Powershell adding CR at the end of regex match group - regex

Question

I'm gettting a CR between the regex match and the ','. What's going on?
$r_date ='ExposeDateTime=([\w /:]{18,23})'
$v2 = (Select-String -InputObject $_ -Pattern $r_date | ForEach-Object {$_.Matches.Groups[1].Value}) + ',';
Example of output:
9/25/2018 8:45:19 AM[CR],
Original String:
ExposeDateTime=9/25/2018 8:45:19 AM
Error=Dap
PostKvp=106
PostMa=400
PostTime=7.2
PostMas=2.88
PostDap=0

Answer 1

Try this:
$original = #"
ExposeDateTime=9/25/2018 8:45:19 AM
Error=Dap
PostKvp=106
PostMa=400
PostTime=7.2
PostMas=2.88
PostDap=0
"#
$r_date ='ExposeDateTime=([\d\s/:]+(?:(?:A|P)M)?)'
$v2 = (Select-String -InputObject $original -Pattern $r_date | ForEach-Object {$_.Matches.Groups[1].Value}) -join ','
Regex details:
ExposeDateTime= Match the characters “ExposeDateTime=” literally
( Match the regular expression below and capture its match into backreference number 1
[\d\s/:] Match a single character present in the list below
A single digit 0..9
A whitespace character (spaces, tabs, line breaks, etc.)
One of the characters “/:”
+ Between one and unlimited times, as many times as possible, giving back as needed (greedy)
(?: Match the regular expression below
(?: Match the regular expression below
Match either the regular expression below (attempting the next alternative only if this one fails)
A Match the character “A” literally
| Or match regular expression number 2 below (the entire group fails if this one fails to match)
P Match the character “P” literally
)
M Match the character “M” literally
)? Between zero and one times, as many times as possible, giving back as needed (greedy)

Answer 2

if your input is a multiline string stored in $Original, then this rather simpler regex seems to do the job. [grin] it uses a named capture group and the multiline regex flag to capture the string after ExposedDateTime= and before the next line ending.
$Original -match '(?m)ExposeDateTime=(?<Date>.+)$'
$Matches.Date
output ...
9/25/2018 8:45:19 AM