XSLT output empty Debugging fails with no output - xslt

I read through forums and i am unable to understand why the output is empty. It might be a simple thing i am missing.
I tried debugging in VS 2017 and it does not give any output any help in this matter is appreciated. IF i input only the ns0:EFACT_D96A_ORDERS_EAN008 node as an input to XSLT the output comes with the "test" content
<?xml version="1.0" encoding="UTF-16"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" xmlns:var="http://schemas.microsoft.com/BizTalk/2003/var" exclude-result-prefixes="msxsl var s0 userCSharp" version="1.0" xmlns:ns1="http://Microsoft.LobServices.Sap/2007/03/Types/Idoc/3/ORDERS05//740" xmlns:ns0="http://Microsoft.LobServices.Sap/2007/03/Idoc/3/ORDERS05//740/Send" xmlns:ns2="http://Microsoft.LobServices.Sap/2007/03/Types/Idoc/Common/" xmlns:s0="http://schemas.microsoft.com/BizTalk/EDI/EDIFACT/2006" xmlns:ns3="http://schemas.microsoft.com/2003/10/Serialization/" xmlns:userCSharp="http://schemas.microsoft.com/BizTalk/2003/userCSharp" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:ins0="http://schemas.microsoft.com/BizTalk/EDI/EDIFACT/2006/InterchangeXML">
<xsl:output omit-xml-declaration="yes" method="xml" version="1.0" />
<xsl:template match="/">
<xsl:apply-templates select="/s0:EFACT_D96A_ORDERS_EAN008" />
</xsl:template>
<xsl:template match="/s0:EFACT_D96A_ORDERS_EAN008">
<ns0:Send>
<ns0:idocData>
Test
</ns0:idocData>
</ns0:Send>
</xsl:template>
</xsl:stylesheet>
Input file-
<ins0:EdifactInterchangeXml DelimiterSetSerializedData="39:-1:-1:43:58:63:-1:46:-1" xmlns:ins0="http://schemas.microsoft.com/BizTalk/EDI/EDIFACT/2006/InterchangeXML">
<ns0:UNA xmlns:ns0="http://schemas.microsoft.com/Edi/EdifactServiceSchema">
<UNA1>58</UNA1>
</ns0:UNA>
<ns0:UNB xmlns:ns0="http://schemas.microsoft.com/Edi/EdifactServiceSchema">
<UNB1>
<UNB1.1>ABCD</UNB1.1>
<UNB1.2>5</UNB1.2>
</UNB1>
</ns0:UNB>
<TransactionSetGroup>
<TransactionSet DocType="http://schemas.microsoft.com/BizTalk/EDI/EDIFACT/2006#EFACT_D96A_ORDERS_EAN008">
<ns0:EFACT_D96A_ORDERS_EAN008 xmlns:ns0="http://schemas.microsoft.com/BizTalk/EDI/EDIFACT/2006">
</ns0:EFACT_D96A_ORDERS_EAN008>
</TransactionSet>
</TransactionSetGroup>
<ns0:UNZ xmlns:ns0="http://schemas.microsoft.com/Edi/EdifactServiceSchema">
<UNZ1>1</UNZ1>
<UNZ2>86</UNZ2>
</ns0:UNZ>
</ins0:EdifactInterchangeXml>

A forward slash / at the start of the expression matches the document node, so doing select="/s0:EFACT_D96A_ORDERS_EAN008" will only select s0:EFACT_D96A_ORDERS_EAN008 if it is a child of the document node. i.e. if it is the root element, which it isn't.
To select s0:EFACT_D96A_ORDERS_EAN008 regardless of where it is in the document do this...
<xsl:apply-templates select="//s0:EFACT_D96A_ORDERS_EAN008" />
You also need to remove the single forward slash from the match expression too (You don't need the double-slashes in the match expression, as the match will work regardless of where the element is in the document)
Try this XSLT
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" xmlns:var="http://schemas.microsoft.com/BizTalk/2003/var" exclude-result-prefixes="msxsl var s0 userCSharp" version="1.0" xmlns:ns1="http://Microsoft.LobServices.Sap/2007/03/Types/Idoc/3/ORDERS05//740" xmlns:ns0="http://Microsoft.LobServices.Sap/2007/03/Idoc/3/ORDERS05//740/Send" xmlns:ns2="http://Microsoft.LobServices.Sap/2007/03/Types/Idoc/Common/" xmlns:s0="http://schemas.microsoft.com/BizTalk/EDI/EDIFACT/2006" xmlns:ns3="http://schemas.microsoft.com/2003/10/Serialization/" xmlns:userCSharp="http://schemas.microsoft.com/BizTalk/2003/userCSharp" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:ins0="http://schemas.microsoft.com/BizTalk/EDI/EDIFACT/2006/InterchangeXML">
<xsl:output omit-xml-declaration="yes" method="xml" version="1.0" />
<xsl:template match="/">
<xsl:apply-templates select="//s0:EFACT_D96A_ORDERS_EAN008" />
</xsl:template>
<xsl:template match="s0:EFACT_D96A_ORDERS_EAN008">
<ns0:Send>
<ns0:idocData>
Test
</ns0:idocData>
</ns0:Send>
</xsl:template>
</xsl:stylesheet>

Related

I need to remove a node from an XML based on a Condition using Group by

I have the following XML:
<?xml version="1.0" encoding="UTF-8"?>
<root>
<EMPLOYEE_ASSIGNMENT>
<REFRESH_DATE>2022-03-10 10:55:35.000</REFRESH_DATE>
<PERSON_ID>11189</PERSON_ID>
<EMPLOYEE_ID>032656300</EMPLOYEE_ID>
<EFFECTIVE_START_DATE>2020-08-19 00:00:00.000</EFFECTIVE_START_DATE>
<EFFECTIVE_END_DATE>4712-12-31 00:00:00.000</EFFECTIVE_END_DATE>
<BUSINESS_PROCESS>Absence Return for XXXXXXXXX last day of absence on 08/18/2020, first day back at work on 08/19/2020</BUSINESS_PROCESS>
<ACT_ASSIGNMENT_STATUS_TYPE_ID>1</ACT_ASSIGNMENT_STATUS_TYPE_ID>
<ACT_ORGANIZATION_ID>601</ACT_ORGANIZATION_ID>
<ACT_JOB_QUINTIQ_POSITION>Trainee</ACT_JOB_QUINTIQ_POSITION>
<ACT_HOURS_PER_WEEK>37.5</ACT_HOURS_PER_WEEK>
<ACT_HOURS_FREQUENCY>W</ACT_HOURS_FREQUENCY>
<ACT_BARGAINING_UNIT_CODE>C</ACT_BARGAINING_UNIT_CODE>
<ACT_PRIMARY_PROVINCE>BC</ACT_PRIMARY_PROVINCE>
</EMPLOYEE_ASSIGNMENT>
<EMPLOYEE_ASSIGNMENT>
<REFRESH_DATE>2022-03-10 10:55:35.000</REFRESH_DATE>
<PERSON_ID>11189</PERSON_ID>
<EMPLOYEE_ID>032656300</EMPLOYEE_ID>
<EFFECTIVE_START_DATE>2020-08-19 00:00:00.000</EFFECTIVE_START_DATE>
<EFFECTIVE_END_DATE>4712-12-31 00:00:00.000</EFFECTIVE_END_DATE>
<BUSINESS_PROCESS>Data Change: XXXXXXXXXXXX</BUSINESS_PROCESS>
<ACT_ASSIGNMENT_STATUS_TYPE_ID>1</ACT_ASSIGNMENT_STATUS_TYPE_ID>
<ACT_ORGANIZATION_ID>856</ACT_ORGANIZATION_ID>
<ACT_JOB_QUINTIQ_POSITION>Employee</ACT_JOB_QUINTIQ_POSITION>
<ACT_HOURS_PER_WEEK>37.5</ACT_HOURS_PER_WEEK>
<ACT_HOURS_FREQUENCY>W</ACT_HOURS_FREQUENCY>
<ACT_BARGAINING_UNIT_CODE>C</ACT_BARGAINING_UNIT_CODE>
<ACT_PRIMARY_PROVINCE>MB</ACT_PRIMARY_PROVINCE>
</EMPLOYEE_ASSIGNMENT>
</root>
The two nodes have the same EFFECTIVE_START_DATE but different BUSINESS_PROCESS for a single EMPLOYEE_ID. I need to transform that XML in a way that: when Two (or more) BUSINESS_PROCESS are present for and EMPLOYEE_ID on the same EFFECTIVE_START_DATE it shows only the one that is of value Data Change: XXXXXXXXX.
I need to transform it to:
<?xml version="1.0" encoding="UTF-8"?>
<root>
<EMPLOYEE_ASSIGNMENT>
<REFRESH_DATE>2022-03-10 10:55:35.000</REFRESH_DATE>
<PERSON_ID>11189</PERSON_ID>
<EMPLOYEE_ID>032656300</EMPLOYEE_ID>
<EFFECTIVE_START_DATE>2020-08-19 00:00:00.000</EFFECTIVE_START_DATE>
<EFFECTIVE_END_DATE>4712-12-31 00:00:00.000</EFFECTIVE_END_DATE>
<BUSINESS_PROCESS>Data Change: XXXXXXXXXXXX</BUSINESS_PROCESS>
<ACT_ASSIGNMENT_STATUS_TYPE_ID>1</ACT_ASSIGNMENT_STATUS_TYPE_ID>
<ACT_ORGANIZATION_ID>856</ACT_ORGANIZATION_ID>
<ACT_JOB_QUINTIQ_POSITION>Employee</ACT_JOB_QUINTIQ_POSITION>
<ACT_HOURS_PER_WEEK>37.5</ACT_HOURS_PER_WEEK>
<ACT_HOURS_FREQUENCY>W</ACT_HOURS_FREQUENCY>
<ACT_BARGAINING_UNIT_CODE>C</ACT_BARGAINING_UNIT_CODE>
<ACT_PRIMARY_PROVINCE>MB</ACT_PRIMARY_PROVINCE>
</EMPLOYEE_ASSIGNMENT>
</root>
Thanks a lot
This is difficult to follow. If (!) I understand your description correctly, you want to do:
XSLT 2.0
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/root">
<xsl:copy>
<xsl:for-each-group select="EMPLOYEE_ASSIGNMENT" group-by="concat(EMPLOYEE_ID,'|', EFFECTIVE_START_DATE)">
<xsl:copy-of select="current-group()[starts-with(BUSINESS_PROCESS, 'Data Change:')]"/>
</xsl:for-each-group>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>

Biztalk Map node validation

I'm mapping home, work and mobile number nodes from the source schema to the home, work and mobile node in the destination schema.
I need to ensure that the data matches destination pattern (No space, punctuation, leading zeros, matching [+0][0-9]*. Can this be achieved via XSLT?
Source
<HTelephone>01656 123 123</HTelephone>
<WTelephone>01656-123-123</WTelephone>
<MTelephone>+447656 123 123</MTelephone>
Destination
<HTelephone>01656123123</HTelephone>
<WTelephone>01656123123</WTelephone>
<MTelephone>+447656123123</MTelephone>
Current Inline XSLT Call Template
<xsl:template name="MNo" xmlns:msxsl="urn:schemas-microsoft-com:xslt" >
<xsl:param name="inTelNo"/>
<xsl:element name="MTelephone" >
<xsl:value-of select="concat('+', translate($inTelNo, translate($inTelNo,'0123456789',''), ''))"/>
</xsl:element>
We need to validation the first character to allow a 0 or + also, any ideas?
Assuming correct input ( a root element to make it well-formed XML) use the concat() and translate functions to change the strings.
Input
<?xml version="1.0" encoding="utf-8"?>
<root>
<HTelephone>01656 123 123</HTelephone>
<WTelephone>01656 123 123</WTelephone>
<MTelephone>01656 123 123</MTelephone>
</root>
Stylesheet
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/root">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="root/*">
<xsl:copy>
<xsl:value-of select="concat('+',translate(.,' ',''))"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Output
<?xml version="1.0" encoding="utf-8"?>
<root>
<HTelephone>+01656123123</HTelephone>
<WTelephone>+01656123123</WTelephone>
<MTelephone>+01656123123</MTelephone>
</root>

How to copy a certain node (with children) from a XML with XSLT in Biztalk specifying a custom namespace?

I need to copy a subnode from a XML to a certain node of a new XML in a Biztalk Map using XSLT.
Consider the following input XML:
<?xml version="1.0" encoding="UTF-8"?>
<ns0:root xmlns:ns0="http://not/useful/data/">
<ns0:notuseful>
<ns0:foo></ns0:foo>
<ns0:foo2></ns0:foo2>
<ns0:blabla></ns0:blabla>
</ns0:notuseful>
<ns0:data>
<ns1:usefulDataList xmlns:ns1="http://useful/data/">
<ns1:usefulData>
<ns1:usefulChild1></ns1:usefulChild1>
<ns1:usefulChild2></ns1:usefulChild2>
<ns1:usefulChild3></ns1:usefulChild3>
<ns1:usefulChild4></ns1:usefulChild4>
<ns1:usefulChild5></ns1:usefulChild5>
</ns1:usefulData>
</ns1:usefulDataList>
</ns0:data>
<ns0:root>
What I need is to extract the node called "usefulDataList", so I need to copy it in a new XML like this one:
<?xml version="1.0" encoding="UTF-8"?>
<ns2:root2 xmln:ns2="http://new/xml">
<ns2:blabla>
<ns2:stuff />
</ns2:blabla>
<ns2:data>
<ns2:usefulDataList>
<ns2:usefulData>
<ns2:usefulChild1></ns2:usefulChild1>
<ns2:usefulChild2></ns2:usefulChild2>
<ns2:usefulChild3></ns2:usefulChild3>
<ns2:usefulChild4></ns2:usefulChild4>
<ns2:usefulChild5></ns2:usefulChild5>
</ns2:usefulData>
</ns2:usefulDataList>
</ns2:data>
</ns2:root2>
This should be done inside a Biztalk Functoid, as you see namespaces from source and target are diferent.
I'm an absolute beginner with XSLT, and I've been doing some tests, but I've something wrong with my XSLT expressions:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:ns2="http://new/xml">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" />
<xsl:template name="testTemplate" match="//*[local-name() = 'usefulDataList ']">
<xsl:element name="ns0:usefulDataList " namespace="">
<xsl:apply-templates mode="copy-no-ns" select="usefulDataList"/>
</xsl:element>
</xsl:template>
<xsl:template mode="copy-no-ns" match="*">
<xsl:element name="{name(.)}" namespace="{namespace-uri(.)}">
<xsl:copy-of select="#*"/>
<xsl:apply-templates mode="copy-no-ns"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
I'd appreciate any tip, with XSLT or Biztalk mapper. I don't like linking a huge amount of fields one by one if I can solve it with a XSLT expression.
Greetings.
Beware you had a space in *[local-name() = 'usefulDataList ']" so that would never match. this works:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ns2="http://new/xml">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" />
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<ns2:root>
<ns2:blabla>
<ns2:stuff />
</ns2:blabla>
<ns2:data>
<xsl:apply-templates mode="copy-no-ns" select="//*[local-name() = 'usefulDataList']"/>
</ns2:data>
</ns2:root>
</xsl:template>
<xsl:template mode="copy-no-ns" match="*">
<xsl:element name="ns2:{local-name(.)}">
<xsl:copy-of select="#*"/>
<xsl:apply-templates mode="copy-no-ns"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>

XSLT transforming name value pairs to its corresponding XML

I am new to XSLT I am trying to transform a name value pair to its corresponding XML. This feature is primarily used in case of special extensions to a standard.
The file I want to transform is the following. There are no spaces expected in any of the extNames.
<?xml version="1.0" encoding="UTF-8"?>
<extensionItems xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:noNamespaceSchemaLocation="ExtensionItems.xsd">
<extensionsItem>
<extName> callCode</extName>
<extValue>1</extValue>
<extType>integer</extType>
</extensionsItem>
<extensionsItem>
<extName>callbackType</extName>
<extValue>All</extValue>
<extType>string</extType>
</extensionsItem>
<extensionsItem>
<extName>callbackEmail</extName>
<extValue>me#mine.org</extValue>
<extType>string</extType>
</extensionsItem>
</extensionItems>
to the following:
<ODEventNotificationExtraField>
<callCode> 1</callCode>
<callbackType> All </callbackType>
<callbackEmail> me#mine.org </callbackEmail>
</ODEventNotificationExtraField>
The following stylesheet produces the desired result:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes" omit-xml-declaration="yes"/>
<xsl:template match="extensionItems">
<ODEventNotificationExtraField>
<xsl:apply-templates/>
</ODEventNotificationExtraField>
</xsl:template>
<xsl:template match="extensionsItem">
<xsl:element name="{extName}">
<xsl:value-of select="extValue"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>

Removing an XML tag that is named like xfdf:field (with a namespace)

I want to remove an XML element from an XML file. The tag that I want to remove is named as xfdf:field.
How do I specify this in my xslt ? I tried this and I am getting an error saything "org.apache.xpath.domapi.XPathStylesheetDOM3Exception: Prefix must resolve to a namespace: xfdf ".
Here is my xslt.
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" />
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*" />
</xsl:copy>
</xsl:template>
<xsl:template match="xfdf:field"></xsl:template>
</xsl:stylesheet>
Here is my xml.
<xfa:datasets
xmlns:xfa="http://www.xfa.org/schema/xfa-data/1.0/"
xmlns:dd="http://ns.adobe.com/data-description/" xmlns:tns="http://hostname"
xmlns:xfdf="http://ns.adobe.com/xfdf/">
<xfa:data>
<tns:form xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<tns:formHeader>
<tns:formId>formid</tns:formId>
<tns:revId>Rev123</tns:revId>
<tns:agencyId>agency</tns:agencyId>
<tns:progId>program</tns:progId>
<tns:serviceId>service</tns:serviceId>
</tns:formHeader>
<tns:formFields>
<tns:date>08-13-1967</tns:date>
<tns:agreementBetween></tns:agreementBetween>
<tns:ncr>xxxx</tns:ncr>
<tns:formConfirmationInfo>
<tns:confNbrLbl>nbrlabel</tns:confNbrLbl>
<tns:confNbrData>1231</tns:confNbrData>
<tns:custNameLbl>3332</tns:custNameLbl>
<tns:custNameData>dasdas</tns:custNameData>
<tns:dateLbl>date</tns:dateLbl>
<tns:dateData>01012001</tns:dateData>
</tns:formConfirmationInfo>
</tns:formFields>
<xfdf:field xmlns:xfdfi="http://ns.adobe.com/xfdf-transition/"
xfdfi:original="FSAPPLICATIONDATA_">
<!--irrelevant data omitted-->
</xfdf:field>
</tns:form>
</xfa:data>
</xfa:datasets>
You need to specify the namespace in your XSLT file:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xfdf="http://ns.adobe.com/xfdf/">