Python date with offset conversion to non-offset [duplicate] - python-2.7

Question

This question already has answers here:
Apply timezone offset to datetime in Python
(3 answers)
Closed 4 years ago.
from dateutil.parser import parse
from dateutil.relativedelta import relativedelta
from dateutil.tz import gettz
from datetime import datetime, timedelta
input_time = '2019-02-01 09:50:08+11:00'
parsed=parse(input_time)
print parsed.tzinfo
I have a time input string:
input_time = '2019-02-01 09:50:08+11:00'
I want to convert it into this format: YYYY-MM-DD HH:MM:SS. Basically, adding the offset to the actual time object. For the above example I am looking for below output:
input_time_converted = '2019-02-01 20:50:08'
Found some useful stuff in dateutil library to parse the date object passed as a string and get the offset details but it gives me this output:
tzoffset(None, 39600)
But I don't know how to get the actual digits from the above and do the rest of the maths.
I have tried to call it with -as explained in the official dateutil parser documentation-
print parsed.tzinfo.tzoffset
But didn't work.

Answer 1

#!/usr/bin/env python2
def process_messed_up_timestamp(ts):
"""Convert messed up timestamps to something else.
Input timestamp is in UTC format with the offset that
should be applied but hasn't been.
"""
from datetime import datetime, timedelta
timestamp, plus, offset = ts[:19], ts[19], ts[20:]
# should validate plus is '+' or '-'
fmt = '%Y-%m-%d %H:%M:%S'
base = datetime.strptime(timestamp, fmt)
hours, minutes = [int(n) for n in offset.split(':')]
delta = timedelta(hours=hours, minutes=minutes)
multiplier = -1 if plus == '-' else 1
return (base + multiplier * delta).strftime(fmt)
input_time = '2019-02-01 09:50:08+11:00'
input_time_converted = '2019-02-01 20:50:08'
assert process_messed_up_timestamp(input_time) == input_time_converted