I am trying to add multiple strings to the Include list of my Render Setup Layer Collection.
See Image Here
Here i can add 'test1' using setPattern
import maya.app.renderSetup.model.renderSetup as renderSetup
"""create render setup instance"""
rs = renderSetup.instance()
"""create the render layer"""
test = rs.createRenderLayer("fg_bty")
"""set render layer to be visible"""
rs.switchToLayer(test)
#create collection
scene_Assets = test.createCollection("scene_Assets")
# add specific items to collection
scene_Assets.getSelector().setPattern('test1')
If I try:
scene_Assets.getSelector().setPattern('test1', 'test2')
I get an error as it only accepts 2 arguments not 3 as given.
If I try:
scene_Assets.getSelector().setPattern('test1')
scene_Assets.getSelector().setPattern('test2')
It just replaces the string test1 with test2
Does anyone know how to append to the list so it doesn't replace? another way to do this? I have got a way to explicitly list the items but I wanted to keep it as an expression in case things need to be added to it later on.
you can set both patterns as a single string:
scene_Assets.getSelector().setPattern('test1, test2')
you can also retrieve a previously set pattern using:
scene_Assets.getSelector().getPattern()
retrieve and append the string, then set the new combined pattern as single string
old_pattern = scene_Assets.getSelector().getPattern()
new_pattern = ', '.join([old_pattern, 'test3', 'test4'])
scene_Assets.getSelector().setPattern(new_pattern)
result: 'test1, test2, test3, test4'
Related
I'm trying to write my own Jekyll plugin to construct an api query from a custom tag. I've gotten as far as creating the basic plugin and tag, but I've run into the limits of my programming skills so looking to you for help.
Here's my custom tag for reference:
{% card "Arbor Elf | M13" %}
Here's the progress on my plugin:
module Jekyll
class Scryfall < Liquid::Tag
def initialize(tag_name, text, tokens)
super
#text = text
end
def render(context)
# Store the name of the card, ie "Arbor Elf"
#card_name =
# Store the name of the set, ie "M13"
#card_set =
# Build the query
#query = "https://api.scryfall.com/cards/named?exact=#{#card_name}&set=#{#card_set}"
# Store a specific JSON property
#card_art =
# Finally we render out the result
"<img src='#{#card_art}' title='#{#card_name}' />"
end
end
end
Liquid::Template.register_tag('cards', Jekyll::Scryfall)
For reference, here's an example query using the above details (paste it into your browser to see the response you get back)
https://api.scryfall.com/cards/named?exact=arbor+elf&set=m13
My initial attempts after Googling around was to use regex to split the #text at the |, like so:
#card_name = "#{#text}".split(/| */)
This didn't quite work, instead it output this:
[“A”, “r”, “b”, “o”, “r”, “ “, “E”, “l”, “f”, “ “, “|”, “ “, “M”, “1”, “3”, “ “]
I'm also then not sure how to access and store specific properties within the JSON response. Ideally, I can do something like this:
#card_art = JSONRESPONSE.image_uri.large
I'm well aware I'm asking a lot here, but I'd love to try and get this working and learn from it.
Thanks for reading.
Actually, your split should work – you just need to give it the correct regex (and you can call that on #text directly). You also need to escape the pipe character in the regex, because pipes can have special meaning. You can use rubular.com to experiment with regexes.
parts = #text.split(/\|/)
# => => ["Arbor Elf ", " M13"]
Note that they also contain some extra whitespace, which you can remove with strip.
#card_name = parts.first.strip
#card_set = parts.last.strip
This might also be a good time to answer questions like: what happens if the user inserts multiple pipes? What if they insert none? Will your code give them a helpful error message for this?
You'll also need to escape these values in your URL. What if one of your users adds a card containing a & character? Your URL will break:
https://api.scryfall.com/cards/named?exact=Sword of Dungeons & Dragons&set=und
That looks like a URL with three parameters, exact, set and Dragons. You need to encode the user input to be included in a URL:
require 'cgi'
query = "https://api.scryfall.com/cards/named?exact=#{CGI.escape(#card_name)}&set=#{CGI.escape(#card_set)}"
# => "https://api.scryfall.com/cards/named?exact=Sword+of+Dungeons+%26+Dragons&set=und"
What comes after that is a little less clear, because you haven't written the code yet. Try making the call with the Net::HTTP module and then parsing the response with the JSON module. If you have trouble, come back here and ask a new question.
I am experimenting using elasticsearch in a dummy project in django. I am attempting to make a search page using django-elasticsearch-dsl. The user may provide a title, summary and a score to search for. The search should match all the information given by the user, but if the user does not provide any info about something, this should be skipped.
I am running the following code to search for all the values.
client = Elasticsearch()
s = Search().using(client).query("match", title=title_value)\
.query("match", summary=summary_value)\
.filter('range', score={'gt': scorefrom_value, 'lte': scoreto_value})
When I have a value for all the fields then the search works correctly, but if for example I do not provide a value for the summary_value, although I am expecting the search to continue searching for the rest of the values, the result is that it comes up with nothing as a result.
Is there some value that the fields should have by default in case the user does not provide a value? Or how should I approach this?
UPDATE 1
I tried using the following, but it returns every time no matter the input i am giving the same results.
s = Search(using=client)
if title:
s.query("match", title=title)
if summary:
s.query("match", summary=summary)
response = s.execute()
UPDATE 2
I can print using the to_dict().
if it is like the following then s is empty
s = Search(using=client)
s.query("match", title=title)
if it is like this
s = Search(using=client).query("match", title=title)
then it works properly but still if i add s.query("match", summary=summary) it does nothing.
You need to assign back into s:
if title:
s = s.query("match", title=title)
if summary:
s = s.query("match", summary=summary)
I can see in the Search example that django-elasticsearch-dsl lets you apply aggregations after a search so...
How about "staging" your search? I can think if the following:
#first, declare the Search object
s = Search(using=client, index="my-index")
#if parameter1 exists
if parameter1:
s.filter("term", field1= parameter1)
#if parameter2 exists
if parameter2:
s.query("match", field=parameter2)
Do the same for all your parameters (with the needed method for each) so only the ones that exist will appear in your query. At the end just run
response = s.execute()
and everything should work as you want :D
I would recommend you to use the Python ES Client. It lets you manage multiple things related to your cluster: set mappings, health checks, do queries, etc.
In its method .search(), the body parameter is where you send your query as you normally would run it ({"query"...}). Check the Usage example.
Now, for your particular case, you can have a template of your query stored in a variable. You first start with, let's say, an "empty query" only with filter, just like:
query = {
"query":{
"bool":{
"filter":[
]
}
}
}
From here, you now can build your query from the parameters you have.
This is:
#This would look a little messy, but it's useful ;)
#if parameter1 is not None or emtpy
#(change the if statement for your particular case)
if parameter1:
query["query"]["bool"]["filter"].append({"term": {"field1": parameter1}})
Do the same for all your parameters (for strings, use "term", for ranges use "range" as usual) and send the query in the .search()'s body parameter and it should work as you want.
Hope this is helpful! :D
I'd like to find a way to replace a part of a string: I'd like to remove everything after a substring, like ",".
Example: If my input string is "Hello, world!", the output should be "Hello".
I was surprised to find a join filter and not a split one.
Do I need to write a custom filter or can I do it with a built-in filter (I can't find it)?
Thank you.
Based on your links, I created a custom template tag myself, it perfectly works, here is the code:
// In a custom template file (see doc)
from django import template
register = template.Library()
#register.filter
def del_after_char(input_str, char):
try:
return input_str.split(char)[0]
except: # Do nothin if an error occurs
return input_str
I've been looking for a way to create a shapefile from a python list (in the case below, uniqueList).
Basically, I have been using SearchCursor's to iterate through a shapefile, and I would like to export the result as a shapefile...I tried CopyFeatures...but it didn't even return a blank file (it returned nothing).
import arcpy
def find_overlaps(input_features, output_features):
uniqueList = []
for row in arcpy.da.SearchCursor(input_features, ('OBJECTID', 'SHAPE#', 'name')):
foundMatch = False
for row2 in uniqueList:
if row[1].equals(row2[1]):
foundMatch = True
break
if foundMatch == False
uniqueList.append(row)
return uniqueList
## no work ##
arcpy.management.CopyFeatures(uniqueList, output_features)
I think you must create the feature class first. Use arcpy.CreateFeatureclass_managment(). In this function you can use template feature to specify fields. You can use your inputp_features and if you want only selected fields, you can use arcpy.MakeFeatureLayer_management (), should work. Alternatively you can create feature class without fields and then use arcpy.AddField_management() to add desired fields. For exact syntax check help there are few useful examples.
Good luck.
I may have overcomplicated things.
I have two views. The first view generates a bunch of temporary data based on the user's input from the form. Each of the generated data contains a name and misc data. I want to pass only the names to the template to be rendered as a list of hyperlinks. If the user clicks on one of them, the second view should be given the specific name the user clicked on so that the view can manipulate it. The only problem is, I don't know how to get the misc data associated with the name.
The misc data generated could contain random characters that's not a standard character in URLs, so I can't turn misc into a hyperlink like I can with just the name.
I have something like this:
views:
# Displays the temp data names
def display(request):
return render_to_response('display.html',{},context_instance=RequestContext(request))
# User provides input, generate temp data to be displayed as hyperlinks
def search(request):
form = SearchForm(request.POST)
if form.is_valid():
usr_input = form.cleaned_data['input']
data = generate_data(usr_input) # generates a list of (name, misc) data.
request.session['hyperlinks'] = get_list_names(data) # returns only names in data
return HttpResponseRedirect('views.display')
else:
....
# User has clicked on a hyperlink, we must process specific data given its name.
def process_data(request, name):
# How to get associated misc data created from search()?
I haven't written the template yet, but the idea is:
template:
{% for name_link in request.session.hyperlinks %}
<a href={% url process name_link %}>
{% endfor %}
One solution could be creating a bunch of session variables:
for name in get_list_names(data):
request.session[name] = // associated misc data
But this seems like a waste. Plus I'd have to manage deleting the session variable later on since this is only temporary data generated based on user input. A new input from the user would create another huge horde of session variables!
Another solution could be to store it temporarily in the database, but that also seems like a bad idea.
EDIT - Trying out suggestion by christophe31:
I'm not quite sure if I understand your suggestion, but is it something like this?
data_dict = {name1:misc1, name2:misc2, etc...}
encoded = urllib.urlencode(data_dict) # encoded = 'name1=misc1&name2:misc2...etc'
request.session['hyperlinks'] = encoded
A few questions on this though:
1) Wouldn't encoding it using urllib defeat the purpose of having a dictionary? It returns a string rather than a dictionary
2) To expand on (1), what if the misc data had '&' and '=' in it? It would screw up parsing which is the key and value by the second view. Also, misc data may have unusual characters, so allowing that to be part of the url to be displayed may be bad.
3) Does Django protect from allowing the user to maliciously modify the session misc data so that the misc data generated from the first view may be different than the one passed to the second view? That would be a problem!
You may want to put a dictionary as a session variable, set a cookie, or pass as get argument throught the link your data.
For me you have to put all these data in a dictionary before export it as get parameters (with urllib2) or store it in your user's session.
Ask me if you want more info on a suggested way.
Edit:
They are 2 ways I see, by session:
data_dict = {name1:misc1, name2:misc2, etc...}
request.session['hyperlinks'] = data_dict
Or passing to the template the data if no session backend:
data_dict = {name1:misc1, name2:misc2, etc...}
encoded = urllib.urlencode(data_dict)
return render(request, "my_template.html", {"url_params":encoded,}
and
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