XSLT passing for each result to another template - xslt

Question

I would like to pass a for each loop as a parameter to another template
<xsl:template name="dataTableGroup">
<xsl:call-template name="test">
<xsl:with-param name="pContent1">
<xsl:for-each
select="NewDataSet/Table[generate-id() = generate-id(key('countryKey', concat(Unit, ReportingBusUnitDesc)))]">
<tr>
<td class="columnTextRight">
<xsl:value-of select="ReportingBusUnitDesc"/>
</td>
</tr>
</xsl:for-each>
</xsl:with-param>
</xsl:call-template>
</xsl:template>
and use it here
<xsl:template name="test">
<xsl:param name="pContent1"/>
<xsl:for-each select="$pContent1">
</xsl:for-each>
</xsl:template>
but instead of nodes I get only values. Idealy I would like to have it work with xslt 1.0.

Answer 1

If you use an XSLT 1.0 processor then the parameter value is a result tree fragment so you need to use a processor specific extension function like exsl:node-set (http://exslt.org/exsl/functions/node-set/index.html) first to convert it into a node set e.g.
<xsl:template name="test">
<xsl:param name="pContent1"/>
<xsl:for-each select="exsl:node-set($pContent1)/tr" xmlns:exsl="http://exslt.org/common">
</xsl:for-each>
</xsl:template>
Node that doing a copy of a result tree fragment is possible without using any extension e.g. <xsl:copy-of select="$pContent1"/> should do.
Also for the completeness of the example I have declared the namespace for the extension function on the xsl:for-each element, normally you would put it on the stylesheet's root element xsl:stylesheet/transform and additionally use exclude-result-prefixes="exsl" to ensure the namespace doesn't occur on any result elements.
With an XSLT 2 or 3 processor you shouldn't have any problems to use the variable directly as a fragment node containing your tr elements.