XSLT 2.0 tokenising delimiters within delimiters - xslt

Question

In XSLT 2.0 I have long string (parameter) with a delimiter (;) inside a delimiter (~), more specifically a triplet inside a delimiter.
Data is organized like so:
<parameter>qrsbfs;qsvsv;tfgz~dknk;fvtea;gtvath~pksdi;ytbdi;oiunhu</parameter>
The first tokenize($mystring,'~') in a for-each produces :
qrsbfs;qsvsv;tfgz
dknk;fvtea;gtvath
pksdi;ytbdi;oiunhu
Within that tokenization, I need to treat it by looping again:
qrsbfs
qsvsv
tfgz
dknk
fvtea
gtvath
pksdi
ytbdi
oiunhu
I can do intensive string manipulation to get there using concat, string-length, and substring-before/substring-after, but I wondered if there wasn't a more elegant solution that my neophyte mind wasn't overlooking?
EDIT, adding nested tokenize that returned incorrect results:
<xsl:for-each select="tokenize($myparameter,'~')">
<xsl:for-each select="tokenize(.,';')">
<xsl:if test="position()=1">
<xsl:value-of select="."/>
</xsl:if>
<xsl:if test="position()=2">
<xsl:value-of select="."/>
</xsl:if>
<xsl:if test="position()=3">
<xsl:value-of select="."/>
</xsl:if>
</xsl:for-each>
</xsl:for-each>

Answer 1

If you wanted a one line solution, you could do something like this, using nested for-in-return statements:
<xsl:sequence select="for $n in tokenize(.,'~') return concat(string-join(tokenize($n,';'),'
'),'
')"/>

Answer 2

If you don't need to tokenize them separately, you could replace the ~ with ; and tokenize all 9 elements at the same time:
tokenize(replace(parameter,'~',';'),';')

Answer 3

For what it's worth, the code in https://xsltfiddle.liberty-development.net/pPqsHUe uses
<xsl:template match="parameter">
<xsl:for-each select="tokenize(., '~')">
<xsl:value-of select="tokenize(., ';')" separator="
"/>
<xsl:text>
</xsl:text>
</xsl:for-each>
</xsl:template>
and with output method text produces
qrsbfs
qsvsv
tfgz
dknk
fvtea
gtvath
pksdi
ytbdi
oiunhu