How to execute Django Query as string - django

Question

I want to make a query in Django ORM like this:
query_string = "optionA=True,optionB=True,optionC=True"
data = ModelObject.objects.filter(query_string)
This code is giving following error:
Traceback (most recent call last):
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/django/core/handlers/exception.py", line 41, in inner
response = get_response(request)
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/django/core/handlers/base.py", line 187, in _get_response
response = self.process_exception_by_middleware(e, request)
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/django/core/handlers/base.py", line 185, in _get_response
response = wrapped_callback(request, *callback_args, **callback_kwargs)
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/django/views/decorators/csrf.py", line 58, in wrapped_view
return view_func(*args, **kwargs)
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/django/views/generic/base.py", line 68, in view
return self.dispatch(request, *args, **kwargs)
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/rest_framework/views.py", line 483, in dispatch
response = self.handle_exception(exc)
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/rest_framework/views.py", line 443, in handle_exception
self.raise_uncaught_exception(exc)
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/rest_framework/views.py", line 480, in dispatch
response = handler(request, *args, **kwargs)
File "/root/hellomeets/hellomeets/frontend/views.py", line 74, in post
filtered_emails = HelloMeetsMailList.objects.filter(final_query)
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/django/db/models/manager.py", line 85, in manager_method
return getattr(self.get_queryset(), name)(*args, **kwargs)
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/django/db/models/query.py", line 784, in filter
return self._filter_or_exclude(False, *args, **kwargs)
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/django/db/models/query.py", line 802, in _filter_or_exclude
clone.query.add_q(Q(*args, **kwargs))
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/django/db/models/sql/query.py", line 1250, in add_q
clause, _ = self._add_q(q_object, self.used_aliases)
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/django/db/models/sql/query.py", line 1276, in _add_q
allow_joins=allow_joins, split_subq=split_subq,
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/django/db/models/sql/query.py", line 1151, in build_filter
arg, value = filter_expr
ValueError: too many values to unpack
I also tried eval() but it didn't work.
Is there any way so that I don't need to write raw sql query

Answer 1

from django.db.models import Q
query_string=Q(optionA=True) & Q(optionB=True) & Q(optionC=True)
data = ModelObject.objects.filter(query_string)
for more details:
https://docs.djangoproject.com/en/2.1/topics/db/queries/#complex-lookups-with-q-objects

Answer 2

If you really need to use that string (which seems like a very hacky way to query Django models) you can split and convert it into a dict:
s = "optionA=True,optionB=True,optionC=True"
kwargs = {}
for e in s.split(','):
k, v = e.split('=')
kwargs[k] = bool(v)
and then unpack that dict in the filter() method
data = ModelObject.objects.filter(**kwargs)
But this is not really recomended!!!