I am getting a generic 'Statement not valid or out of order' message with the below:
%macro test;
data _null_;
%if %sysfunc(fileexist("C:\report_201809.xlsx")) = 1 %then %do;
rc=%sysfunc(rename("C:\report_201809.xlsx",
"C:\report_201809.xlsx"_old.xlsx",'file'));
%end;
%mend;
%test;
The code below should get you what you need. While you can use %if statements in a data step you generally won't need to. I'm guessing the error is coming from the %sysfunc function around the fileexist and rename functions. %sysfunc allows you to call data step functions outside of a data step so it is not needed here.
%macro test;
data _null_;
if fileexist("C:\file.txt") then do;
rc = rename("C:\file.txt", "C:\file2.txt", 'file');
end;
run;
%mend;
Alternatively, you could use an X Command that allows you to execute Windows commands. You could replace the rename function with the following statement.
x move C:\file.txt C:\file2.txt;
Remove the DATA _NULL_ or proceed per #J_Lard.
Macro arguments used in %sysfunc invoked function calls are implicitly quoted and do not need additional ' or "
%macro test;
%local rc;
%if %sysfunc(fileexist(C:\report_201809.xlsx)) = 1 %then %do;
%let rc = %sysfunc(rename(C:\report_201809.xlsx,C:\report_201809_old.xlsx,file));
%end;
%test;
You original code may have worked (by way of non-obvious side effect) if the filename "C:\report_201809.xlsx"_old.xlsx" (having an extraneous ") was corrected to "C:\report_201809_old.xlsx"
Related
I am trying to solve a problem in which, based on certain conditions, it assigns you a parameter with the let function. For this exercise I am using %if with %let conditions on the code. The code I have written so far in simplified way is the following:
%let anio = 2022;
%let base = 2;
%Macro Data;
%if &anio = 2022 %then %do;
%Let year_add = %Str(&Base.C);
%Let year_add1 = %Str(&Base.B);
%mend;
%Data;
%put &=year_add;
%put &=year_add1;
The problem is that apparently the macro is not assigning any value to me in the second let statement
The first %put = &year_add gives me the correct result 2C.
Unfortunately with the second %put = &year_add1 it appears the following message: apparent symbolic referenc yeard_add1 not resolved
Can anyone can give me a hand or advise on how I can assign different let statements based on a condition?
Thanks in advance.
Your macro definition is missing an %END for the %DO.
%macro data;
%if &anio = 2022 %then %do;
%let year_add = &Base.C;
%let year_add1 = &Base.B;
%end;
%mend;
If the target macro variables, YEAR_ADD and YEAR_ADD1 do not already exist then your macro will create them as LOCAL to the DATA macro. So once the macro finishes they will be removed.
The easiest solution is just to make sure the macro variables exist before you call the macro.
%let anio = 2022;
%let base = 2;
%let year_add=;
%let year_add1=;
%data;
%put &=year_add;
%put &=year_add1;
If you are certain the macro variables do not already exist in some other macro that is calling %DATA() then you could add a %GLOBAL statement to define them in the GLOBAL macro scope so they will not be removed when the macro finishes by adding this to the macro definition:
%global year_add year_add1 ;
But that will generate an error if they have been defined as LOCAL to some other macro that called %DATA. So to be safe only force them into the GLOBAL scope if they do not already exist.
%if not %symexist(year_add) %then %global year_add;
%if not %symexist(year_add1) %then %global year_add1;
But the logic does not require you to define a macro. Just use the %IF/%THEN/%DO/%END block in open code. Then you won't have any macro variable scoping issues.
%if &anio = 2022 %then %do;
%let year_add = &Base.C;
%let year_add1 = &Base.B;
%end;
That works fine unless you are running on some really old version of SAS.
so I have a code like below
%let THIS_YEAR=2020;
%macro programall;
%do i = 2016 %to &THIS_YEAR;
%let num2 =%eval(&i-2000);
%let xxx= CAT("MP",&num2);
data t_&i.;
set table1;
where GROUP in ("&xxx");
run;
%end;
for example
when i=2016
num2 = 2016-2000;
num2 = 16;
and try to concatenate with "MP", so it should create xxx=MP16.
and try to use in where statement.
but it is causing error.
how can I create Macro Variable like "MP16"correctly, so I can use it in where clause?
Thanks
You cannot use functions in macro code, they are just treated as any other text to the macro processor. But there is no need to use a function to concatenate text in macro code. Just expand the macro variable where you want to use the text it contains.
%let xxx= MP&num2 ;
Macro variables are just text (not strings, text as in the thing you type in). So to concatenate macro variables, just put them next to each other.
%let var1=Banana;
%let var2=Pepper;
%let var3=&var1. &var2.;
%put &=var3;
You don't actually have to use the third variable of course, you could just use "&var1. &var2." or whatever in your code directly.
Try
%let THIS_YEAR=2020;
%macro programall;
%local year;
%do year = 2016 %to &THIS_YEAR;
data t_&year.;
set table1;
where GROUP in ("MP%eval(&year-2000)");
run;
%end;
%mend;
options mprint;
%programall
I am new to SAS macro writing and I have been struggling with writing a code for the following instance.
%let DateOfInterest= "15jul2016"d;
%let yearyyyy=%sysfunc(putn(&DateOfInterest,year4.));
%let yearyyyy2=eval(yearyyyy+1);
data _null_;
if "01JAN2016"d<=&DateOfInterest<="31MAR2016"d then do;
%let reportdate="31MAR2016"d;
%let reportdate2="01APR2016"d;
%let reportdate3="01JAN2016"d;
%let QuarterOfInterest=Q1;
if "31MAR2016"d<&DateOfInterest<="30JUN2016"d then do;
%let reportdate="30JUN2016"d;
%let reportdate2="01JUL2016"d;
%let reportdate3="01APR2016"d;
%let QuarterOfInterest=Q2;
if "30JUN2016"d<&DateOfInterest<="30SEP2016"d then do;
%let reportdate="30SEP2016"d;
%let reportdate2="01OCT2016"d;
%let reportdate3="01JUL2016"d;
%let QuarterOfInterest=Q3;
if "30SEP2016"d<&DateOfInterest<="31DEC2016"d then do;
%let reportdate="31DEC2016"d;
%let reportdate2="01JAN2017"d;
%let reportdate3="01OCT2016"d;
%let QuarterOfInterest=Q4;
end;
end;
end;
end;
run;
The code runs without any problem. However, whatever DateOfInterest I choose, the reportdate variables come out to be the ones specified in the last if loop. is there a way to change the code in order to have reportdates variable in line with the DateOfInterest?
Thanks.
You're combining macro with data step in a way that doesn't work. Macro language and data step language are basically unrelated: macro language can write data step code, and the other way around, but not affect each other generally.
In particular, macro code is compiled and executed first, before any dataset is opened or any data step code is compiled or executed. That's the point really - it lets you write datastep code pre-compilation.
So
if ... then do;
%let something
end;
That doesn't work, because the macro %let happens first, then later the data step happens.
%if ... %then %do;
%let something
%end;
That works, because it's all in the macro language. Generally speaking, if it doesn't have a % at the start, it's not a macro statement/function, and won't work on the macro language.
What you're doing is going to have some more complications, though. You have to be in a macro to use %if, but you also have scoping issues.
So a general small macro like this would be:
%let mval=1;
%macro set_things;
%if &mval=1 %then %do;
%let mval1=1;
%end;
%else %if &mval=2 %then %do;
%let mval2=1;
%end;
%else %do;
%let mval0=1;
%end;
%mend;
%set_things();
%put &=mval &=mval0 &=mval1 &=mval2;
Notice that doesn't work: because it's not global, so you need one more line inside the macro:
%global mval0 mval1 mval2;
That tells SAS to make them available in the global area.
I have a data set called monthlypayments, which is located in a folder I have assigned ‘training’ and it has a variable payments.
I want to output ‘payment type’ which is “high payment” if the payment>400 and “low payment” otherwise.
I keep getting this error
ERROR: DS-00075 : Parsing error occurred while trying to %EVAL an
expression: Invalid syntax found in call to %EVAL**
Can someone tell me what I'm doing wrong?
%LET root=D:\Users\Data;
libname training "&root.";
%LET dataset=training.monthlypayments;
%LET outlib=out;
%LET outfile=monthlypaymentsclassified;
%LET variable=payment;
%IF %EVAL(&VARIABLE.>400) %THEN %DO;
data &outlib..&outfile.;
set &dataset.;
paymenttype="high payment";
run;
%ELSE %DO;
data &outlib..&outfile.;
set &dataset.;
paymenttype="low payment";
run;
%END;
If you want to make a subset of the data based on values of the variables in the data then you need to use normal SAS code and not macro logic statements. If looks like your macro variable just tells you which data step variable to use in your IF statement.
data &outlib..&outfile.;
set &dataset.;
if &variable > 400 then paymenttype="high payment";
else paymenttype="low payment";
run;
I have a dataset naming error_table as follows. All the variables are character
Errorno Error Resolution
001 login check
002 datacheck check
I wanted a logic that executes a sas program If the Errorno is not in 001 and 002. Else stop execution and display the error_table.
I tried the following
%macro test();
proc sql;
select trim(Error_No) into: num from error_table;
quit;
%if &num. not in ("001","002") %then %do;
%include "/path/dev/program.sas";
%end;
%else %do;
proc print data = error_table;
run;
%end;
%mend;
%test;
But, it is throwing an error.
Can anyone please correct the logic.
You need to watch out for the case when the SELECT returns zero rows. You should set a default value to the macro variable NUM.
Is your dataset variable numeric or character? Use the TRIMMED or SEPARATED BY clause instead of the TRIM() function to prevent spaces in the macro variable that is generated by the INTO clause.
%let num=NONE;
select Error_No into: num trimmed from error_table;
Remember that to the macro processor everything is a string so don't but quotes around the values you are trying to match unless they are actually part of the value.
%if NOT (&num. in (001,002)) %then %do;
Also to use the IN operator in macro code you need to make sure you have set the MINDELIMITER option.
I would sugest moving condition with error codes to proc sql.
proc sql;
select count(*) into :num_errors
from error_table
where Errorno in ("001", "002");
quit;
Then in macrovariable you have number of errors that are 001 or 002.
Next step is to check macro-condition:
%if &num_errors. > 0 %then %do;
%include "/path/dev/program.sas";
%end;
%else %do;
proc print data = error_table;
run;
%end;
%mend;