Why does adding static data member result in linker failure? [duplicate] - c++

This question already has answers here:
Why does a static data member need to be defined outside of the class?
(4 answers)
Closed 4 years ago.
Attempted to build a doubly linked list and printing it out. However, I received a linker command failed after adding "static Node* lastAdded". Not sure what the reason is.
Also, for the head node, I would like leave "int data" uninitialized. Is there a better way to leaves data uninitialized than what I have below?
#include <iostream>
#include <string>
using namespace std;
struct Node {
static Node* lastAdded;
Node(const int data); // General data node constructor
Node(); // head constructor
static void push(Node* previousNode);
int data;
Node* previous;
Node* next;
};
Node::Node(const int data) {
this->data = data;
}
Node::Node() {
// Note that data is left uninitalized for head node
previous = nullptr;
next = nullptr;
lastAdded = this;
}
static void push(Node* currentNode, Node* previousNode) {
previousNode->next = currentNode;
currentNode->previous = previousNode;
currentNode->next = nullptr;
Node::lastAdded = currentNode;
}
int main()
{
Node* head = new Node();
push(new Node(1), Node::lastAdded);
push(new Node(12), Node::lastAdded);
for (Node* temp = head; temp->next != nullptr; temp++) {
if (temp->previous == nullptr)
temp++;
cout << temp->data << endl;
}
}

You need to define/initialize your static variable which declared inside the class
static inline Node* lastAdded {nullptr};
in c++17 you can use inline to define static variable
#include <iostream>
#include <string>
using namespace std;
struct Node {
static inline Node* lastAdded {nullptr};
Node(const int data); // General data node constructor
Node(); // head constructor
static void push(Node* previousNode);
int data;
Node* previous;
Node* next;
};
Node::Node(const int data) {
this->data = data;
}
Node::Node() {
// Note that data is left uninitalized for head node
previous = nullptr;
next = nullptr;
lastAdded = this;
}
static void push(Node* currentNode, Node* previousNode) {
previousNode->next = currentNode;
currentNode->previous = previousNode;
currentNode->next = nullptr;
Node::lastAdded = currentNode;
}
int main()
{
Node* head = new Node();
push(new Node(1), Node::lastAdded);
push(new Node(12), Node::lastAdded);
for (Node* temp = head->next; temp != nullptr; temp=temp->next) {
cout << temp->data << endl;
}
}
output
1
12
Program ended with exit code: 0

Related

exception thrown in the pointer of singly linked list

ok, I created a linked list using the Node class and List class. But whenever I run it using the List object, it throws an exception when I return the head in the getHead() function in Node.cpp
these are the files that I created please if anyone could know why this exception is coming it would be a blessing
//**NODE.h**
#include<iostream>
using namespace std;
class Node{
private:
Node* head;
int data;
public:
Node();
Node(int); //insert data
void setHead(Node*);
Node* getHead();
void setData(int);
int getData();
void printData(Node*);
};
//**Node.cpp**
#include"Node.h"
Node::Node(){
//Node* head = new Node();
head = NULL;
data = 0;
}
Node::Node(int DATA){
//Node* head = new Node();
head = nullptr;
data = DATA;
}
int Node::getData(){ //DATA SETTER
return this->data;
}
void Node::setData(int DATA){ //DATA GETTER
this->data = DATA;
}
Node* Node::getHead(){
return head;
}
void Node::setHead(Node* NextAddress){
this->head = NextAddress;
}
void Node::printData(Node* node){
while(node != nullptr){
cout<< this->data <<"\n";
node = node->head;
}
}
//**List.h**
#include"Node.h"
class List : public Node{
private:
Node* head;
Node* current;
Node* prevcurrent;
public:
List();
//void setList(int);
void insertAtBack(Node* , int);
void insertAtFront(Node* , int);
bool search(int);
void print();
~List();
};
//**List.cpp**
#include"List.h"
List::List(){
head=nullptr;
current=nullptr;
prevcurrent=nullptr;
}
void List::insertAtBack(Node* head , int Data){
Node* newNode = new Node();
newNode->setData(Data);
newNode->setHead(head); //sets the address of the next node into the newly added node
head = newNode;
}
void List::insertAtFront(Node* head, int Data) {
Node* temp = new Node();
}
bool List::search(int num){
Node* temp = head;
while (temp->getHead()!=nullptr)
{
if (temp->getData() == num)
{
return true;
}
temp->setHead(temp->getHead()); //itereates the adress in the emp node to store the address of the next node fro the while loop
}
}
void List::print(){
Node* temp=head;
while (temp->getHead() != nullptr)
{
cout<<temp->getData()<<" ";
}
}
List::~List() {
Node* temp = head;
while (temp->getHead() != nullptr)
{
Node* temp2 = temp;
temp = temp->getHead();
delete temp2;
}
}
//**main.cpp**
#include"List.h"
int main(){
// cout<<"running\n";
// Node box(5); this works
// cout<<box.getData();
List obj;
Node node; //this will throw an exception
obj.insertAtBack(&node,5);
obj.print();
}
Exception is thrown due to print:
void List::print() {
Node *temp = head;
while (temp->getHead() != nullptr) {
cout << temp->getData() << " ";
}
}
Here, a check is missing if temp (or equally head) is a nullptr before you dereference it in temp->getHead()
Same on List::~List

While running my linked list code the compiler does not give any outputs after giving a print function too

I have given insert and a print function to insert data in a linked list and then print it.
But somehow it does not give any output and keeps running for a infinite time.
What is wrong?
Here is the code I have written. This is a simple program to create a linked list using loops and functions.
#include<iostream>
using namespace std;
struct node{
int data;
struct node* next;
};
struct node* head;
void insert(int data){
struct node* temphead=head;
if (temphead == NULL)
{
node* temp = new node();
temp->data=data;
temp->next=NULL;
while (temphead == NULL){
head==temp;
}
}
else if (temphead != NULL)
{
node* temp = new node();
temp->data=data;
temp->next=NULL;
while (temphead != NULL)
{
temphead->next= temp;
temphead=temphead->next;
}
}
}
void print(){
struct node* tempptr = head;
while (tempptr->next != NULL)
{
cout<<tempptr->data<<"_";
tempptr=tempptr->next;
}
}
int main(){
head=NULL;
insert(2);
insert(4);
insert(8);
insert(6);
//list - 2_4_8_6
print();
return 0;
}
There were few bugs in your code and also typos. Please read the comments marked with // CHANGE HERE for the description of the changes I did:
#include <iostream>
using namespace std;
struct node{
int data;
struct node* next;
};
struct node* head;
void insert(int data){
struct node* temphead = head;
if (temphead == nullptr)
{
node* temp = new node();
temp->data = data;
temp->next = nullptr;
// CHANGE HERE: removed unnecessary while loop
// Directly assign temp to head
head = temp;
}
else
{
node* temp = new node();
temp->data=data;
temp->next=nullptr;
// CHANGE HERE: check for temphead->next instead of temphead
while (temphead->next != nullptr)
{
// CHANGE HERE: remove unnecessary line: temphead->next= temp;
temphead=temphead->next;
}
// CHANGE HERE: assign temp to temphead->next (i.e. to last node)
temphead->next = temp;
}
}
void print(){
struct node* tempptr = head;
// CHANGE HERE: check for tempptr instead of tempptr->next
while (tempptr != nullptr)
{
cout<<tempptr->data<<"_";
tempptr=tempptr->next;
}
}
int main(){
head=nullptr;
insert(2);
insert(4);
insert(8);
insert(6);
//list - 2_4_8_6
print();
return 0;
}
NOTE: Your code uses new for dynamic memory allocation but doesn't use delete to de-allocate the memory when not required. If you want to avoid using new/delete, you can explore about smart pointers.

Template Linked List | Uninitialized variable error

I'm practicing implementing a Template Class Linked List with the Node struct within the implementation of the Linked List Class. In the createNode() member function, when I initialize a pointer variable to a node struct, I get the compiler error: "Uninitialized local variable 'newNode' used"
I've found if I change the initialization to:
Node* newNode = new Node();
That it works just fine. I'm a bit confused as to why this matters if I can initialize the basic data types like int as:
int* intPtr;
Why can't I do the same with structs?? My code is below:
#include <iostream>
#include <string>
template<class T>
class LinkedList
{
private:
struct Node
{
T data;
Node* next;
};
Node* head;
Node* tail;
int size;
public:
LinkedList() : head{ nullptr }, tail{ nullptr }, size{ 0 }
{
}
Node* createNode(T data)
{
Node* newNode;
newNode->data = data;
newNode->next = nullptr;
return newNode;
}
void display()
{
Node* currentNode = head;
while (currentNode)
{
std::cout << currentNode->data << std::endl;
currentNode = currentNode->next;
}
}
void push(T data)
{
Node* newNode = createNode(data);
if (size == 0)
{
head = newNode;
tail = newNode;
}
else
{
tail->next = newNode;
tail = newNode;
}
++size;
}
};
int main()
{
LinkedList<int> list;
list.push(5);
list.push(3);
list.push(6);
list.display();
std::cin.clear();
std::cin.ignore(32767, '\n');
std::cin.get();
return 0;
}
You said:
I'm a bit confused as to why this matters if I can initialize the basic data types like int as:
int* intPtr;
That's a wrong conclusion. If you use:
int* intPtr;
*intPtr = 10;
you'll probably see the same warning/error from the compiler. The correct way to use intPtr will be to make sure it is initialized to point to a valid object before anything is assigned to it using *intPtr.
int* intPtr = new int;
*intPtr = 10;
This is similar to using
Node* newNode = new Node();
newNode->data = data;
newNode->next = nullptr;
in your code.

Simple linked list in C++

I am about to create a linked that can insert and display until now:
struct Node {
int x;
Node *next;
};
This is my initialisation function which only will be called for the first Node:
void initNode(struct Node *head, int n){
head->x = n;
head->next = NULL;
}
To add the Node, and I think the reason why my linked list isn't working correct is in this function:
void addNode(struct Node *head, int n){
struct Node *NewNode = new Node;
NewNode-> x = n;
NewNode -> next = head;
head = NewNode;
}
My main function:
int _tmain(int argc, _TCHAR* argv[])
{
struct Node *head = new Node;
initNode(head, 5);
addNode(head, 10);
addNode(head, 20);
return 0;
}
Let me run the program as I think it works. First I initialise the head Node as a Node like this:
head = [ 5 | NULL ]
Then I add a new node with n = 10 and pass head as my argument.
NewNode = [ x | next ] where next points at head. And then I change the place where head is pointing to NewNode, since NewNode is the first Node in LinkedList now.
Why isn't this working? I would appreciate any hints that could make me move in the right direction. I think LinkedList is a bit hard to understand.
When I'm printing this, it only returns 5:
This is the most simple example I can think of in this case and is not tested. Please consider that this uses some bad practices and does not go the way you normally would go with C++ (initialize lists, separation of declaration and definition, and so on). But that are topics I can't cover here.
#include <iostream>
using namespace std;
class LinkedList{
// Struct inside the class LinkedList
// This is one node which is not needed by the caller. It is just
// for internal work.
struct Node {
int x;
Node *next;
};
// public member
public:
// constructor
LinkedList(){
head = NULL; // set head to NULL
}
// destructor
~LinkedList(){
Node *next = head;
while(next) { // iterate over all elements
Node *deleteMe = next;
next = next->next; // save pointer to the next element
delete deleteMe; // delete the current entry
}
}
// This prepends a new value at the beginning of the list
void addValue(int val){
Node *n = new Node(); // create new Node
n->x = val; // set value
n->next = head; // make the node point to the next node.
// If the list is empty, this is NULL, so the end of the list --> OK
head = n; // last but not least, make the head point at the new node.
}
// returns the first element in the list and deletes the Node.
// caution, no error-checking here!
int popValue(){
Node *n = head;
int ret = n->x;
head = head->next;
delete n;
return ret;
}
// private member
private:
Node *head; // this is the private member variable. It is just a pointer to the first Node
};
int main() {
LinkedList list;
list.addValue(5);
list.addValue(10);
list.addValue(20);
cout << list.popValue() << endl;
cout << list.popValue() << endl;
cout << list.popValue() << endl;
// because there is no error checking in popValue(), the following
// is undefined behavior. Probably the program will crash, because
// there are no more values in the list.
// cout << list.popValue() << endl;
return 0;
}
I would strongly suggest you to read a little bit about C++ and Object oriented programming. A good starting point could be this: http://www.galileocomputing.de/1278?GPP=opoo
EDIT: added a pop function and some output. As you can see the program pushes 3 values 5, 10, 20 and afterwards pops them. The order is reversed afterwards because this list works in stack mode (LIFO, Last in First out)
You should take reference of a head pointer. Otherwise the pointer modification is not visible outside of the function.
void addNode(struct Node *&head, int n){
struct Node *NewNode = new Node;
NewNode-> x = n;
NewNode -> next = head;
head = NewNode;
}
I'll join the fray. It's been too long since I've written C. Besides, there's no complete examples here anyway. The OP's code is basically C, so I went ahead and made it work with GCC.
The problems were covered before; the next pointer wasn't being advanced. That was the crux of the issue.
I also took the opportunity to make a suggested edit; instead of having two funcitons to malloc, I put it in initNode() and then used initNode() to malloc both (malloc is "the C new" if you will). I changed initNode() to return a pointer.
#include <stdlib.h>
#include <stdio.h>
// required to be declared before self-referential definition
struct Node;
struct Node {
int x;
struct Node *next;
};
struct Node* initNode( int n){
struct Node *head = malloc(sizeof(struct Node));
head->x = n;
head->next = NULL;
return head;
}
void addNode(struct Node **head, int n){
struct Node *NewNode = initNode( n );
NewNode -> next = *head;
*head = NewNode;
}
int main(int argc, char* argv[])
{
struct Node* head = initNode(5);
addNode(&head,10);
addNode(&head,20);
struct Node* cur = head;
do {
printf("Node # %p : %i\n",(void*)cur, cur->x );
} while ( ( cur = cur->next ) != NULL );
}
compilation: gcc -o ll ll.c
output:
Node # 0x9e0050 : 20
Node # 0x9e0030 : 10
Node # 0x9e0010 : 5
Below is a sample linkedlist
#include <string>
#include <iostream>
using namespace std;
template<class T>
class Node
{
public:
Node();
Node(const T& item, Node<T>* ptrnext = NULL);
T value;
Node<T> * next;
};
template<class T>
Node<T>::Node()
{
value = NULL;
next = NULL;
}
template<class T>
Node<T>::Node(const T& item, Node<T>* ptrnext = NULL)
{
this->value = item;
this->next = ptrnext;
}
template<class T>
class LinkedListClass
{
private:
Node<T> * Front;
Node<T> * Rear;
int Count;
public:
LinkedListClass();
~LinkedListClass();
void InsertFront(const T Item);
void InsertRear(const T Item);
void PrintList();
};
template<class T>
LinkedListClass<T>::LinkedListClass()
{
Front = NULL;
Rear = NULL;
}
template<class T>
void LinkedListClass<T>::InsertFront(const T Item)
{
if (Front == NULL)
{
Front = new Node<T>();
Front->value = Item;
Front->next = NULL;
Rear = new Node<T>();
Rear = Front;
}
else
{
Node<T> * newNode = new Node<T>();
newNode->value = Item;
newNode->next = Front;
Front = newNode;
}
}
template<class T>
void LinkedListClass<T>::InsertRear(const T Item)
{
if (Rear == NULL)
{
Rear = new Node<T>();
Rear->value = Item;
Rear->next = NULL;
Front = new Node<T>();
Front = Rear;
}
else
{
Node<T> * newNode = new Node<T>();
newNode->value = Item;
Rear->next = newNode;
Rear = newNode;
}
}
template<class T>
void LinkedListClass<T>::PrintList()
{
Node<T> * temp = Front;
while (temp->next != NULL)
{
cout << " " << temp->value << "";
if (temp != NULL)
{
temp = (temp->next);
}
else
{
break;
}
}
}
int main()
{
LinkedListClass<int> * LList = new LinkedListClass<int>();
LList->InsertFront(40);
LList->InsertFront(30);
LList->InsertFront(20);
LList->InsertFront(10);
LList->InsertRear(50);
LList->InsertRear(60);
LList->InsertRear(70);
LList->PrintList();
}
Both functions are wrong. First of all function initNode has a confusing name. It should be named as for example initList and should not do the task of addNode. That is, it should not add a value to the list.
In fact, there is not any sense in function initNode, because the initialization of the list can be done when the head is defined:
Node *head = nullptr;
or
Node *head = NULL;
So you can exclude function initNode from your design of the list.
Also in your code there is no need to specify the elaborated type name for the structure Node that is to specify keyword struct before name Node.
Function addNode shall change the original value of head. In your function realization you change only the copy of head passed as argument to the function.
The function could look as:
void addNode(Node **head, int n)
{
Node *NewNode = new Node {n, *head};
*head = NewNode;
}
Or if your compiler does not support the new syntax of initialization then you could write
void addNode(Node **head, int n)
{
Node *NewNode = new Node;
NewNode->x = n;
NewNode->next = *head;
*head = NewNode;
}
Or instead of using a pointer to pointer you could use a reference to pointer to Node. For example,
void addNode(Node * &head, int n)
{
Node *NewNode = new Node {n, head};
head = NewNode;
}
Or you could return an updated head from the function:
Node * addNode(Node *head, int n)
{
Node *NewNode = new Node {n, head};
head = NewNode;
return head;
}
And in main write:
head = addNode(head, 5);
The addNode function needs to be able to change head. As it's written now simply changes the local variable head (a parameter).
Changing the code to
void addNode(struct Node *& head, int n){
...
}
would solve this problem because now the head parameter is passed by reference and the called function can mutate it.
head is defined inside the main as follows.
struct Node *head = new Node;
But you are changing the head in addNode() and initNode() functions only. The changes are not reflected back on the main.
Make the declaration of the head as global and do not pass it to functions.
The functions should be as follows.
void initNode(int n){
head->x = n;
head->next = NULL;
}
void addNode(int n){
struct Node *NewNode = new Node;
NewNode-> x = n;
NewNode->next = head;
head = NewNode;
}
I think that, to make sure the indeep linkage of each node in the list, the addNode method must be like this:
void addNode(struct node *head, int n) {
if (head->Next == NULL) {
struct node *NewNode = new node;
NewNode->value = n;
NewNode->Next = NULL;
head->Next = NewNode;
}
else
addNode(head->Next, n);
}
Use:
#include<iostream>
using namespace std;
struct Node
{
int num;
Node *next;
};
Node *head = NULL;
Node *tail = NULL;
void AddnodeAtbeggining(){
Node *temp = new Node;
cout << "Enter the item";
cin >> temp->num;
temp->next = NULL;
if (head == NULL)
{
head = temp;
tail = temp;
}
else
{
temp->next = head;
head = temp;
}
}
void addnodeAtend()
{
Node *temp = new Node;
cout << "Enter the item";
cin >> temp->num;
temp->next = NULL;
if (head == NULL){
head = temp;
tail = temp;
}
else{
tail->next = temp;
tail = temp;
}
}
void displayNode()
{
cout << "\nDisplay Function\n";
Node *temp = head;
for(Node *temp = head; temp != NULL; temp = temp->next)
cout << temp->num << ",";
}
void deleteNode ()
{
for (Node *temp = head; temp != NULL; temp = temp->next)
delete head;
}
int main ()
{
AddnodeAtbeggining();
addnodeAtend();
displayNode();
deleteNode();
displayNode();
}
In a code there is a mistake:
void deleteNode ()
{
for (Node * temp = head; temp! = NULL; temp = temp-> next)
delete head;
}
It is necessary so:
for (; head != NULL; )
{
Node *temp = head;
head = temp->next;
delete temp;
}
Here is my implementation.
#include <iostream>
using namespace std;
template< class T>
struct node{
T m_data;
node* m_next_node;
node(T t_data, node* t_node) :
m_data(t_data), m_next_node(t_node){}
~node(){
std::cout << "Address :" << this << " Destroyed" << std::endl;
}
};
template<class T>
class linked_list {
public:
node<T>* m_list;
linked_list(): m_list(nullptr){}
void add_node(T t_data) {
node<T>* _new_node = new node<T>(t_data, nullptr);
_new_node->m_next_node = m_list;
m_list = _new_node;
}
void populate_nodes(node<T>* t_node) {
if (t_node != nullptr) {
std::cout << "Data =" << t_node->m_data
<< ", Address =" << t_node->m_next_node
<< std::endl;
populate_nodes(t_node->m_next_node);
}
}
void delete_nodes(node<T>* t_node) {
if (t_node != nullptr) {
delete_nodes(t_node->m_next_node);
}
delete(t_node);
}
};
int main()
{
linked_list<float>* _ll = new linked_list<float>();
_ll->add_node(1.3);
_ll->add_node(5.5);
_ll->add_node(10.1);
_ll->add_node(123);
_ll->add_node(4.5);
_ll->add_node(23.6);
_ll->add_node(2);
_ll->populate_nodes(_ll->m_list);
_ll->delete_nodes(_ll->m_list);
delete(_ll);
return 0;
}
link list by using node class and linked list class
this is just an example not the complete functionality of linklist, append function and printing a linklist is explained in the code
code :
#include<iostream>
using namespace std;
Node class
class Node{
public:
int data;
Node* next=NULL;
Node(int data)
{
this->data=data;
}
};
link list class named as ll
class ll{
public:
Node* head;
ll(Node* node)
{
this->head=node;
}
void append(int data)
{
Node* temp=this->head;
while(temp->next!=NULL)
{
temp=temp->next;
}
Node* newnode= new Node(data);
// newnode->data=data;
temp->next=newnode;
}
void print_list()
{ cout<<endl<<"printing entire link list"<<endl;
Node* temp= this->head;
while(temp->next!=NULL)
{
cout<<temp->data<<endl;
temp=temp->next;
}
cout<<temp->data<<endl;;
}
};
main function
int main()
{
cout<<"hello this is an example of link list in cpp using classes"<<endl;
ll list1(new Node(1));
list1.append(2);
list1.append(3);
list1.print_list();
}
thanks ❤❤❤
screenshot https://i.stack.imgur.com/C2D9y.jpg

Why does my linked list code result in link errors?

I'm new to linklist, and i'm having a tough time with it. I'm trying to display some values that i've appended to the nodes, But i keep getting linkerror messages. Here is what I have so far.
LinkList.h
-
#ifndef LINKLIST_H
#define LINKLIST_H
class LinkList
{
private:
struct ListNode
{
int value;
ListNode *next;
};
ListNode *head;
public:
LinkList();
void insertNode(int);
void deleteNode(int);
void appendNode(int);
void display() const;
//~LinkList();
};
#endif
Impl.cpp
-
#include <iostream>
#include "LinkList.h"
using namespace std;
void LinkList::appendNode(int num)
{
ListNode * newNode;
ListNode * nodePtr;
newNode = new ListNode;
newNode->value = num;
newNode->next = NULL;
if(!head)
{
head = newNode;
head->value = num;
head->next=NULL;
}
else
{
nodePtr = head;
while(nodePtr->next!=NULL)
nodePtr = nodePtr->next;
newNode = new ListNode;
newNode->value = num;
newNode->next = NULL;
nodePtr->next = newNode;
}
}
void LinkList::display() const
{
ListNode *nodePtr;
nodePtr = head;
while (nodePtr != NULL)
{
cout << nodePtr->value << endl;
nodePtr = nodePtr->next;
}
}
LinkList::LinkList()
{
head = NULL;
}
main.cpp
-
#include <iostream>
#include "LinkList.h"
using namespace std;
int main()
{
LinkList mine;
mine.appendNode(6);
mine.appendNode(9);
mine.appendNode(11);
mine.display();
return 0;
}
I fixed some of the initial problems but the program just crashes when it runs and i'm not sure why
I'm not sure what the problems is, any help would be greatly appreciated.
You declared a LinkList constructor, and a destructor, but you did not define them:
LinkList::LinkList() : head(NULL)
{
}
LinkList::~LinkList()
{
// delete your memory here...
}