flip all bits for a Long (in java) - bit-manipulation

Curious why this works
public long flip(long n) {
long finalResult = 0;
for (int i = 0; i < 32; i++) {
finalResult = finalResult | (1L << i);
}
return n ^ finalResult;
}
but this doesn't
public long flip(long n) {
long finalResult = 0;
for (int i = 0; i < 32; i++) {
finalResult = finalResult | (1 << i);
}
return n ^ finalResult;
}
I know that finalResult '11111111111111111111111111111111' will be -1 (and maybe that causes an issue) but i'm still not sure why it causes issues when simply flipping bits in n.

Related

RC4 Not generating the proper scrambled state array

I have the follow code below to generate a scrambled state array, however, it does not seem to be generating the properly randomized state array for the key (51323).
unsigned char* generateStateArray(unsigned long key) {
unsigned char s[256];
//Load the state array from 1-255
for (int i = 0; i < 256; i++) {
s[i] = i;
}
//Get the binary representation of the key
unsigned long n = key;
int binary[64];
for (int i = 0; i < 64; i++) {
binary[i] = 0;
std::cout << binary[i];
}
std::cout << std::endl;
for (int i = 0; n > 0; i++) {
binary[i] = n % 2;
n /= 2;
}
//Randomize the entries
int j = 0;
for (int i = 0; i < 256; i++) {
j = (j + binary[i % 64] + s[i]) & 255;
char c = s[i];
s[i] = s[j];
s[j] = c;
}
}
The output for S should look like:
But it gives me this output:
Any idea what I'm doing wrong and how I can fix it?

Getting the bits of a string in C++

I need to get bits of a character. I haven't used C++ bitwise operators before, and I can't figure out what I'm doing wrong.
int main()
{
bool bits[8];
char c = static_cast<char>(0b11101101);
for(int i = 0; i < 8; i++) {
bits[i] = (c >> i) & 1;
}
for(int i = 0; i < 8; i++) {
std::cout << bits[i];
}
}
//output: 10110111
Just change your first loop to:
for(int i = 0; i < 8; i++) {
bits[7-i] = (c >> i ) & 1;
}

Convert decimal to binary in big number

I want to create a big number with 128 bit.
When I convert the string decimal to binary and set bit to the new data QInt :__int64 a[2], it only true for a small number (about 10 digits).
This is my code: http://codepad.org/HmYqMQme
#include<iostream>
#include<stdio.h>
#include<string>
using namespace std;
//new data
class QInt
{
private:
__int64 a[2];
public:
void Get()
{
cout << a[0] << endl;
cout << a[1] << endl;
}
QInt()
{
a[0] = 0;
a[1] = 0;
}
//the funtion get the string binary of a[1]
char* GetQInt(char *A);
//the devide two of string decimal
char* Div2(char *Str);
//the funtion set bit to a[0] and a[1]
void Setbit(int i, int bit);
//con vert decimal to binary
QInt ConvertDecimalToBinary(char *De, char *Bi);
};
//the funtion get the string binary of a[1]
char *QInt::GetQInt(char *A)
{
for (int i = 0; i < 64; i++)
{
if (((a[1] >> i) & 1) != 0)
{
A[63 - i] = 49;
}
else
{
A[63 - i] = 48;
}
}
return A;
}
// the funtion set bit to a[0] and a[1]
void QInt:: Setbit(int i, int bit)
{
//if i<64 we set bit to a[1]
if (i < 64)
{
if (bit==1)
{
a[1]=(1 << i) | a[1];
}
}//similar to a[1]
else
{
if (bit == 1)
a[0]=(1 << i) | a[0];
}
}
//the devide two of string decimal
char*QInt:: Div2(char *Str)
{
char Arr[100];
int n = strlen(Str);
int a = 0;//lay phan du
int i = 0;
int j = 0;
while (Str[i] == 0)
{
i++;
}
for (i; i < n; i++)
{
int c = Str[i] - 48 + a * 10;
a = c % 2;
Arr[j] = c / 2 + 48;
j++;
}
Arr[i] = '\0';
for (i = 0; i < strlen(Arr); i++)
{
Str[i] = Arr[i];
}
Str[i] = '\0';
return Str;
}
//con vert decimal to binary
QInt QInt::ConvertDecimalToBinary(char *De,char *Bi)
{
int bit;
int i = 127;
int lenth = strlen(De);
while (1)
{
//variable h use to count the number 0 of the string decimal,if h=lenth,exit
int k = 0;
int h = 0;
while (De[k])
{
if (De[k] == '0')
h++;
k++;
}
if (h == lenth)
break;
else
{
bit = (De[lenth - 1] - 48) % 2;
Bi[i] = bit + 48;
Setbit(127 - i, bit);
De = Div2(De);
i--;
}
}
Bi[128] = NULL;
return *this;
}
int main()
{
char s[100];
char b[200];
char c[200];
for (int i = 0; i < 128; i++)
{
b[i] = 48;
}
cout << "Please enter a string : ";
gets_s(s, 99);
QInt a;
a.ConvertDecimalToBinary(s, b);
a.Get();
a.GetQInt(c);
for (int i = 0; i < 64; i++)
cout << b[i];
cout << endl;
for (int i = 64; i < 128; i++)
cout << b[i];
cout << endl;
for (int i = 0; i < 64; i++)
{
cout << c[i];
}
cout << endl;
system("pause");
return 0;
}
If i==100, what do you think (1 << i) does? What should it do? And why are you ignoring a[0] in GetQInt ?
In general, you have quite a few problems. You're not comfortable with std::string, and making a mess of the char* everywhere. You're not clearly articulating (not even to yourself) what methods are supposed to be doing. You're putting mathods in a class that are unrelated to the class. Even worse, some of those methods redefine the name a ! That is very confusing.

radix sort array of strings

I am trying to use radix sort to sort file contain social security and date of birth the format looks like this "###-##-####,#######.I have to apply radix sort on each fields according to command line switch. I have a radix sort that is work for int array and i am trying to modify the code for string type array but i am not sure how to accomplish this. I did a quick sort for string type by comparing strings and pivot and that is work fine however for radix sort I am not if I can do this with string type or I have to convert the string to integer. I have tried to use "atoi" to convert to integer but I am not sure how to correctly do this if I have to.
string getMax(string arr[], int n){
string max = arr[0];
for (int i = 1; i < n; i++){
if (arr[i]>max)
max = arr[i];
}
return max;
}
void countSort(string a[], int size, int k){
string *b = NULL; int *c = NULL;
b = new string[size];
c = new int[k];
for (int i = 0; i <k; i++){
c[i] = 0;
//cout << c[i] << "\n";
}
for (int j = 0; j <size; j++){
c[(a[j]/k)%10]++; //a[j] is a string
//cout << c[a[j]] << endl;
}
for (int f = 1; f <10; f++){
c[f] += c[f - 1];
}
for (int r = size - 1; r >= 0; r--){
b[c[(a[r] / k) % 10] - 1] = a[r];
c[(a[r] / k) % 10]--;
}
for (int l = 0; l < size; l++){
a[l] = b[l];
}
}
void radixSort(string b[], int r){
string max = getMax(b, r);
for (int digit = 1; max / digit > 0; digit *= 10){
countSort(b, r, digit);
}
};
I didn't try, but I think you can do radix sort for string.
Calculate the length of the longest string in the array to sort.
Do radix sort just like for integers. Do sorting using each characters in the string.
If a string is shorter than another and there is no character in the "digit", consider its value as -65536 (or a smaller value than any other characters).
UPDATE: I tested my idea and it seems working.
#include <cstdio>
#include <string>
using std::string;
size_t getMax(string arr[], int n){
size_t max = arr[0].size();
for (int i = 1; i < n; i++){
if (arr[i].size()>max)
max = arr[i].size();
}
return max;
}
void countSort(string a[], int size, size_t k){
string *b = NULL; int *c = NULL;
b = new string[size];
c = new int[257];
for (int i = 0; i <257; i++){
c[i] = 0;
//cout << c[i] << "\n";
}
for (int j = 0; j <size; j++){
c[k < a[j].size() ? (int)(unsigned char)a[j][k] + 1 : 0]++; //a[j] is a string
//cout << c[a[j]] << endl;
}
for (int f = 1; f <257; f++){
c[f] += c[f - 1];
}
for (int r = size - 1; r >= 0; r--){
b[c[k < a[r].size() ? (int)(unsigned char)a[r][k] + 1 : 0] - 1] = a[r];
c[k < a[r].size() ? (int)(unsigned char)a[r][k] + 1 : 0]--;
}
for (int l = 0; l < size; l++){
a[l] = b[l];
}
// avold memory leak
delete[] b;
delete[] c;
}
void radixSort(string b[], int r){
size_t max = getMax(b, r);
for (size_t digit = max; digit > 0; digit--){ // size_t is unsigned, so avoid using digit >= 0, which is always true
countSort(b, r, digit - 1);
}
}
int main(void) {
string data[] = {
"aaaba",
"dfjasdlifjai",
"jiifjeogiejogp",
"aabaaaa",
"gsgj",
"gerph",
"aaaaaaa",
"htjltjlrth",
"joasdjfisdjfdo",
"hthe",
"aaaaaba",
"jrykpjl",
"hkoptjltp",
"aaaaaa",
"lprrjt"
};
puts("before sorting:");
for (size_t i = 0; i < sizeof(data) / sizeof(data[0]); i++) {
printf(" %s\n", data[i].c_str());
}
radixSort(data, (int)(sizeof(data) / sizeof(data[0])));
puts("after sorting:");
for (size_t i = 0; i < sizeof(data) / sizeof(data[0]); i++) {
printf(" %s\n", data[i].c_str());
}
return 0;
}

Shouldn't this recursive method end as soon as you get to the return?

I would like to know why my output is:
a-b-b-b-b-0
When I think it should just be a-1.
Shouldn't a recursive method end as soon as you get to a return? and why doesn't it here?
I only put the letters with '-' to clarify that the returns are being met but not stopping there.
#include <stdio.h>
#include <iomanip>
#include <iostream>
using namespace std;
void printv(int mask[], int elements[], int n)
{
int i;
printf("{ ");
for (i = 0; i < n; i++)
if (mask[i])
printf("%d ", elements[i]);
printf("}");
}
int next(int mask[], int size)
{
int i;
for (i = 0; (i < size) && mask[i]; i++)
mask[i] = 0;
if (i < size) {
mask[i] = 1;
return 1;
}
return 0;
}
void nSubsets(int mask[], int elements[], int size, int n)
{
int sum = 0;
int temp[10], count = 0;
for (int i = 0; i < 10; i++) //this MUST be here
temp[i] = 0;
for (int i = 0; i < size; i++)
{
if (mask[i])
{
count++;
for (int k = 0; k < 44; k++)
if (temp[k] == 0)
{
temp[k] = elements[i];
sum += elements[i];
break;
}
}
}
if (sum == n)
{
cout << "{ ";
for (int l = 0; l < count; l++)
cout << temp[l] << " ";
cout << "}";
}
}
int isEmptySet(int mask[], int elements[], int size, int n, int sizeRecursion)
{
int sum = 0;
int temp[10], count = 0;
for (int i = 0; i < 10; i++) //this MUST be here
temp[i] = 0;
for (int i = 0; i < size; i++)
{
if (mask[i])
{
count++;
for (int k = 0; k < 44; k++)
if (temp[k] == 0)
{
temp[k] = elements[i];
sum += elements[i];
break;
}
}
}
if (sum == n)
{
cout << "a-";
return 1;
}
sizeRecursion--;
if (sizeRecursion > 0)
{
next(mask, size);
isEmptySet(mask, elements, size, n, sizeRecursion);
}
cout << "b-";
return 0;
}
int main()
{
int n, size = 10;
int elements[size];
size = 6; n = 5;
elements[0] = 5;
elements[1] = 2;
elements[2] = 3;
elements[3] = 2;
elements[4] = 1;
elements[5] = 1;
int mask[10];
int i;
for (i = 0; i < size; ++i)
mask[i] = 0;
cout << "Subsets of elements: ";
printv(mask, elements, size); //this prints first subset
while (next(mask, size))
printv(mask, elements, size);
n = 3;
cout << "\nSubsets equal to " << n << "\n";
while (next(mask, size))
nSubsets(mask, elements, size, n);
cout << "\n" << isEmptySet(mask, elements, size, n, size);
return 0;
}
Shouldn't a recursive method end as soon as you get to a return? and why doesn't it here?
No, the way it works in general is that when a function call returns, it only returns for that function call, and then the immediate caller may continue execution. It doesn't matter whether the function is recursive or not, each function call is separate and each call needs to hit a return statement at some point (unless the return type is void).
When you have this code
...
if(sizeRecursion > 0)
{
next(mask,size);
isEmptySet(mask, elements, size, n,sizeRecursion);
}
cout<<"b-";
return 0;
}
What's going to happen is, as soon as the recursive call to isEmptySet returns, its going to go right to the cout << "b-"; line and then to return 0;. If you don't want that then you should put those in an else block, and maybe also modify the line that calls isEmptySet so that it returns the value returned from that call.