Don't know how to add loop to my program...? - c++

Question

Okay I was told to write a rock/paper/scissors game using "switch statements." I finished that, but today in class we were asked to add a loop to our existing game.
I understand the basics about for loops and while loops, however I don't understand how to add them to an existing program.
Which one is better to use? And what do I do?
Thanks guys
So again, I understand the basics of for loops and while loops. But I don't understand if there is anything else I need to declare, what I need to input to receive the correct output/loop.
#include <iostream>
using namespace std;
int main()
{ // opening bracket
int game;
cout <<"Let's play Rock, Paper, Scissors \nEnter 1 for rock, 2 for paper,3 for scissors"<< endl ;
cin >> game;
switch(game)
{
case 1:
cout << "You chose rock" << endl;
break;
case 2:
cout << "You chose paper" << endl;
break;
case 3:
cout << "You chose scissors" << endl;
break;
default:
cout<<game << " is not a valid choice"<< endl;
}
} // closing bracket
BELOW IS MY PROFESSOR'S INSTRUCTIONS:
Create the second part of a Rock, Paper, Scissors game. Enhance lab 5 so that the user keeps playing as long as they enter in 'Y'. Make this case sensitve; if they enter a lower case y the game will not continue. If the user enters in anything besides upper case Y the game will end.
Your text must exatly match the examples below:
Example 1 with correct input
Let's play Rock, Paper, Scissors
Enter 1 for rock, 2 for paper, 3 for scissors
2
You chose paper
Would you like to play again (Y for yes, N for no)?
Y
Enter 1 for rock, 2 for paper, 3 for scissors
1
You chose rock
Would you like to play again (Y for yes, N for no)?
N
Example 2 with incorrect input
Let's play Rock, Paper, Scissors
Enter 1 for rock, 2 for paper, 3 for scissors
5
5 is not a valid choice
Would you like to play again (Y for yes, N for no)?
y

Answer 1

Its probably best for you to watch some youtube videos or read up on basics about loops. Anyways, here is a very simple way to understand this
#include <iostream>
int main(){
char choice = 'Y';
//enter this loop since 'choice' equals Y
while(choice == 'Y'){
//run the game
//if they enter anything else other than Y, it will stop the loop
std::cout << "Would you like to play again (Y for yes, N for no)? \n";
std::cin >> choice;
}
return 0;
}

Answer 2

Here is what you have now:
//some code that plays a game
Here is what you want:
while player wishes to continue playing
//same code that plays the game
end while
or alternatively use a for loop but exiting that will be different, you will need to "break" out of it.

Answer 3

You can also make use of infinite loop to make it work.
#include <iostream>
using namespace std;
int main()
{ // opening bracket
int game;
while(1) //you can comment this line and uncomment below line rest all will be same
//for(;;)
{
cout << "\nLet's play Rock, Paper, Scissors \n Enter \"1\" for rock\n Enter \"2\" for paper\n Enter \"3\" for scissors\n **Press any other key to exit from the game." << endl ;
cout << "\nYour option is : ";
cin >> game;
switch(game)
{
case 1:
cout << "You chose rock\n" << endl;
break;
case 2:
cout << "You chose paper\n" << endl;
break;
case 3:
cout << "You chose scissors\n" << endl;
break;
default:
cout << game << " is not a valid choice\n"<< endl;
return 0;
}
}
} // closing bracket