Printing two-dimensional array - c++

Question

I have this two-dimensial array array[y][x] (where x is horizontal and y vertical):
3 2 0 0 0 0 0 0 0 0
1 4 3 0 0 0 0 0 0 0
2 4 0 0 0 0 0 0 0 0
2 4 0 0 0 0 0 0 0 0
1 3 0 0 0 0 0 0 0 0
4 2 5 1 0 0 0 0 0 0
1 3 0 0 0 0 0 0 0 0
2 3 0 0 0 0 0 0 0 0
2 3 0 0 0 0 0 0 0 0
And I need to print it like this:
3 1 2 2 1 4 1 2 2
2 4 4 4 3 2 3 3 3
3 5
1
How would I do this using c++?
Note that there are no empty lines. If the whole column only has zero's in them, there shouldn't be an endl

Answer 1

You need to iterate over and print out each element. You can flip the elements around by swapping the indices used to get the value out of the array.
#include<iostream>
#include<iomanip>
int gridWidth = 10;
int gridHeight = 10;
int cellWidth = 2;
for (int i = 0; i < gridHeight; i++){
bool anyVals = false;
for (int j = 0; j < gridWidth; j++){
int val = array[i][j]; //Swap i and j to change the orientation of the output
if(val == 0){
std::cout << std::setw(cellWidth) << " ";
}
else{
anyVals = true;
std::cout << std::setw(cellWidth) << val;
}
}
if(anyVals)
std::cout << std::endl;
}
Remember that if you swap i and j then you will need to swap gridWidth and gridHeight.
Just to avoid confusion std::setw(cellWidth) thing is a convenient way to print fixed-width text (like text that must always be two characters long). It takes whatever you print out and adds spaces to it to make it the right length.

Answer 2

Take the transpose of your matrix , make 2 loops(outer and inner ) and print only if the no is greater than zero and print space for every zero. when you go back again to the outer loop ,print new line .

Answer 3

Something like this should help you.
for (int i = 0; i < y; i++)
for (int j = 0; j < x; j++)
if (array[i][j] != 0)
cout << array[i][j];
else
cout << " ";
cout << endl;