how to store user input into array in C++ - c++

Question

I am new to C++, and want to ask this basic question
what i want: user input data like 2:3American, 4:2China (this means my country team wins 2 points lose 3 points againts American. my country team win 4 points and China team win 2 points)
in console:
please input the result for your team against other teams, input negative number to exit
2:3American
4:2China
-1
result win:1
lose:1
draw:0

Answer 1

If there is no specific encoding is given to you by some authority, use as simple as possible. A better was "2 3 American 4 2 China". So that you only deal with a simple for loop.
The result line is not calculated. Convert each string to integer to calculate.
int main( int argc, char* argv[]) {
std::vector<std::string> arguments(argv + 1, argv + argc);
std::cout << "arguments contains \n";
for (std::vector<std::string>::iterator it = arguments.begin() ; it != arguments.end(); ++it) {
int firstPos = it->find_first_of(":");
int secPos = 0;
std::string firstInteger = it->substr(0,firstPos);
std::string secondInteger;
if ( firstInteger.compare("-1") == 0 ) {
std::cout << "breaking \n";
return 0;
} else {
std::cout << " f=<" << firstInteger << ">";
secPos = it->find_first_not_of( "012345678:", firstPos);
if ( secPos == std::string::npos )
std::cout << "not found";
std::cout << " s=<" << it->substr(firstPos+1 ,secPos-firstPos-1 ) << "> ";
std::string teamName = it->substr(secPos);
std::cout << teamName ;
std::cout << std::endl;
}
}
std::cout << '\n';
return 0;
}

Answer 2

I've written a code similar to this problem a long time ago. made a small change to solve your problem.
So i think this is what you want
INPUT "2:3American 4:2China -1" (SINGLE LINE)
OUTPUT as expected
#include <iostream>
using namespace std;
size_t non_int(int index,string* s)
{
int i=index;
for( i=index;i<s->length();i++){
if(s->at(i) >= '0' && s->at(i) <= '9')
{
// cout << s->at(i) << " is a Digit";
}
else{
return (i-1)<index?(std::string::npos):(i-1);
}
}
return (i-1)<index?(std::string::npos):(i-1);;
}
int main()
{
cout << "Please input the match result such as 2:3American " << endl;
string str;
std::getline (std::cin,str);
//cout<<str;// i want to see did the first user input stored in array. But seems the console..does not print out temp[0] and just skipt it
int win,lose,draw=0;
std::size_t found = 0;
string s1,s2;
int i1,i2;
std::size_t f1,f2;
while( found !=std::string::npos)
{
f1 = str.find(":",found);
if (f1!=std::string::npos){
i1 = stoi(str.substr(found,f1-found));
f2 = non_int(f1+1,&str);
if (f2!=std::string::npos){
i2 = stoi(str.substr(f1+1,f2-f1));
if(i1>i2) win++;
else if(i1<i2)lose++;
else draw++;
}
else {
cout<<"ERROR :invalid input ";
}
}
else {
//exit on -ve input
// cout<<"ERROR 45 ";
}
found = str.find(" ",found+1);
}
cout<<"win:"<<win<<"lose:"<<lose<<"draw:"<<draw<<endl;
return 0;
}

Answer 3

Step 1:
Define a class that represents an input token.
struct Segment
{
int myCountryScore;
int otherCountryScore;
std::string otherCountry;
};
Step 2
Define an input function that reads a Segment from a stream.
std::istream& operator>>(std::istream& s, Segment& data)
{
Segment tmp;
char sep;
int firstNumber;
bool good = false;
if (s >> firstNumber && firstNumber >= 0)
{
tmp.myCountryScore = firstNumber;
if (s >> std::noskipws >> sep >> tmp.otherCountryScore >> tmp.otherCountry >> std::skipws) && (sep == ':'))
{
// The read worked. Copy it to the output object.
data = tmp;
good = true;
}
}
if (!good) {
// If there was an error reading.
// Or we reached the end (negative number read)
// Then set the state of the stream to failure mode.
s.setstate(std::ios::failbit);
}
return s;
}
Step 3
Write a loop that reads Segments from a stream in a loop.
Segment object;
while(std::cin >> object) {
// You have correctly read an object
// Add your code to handle it here.
}
Step 3 Alternative.
Rather than read the Segment one by one you can copy them into a vector simply using a stream iterator.
std::vector<Segment> data(std::istream_iterator<Segment>(std::cin),
std::istream_iterator<Segment>());