Windows FileOpenDialog returning wrong path - c++

Question

I want to have a simple file dialog in which the user can select a folder like the following.
When executing the following code snippet on Windows 10 build with the current Visual Studio 2017, I run into a weird problem. What I do
create a new folder within the opened filedialog
type in a new name for the folder
while the text cursor is still visible for the new folder, I click on "Select Folder".
Instead of the name I typed in for the selected folder, pszFilePath is "New folder".
Instead I would expect the Dialog to first remove the focus from the new folder when I click on "Select Folder" and then I need a second click, to actually select the folder.
Strangely enough this doesn't happen on all Windows 10 systems I tested this code on. Sometimes I can't reproduce the issue.
Anyone with the same problem and maybe a workaround?
#include <shobjidl.h>
#include <windows.h>
void winOpenFileDialog ()
{
HRESULT hr = CoInitializeEx (NULL, COINIT_APARTMENTTHREADED | COINIT_DISABLE_OLE1DDE);
if (SUCCEEDED (hr))
{
IFileOpenDialog* pFileOpen;
// Create the FileOpenDialog object.
hr = CoCreateInstance (CLSID_FileOpenDialog, NULL, CLSCTX_ALL, IID_IFileOpenDialog,
reinterpret_cast<void**> (&pFileOpen));
if (SUCCEEDED (hr))
{
pFileOpen->SetOptions (FOS_PICKFOLDERS);
// Show the Open dialog box.
hr = pFileOpen->Show (NULL);
FILEOPENDIALOGOPTIONS opt;
pFileOpen->GetOptions (&opt);
// Get the file name from the dialog box.
if (SUCCEEDED (hr))
{
IShellItem* pItem;
hr = pFileOpen->GetResult (&pItem);
if (SUCCEEDED (hr))
{
PWSTR pszFilePath;
hr = pItem->GetDisplayName (SIGDN_FILESYSPATH, &pszFilePath);
// Display the file name to the user.
if (SUCCEEDED (hr))
{
MessageBox (NULL, pszFilePath, L"File Path", MB_OK);
CoTaskMemFree (pszFilePath);
}
pItem->Release ();
}
}
pFileOpen->Release ();
}
CoUninitialize ();
}
}