Get regex to match multiple instances of the same pattern - regex

Question

So I have this regex - regex101:
\[shortcode ([^ ]*)(?:[ ]?([^ ]*)="([^"]*)")*\]
Trying to match on this string
[shortcode contact param1="test 2" param2="test1"]
Right now, the regex matches this:
[contact, param2, test1]
I would like it to match this:
[contact, param1, test 2, param2, test1]
How can I get regex to match the first instance of the parameters pattern, rather than just the last?

Answer 1

You may use
'~(?:\G(?!^)\s+|\[shortcode\s+(\S+)\s+)([^\s=]+)="([^"]*)"~'
See the regex demo
Details
(?:\G(?!^)\s+|\[shortcode\s+(\S+)\s+) - either the end of the previous match and 1+ whitespaces right after (\G(?!^)\s+) or (|)
\[shortcode - literal string
\s+ - 1+ whitespaces
(\S+) - Group 1: one or more non-whitespace chars
\s+ - 1+ whitespaces
([^\s=]+) - Group 2: 1+ chars other than whitespace and =
=" - a literal substring
([^"]*) - Group 3: any 0+ chars other than "
" - a " char.
PHP demo
$re = '~(?:\G(?!^)\s+|\[shortcode\s+(\S+)\s+)([^\s=]+)="([^"]*)"~';
$str = '[shortcode contact param1="test 2" param2="test1"]';
$res = [];
if (preg_match_all($re, $str, $matches, PREG_SET_ORDER, 0)) {
foreach ($matches as $m) {
array_shift($m);
$res = array_merge($res, array_filter($m));
}
}
print_r($res);
// => Array( [0] => contact [1] => param1 [2] => test 2 [3] => param2 [4] => test1 )

Answer 2

Try using the below regex.
regex101
Below is your use case,
var testString = '[shortcode contact param1="test 2" param2="test1"]';
var regex = /[\w\s]+(?=[\="]|\")/gm;
var found = paragraph.match(regex);
If you log found you will see the result as
["shortcode contact param1", "test 2", " param2", "test1"]
The regex will match all the alphanumeric character including the underscore and blank spaces only if they are followed by =" or ".
I hope this helps.