How do I save a '.txt' file as a '.mat' file, using either MATLAB or Python?
I tried using textscan() (in MATLAB), and scipy.io.savemat() (in Python). Both didn't help.
My text file is of the format: value1,value2,value3,valu4 (each row) and has over 1000 rows.
Appreciate any help is appreciated. Thanks in advance.
You can use textscan to read the file and save to save the variables into a .mat file
fid = fopen('yourTextFile.txt');
C = textscan(fid,'%f %f %f %f');
fclose(fid);
% maybe change the cells from `C` to a single matrix
M = cell2mat(C);
save('myMatFile.mat','M');
This works because your file seems to have a fixed format.
Have a look at this and this
I was able to get it to work using csvread() as follows:
file = csvread('yourTextFile.txt');
save('myMatFile.mat','file');
if what you need is to change file format:
mv example.mat example.txt
Related
I have a dataset, a ".inp" format file, and I need to read this file in c++. However, the fopen() fread() method seemed to fail and read the wrong data(e.g. the first integer should be 262144, the fread yields an integer much larger than this nevertheless).
To be more specific, my ".inp" file contains a few integers and float points, how can I read them successfully in c++?
enter image description here
This is the screenshot of the "*.inp" file from Notepad++. Basically this is a text file.
I solved it by coping the data into a txt. However, I am still not aware how to read "*.inp"
I found some info about INP file extension. It seems like there are multiple variances of it, each meant to be used for different purpose. Where is your file coming from? As for soultion, if you can't open the file using fopen/fstream normally, you could treat it as binary and read each value in the way you specify. Other than that, I could think of calling system functions to get file contents (like cat in linux for example), then if there are some random characters, you could parse your string to ommit them.
Here is example of how to call cat in C++:
Simple way to call 'cat' from c++?
I have file.txt with this structure (in picture):
and I want to read this file and i'dont know if there is a methode to read file by column because when i get for exemple 25 from my file i need to know that it is the VEHICLE NUMBER.
I think use to lines to do this!! any idea please?
There is no function in C++ to read a file by column. You have to write your own function to do that.
A text file is stored on disk line-by-line, so you have to read the whole file line-by-line and on each line parse out the column data you are interested in.
The problem is I have large amounts of data in OpenOffice Calc, approximately 3600 entries for each of 4 different categories and 3 different sets of this data, and I need to run some calculations on it in python. I want to create lists corresponding each of the four categories. I am hoping someone can help guide me to an easy-ish, efficient way to do this whether it be script or importing data. I am using python 2.7 on a windows 8 machine. Any help is greatly appreciated.
My current method i am trying is to save odf file as cvs then use genfromtxt(from numpy).
from numpy import genfromtxt
my_data = genfromtxt('C:\Users\tomdi_000\Desktop\Load modeling(WSU)\PMU Data\Data18-1fault-Alvey-csv trial.csv', delimiter=',')
print(my_data)
File "C:\Program Files (x86)\Wing IDE 101 5.0\src\debug\tserver\_sandbox.py", line 5, in <module>
File "c:\Python27\Lib\site-packages\numpy\lib\npyio.py", line 1352, in genfromtxt
fhd = iter(np.lib._datasource.open(fname, 'rbU'))
File "c:\Python27\Lib\site-packages\numpy\lib\_datasource.py", line 147, in open
return ds.open(path, mode)
File "c:\Python27\Lib\site-packages\numpy\lib\_datasource.py", line 496, in open
raise IOError("%s not found." % path)
IOError: C:\Users omdi_000\Desktop\Load modeling(WSU)\PMU Data\Data18-1fault-Alvey-csv trial.csv not found.
the error stems from this code in _datasource.py
# NOTE: _findfile will fail on a new file opened for writing.
found = self._findfile(path)
if found:
_fname, ext = self._splitzipext(found)
if ext == 'bz2':
mode.replace("+", "")
return _file_openers[ext](found, mode=mode)
else:
raise IOError("%s not found." % path)
Your problem is that your path string 'C:\Users\tomdi_000\Desktop\Load modeling(WSU)\PMU Data\Data18-1fault-Alvey-csv trial.csv' contains an escape sequence - \t. Since you are not using raw string literal, the \t is being interpreted as a tab character, similar to the way a \n is interpreted as a newline. If you look at the line starting with IOError:, you'll see a tab has been inserted in its place. You don't get this problem with UNIX-style paths, as they use forward slashes /.
There are two ways around this. The first is to use a raw string literal:
r'C:\Users\tomdi_000\Desktop\Load modeling(WSU)\PMU Data\Data18-1fault-Alvey-csv trial.csv'
(note the r at the beginning). As explained in the link above, raw string literals don't interpret back slashes \ as beginning an escape sequence.
The second way is to use a UNIX-style path with forward slashes as path delimiters:
'C:/Users/tomdi_000/Desktop/Load modeling(WSU)/PMU Data/Data18-1fault-Alvey-csv trial.csv'
This is fine if you're hard-coding the paths into your code, or reading from a file that you generate, but if the paths are getting generated automatically, such as reading the results of an os.listdir() command for example, it's best to use raw strings instead.
If you're going to be using numpy to do the calculations on your data, then using np.genfromtxt() is fine. However, for working with CSV files, you'd be much better off using the csv module. It includes all sorts of functions for reading columns and rows, and doing data transformation. If you're just reading the data then storing it in a list, for example, csv is definitely the way to go.
I have the file /etc/mydata which is in data format
$ file /etc/mydata
/etc/mydata: data
is there any fast way to convert
/etc/mydata: data
from data format to ASCII format to have this
/etc/mydata: ASCII text
thank you!
thank you
strings will filter any ASCII text in the file. But it's probably not what you actually need.
Hello I want to read from a text file full of directory contents
Here's my example:
below is my text file called MyText.txt
MyText.txt
title.txt,image.png,sound.mp3
I want to be able to read that .txt extension not the filename and I want it to be for file extensions only for example .txt or .mp3 how would I do that in c++?.
When I mean read I mean reference it in a if statement like this:
if(.mp3 exists in a text file)
{
fprintf(stderr,"sees the mp3 extensions");
}
I'm running Windows 7 32-bit.
I need a more cross platform approach.
May I suggest you to read a tutorial on C++ file handling and another one on C++ strings?
There is no a quick solution: you have to read the file using the ifstream class.
After reading the file and storing it in one or more strings, you can then use the find and substr string methods to create a queue of discrete filenames. Using the same methods, you can then split the queued elements again, in order to find the extensions and add them to a set. A set does not allow duplicates, so you are sure all the extensions will appear only once.