Using re.findall to match a string in html - regex

Question

I want to use re.findall() to match instances of business names from a review website. For example, I'd like to capture names in a list like the ones in the example below:
website_html = ', Jimmy Bob's Tune & Lube, Allen's Bar & Grill, Joanne's - Restaurant,'
name_list = re.findall('[,]\s*([\w\'&]*\s?)*[,]', website_html)
My code isn't catching any patterns. Any ideas?

Answer 1

You only provided one input example, so this answer is based on your question as is:
# I replace the single quotes at the start and end of your input, because
# Bob's throws a SyntaxError: invalid syntax
#
website_html = ", Jimmy Bob's Tune & Lube,"
# I removed re.findall, because you only had one example so re.search or
# re.match works.
name_list = re.search(r'[,]\s*([\w\'&]*\s?)*[,]', website_html)
print (name_list.group(0))
# output
, Jimmy Bob's Tune & Lube,
If you have additional input values in website_html please provide them, so that I can modified my answer.
Here is the version that uses re.findall.
# I replace the single quotes at the start and end of your input, because
# Bob's throws a SyntaxError: invalid syntax
#
website_html = ", Jimmy Bob's Tune & Lube,"
# I wrapped your pattern as a capture group
name_list = re.findall(r'([,]\s*([\w\'&]*\s?)*[,])', website_html)
print (type(name_list))
# output
<class 'list'>
print (name_list)
# output
[(", Jimmy Bob's Tune & Lube,", '')]
UPDATED ANSWER
This answer is based on the modified input to your original question.
website_html = ", Jimmy Bob's Tune & Lube, Allen's Bar & Grill, Joanne's - Restaurant,"
name_list = re.findall(r'[?:,].*[?:,]', website_html)
for item in name_list:
split_strings = (str(item).split(','))
for string in split_strings:
print (string)
# output
Jimmy Bob's Tune & Lube
Allen's Bar & Grill
Joanne's - Restaurant