My c++ program terminated without taking the input.What should i do? - c++

Question

The code below,works fine but it does not take any value for age and terminates.`
#include <iostream>
#include <string>
using namespace std;
class user{
int id,level=1,kills=0,age;
char name[20],server[40];
public:
void get(){
cout<<"Enter your name:";
cin>>name[20];
cout<<"Enter your age:";
cin>>age;
}
};
int main(){
user u;
u.get();
return 0;
}
/*Output
Enter your name:Jack
Enter your age:
C:\Users\user\documents\c++
*/
In the output section ,age is not accepted and the program terminates.

Answer 1

Use string name instead of char name[20] to take multi-character value. char name[20] will terminate after taking a single character.
Also, its valued will not be displayed on giving output.
Modified code for reference.
#include <iostream>
#include <string>
using namespace std;
class user{
int id,level=1,kills=0,age;
string name,server;
public:
void get(){
cout<<"Enter your name:";
cin>>name;
cout<<"Enter your age:";
cin>>age;
}
//test output
void put(){
cout<<name<<endl;
cout<<age<<endl;
}
};
int main(){
user u;
u.get();
//test
u.put();
return 0;
}

Answer 2

Just modify the code to this :
#include <iostream>
#include <string>
using namespace std;
class user{
int id,level=1,kills=0,age;
char name[20],server[40];
public:
void get(){
cout<<"Enter your name:";
cin>>name; // changes done here
cout<<"Enter your age:";
cin>>age;
}
};
int main(){
user u;
u.get();
return 0;
}
Job Done :)

Answer 3

Your problem is here:
cin>>name[20];
Why:
'name[20]' is 21th char of the array you defined before. It counts from 0! As this, it is simply a single char. If you now enter more than a single char, the rest is read by the cin>>age.
Example:
cout<<"Enter your name:";
cin>>name[20];
cout<<"Enter your age:";
cin>>age;
std::cout << "Name " << name << std::endl;
std::cout << "Age " << age << std::endl;
And entering:
Enter your name:1234
Enter your age:Name
Age 234
As you see, the '1' is now in the name and the rest is stored in age.
But attention: You defined your array as `name[20], which means you have 0..19 elements. Accessing name[20] is wrong!
But what you simply want to do was:
cin >> name;

Answer 4

The easiest way to handle strings (a long sequence of characters) or even the strings that have spaces just use the following library in C++.
#include <bits/stdc++.h>
Then just declare a string variable.
String name;
Now you can save a very long string without any error. e.g.
name = jshkad skshdur kslsjue djsdf2341;
and you'll get no error, enjoy ;)