So in my PostgreSQL 10 I have a column of type integer. This column represents a code of products and it should be searched against another code or part of the code. The values of the column are made of three parts, a five-digit part and two two-digit parts. Users can search for only the first part, the first-second or first-second-third.
So, in my column I have , say 123451233 the user searches for 12345 (the first part). I want to be able to return the 123451233. Same goes if the users also searches for 1234512 or 123451233.
Unfortunately I cannot change the type of column or break the one column into three (one for every part). How can I do this? I cannot use LIKE. Maybe something like a regex for integers?
Thanks
Consider to use simple arithmetic.
log(value)::int + 1 returns the number of digits in integer part of the value and using this:
value/(10^(log(value)::int-log(search_input)::int))::int
returns value truncated to the same digits number as search_input so, finally
search_input = value/(10^(log(value)::int-log(search_input)::int))::int
will make the trick.
It is more complex literally but also could be more efficient then strings manipulations.
PS: But having index like create index idx on your_table(cast(your_column as text)); search like
select * from your_table
where cast(your_column as text) like search_input || '%';
is the best case IMO.
You do not need regex functions. Cast the integer to text and use the function left(), example:
create table my_table(code int); -- or bigint
insert into my_table values (123451233);
with input_data(input_code) as (
values('1234512')
)
select t.*
from my_table t
cross join input_data
where left(code::text, length(input_code)) = input_code;
code
-----------
123451233
(1 row)
Related
I have a table with a column po_number of type varchar in Postgres 8.4. It stores alphanumeric values with some special characters. I want to ignore the characters [/alpha/?/$/encoding/.] and check if the column contains a number or not. If its a number then it needs to typecast as number or else pass null, as my output field po_number_new is a number field.
Below is the example:
SQL Fiddle.
I tired this statement:
select
(case when regexp_replace(po_number,'[^\w],.-+\?/','') then po_number::numeric
else null
end) as po_number_new from test
But I got an error for explicit cast:
Simply:
SELECT NULLIF(regexp_replace(po_number, '\D','','g'), '')::numeric AS result
FROM tbl;
\D being the class shorthand for "not a digit".
And you need the 4th parameter 'g' (for "globally") to replace all occurrences.
Details in the manual.
For a known, limited set of characters to replace, plain string manipulation functions like replace() or translate() are substantially cheaper. Regular expressions are just more versatile, and we want to eliminate everything but digits in this case. Related:
Regex remove all occurrences of multiple characters in a string
PostgreSQL SELECT only alpha characters on a row
Is there a regexp_replace equivalent for postgresql 7.4?
But why Postgres 8.4? Consider upgrading to a modern version.
Consider pitfalls for outdated versions:
Order varchar string as numeric
WARNING: nonstandard use of escape in a string literal
I think you want something like this:
select (case when regexp_replace(po_number, '[^\w],.-+\?/', '') ~ '^[0-9]+$'
then regexp_replace(po_number, '[^\w],.-+\?/', '')::numeric
end) as po_number_new
from test;
That is, you need to do the conversion on the string after replacement.
Note: This assumes that the "number" is just a string of digits.
The logic I would use to determine if the po_number field contains numeric digits is that its length should decrease when attempting to remove numeric digits.
If so, then all non numeric digits ([^\d]) should be removed from the po_number column. Otherwise, NULL should be returned.
select case when char_length(regexp_replace(po_number, '\d', '', 'g')) < char_length(po_number)
then regexp_replace(po_number, '[^0-9]', '', 'g')
else null
end as po_number_new
from test
If you want to extract floating numbers try to use this:
SELECT NULLIF(regexp_replace(po_number, '[^\.\d]','','g'), '')::numeric AS result FROM tbl;
It's the same as Erwin Brandstetter answer but with different expression:
[^...] - match any character except a list of excluded characters, put the excluded charaters instead of ...
\. - point character (also you can change it to , char)
\d - digit character
Since version 12 - that's 2 years + 4 months ago at the time of writing (but after the last edit that I can see on the accepted answer), you could use a GENERATED FIELD to do this quite easily on a one-time basis rather than having to calculate it each time you wish to SELECT a new po_number.
Furthermore, you can use the TRANSLATE function to extract your digits which is less expensive than the REGEXP_REPLACE solution proposed by #ErwinBrandstetter!
I would do this as follows (all of the code below is available on the fiddle here):
CREATE TABLE s
(
num TEXT,
new_num INTEGER GENERATED ALWAYS AS
(NULLIF(TRANSLATE(num, 'ABCDEFGHIJKLMNOPQRSTUVWXYZ. ', ''), '')::INTEGER) STORED
);
You can add to the 'ABCDEFG... string in the TRANSLATE function as appropriate - I have decimal point (.) and a space ( ) at the end - you may wish to have more characters there depending on your input!
And checking:
INSERT INTO s VALUES ('2'), (''), (NULL), (' ');
INSERT INTO t VALUES ('2'), (''), (NULL), (' ');
SELECT * FROM s;
SELECT * FROM t;
Result (same for both):
num new_num
2 2
NULL
NULL
NULL
So, I wanted to check how efficient my solution was, so I ran the following test inserting 10,000 records into both tables s and t as follows (from here):
EXPLAIN (ANALYZE, BUFFERS, VERBOSE)
INSERT INTO t
with symbols(characters) as
(
VALUES ('ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789')
)
select string_agg(substr(characters, (random() * length(characters) + 1) :: INTEGER, 1), '')
from symbols
join generate_series(1,10) as word(chr_idx) on 1 = 1 -- word length
join generate_series(1,10000) as words(idx) on 1 = 1 -- # of words
group by idx;
The differences weren't that huge but the regex solution was consistently slower by about 25% - even changing the order of the tables undergoing the INSERTs.
However, where the TRANSLATE solution really shines is when doing a "raw" SELECT as follows:
EXPLAIN (ANALYZE, BUFFERS, VERBOSE)
SELECT
NULLIF(TRANSLATE(num, 'ABCDEFGHIJKLMNOPQRSTUVWXYZ. ', ''), '')::INTEGER
FROM s;
and the same for the REGEXP_REPLACE solution.
The differences were very marked, the TRANSLATE taking approx. 25% of the time of the other function. Finally, in the interests of fairness, I also did this for both tables:
EXPLAIN (ANALYZE, BUFFERS, VERBOSE)
SELECT
num, new_num
FROM t;
Both extremely quick and identical!
Morning everybody ,, this is my first time to use solr after reading some document about q , and fq i want to make query that return all rows that have last digit equal 3 for example .
I tried to use regex like condition id:/.*3/ , but this return no data .
Now i want to do this using mod function , Please explain your solution .
Thanks for help.
You don't need a regular expression to do that, q=id:*3 works right out of the box.
You can apply a function query to your field using the {!frange} parser, which will return any document where the result of the function behind it returns a value within the range defined.
q={!frange l=0 u=0}mod(id, 3)
.. assuming that id is an integer. This will only give you values where the function evaluates as 0, as both the upper and lower bounds are 0 (and by default, the lower/upper is included in the range).
I have a column in Oracle which can contain up to 5 separate values, each separated by a '|'. Any of the values can be present or missing. Here are come examples of how the data might look:
100-1
10-3|25-1|120/240
15-1|15-3|15-2|120/208
15-1|15-3|15-2|120/208|STA-2
112-123|120/208|STA-3
The values are arbitrary except for the order. The numerical values separated by dashes always come first. There can be 1 to 3 of these values present. The numerical values separated by a slash (if it is present) is next. The string, 'STA', and a numerical value separated by a dash is always last, if it is present.
What I would like to do is reformat this column to only ever include the first three possible values, those being the three numerical values separated by dashes. Afterwards, I want to replace 2nd numeric in each value (the numeric after the dash) using the following pattern:
1 = A
2 = B
3 = C
I would also like to remove the dash afterwards, but not the '|' that separates the values unless there is a trailing '|'.
To give you an idea, here's how the values at the beginning of the post would look after the reformatting:
100A
10C|25A
15A|15C|15B
15A|15C|15B
112ABC
I'm thinking this can be done with regex expressions but it's got me a little confused. Does anyone have a solution?
If I have to solve this problem I will solve it in following ways.
SELECT
REGEXP_REPLACE(column,'\|\d+\/\d+(\|STA-\d+)?',''),
REGEXP_REPLACE(column,'(\d+)-(1)([^\d])','\1A\3'),
REGEXP_REPLACE(column,'(\d+)-(2)([^\d])','\1B\3'),
REGEXP_REPLACE(column,'(\d+)-(3)([^\d])','\1C\3'),
REGEXP_REPLACE(column,'(\d+)-(123)([^\d])','\1ABC')
FROM table;
Explanation: Let us break down each REGEXP_REPLACE statement one by one.
REGEXP_REPLACE(column,'\|\d+\/\d+(\|STA-\d+)?','')
This will replace the end part like 120/208|STA-2 with empty string so that further processing is easy.
Finding match was easy but replacing A for 1, B for 2 and C for 3 was not possible ( as per my knowledge ) So I did those matching and replacements separately.
In each regex from second statement (\d+)-(yourNumber)([^\d]) first group is number before - then yourNumber is either 1,2,3 or 123 followed by |.
So the replacement will be according to yourNumber.
All demos here from version 1 to 5.
Note:- I have just done replacement for combination of yourNUmber for those present in question. You can do likewise for other combinations too.
you can do this in one line, but you can write simple function to do that
SELECT str, REGEXP_REPLACE(str,'(\|\d+\/\d+)?(\|STA-\d+)?','') cut
, REGEXP_REPLACE(REGEXP_REPLACE(str,'(\|\d+\/\d+)?(\|STA-\d+)?',''), '(\-)([1,2]*)(3)([1,2]*)', '\1\2C\4') rep3toC
, REGEXP_REPLACE(REGEXP_REPLACE(REGEXP_REPLACE(str,'(\|\d+\/\d+)?(\|STA-\d+)?',''), '(\-)([1,2]*)(3)([1,2]*)', '\1\2C\4'), '(\-)([1,C]*)(2)([1,C]*)', '\1\2B\4') rep2toB
, REGEXP_REPLACE(REGEXP_REPLACE(REGEXP_REPLACE(REGEXP_REPLACE(str,'(\|\d+\/\d+)?(\|STA-\d+)?',''), '(\-)([1,2]*)(3)([1,2]*)', '\1\2C\4'), '(\-)([1,C]*)(2)([1,C]*)', '\1\2B\4'), '(\-)([B,C]*)(1)([B,C]*)', '\1\2A\4') rep1toA
, REGEXP_REPLACE(REGEXP_REPLACE(REGEXP_REPLACE(REGEXP_REPLACE(REGEXP_REPLACE(str,'(\|\d+\/\d+)?(\|STA-\d+)?',''), '(\-)([1,2]*)(3)([1,2]*)', '\1\2C\4'), '(\-)([1,C]*)(2)([1,C]*)', '\1\2B\4'), '(\-)([B,C]*)(1)([B,C]*)', '\1\2A\4'), '-', '') "rep-"
FROM (
SELECT '100-1' str FROM dual UNION
SELECT '10-3|25-1|120/240' str FROM dual UNION
SELECT '15-1|15-3|15-2|120/208' str FROM dual UNION
SELECT '15-1|15-3|15-2|120/208|STA-2' str FROM dual UNION
SELECT '112-123|120/208|STA-3' FROM dual
) tab
I have a table in Oracle with a VARCHAR column called DESCRIPTION. Some of the rows contain non-printable characters such as the character with numeric value 150 (which is not in Latin-1 and is "Start of Protected Area" in Unicode).
I want to select all the rows whose DESCRIPTION columns contain a character whose numeric value is between 128 and 160. Is there a way to do this without a long list of LIKE clauses OR'ed together? I suppose it can be done with regular expressions, but I haven't found a way to do it.
I had to do something very like this recently and used some SQL like this:
with codes as (select rownum code from dual connect by level <= 160)
select distinct t.id, t.description
from mytable t, codes c
where t.description like '%' || chr(c.code) || '%'
and c.code >= 128;
Vincent's post helped me a lot with this problem! I wanted to find all rows that had any extended ASCII: 128-255, so I shortened the statement to this:
SELECT description
FROM your_table
WHERE regexp_like (description, '['||chr(128)||'-'||chr(255)||']');
Short way to grab a range.
You could use a regular expression, it may perform better than 30+ single WHERE clause but it won't be much prettier:
SELECT *
FROM your_table
WHERE regexp_like(description, '['||chr(128)||chr(129)||...||chr(160)||']')
I have a table with the following values:
ID NAME ADDRESS
1 Bob Super stree1 here goes
2 Alice stree100 here goes
3 Clark Fast left stree1005
4 Magie Right stree1580 here goes
I need to make a query using LIKE and get only the row having stree1 (in this case only get the one with ID=1) and I use the following query:
select * from table t1 WHERE t1.ADDRESS LIKE '%stree1%';
But the problem is that I get all rows as each of them contains stree1 plus some char/number after.
I have found out that I can use REGEXP_LIKE as I am using oracle, what would be the proper regex to use in:
select * from table t1 WHERE regexp_like(t1.ADDRESS ,'stree1');
I would think that this would be the reg-ex you are seeking:
select * from table t1 WHERE regexp_like(t1.ADDRESS ,'stree1(?:[^[:word:]]|$)');
If you want to, you can further simplify this to:
select * from table t1 WHERE regexp_like(t1.ADDRESS ,'stree1(?:\W|$)');
That is, 'stree1' is not followed by a word character (i.e., is followed by space/punctuation/etc...) or 'stree1' appears at the end of the string. Of course there are many other ways to do the same thing, including word boundaries 'stree1\b', expecting particular characters after the 1 in stree1 (e.g., a white-space with 'stree1\s'), etc...
This may help:
stree1\b
The first '\W' is tells it it a non-word character since you need noting after 'stree1' but space
and '$' tells take it as a valid string if it ends with stree1
select *
from table1
where regexp_like(address,'stree1(\W|$)')