Condensing output into single line - c++

Question

I'm working on an assignment that allows a user to enter integers (up to 20 entries) and displays a list of odd entries and even entries, when '0' is entered. The assignment requires the user to input a single integer per line.
I have managed to extract and segregate the odd and even entries, however the assignment requires that the odds be displayed on a single line, and the evens on another single line below that.
For example, if the user entered integers 1-9:
Odds: 1 3 5 7 9
Evens: 2 4 6 8
Currently, it returns:
Even: 2
Even: 4
Even: 6
Odd: 1
Odd: 3
Odd: 5
etc...
I am hoping that my program will even allow this, but I suspect the problem lies in the way I have set up the loops.
#include <iostream>
using namespace std;
bool isEven(int x) {
if ((x%2) == 0) {
return true;
} else {
return false;
}
}
int main(){
const int x = 20;
int list[x];
int counter;
cout<<"Enter up to 20 integers or press 0 to display list"<<endl;
for (counter=0; counter<x; counter++) { //main loop
cout<<"Enter number: ";
cin>>list[counter];
if (list[counter]==0) {
for (int i =0; i<counter; i++) {
if (isEven(list[i])==true) {
cout<<"Even: "<<list[i];
}
}
for (int j = 0; j<counter; j++) {
if (isEven(list[j])==false) {
cout<<"Odd: "<<list[j];
}
}
break;
}
}
return 0;
}

Answer 1

Split input and output to separate loops:
for (counter=0; counter<x; counter++) {
// input
}
for (counter=0; counter<x; counter++) {
// output
}
Print labels before going through each value and use \n to print a newline:
cout << "Even: ";
for (int i =0; i<counter; i++) {
if (isEven(list[i])==true) {
cout << list[i];
}
}
cout << "\nOdd: ";
for (int j = 0; j<counter; j++) {
if (isEven(list[j])==false) {
cout << list[j];
}
}
cout << "\n";