Read File and store in a array of chars - c++ - c++

Question

I'm trying to open a file and save the information there in an array of chars, however I'm not getting it. To save in a string use this:
int main(){
string line1;
ifstream myfile;
myfile.open("example.txt");
if(!myfile){
cout<<"Unable to open the file."<<endl;
exit(0);
}
while(getline(myfile,line1)){
ReadFile(myfile);
}
}
And It works.
When I use an array of chars, I code like this:
int main(){
int size=100;
char line1[size];
ifstream myfile;
myfile.open("example.txt");
if(!myfile){
cout<<"Unable to open the file."<<endl;
exit(0);
}
while(myfile.peek()!EOF){
line1[size]->ReadFile();
}
}
The function ReadFile is this:
void ReadFile(ifstream &is){
char aux[100];
is.getline(aux,100);
}

Answer 1

To read in an array of characters, or text, you can use std::getline and std::string:
std::string text;
std::getline(myfile, text);
To process text lines in a file:
std::string text;
while (std::getline(myfile, text))
{
Process_Text(text);
}
Don't use arrays of characters, as they can overflow. Also, instead of using == to compare, you'll have to use strcmp. Always verify that your array of characters is terminated by a nul character, '\0', otherwise the string functions will go beyond your array, not stopping until a nul is found.
Edit 1: Space separated
To read in text that is space separated, use:
std::string text;
myfile >> text;
Edit 2: Counting characters in a string
You can count characters in a string by using another array.
unsigned int frequency[128] = {0}; // Let's assume ASCII, one slot for each character.
// ... read in string
const size_t length(text.length());
for (size_t index = 0; index < length; ++index)
{
const char letter = text[index];
++frequency[letter];
}