Django Form based on Form - django

Question

I am writing my code based on the principle don't repeat yourself. I keep violating that rule because I am new to Django but this one should be straight forward.
The code below is no problem for ModelAForm:
model.py
class ModelA(models.Model):
id = model.AutoField(primary_key=True)
name1 = models.CharField(max_length=100)
name2 = models.CharField(max_length=100)
...
right = models.BooleanField(default=True)
class ModelB(models.Model):
id = model.AutoField(primary_key=True)
mod = model.ForeignKey(ModelA, on_delete=models.CASCADE)
above30 = models.BooleanField(default=True)
forms.py
class ModelAForm(forms.ModelForm):
class Meta:
model = ModelA
exclude = ['id']
class ModelBForm(forms.ModelForm):
class Meta:
model = ModelB
exclude = ['id']
But this way I don't see the other fields of modelA in the ModelBForm. How can I do this?
Thanks!

Answer 1

Well, it should not. Because its FK relation between ModelB and ModelA. So in ModelB form, the ModelA entries should appear as a choice field. If you want to show fields of ModelA then try like this:
First, remove the FK reference field from ModelBForm:
class ModelBForm(forms.ModelForm):
class Meta:
model = ModelB
exclude = ['id', 'mod']
Now Use both those forms in your view:
def some_view(request):
if request.method == 'GET':
return render(request, 'template.html', {'form_a': ModelAForm(), 'form_b': ModelBForm()})
if request.method == 'POST':
form_a = ModelAForm(request.POST)
form_a = ModelBForm(request.POST)
if form_a.is_valid() and form_a.is_valid():
instance_a = form_a.save() # get model a instance
instance_b = form_b.save(commit=False)
instance_b.mod = instance_a # set model a instance as FK
instance_b.save()
Render the Form Like this:
<form action="." method="post">
{% csrf_token %}
{{ form_a.as_p }}
{{ form_b.as_p }}
<input type="submit" value="Submit">
</form>