English to Pig Latin in C++ using specific functions - c++

Question

Ok, so I'm working on a project that requires us to translate English to Pig Latin. I was trying to kind of copy and tweak some code I found online that did the opposite because the functions kind of looked similar. In my class, we are given certain functions that have to be implemented in our code.
This has to be present in my source code:
struct Word
{
string english;
string pigLatin;
};
Function 1: Word * splitSentence(const string words, int &size); ~ Takes the English sentence as 1 string
Function 2: void convertToPigLatin(Word [] wordArr, int size); ~ Converts English to Pig Latin
Function 3: void convertToPigLatin(Word [] wordArr, int size); ~ Display
Here is the code that I have.
Edit: The problem I'm having is that I don't have wordArr declared anywhere in my code so it can't compile. I also noticed a few minor errors and changed my code a little. You'll have to excuse me I'm very tired right now.
#include <iostream>
#include <string>
#include <cctype>
using namespace std;
struct Word
{
string english;
string pigLatin;
};
Word * splitSentence(wordArr&; int &);
void convertToPigLatin (Word[], int);
void displayPigLatin (Word[], int);
int main()
{
string userInput;
int size;
cout <<"This is an English to Pig Latin translator.\n";
cout <<"Enter a sentance that you want to translate.\n";
getline(cin, userInput);
Word *wordArr = convertToPigLatin(userInput, size);
displayPigLatin(wordArr, size);
return 0;
}
Word * splitSentence(const Word [] wordArr, int &size)
{
int num = 0;
int phraseLength = userInput.length();
for (int i = 0; i < size; i++)
{
if (isspace(userInput[i]))
{
if (isspace(userInput[ i - 1]))
{
num--;
}
num++;
}
}
if (ispunct(userInput[i]))
{
if (i != (phraseLength - 1))
{
userInput.erase(1--, 1)
}
}
}
void convertToPigLatin(Word wordArr[], int size)
{
for (int i = 0; i < size; i++)
{
int stringLength;
if (i == (size - 1))
{
stringLength = wordArr[i].userInput.length();
}
else
{
stringLength = wordArr[i].userInput.length() - 1;
}
string vowel, way;
vowel = wordArr[i].userInput.at(stringLength - stringLength);
way = wordArr[i].userInput.at(stringLength - 3);
bool markV = ((vowel == 'A') || (vowel == 'a') (vowel == 'E') || (vowel == 'e')
(vowel == 'I') || (vowel == 'i') (vowel == 'O') || (vowel == 'o')
(vowel == 'U') || (vowel == 'u'));
wordArr[i].userInput.erase(stringLength - 3, 3);
if (!(markV && (way == 'w')))
{
wordArr[i].english = way + wordArr[i].userInput;
}
}
displayPigLatin(wordArr, stringLength);
}
void displayPigLatin(const Word wordArr[], int size);
{
cout << "\nHere is your phrase in PigLatin: ";
for (int i = 0 i < size; i++)
{
cout << wordArr[i].userInput << " ";
}
}

Answer 1

Important Note: You can only use range based for-loops in C++11 or higher if your compiler doesn't support C++11 or higher, use regular for-loops...
Given your question, you have to use this structure (It is equivalent to the one in the question):
typedef struct
{
std::string english;
std::string pig_latin;
} Word;
This is a macro which is going to be used to check if the first letter is a vowel or a consonant (Hence, !IS_VOWEL(some_char))...
#define IS_VOWEL(x) ((x) == 'A' || (x) == 'E' || (x) == 'I' || (x) == 'O' || (x) == 'U' || \
(x) == 'a' || (x) == 'e' || (x) == 'i' || (x) == 'o' || (x) == 'u')
Another function which we need to acquire only the part of the word which has letters (not symbols and numbers):
std::pair<unsigned, unsigned> GetWord(std::string word)
{
auto start = word.end();
for (auto it = word.begin(); it != word.end(); ++it)
if (tolower(*it) >= 'a' && tolower(*it) <= 'z' && start == word.end())
start = it;
else if (start != word.end() && !(tolower(*it) >= 'a' && tolower(*it) <= 'z'))
return std::make_pair(std::distance(word.begin(), start), std::distance(word.begin(), it));
return std::make_pair(start == word.end() ? 0 : std::distance(word.begin(), start), std::distance(word.begin(), word.end()));
}
And last but not least, the function to convert English to Pig-Latin (I know it is huge):
std::vector<Word> CreatePigLatinWordsFromEnglish(std::string english, bool sentence_case = true)
{
// You can break it from here to use inside another function (viz., splitSentence)
std::transform(english.begin(), english.end(), english.begin(), ::tolower);
std::stringstream english_stream(english);
std::vector<Word> words;
std::string temporary;
while (std::getline(english_stream, temporary, ' '))
words.emplace_back(Word({ temporary, "" }));
// Till here...
// From here the conversion starts...
for (auto &word : words)
{
auto const word_it = GetWord(word.english);
if (!IS_VOWEL(word.english[word_it.first]) && !std::string(std::next(word.english.begin(), word_it.first),
std::next(word.english.begin(), word_it.second)).empty())
{
word.pig_latin.append(std::string(word.english.begin(), std::next(word.english.begin(), word_it.first)));
word.pig_latin.append(std::string(std::next(word.english.begin(), word_it.first + 1), std::next(word.english.begin(), word_it.second)));
word.pig_latin.append(1, word.english[word_it.first]);
word.pig_latin.append(std::string("ay"));
word.pig_latin.append(std::next(word.english.begin(), word_it.second), word.english.end());
}
else
word.pig_latin = std::string(word.english.begin(), std::next(word.english.begin(), word_it.second)) + "way"
+ std::string(std::next(word.english.begin(), word_it.second), word.english.end());
}
// Conversion ends here...
// Changing the case from lower case to sentence case if needed...
if (sentence_case)
{
words[0].english[0] = toupper(words[0].english[0]);
words[0].pig_latin[0] = toupper(words[0].pig_latin[0]);
}
return words; // Returning the list of words we got...
}
Well, an example to demonstrate this method:
int main()
{
auto const test = "An apple a day keeps the doctor away!";
for (auto word : CreatePigLatinWordsFromEnglish(test))
std::cout << word.pig_latin << " ";
return 0;
}
Output:
Anway appleway away ayday eepskay hetay octorday awayway!
Try it out and see whether it gives you the required result...
Kind regards,
Ruks.