Recursive function outputs a wrong value - c++

Question

In this code the output is 'r' instead of 'r0'
Instead of doing the operations it outputs me the first 'r' (equals 100) and does not do the process.
I´m trying to program an operation like (x_0 = x + (nt²/(2(x+(n(t-1)²/2(x+(n(t-3)²/2(x + (n(t-4)²...)²)²)²)²)²)²)²)²) in where the process is repeated until the variable 't' is '0'(because each time the operation is done 't' get a '-1').
#include <iostream>
#include "math.h"
using namespace std;
int operation(float r,
float r0,
float recursiva,
float operacion,
float recursivaPrincipal2,
float recursivaPrincipal,
float p,
float n,
long long t,
float q,
float potenciaQ,
float c,
float potenciaC,
float t2,
float division);
float r = 100;
float t = 10000;
float r0;
float recursiva;
float operacion;
float recursivaPrincipal2;
float recursivaPrincipal;
float p;
float n;
float q;
float potenciaQ;
float c;
float potenciaC;
float t2;
float division;
int main() {
r0 = r + operacion;
potenciaQ = pow(10,10);
q = 6 * potenciaQ;
potenciaC = pow(10,2);
c = 5 * potenciaC;
while (t = 10000, t = t - 1, t > 0) {
t2 = t * t;
n = q * t2;
operacion = n / recursivaPrincipal;
recursivaPrincipal2 = recursiva * recursiva;
recursivaPrincipal = 2 * recursivaPrincipal2;
recursiva = r + operacion;
if (t == 0) {
system("pause");
return 0;
}
cout << "Solucion: " << r0 << endl;
}
}
i want to do something like this
I'm so sorry if this code offended you (comments look like it) but I'm not very good, this is my first c++ code (and last I think)

Answer 1

The answer is based on what i get from your question
Please do expand your mathematical expression for t=3 and append an image of it
by far what i got from your expression you need this
float func(int t,int n,int x)
{
if (t==1)
{
return (x + (n/2)*(n/2)) * (x + (n/2)*(n/2));
}
return x + (n*t*t)/(2*func(t-1,n,x)) ;
}
According to the picture you have uploaded this is my code
Don't use 0 for n
#include<iostream>
using namespace std;
double partSolver(int x,int p, int n)
{
if(n==0) return 2*x*x;
double val = x - ( (p*n*n) / partSolver(x,p,n-1) );
return 2*val*val ;
}
double solver(int x,int p,int n)
{
return (n*n * 2) / partSolver(x,p,n-1);
}
int main()
{
cout<<"The Solution is: "<<solver(3,2,1)<<endl;
return 0;
}