In Jenkins with Git Parameter plugin (which helps me filter out tags)
I have this pattern *-rc this simply display all tags with -rc as a suffix. But how do I negate this pattern. I already have this (?!-rc).*$ but it is not working.
EDIT 1
I have tags named:
3.11.2-rc
3.11.1-rc
3.11.0
3.10.0
so on and so fort...
with this pattern *-rc I can simply display tags with '-rc'
now, what I want to achieve is display all tags without '-rc'
EDIT 2
As seen in this blog post, you could use the Extensible Choice plugin and:
add 'Extensible Choice' as a second parameter (as seen here)
write a groovy script which does the filtering for you
You can see an example here for branches, that you can adapt for tags.
You need to first turn on the regex option - see this answer for how to do that.
Use this negative look behind based regex:
.*(?<!-rc)$
See live demo of this regex with your sample data.
The look behind, which is anchored to end of input via $, requires that the preceding chars not be "-rc".
Related
I want to get the thread-id of an url via regex.
The Url can have these states:
https://mypage.com/threads/an-example-thread/
https://mypage.com/threads/an-example-thread/page-1
https://mypage.com/threads/an-example-thread
My pattern .+/threads/(.+)/.+ covers the first two options. Now I need a pattern, that also covers option 3. .+/threads/(.+)(/.+|$) works. But I use the first group to get the tread-id/name. So how is is possible to create an or-pattern without grouping?
As mentioned in the comments, try to use /threads/([^\/]*), that will match all 3.
I'm trying to figure out what landing page regex to use to only show URLs that have only two sub-folders, e.g. see image below: just show green URLs but not the read ones as they have 3+ subfolders. Any advice on how to do this in GA with regex?
Cheers
If you want to match a path having only two components, e.g.
/component1/component2/
Then you may use the following regex:
/[^/]+/[^/]+/
Demo
If your regex tool requires anchors, then add them:
^/[^/]+/[^/]+/$
Is this what you are looking for?
^\/[!#$&-;=?-[]_a-z~]+\/[!#$&-;=?-[]_a-z~]+\/$
The two sections contain all the valid html characters. We're also forcing the regex to start with slash, end with slash and have only one slash in between.
I'm very very new to regex. I'd managed to not touch it with a 10-foot pole for so long. And I tried my best to avoid it so far. But now a personal project is pushing me to learn it.
So I started. And I'm going through the tutorial located here:http://www.regular-expressions.info/tutorial.html
Currently I'm here: http://www.regular-expressions.info/repeat.html
My question is:
The tutorial says <[A-Za-z][A-Za-z0-9]*> will match an HTML tag.
But wouldn't it also match invalid html tags like - <h11> or <h111>?
Also how would it match the closing tags?
Edit - My question is very specific. I am referring to one particular example in one particular tutorial to clarify whether or not my understanding of repetitions is correct. Again, I REPEAT, I DO NOT care about html parsing with regex.
I don't see any harm in answering your question seeing as how you are attempting to learn regex:
1) Yes, it will match invalid tags as well because it's any letter followed by any zero or more matches of another letter or a number.
2) It will not match closing tags (there would have to be a search for a / somewhere in there).
One more comment: one way people used to use to look for html tags inside a document was to look for the pattern of opening and closing brackets, like so:
<\/?[^>]*>
That's opening-bracket, an optional slash, (anything but a closing bracket)-repeated and then a closing bracket. Of course, I am not recommending anyone do this. It's merely left here as an exercise.
The tutorial says <[A-Za-z][A-Za-z0-9]*> will match an HTML tag.
But wouldn't it also match invalid html tags like - or ?
Also how would it match the closing tags?
Yes, that will match <h11> as well as <X098wdfhfdshs98fhj2hsdljhkvjnvo9sudvsodfih23234osdfs>.
If you want to just match a letter followed by an optional single digit, so you'd match <h1>, then you want <[A-Za-z][0-9]?>
I'm using Autoblogged to pull a feed in as a blog post. I need to create a reg expression to convert the title of the item to things I can use as meta data. I've attached a screen of the backend I have access to. Any help would be greatly appreciated!
Here are examples of the title from the feed.
Type One Training Event New New Mexico, WY November 2012
Type Two Training Event Seattle, WA November 2012
I need that to become this:
<what>Type One Training Event</what> <city>New New Mexico</city>, <%state>WY</state> <month>November</month> <year>2012</year>
<what>Type Two Training Event</what> <city>Seattle</city>, <state>WA</state> <month>November</month> <year>2012</year>
Essentially says take whatever is before the word event and make that "what"
Take anything after the word event and before the comma and make that "city"
Take the two letters after the comma and make that "state"
Take the last two words and make em month and year
Autblogged backend:
We actually have an email in queue to respond to you directly once we get our v2.9 update out. The update fixes a bug in the regex feature but I thought I would go ahead and comment here so this question isn't just left open.
The ability to extract info from a feed is one of the coolest and most powerful features of AutoBlogged and this is a perfect example of what you can do with those features.
First of all, here are the regex patterns you would use:
What: (.*)\sTraining\sEvent
City: Training\sEvent\s([^,]*)
State: .*,\s([A-Z]{2})
To use these, you create new custom fields in the feed settings. Note that the custom fields also use the same syntax as the post templates so you can use the powerful regex function to extract info from the feed. This is how the fields should look:
Once you create these custom fields you can use them in your post templates and they will be added as custom fields to your post in WordPress.
Once you have these custom fields set up, you can use them in your post template as %what%, %city% or %state_code%. As I mentioned before this will also create custom fields on your blog post in WordPress as well. If you don't want that, you can just use %regex("%title%", "(.*)\sTraining\sEvent", "1")% instead of %what% directly in your post template.
Quick explanation of the syntax:
If you use %regex("%title%", "(.*)\sTraining\sEvent", "1")% it means this:
Get this info from the %title% field
Use the regex pattern (.*)\sTraining\sEvent
Use match reference 1, the (.*) part.
Perhaps match:
^(.* Event) (.*), ([A-Z]{2}) +(?i(Jan(?:uary)?|Feb(?:ruary)?|Mar(?:ch)?|Apr(?:il)?|May|June?|July?|Aug(?:ust)?|Sep(?:tember)?|Oct(?:ober)?|Nov(?:ember)?|Dec(?:ember)?)) +((?:19|20)\d{2})\b
EDIT: re your comment, it looks like you have to surround your regex in delimiters. Try:
/insert_above_regex_here/
If you want case-insensitive, then do:
/insert_above_regex_here_but_remove_(?i_and_matching_)/i
However if you do case-insensitive, your state ([A-Z]{2}) will also match two lower-case letters. If this is OK then go for it. You culd also try changing that part of the regex to (?-i([A-Z]{2})) which says "be case-sensitive for this part", but it depends on whether that engine supports it (don't worry, you'll get an error if it doesn't).
Then replace with:
<what>$1</what> <city>$2</city>, <state>$3</state> <month>$4</month> <year>$5</year>
I'm not sure what flavour of regex that interface has so you might not be able to do the (?i bit in the Month regex (it just makes that bit case insensitive) -- you'll just have to be careful then to write your months with one capital letter and the rest lowercase, or you can modify the regex to allow upper-case too.
Hopefully someone can help me out. Been all over google now.
I'm doing some zone-ocr of documents, and want to extract some text with regex. It is always like this:
"Til: Name Name Name org.nr 12323123".
I want to extract the name-part, it can be 1-4 names, but "Til:" and "org.nr" is always before and after.
Anyone?
If you can't use capturing groups (check your documentation) you can try this:
(?<=Til:).*?(?=org\.nr)
This solution is using look behind and lookahead assertions, but those are not supported from every regex flavour. If they are working, this regex will return only the part you want, because the parts in the assertions are not matched, it checks only if the patterns in the assertions are there.
Use the pattern:
Til:(.*)org\.nr
Then take the second group to get the content between the parenthesis.