Push back data into a 2D vector - c++

Question

I am trying to create a 2d vector of set size and then insert data into it. The issue I am having is being able to insert the data filling up each column and row in the 2d vector.
I have read through various other threads, but cannot find an implementation that works for me.
Here is some sample code for my issue:
int main()
{
vector<string> strVec = { "a","b","c","d" };
// letters to insert into vector
// this is just a sample case
vector< vector<string>> vec; // 2d vector
int cols = 2; // number of columns
int rows = 2; // number of rows
for (int j = 0; j < cols; j++) // inner vec
{
vector<string>temp; // create a temporary vec
for (int o = 0; o < rows; o++) // outer vec
{
temp.push_back("x"); // insert temporary value
}
vec.push_back(temp); // push back temp vec into 2d vec
}
// change each value in the 2d vector to one
// in the vector of strings
// (this doesn't work)
// it only changes the values to the last value of the
// vector of strings
for (auto &v : strVec)
{
for (int i = 0; i < vec.size(); i++)
{
for (int j = 0; j < vec[i].size(); j++)
{
vec[i][j] = v;
}
}
}
// print 2d vec
for (int i = 0; i < vec.size(); i++)
{
for (int j = 0; j < vec[i].size(); j++)
{
cout << vec[i][j];
}
cout << endl;
}
}

Answer 1

You are assigning same string to all elements of vec again and again in the loop for (auto &v : strVec).
That is, vec[0][0]=vec[0][1]=vec[1][0]=vec[1][1]=a, vec[0][0]=vec[0][1]=vec[1][0]=vec[1][1]=b, and so on.
Removing this outer loop and assigning strVec[i*cols+j] to vec[i][j], we can get desired output.
DEMO is here.
for (int i = 0; i < vec.size(); i++)
{
for (int j = 0; j < vec[i].size(); j++)
{
vec[i][j] = strVec[i*cols+j];
}
}

Answer 2

for (int i = 0; i < vec.size(); i++)
{
for (int j = 0; j < 2; j++)
{
cout << vec[i][j];
}
cout << endl;
}