : index_list<0> {};
// </>
template <typename T, typename = typename make_indices<std::tuple_size<T>::value>::type> struct offsets;
template <typename... T, std::size_t... indices>
struct offsets<std::tuple<T...>, index_list<indices...>>
{
static std::size_t index_of(void* p, std::tuple<T...> const& t)
{
static const std::tuple<T...> tuple;
static const std::ptrdiff_t array[]
{
reinterpret_cast<char const*>(&std::get<indices>(tuple)) - reinterpret_cast<char const*>(&tuple)...
};
auto offset_p_t = static_cast<char const*>(p) - reinterpret_cast<char const*>(&t);
auto iter = std::lower_bound( std::begin(array), std::end(array), offset_p_t, std::greater<>() );
if (iter == std::end(array)
|| *iter != offset_p_t)
return -1;
return iter - std::begin(array);
}
};
template <typename... T>
std::size_t index_of(void* p, std::tuple<T...> const& t) {return offsets<std::tuple<T...>>::index_of(p, t);}
int main ()
{
std::tuple<int, double, std::string> t;
void* p = &std::get<2>(t);
std::cout << index_of(p, t);
}
Demo.