Using regex on spaCy PhraseMatcher [duplicate] - regex

Question

I am creating a spaCy regular expression matches for matching number and extracting it pandas data frame.
Question: Panda picks up from number but overwrites value instead of appending. How to solve it?
(original code credit: yarongon)
from __future__ import unicode_literals
import spacy
import re
import pandas as pd
from datetime import date
nlp = spacy.load('en_core_web_sm', disable=['parser', 'tagger', 'ner'])
doc = nlp("This is a sample number: 11. This is second sample number: 1145.")
NUM_PATTERN = re.compile(r"\d+")
for match in re.finditer(NUM_PATTERN, doc.text):
start, end = match.span()
Number = doc.char_span(start, end)
print Number
pandas_attributes = [Number,]
df = pd.DataFrame(pandas_attributes,
columns=['Number'])
print df
Output:
11
1145
Number
0 1145
Expected output:
Number
o 11
1 1145
Edit 1:
I am trying multiple pattern match on single text.
from __future__ import unicode_literals
import spacy
import re
import pandas as pd
from datetime import date
nlp = spacy.load('en_core_web_sm', disable=['parser', 'tagger', 'ner'])
doc = nlp("This is a sample-number: 11. This is second sample number: 1145.")
NUM_PATTERN = re.compile(r"\d+")
HYPH_PATTERN = re.compile('\w+(?:-)\w+')
for match in re.finditer(NUM_PATTERN, doc.text):
start, end = match.span()
Number = doc.char_span(start, end)
print Number
for match in re.finditer(HYPH_PATTERN, doc.text):
start, end = match.span()
Hyph_word = doc.char_span(start, end)
print Hyph_word
pandas_attributes = [Number,Hyph_word]
df = pd.DataFrame(pandas_attributes,
columns=['Number','Hyphenword'])
print df
Current output.
Output:
11
1145
sample-number
AssertionError: 2 columns passed, passed data had 3 columns
Expected output:
Number Hyphen_word
11 sample-number
1145
edit 2: output
Number Hyphenword
0 (11) (1145)
1 (sample, -, number) Non
Expected output:
Number Hyphenword
0 11 sample-word
1 1145 Non

Answer 1

You need append values to list in loop:
L = []
for match in re.finditer(NUM_PATTERN, doc.text):
start, end = match.span()
L.append(doc.char_span(start, end))
and then use DataFrame constructor:
df = pd.DataFrame(L,columns=['Number'])
You can also append tuples with multiple values:
Sample:
L = []
for x in range(3):
Number = x + 1
Val = x + 4
L.append((Number, Val))
print (L)
[(1, 4), (2, 5), (3, 6)]
df = pd.DataFrame(L,columns=['Number', 'Val'])
print (df)
Number Val
0 1 4
1 2 5
2 3 6
I believe you can use double append:
PATTERNS = [NUM_PATTERN, HYPH_PATTERN]
pandas_attributes = []
for pat in PATTERNS:
L = []
for match in re.finditer(pat, doc.text):
start, end = match.span()
L.append(doc.char_span(start, end))
pandas_attributes.append(L)
df = pd.DataFrame(pandas_attributes,
index=['Number','Hyphenword']).T