How to write nested regex to find words below some string? - regex

Question

I am converting one pdf to text with xpdf and then find some words
with help of regex and preg_match_all.
I am seperating my words with colon in pdftotext.
Below is my pdftotext output:
In respect of Shareholders
Name: xyx
Residential address: dublin
No of Shares: 2
Name: abc
Residential address: canada
No of Shares: 2
So i write one regex that will show me words after colon in text().
$regex = '/(?<=: ).+/';
preg_match_all($regex, $string, $matches);
But Now i want regex that will display all data after In respect of Shareholders.
So, i write $regex = '/(?<=In respect of Shareholders).*?(?=\s)';
But it shows me only :
Name: xyx
I want first to find all data after In respect of shareholders and then another regex to find words after colon.

Answer 1

You may use
if (preg_match_all('~(?:\G(?!\A)|In respect of Shareholders)\s*[^:\r\n]+:\h*\K.*~', $string, $matches)) {
print_r($matches[0]);
}
See the regex demo
Details
(?:\G(?!\A)|In respect of Shareholders) - either the end of the previous successful match or In respect of Shareholders text
\s* - 0+ whitespaces
[^:\n\r]+ - 1 or more chars other than :, CR and LF
: - a colon
\h* - 0+ horizontal whitespaces
\K - match reset operator that discards all text matched so far
.* - the rest of the line (0 or more chars other than line break chars).

Answer 2

In your regex (?<=: ).+ you will match any character 1+ times after a colon and a space. To capture all that follows the spaces or tabs in a group, you could use (?<=: )[\t ](.+)
Another way to match the texts using a capturing group could be:
^.*?:[ \t]+(\w+)
Explanation
^ Assert start of the string
.*?: Match any character non greedy followed by a :
[ \t]+ Match 1+ times a space or a tab
(\w+) Capture in a group 1+ word characters
Regex demo | Php demo
Or use \K to forget what was matched if that is supported:
^.*?:\h*\K\w+
Regex demo