The OpenGL gl_VertexID page clearly states:
gl_VertexID is a vertex language input variable that holds an integer index for the vertex
while the OpenGL Vertex Shader page says it is
the index of the vertex currently being processed. When using non-indexed rendering, it is the effective index of the current vertex (the number of vertices processed + the first value).
May I assume 100% that in non-indexed rendering commands gl_VertexID is the int vertex index in the bound vertex buffer? or is it rather the index of the vertex as being processed by the rendering command (which may or may be not follow the order in the vertex buffer)
The doubt comes form the description part inside (), as for the number of processed vertices to be equal to the index of the current vertex in the vertex buffer, the vertices must be processed linearly. May I assume it will always be the case? Or maybe there are OpenGL implementations that process vertices backwards, or in buckets, etc..
tl;dr: yes, gl_VertexID is always going to be the logical index of the respective vertex in the sequence of primitives specified by your draw call (effectively the index from where in a vertex buffer the vertex data would be read). It does not depend on the way or order in which vertices are actually processed (if it did, that would make it a rather useless feature since it would provide no reliable behavior whatsoever).
From the OpenGL 4.6 specification (11.1.3.9 Shader Inputs):
gl_VertexID holds the integer index i implicitly passed by DrawArrays or
one of the other drawing commands defined in section 10.4.
and from 10.4:
The index of any element transferred to the GL by DrawArraysOneInstance
is referred to as its vertex ID, and may be read by a vertex shader as gl_VertexID. The vertex ID of the ith element transferred is first + i.
and
The index of any element transferred to the GL by DrawElementsOneInstance
is referred to as its vertex ID, and may be read by a vertex shader as
gl_VertexID. The vertex ID of the ith element transferred is the sum of
basevertex and the value stored in the currently bound element array buffer at offset indices + i.
Now, the behavior of all the non-indexed draw calls is specified in terms of the abstract DrawArraysOneInstance command. And the behavior of all the indexed draw calls is specified in terms of the abstract DrawElementsOneInstance command. Without going into any more detail (you can go dig around in section 10.4. if you want to find out more), all the above basically means that if you draw with an index buffer, then gl_VertexID is going to be the index of the vertex as specified by the index buffer and if you draw without an index buffer, then gl_VertexID is going to be the index of the vertex as given by your primitive sequence…
Related
https://www.khronos.org/opengl/wiki/Vertex_Shader says that "The vertex shader will be executed roughly once for every vertex in the stream."
If we are rendering a cube, vertex could refer to the 8 vertexes of the entire shape (meaning One). Or, it could refer to the 24 vertexes of the 6 squares with 4 corners each (meaning Two).
As I understand it, if a cube is being rendered, the 8 corners of the cube have to be converted into the coordinate system of the viewer. But also there are texture coordinates that have to be calculated based on the individual textures associate with each face of the cube.
So if "vertex" is intended by meaning One, then why are textures being supplied to a shader which is a per face concept? Or if "vertexes" are being fed to the shader by meaning two, does that mean that the coordinate transforms and projections are all being done redundantly? Or is something else going on? These guides seem to have an allergy to actually saying what is going on.
The page on Vertex Specification could be a bit more clear on this, but a vertex is just a single index in the set of vertex arrays as requested by a rendering operation.
That is, you render some number of vertices from your vertex arrays. You could be specifying these vertices as a range of indices from a given start index to an end index (glDrawArrays), or you could specify a set of indices in order to use (glDrawElements). Regardless of how you do it, you get one vertex for each datum specified by your rendering command. If you render 10 indices with indexed rendering, you get 10 vertices.
Each vertex is composed of data fetched from the active vertex arrays in the currently bound VAO. Given the index for that vertex, a value is fetched from each active array at that index. Each individual array feeds a vertex attribute, which is passed to the vertex shader.
A vertex shader operates on the attributes of a vertex (passed as in qualified variables).
The relationship between a "vertex" and your geometry's vertices is entirely up to you. Vertices usually include positions as part of their vertex attributes, but they usually also include other stuff. The only limitation is that the value fetched for each attribute of a particular vertex always uses the same vertex index.
How you live within those rules is up to you and your data.
Does the Geometry Shader affects the buffer of vertices and indices (VBO and EBO data in GPU memory) initially specified in the cpu side?
For example, suppose I have a vertex buffer containing three vertices, each with some attributes attached to it. Suppose then these three vertices are given to the geometry shader as input and the geometry shader outputs out a large set of vertices based of off the first three where it started with, generating thus a new polygon made up of more than 3 vertices. Does this process alters the content of the element array and vertex buffers?
Only thing I know is that of course it doesn't get altered. Because otherwise the next rendering call would generate even more vertices and that would be a mess. So where does OpenGL store the new generated vertices?
Suppose then these three vertices are given to the geometry shader as input
That doesn't happen. The GS is fed by the vertex shader's outputs. GSs never have any direct contact with the initial vertex data.
So where does OpenGL store the new generated vertices?
Wherever the implementation needs to. The rasterizer hardware will generally have a small buffer for primitive data to be rasterized. That's where the GS outputs will go.
But that's an implementation detail which is not exposed to OpenGL.
I'm rendering a line that is composed of triangles in OpenGL.
Right now I have it working where:
Vertex buffer: {v0, v1, v2, v3}
Index buffer (triangle strip): {0, 1, 2, 3}
The top image is the raw data passed into the vertex shader and the bottom is the vertex shader output after applying an offset to v1 and v3 (using a vertex attribute).
My goal is to use one vertex per point on the line and generate the offset some other way. I was looking at gl_VertexID, but I want something more like an element ID. Here's my desired setup:
Vertex buffer: {v0, v2}
Index buffer (triangle strip): {0, 0, 1, 1}
and use an imaginary gl_ElementID % 2 to offset every other vertex.
I'm trying to avoid using geometry shaders or additional vertex attributes. Is there any way of doing this? I'm open to completely different ideas.
I can think of one way to avoid the geometry shader and still work with a compact representation: instanced rendering. Just draw many instances of one quad (as a triangle strip), and define the two positions as per-instance attributes via glVertexAttribDivisor().
Note that you don't need a "template quad" with 4 vertices at all. You just need conceptually two attributes, one for your start point, and one for your end point. (If you work in 2D, you can fuse that into one vec4, of course). In each vertex shader invocation, you will have access to both points, and can construct the final vertex position based on that and the value of gl_VertexID (which will only be in range 0 to 3). That way, you can get away with exactly that vertex array layout of two points per line segment you are aiming for, and still only need a single draw call and a vertex shader.
No, that is not possible, because each vertex is only processed once. So if you're referencing a vertex 10 times with an index buffer, the corresponding vertex shader is still only executed one time.
This is implemented in hardware with the Post Transform Cache.
In the absolute best case, you never have to process the same vertex
more than once.
The test for whether a vertex is the same as a previous one is
somewhat indirect. It would be impractical to test all of the
user-defined attributes for inequality. So instead, a different means
is used.
Two vertices are considered equal (within a single rendering command)
if the vertex's index and instance count are the same (gl_VertexID
and gl_InstanceID in the shader). Since vertices for non-indexed
rendering are always increasing, it is not possible to use the post
transform cache with non-indexed rendering.
If the vertex is in the post transform cache, then that vertex data is
not necessarily even read from the input vertex arrays again. The
process skips the read and vertex shader execution steps, and simply
adds another copy of that vertex's post-transform data to the output
stream.
To solve your problem I would use a geometry shader with a line (or line strip) as input and a triangle strip as output. With this setup you could get rid of the index buffer, since it's only working on lines.
I am writing an OpenGL3+ application and have some confusion about the use of VAOs. Right now I just have one VAO, a normalised quad set around the origin. This single VAO contains 3 VBOs; one for positions, one for surface normals, and one GL_ELEMENT_ARRAY_BUFFER for indexing (so I can store just 4 vertices, rather than 6).
I have set up some helper methods to draw objects to the scene, such as drawCube() which takes position and rotation values and follows the procedure;
Bind the quad VAO.
Per cube face:
Create a model matrix that represents this face.
Upload the model matrix to the uniform mat4 model vertex shader variable.
Call glDrawElements() to draw the quad into the position for this face.
I have just set about the task of adding per-cube colors and realised that I can't add my color VBO to the single VAO as it will change with each cube, and this doesn't feel right.
I have just read the question; OpenGL VAO best practices, which tells me that my approach is wrong, and that I should use more VAOs to save the work of setting the whole scene up every time.
How many VAOs should be used? Clearly my approach of having 1 is not optimal, should there be a VAO for every static surface in the scene? What about ones that move?
I am writing to a uniform variable for each vertex, is that correct? I read that uniform shader variables should not change mid-frame, if I am able to write different values to my uniform variable, how do uniforms differ from simple in variables in a vertex shader?
Clearly my approach of having 1 is not optimal, should there be a VAO for every static surface in the scene?
Absolutely not. Switching VAOs is costly. If you allocate one VAO per object in your scene, you need to switch the VAO before rendering such objects. Scale that up to a few hundred or thousand objects currently visible and you get just as much VAO changes. The questions is, if you have multiple objects which share a common memory layout, i.e. sizes/types/normalization/strides of elements are the same, why would you want to define multiple VAOs that all store the same information? You control the offset where you want to start pulling vertex attributes from directly with a corresponding draw call.
For non-indexed geometry this is trivial, since you provide a first (or an array of offsets in the multi-draw case) argument to gl[Multi]DrawArrays*() which defines the offset into the associated ARRAY_BUFFER's data store.
For indexed geometry, and if you store indices for multiple objects in a single ELEMENT_ARRAY_BUFFER, you can use gl[Multi]DrawElementsBaseVertex to provide a constant offset for indices or manually offset your indices by adding a constant offset before uploading them to the buffer object.
Being able to provide offsets into a buffer store also implies that you can store multiple distinct objects in a single ARRAY_BUFFER and corresponding indices in a single ELEMENT_ARRAY_BUFFER. However, how large buffer objects should be depends on your hardware and vendors differ in their recommendations.
I am writing to a uniform variable for each vertex, is that correct? I read that uniform shader variables should not change mid-frame, if I am able to write different values to my uniform variable, how do uniforms differ from simple in variables in a vertex shader?
First of all, a uniforms and shader input/output variables declared as in/out differ in various instances:
input/output variables define an interface between shader stages, i.e. output variables in one shader stage are backed by a corresponding and equally named input variable in the following stage. A uniform is available in all stages if declared with the same name and is constant until changed by the application.
input variables inside a vertex shader are filled from an ARRAY_BUFFER. Uniforms inside a uniform block are backed a UNIFORM_BUFFER.
input variables can also be written directly using the glVertexAttrib*() family of functions. single uniforms are written using the glUniform*() family of functions.
the values of uniforms are program state. the values of input variables are not.
The semantic difference should also be obvious: uniforms, as their name suggests, are usually constant among a set of primitives, whereas input variables usually change per vertex or fragment (due to interpolation).
EDIT: To clarify and to factor in Nicol Bolas' remark: Uniforms cannot be changed by the application for a set of vertices submitted by a single draw call, neither can vertex attributes by calling glVertexAttrib*(). Vertex shader inputs backed by a buffer objects will change either once per vertex or at some specific rate set by glVertexAttribDivisor.
EDIT2: To clarify how a VAO can theoretically store multiple layouts, you can simply define multiple arrays with different indices but equal semantics. For instance,
glVertexAttribPointer(0, 4, ....);
and
glVertexAttribPointer(1, 3, ....);
could define two arrays with indices 0 and 1, component sized 3 and 4 and both refer to position attributes of vertices. However, depending on what you want to render, you can bind a hypothetical vertex shader input
// if you have GL_ARB_explicit_attrib_location or GL3.3 available, use explicit
// locations
/*layout(location = 0)*/ in vec4 Position;
or
/*layout(location = 1)*/ in vec3 Position;
to either index 0 or 1 explicitly or glBindAttribLocation() and still use the same VAO. AFAIK, the spec says nothing about what happens if an attribute is enabled but not sourced by the current shader but I suspect implementation to simply ignore the attribute in that case.
Whether you source the data for said attributes from the same or a different buffer object is another question but of course possible.
Personally I tend to use one VBO and VAO per layout, i.e. if my data is made up of an equal number of attributes with the same properties, I put them into a single VBO and a single VAO.
In general: You can experiment with this stuff a lot. Do it!
Whenever we use an index array to render textured polygons with glDraw*Elements*, we can provide an array of vertices and an array of texture coordinates. Then each index in the index array refers to a vertex at some position in the vertex array and the corresponding texture coordinate at the same position in the texture array. Now, if for instance several separate primitives (like QUADS) share one vertex, but require different texture coordinates for that vertex, we have to duplicate that vertex in our array as many times as we have different texture coordinates for it. Therefore, it would be much more convenient if the texture coordinate array could be associated with the positions in the index array. That way no vertex duplication would be necessary to associate one specific vertex with different texture coordinates.
Is this possible? If yes, what syntax to use?
No. Not in a simple way.
You could use buffer textures and shader logic to implement it. But there is no simple API to make attributes index the way you want. All attributes are sampled from the same index (except when instanced array divisors are used, but that won't help you either).
Note that doing this will be a memory/performance tradeoff. Using buffer textures to access vertex data will take up less memory, but it will be significantly slower and more limiting than just using regular attributes. You won't have access to normalized vertex attributes, so compressing the vertex data will require explicit shader logic. And accessing buffer textures is just slower overall.
You should only do this if memory is at a premium.
Now, if for instance several separate primitives (like QUADS) share one vertex, but require different texture coordinates for that vertex, we have to duplicate that vertex in our array as many times as we have different texture coordinates for it.
If the texture coordinates differ on primitives sharing a vertex position, then the vertices at a whole are not shared! A vertex is a single vector consisting of
position
normal
texture coordinate(s)
other attributes
You alter any of these, you end up with a different vertex. Because of that vertex sharing does not the way you thought.
You can duplicate the vertices so that 1 has 1 texture coord & the other has the other. The only downfall of that is if you need to morph the surface - you may move 1 vertex but not both. Of course it is possible to do it "imperatively" - ie when you just run thru a loop & use different texture coord as you go - but that would not be VBO & much slower