REGEX Capturing differing sets of repeating groups - regex

Question

this is a two-part question, but I feel the answers will be related.
I have this regex pattern:
(\d+)(aa|bb) which I use to capture this string: 1bb2aa3aa4bb5bb6aa7bb8cc9cc
See demo: example 1
The way it captures the random series of aa and bb (both preceded by a digit) is exactly what I want, and is good as far as it goes.
So we get this match on regex101:
Match 1
Full match 0-3 `1bb`
Group 1. 0-1 `1`
Group 2. 1-3 `bb`
Match 2
Full match 3-6 `2aa`
Group 1. 3-4 `2`
Group 2. 4-6 `aa`
Match 3
Full match 6-9 `3aa`
Group 1. 6-7 `3`
Group 2. 7-9 `aa`
Match 4
Full match 9-12 `4bb`
Group 1. 9-10 `4`
Group 2. 10-12 `bb`
Match 5
Full match 12-15 `5bb`
Group 1. 12-13 `5`
Group 2. 13-15 `bb`
Match 6
Full match 15-18 `6aa`
Group 1. 15-16 `6`
Group 2. 16-18 `aa`
Match 7
Full match 18-21 `7bb`
Group 1. 18-19 `7`
Group 2. 19-21 `bb`
As expected, the 8cc9ccbit at the end is ignored. I would like capture this as well, in the same way I have captured the first repeating groups, in the same expression. So in the final output, I'd get something like this added to the end of the output. This should work for any amounts of matches on either side. This text is just one example.
Full match 21-24 `8cc`
Group 1. 21-22 `8`
Group 2. 22-24 `cc`
Match 7
Full match 24-27 `9cc`
Group 1. 24-25 `9`
Group 2. 25-27 `cc`
Also, I'd like to do similar but flipping the 'or' group to the end i.e. this:
1cc2cc3cc4cc5cc6cc7ccb8aa9bb
My current regex pattern (\\d+)(cc) only matches the repeating 'cc' groups.
See demo: example 2
I would like a similar full capture, with any amount of permissible entries of each group.
Any thoughts?

Answer 1

You may use
(?:\G(?!^)(?(?=\d+(?:aa|bb))(?<!\dcc))|(?=(?:\d+(?:aa|bb))+(?:\d+cc)+))(\d+)(aa|bb|cc)
See the regex demo
The regex will only match the string that meets the pattern in the (?=(?:\d+(?:aa|bb))+(?:\d+cc)+) lookahead, and then will consecutively match and capture digits and aa, bb or cc, but digits + aa or bb will be matched unless digits + cc is not in front.
Details
(?:\G(?!^)(?(?=\d+(?:aa|bb))(?<!\dcc))|(?=(?:\d+(?:aa|bb))+(?:\d+cc)+)) - either of the two alternatives:
\G(?!^) - end of the previous successful match
(?(?=\d+(?:aa|bb))(?<!\dcc)) - if-then-else construct: if there is 1+ digits and aa or bb immediately to the right of the current location ((?=\d+(?:aa|bb)), then only continue matching if there is no digit followed with cc immediately to the left of the current location ((?<!\dcc))
| - or
^ - start of string
(?=(?:\d+(?:aa|bb))+(?:\d+cc)+) - a positive lookahead that, immediately to the right of the current location, searches for the following (and returns true if it finds the patterns, or false if it does not):
(?:\d+(?:aa|bb))+ - one or more occurrences of 1+ digits followed with aa or bb
(?:\d+cc)+ - one or more occurrences of 1+ digits followed with cc
(\d+) - Group 1: one or more digits
(aa|bb|cc) - aa, bb or cc.
For the second pattern, replace cc with (?:aa|bb):
(?:\G(?!^)(?(?=\d+cc)(?<!\d(?:aa|bb)))|(?=(?:\d+cc)+(?:\d+(?:aa|bb))+))(\d+)(aa|bb|cc)

Answer 2

I'm no expert with perl, so I'll give a bit of pseudo code here. Feel free to suggest an edit.
You can start by matching any number of xaa or xbb combos, followed by one or more xcc combos using this pattern: ^(?:\d+(?:aa|bb))+(?:\dcc)+$
Once you have that you can use this pattern to capture the appropriate groups: (\d+)(aa|bb|cc)
Demo 1
Demo 2
Something like:
if(ismatch("^(?:\d+(?:aa|bb))+(?:\dcc)+$", inputString))
{
match = match("(\d+)(aa|bb|cc)", inputString);
}
from here you can extract the information using the groups.