Connecting selection of row in 2 QTableWidget - c++

Question

I am trying to connect row selections from two QTableWidget.
I mean, when I select one row in Table 1, I want my program selects the same row in table 2. The two table dont have the same number of column so I cannot just select one item for the first and select the same item on the second able.
I have tried to use the following without success:
connect(ui->table1->selectionModel(), SIGNAL(currentRowChanged(QModelIndex, QModelIndex)), ui->table2->selectionModel(), SLOT(setCurrentIndex(QModelIndex)));
It is written:
QObject::connect: No such slot QItemSelectionModel::setCurrentIndex(QModelIndex)
Do you know what is going wrong?

Answer 1

The problem is caused because setCurrentIndex() has two parameters, and not just one, plus the signatures do not match. So in these cases you should use a lambda and use selectRow():
#include <QApplication>
#include <QHBoxLayout>
#include <QTableWidget>
#include <QItemSelectionModel>
int main(int argc, char *argv[])
{
QApplication a(argc, argv);
auto *table1 = new QTableWidget(4, 3);
table1->setSelectionBehavior(QAbstractItemView::SelectRows);
auto table2 = new QTableWidget(4, 4);
table2->setSelectionBehavior(QAbstractItemView::SelectRows);
QObject::connect(table1->selectionModel(), &QItemSelectionModel::currentRowChanged,
[table2](const QModelIndex &current, const QModelIndex & previous)
{
if(previous.isValid())
table2->selectRow(current.row());
});
QWidget w;
auto lay = new QHBoxLayout(&w);
lay->addWidget(table1);
lay->addWidget(table2);
w.show();
return a.exec();
}