How to create a regexp that ends in a line break? [duplicate] - regex

Question

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Differences between`[.]` vs `.` in regex
(2 answers)
Closed 3 years ago.
I have (looong) inputs that are lists of sentences/bullets like the following:
Broker and broker´s fees: 不適合
Specific purpose or use for the present acquisition or disposal: 因應內部管理需要，調整投資架構
Other issues to be disclosed: 無
In order to "translate" the Chinese text, I want to create objects, in a regexp fashion, so I can later transform the second captured group according to what it says.
I thought something like the following would work:
Specific_purpose = /(Specific purpose or use for the present acquisition or disposal: )([.]+)(\n)/
Other_issues = /(Other issues to be disclosed: )([.]+)(\n)/
i.e. this regexps should be composed of captured group 1 (the title in English), captured group 2 (the section in Chinese) and the captured group 3, i.e. the new line that indicates where the object ends.
Still, the code does not work and I cannot even get Ruby to find the needed objects in the input. If, for example, I add:
if input.include? Specific_purpose.to_s
puts "Yes, I found such bullet "
else
puts "No, there is no such bullet"
end
I keep getting "No, there is no such bullet", no matter how I rewrite the regexp.
Am I doing something wrong here? How do I create a regexp that will match everything until the line break?

Answer 1

As your line contains a colon which also acts as a separator for english and Chinese text, you can use this regex to capture English in group1 and Chinese in group2 to capture the text respectively. Try using this regex,
(.+):\s+(.+)
Demo
Let me know if you face any issues.