User Profile 'Syntax Erro'r in Django - django

Question

I am trying to create the user profile in Django. t is a new User model that inherits from AbstractUser. It requires special care and to update some references through the settings.py. Ideally, it should be done at the beginning of the project, since it will dramatically impact the database schema. Extra care while implementing it.
Traceback (most recent call last):
File "manage.py", line 22, in <module>
execute_from_command_line(sys.argv)
File "/home/user/anaconda3/lib/python3.6/site-packages/django/core/management/__init__.py", line 381, in execute_from_command_line
utility.execute()
File "/home/user/anaconda3/lib/python3.6/site-packages/django/core/management/__init__.py", line 357, in execute
django.setup()
File "/home/user/anaconda3/lib/python3.6/site-packages/django/__init__.py", line 24, in setup
apps.populate(settings.INSTALLED_APPS)
File "/home/user/anaconda3/lib/python3.6/site-packages/django/apps/registry.py", line 112, in populate
app_config.import_models()
File "/home/user/anaconda3/lib/python3.6/site-packages/django/apps/config.py", line 198, in import_models
self.models_module = import_module(models_module_name)
File "/home/user/anaconda3/lib/python3.6/importlib/__init__.py", line 126, in import_module
return _bootstrap._gcd_import(name[level:], package, level)
File "<frozen importlib._bootstrap>", line 994, in _gcd_import
File "<frozen importlib._bootstrap>", line 971, in _find_and_load
File "<frozen importlib._bootstrap>", line 955, in _find_and_load_unlocked
File "<frozen importlib._bootstrap>", line 665, in _load_unlocked
File "<frozen importlib._bootstrap_external>", line 674, in exec_module
File "<frozen importlib._bootstrap_external>", line 781, in get_code
File "<frozen importlib._bootstrap_external>", line 741, in source_to_code
File "<frozen importlib._bootstrap>", line 219, in _call_with_frames_removed
File "/home/user/Desktop/vmail/vm/models.py", line 21
user = models.OneToOneField(User, on_delete=models, CASCADE)
^
SyntaxError: positional argument follows keyword argument
how to solve this syntax error?
my models.py
# -*- coding: utf-8 -*-
from __future__ import unicode_literals
from django.db import models
from django.utils import timezone
from django.contrib.auth.models import User
from django.db.models.signals import post_save
from django.dispatch import receiver
# Create your models here.
class login(models.Model):
title=models.CharField(max_length=50, blank=True, null=True)
content=models.TextField(blank=True, null=True)
date=models.DateTimeField(default=timezone.now())
def __str__(self):
return self.title
class UserProfileModel(models.Model):
user = models.OneToOneField(User, on_delete=models, CASCADE)
gender = models.CharField(max_length='1', choices=(('M','Male'),('F','Female')), blank=True)
age = models.PositiveIntegerField(blank=True, null=True)
def __str__(self):
return self.user.username
class Meta:
verbose_name = 'Profile'
verbose_name_plural = 'Profiles'

Answer 1

Change this to
user = models.OneToOneField(User, on_delete=models.CASCADE)