Bash add regex values to an array - regex

Question

I am trying to write a bash script that will take in a file and look for all values matching a regular expression, and then add those to an array.
As a first step, I wrote a script that adds all lines in the log file to an array, and echoes them. Then, I tried editing that script to search for the regular expression in the log file, which is where I got a tremendous amount of errors.
What I am trying to do is grab the value inside the brackets of the log file. Some lines in the log file contain a syntax like [23423234 s] which is a time stamp. I want to grab the values (digits, space, and the "s") inside the brackets( but not the brackets!) and add those values to an array.
My initial script is below:
#!/bin/bash
echo "STARTING SCRIPT"
getArray(){
array=()
while IFS= read -r line
do
array+=("$line")
done <"$1"
}
getArray "testlog.txt"
for e in "${array[#]}"
do
echo "$e"
done
echo "DONE SCRIPT"
The log I am looking at looks like this:
[1542053213 s] Starting Program:
-----------------------------------------
[1542053213 s] PROGRAM ERROR
ERRHAND: 1033
ERRHAND: 233545
ERRHAND: 1
[1542053213 s] Program completed!
[1542053213 s] Config File complete. Stopping!
What I am aiming to do is do something with the following pseudocode:
For each line in file{
regex = [\d\ws]
if line matches regex{
add to array
}
}
for each item in array{
echo item
}
Currently, I have edited my script to look like below:
#!/bin/bash
echo "STARTING SCRIPT"
getArray(){
array=()
while IFS= read -r line
do
if [[$line =~ [\d\ws]; then
array+=("$line");
fi
done <"$1"
}
getArray "log.txt"
for e in "${array[#]}"
do
echo "$e"
done
echo "DONE SCRIPT"
But whenever I run it, I get the following set of errors:
[jm#local Home]$ ./Parser.sh
STARTING SCRIPT
./Parser.sh: line 9: [[[1542053213: command not found
./Parser.sh: line 9: [[-----------------------------------------: command not found
./Parser.sh: line 9: [[[1542053213: command not found
./Parser.sh: line 9: [[ERRHAND:: command not found
./Parser.sh: line 9: [[ERRHAND:: command not found
./Parser.sh: line 9: [[ERRHAND:: command not found
./Parser.sh: line 9: [[[1542053213: command not found
./Parser.sh: line 9: [[: command not found
./Parser.sh: line 9: [[[1542053213: command not found
DONE SCRIPT
Any advice would be greatly appreciated. I have tried looking at other posts but none have been able to really address my problem, which is creating a proper regex for the [2342323 s] pattern, and then adding that to an array. TiA

Answer 1

As pointed out in the comments
if [[ is missing its closing ]].
In a regex [ is not a literal, but starts a character group. To match something like [1234 s] you have to write \[[0-9]* s\].
To extract just the number 1234 from \[1234 s\] you can use tr, sed, perl -P, or a second grep -o.
Overall, your script seems way too complicated. You can drastically simplify it. Replace the for loop by mapfile and use grep -o to extract matches. You can replace your whole script with this
mapfile -t array < <(grep -o '\[[0-9]* s\]' logfile | tr -d '[] s')
printf '%s\n' "${array[#]}"
Note that if you only want to print the matches then you don't need an array. Just the grep part would be sufficient:
grep -o '\[[0-9]* s\]' logfile | tr -d '[] s'