I have a text column in PowerBI, with numeric digits separated by a hyphen. I need the left side to be exactly 5 digits. If it is less, then add leading zeros. The right side needs to be 4 digits. Any less, add leading zeros.
For example:
0002-800 -> 00002-0800
0001-0800 -> 00001-0800
12345-220 -> 12345-0220
Any help is appreciated.
Thanks
Edit the query. Let's assume the text is in a column called "code".
Split the column by delimiter, using the dash as the delimiter
Create a new column that pads the code.1 with 0 if its length is less than 5, else use code.1
Create a new column that pads the code.2 with 0 if its length is less than 4, else use code.2
append the two helper columns with a dash in between
remove the code and helper columns and rename the remaining column to your liking.
Text.Length will return the length of a string, Text.PadStart() will pad text. The formula for step 3 above is
if Text.Length([code.1]) < 5 then
Text.PadStart([code.1], 5, "0")
else
[code.1])
You can do this with one step:
= Table.TransformColumns(
Source, {"Column", each Text.Combine({
Text.PadStart(Text.BeforeDelimiter(_, "-"),5,"0"),
Text.PadStart(Text.AfterDelimiter(_, "-"),4,"0")
},"-"
),type text}
)
Related
In my table I have a text column, and I need to check if the 5 characters of the string is specifically an exclamation point followed by 4 (dynamic) numbers - '!XXXX' - example !0422, the 4 numbers are not known, just need to know it there's a ! followed by 4 numbers.
Is there an M function to handle that without creating a 9,999 if statement?
add column, custom column, with formula as below, replacing [Column1] with the name of your text column
= try if Text.Start([Column1],1)="!" and Number.From(Text.End([Column1],4))>=0 then "YES" else "NO" otherwise "NO"
if you are not sure it will always be 5 characters, you could also check length:
= try if Text.Start([Column1],1)="!" and Text.Length([Column1])=5 and Number.From(Text.End([Column1],4))>=0 then "YES" else "NO" otherwise "NO"
I'd need to split or extract only numbers made of 8 digits from a string in Google Sheets.
I've tried with SPLIT or REGEXREPLACE but I can't find a way to get only the numbers of that length, I only get all the numbers in the string!
For example I'm using
=SPLIT(lower(N2),"qwertyuiopasdfghjklzxcvbnm`-=[]\;' ,./!:##$%^&*()")
but I get all the numbers while I only need 8 digits numbers.
This may be a test value:
00150412632BBHBBLD 12458 32354 1312548896 ACT inv 62345471
I only need to extract "62345471" and nothing else!
Could you please help me out?
Many thanks!
Please use the following formula for a single cell.
Drag it down for more cells.
=INDEX(TRANSPOSE(QUERY(TRANSPOSE(IF(LEN(SPLIT(REGEXREPLACE(A2&" ","\D+"," ")," "))=8,
SPLIT(REGEXREPLACE(A2&" ","\D+"," ")," "),"")),"where Col1 is not null ",0)))
Functions used:
QUERY
INDEX
TRANSPOSE
IF
LEN
SPLIT
REGEXREPLACE
If you only need to do this for one cell (or you have your heart set on dragging the formula down into individual cells), use the following formula:
=REGEXEXTRACT(" "&N2&" ","\s(\d{8})\s")
However, I suspect you want to process the eight-digit number out of all cells running N2:N. If that is the case, clear whatever will be your results column (including any headers) and place the following in the top cell of that otherwise cleared results column:
=ArrayFormula({"Your Header"; IF(N2:N="",,IFERROR(REGEXEXTRACT(" "&N2:N&" ","\s(\d{8})\s")))})
Replace the header text Your Header with whatever you want your actual header text to be. The formula will show that header text and will return all results for all rows where N2:N is not null. Where no eight-digit number is found, null will be returned.
By prepending and appending a space to the N2:N raw strings before processing, spaces before and after string components can be used to determine where only eight digits exist together (as opposed to eight digits within a longer string of digits).
The only assumption here is that there are, in fact, spaces between string components. I did not assume that the eight-digit number will always be in a certain position (e.g., first, last) within the string.
Try this, take a look at Example sheet
=FILTER(TRANSPOSE(SPLIT(B2," ")),LEN(TRANSPOSE(SPLIT(B2," ")))=8)
Or this to get them all.
=JOIN(" ,",FILTER(TRANSPOSE(SPLIT(B2," ")),LEN(TRANSPOSE(SPLIT(B2," ")))=8))
Explanation
SPLIT with the dilimiter set to " " space TRANSPOSE and FILTER TRANSPOSE(SPLIT(B2," ") with the condition1 set to LEN(TRANSPOSE(SPLIT(B2," "))) is = 8
JOIN the outputed column whith " ," to gat all occurrences of number with a length of 8
Note: to get the numbers with the length of N just replace 8 in the FILTER function with a cell refrence.
Using this on a cell worked just fine for me:
(cell_with_data)=REGEXEXTRACT(A1,"[0-9]{8}$")
I am trying to split a string (the string length is uncertain; it could be 500 characters or 1500 characters) into multiple columns, and each column should only contain 5 characters.
For example,
If column A contains the string:
AAGANAB5ARAB7AAAB9AAAC--CAC--1ACMRD
Then, I need Column B to Column H to be:
AAGAN,
AB5AR,
AB7AA,
AB9AA,
AC--C,
AC--1,
ACMRD
Also, the string contains “-“, but it is NOT delimiter. It should also be counted as a part of 5 char strings.
I know RegEx is probably the function I should use, and just by putting "(.....)" in the Regular Expression, Alteryx can extract the first 5 characters. But I don't know how to ask Alteryx to automatically split the entire string (length varies each row) to columns of 5 chars.
In Alteryx, use their RegEx tool (instead of the Formula tool with one of their REGEX expressions). In the config panel of the RegEx tool, and simply enter ..... as the RegEx, and the key is to select "Split to Rows"... this will give you rows with a new field that is the result of the applied RegEx.
I have a dataframe and in 2 columns i have to change values removing all that is not a number or ".". The final result should be only dotted numbers. thank you very much for those of you can help me. I attach how columns areenter image description here
The regex you're after is:
/[0-9.]+/
Explanation:
[0-9.] Looks for one character that is a digit or .
+ repeats last character unlimited times
let regex = /[0-9.]+/;
console.log("1.0.0".match(regex)); //["1.0.0"]
console.log("1.2.4".match(regex)); //["1.2.4"]
console.log("NaN".match(regex)); //[]
console.log("1.1".match(regex)); //["1.1"]
console.log("6.1.61.1".match(regex)); //["6.1.61.1"]
console.log("4.0.3 and up".match(regex)); //["4.0.3"]
This will match any combination of numbers and . of any character length.
For example:
I have 6 fields in a row in open office, the 1st is a word, the 2nd, 3rd, and 4th are a number with a leading zero, the 5th and 6th are regular numbers. How do I join them all together with a comma between them so that the leading zero stays?
Based on your comment about your numbers having a leading 0 in virtue of a custom number format, you need to incorporate TEXT() functions into your formula to retain (i.e., add) your leading 0s.
=CONCATENATE(A1,",",TEXT(B1,"0#####"),",",TEXT(C1,"0#####"),",",TEXT(D1,"0#####"),",",E1,",",F1)
Just be sure to include as many #'s as the max length of a number in that field.
Please try:
=A1&",0"&B1&",0"&C1&",0"&D1&","&E1&","&F1