Do not print if $previous_line matches $current_line.* [closed] - regex

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I would like to be able to use awk in place of a while loop to remove subdomains from an input string if it also contains the main domain.
Source file:
1234.f.dsfsd.test.com
abc.test.com
ad.sdk.kaffnet.com
amazon.co.uk
analytics.test.dailymail.co.uk
bbc.co.uk
bbc.test.com
dailymail.co.uk
kaffnet.com
sdk.kaffnet.com
sub.test.bbc.co.uk
t.dailymail.co.uk
test.amazon.co.uk
test.bbc.co.uk
test.com
test.dailymail.co.uk
Desired Output:
amazon.co.uk
bbc.co.uk
dailymail.co.uk
kaffnet.com
test.com
Solution: #EdMorton

Check the last part of a domain and see which string is the shortest one among them:
BEGIN{FS="."}
{
ind=$(NF-1) FS $NF;
if (!(ind in size) || (size[ind] > length)) {
size[ind]=length # check the minimum size for this domain
domain[ind]=$0 # store the string with the minimum size on this domain
}
}
END {for (ind in domain) print domain[ind]}
As a one-liner:
$ awk 'BEGIN{FS="."} {ind=$(NF-1) FS $NF; if (!(ind in size) || (size[ind] > length)) { size[ind]=length; domain[ind]=$0}} END {for (ind in domain) print domain[ind]}' file
test.com
bbc.co.uk
Previous approach, that works for top level domains:
Just make use of the field separator and set it to the dot. This way, it is just a matter of storing the penultimate and last one as a string and check how many different ones you find:
$ awk -F. '{a[$(NF-1) FS $NF]} END{for (i in a) print i}' file
test.com
How does this work? a[] is an array to which we keep adding indeces. The index is defined with the penultimate field followed by a dot and the last field. This way, any new bla.test.com will still have the same index and do not add extra info into the array.
With other inputs:
$ cat file
1234.f.dsfsd.test.com
abc.test.com
bbc.test.com
test.com
bla.com
another.bla.com
$ awk -F. '{a[$(NF-1) FS $NF]} END{for (i in a) print i}' file
test.com
bla.com

New answer based on new requirements and new sample input file:
$ cat tst.awk
{ doms[$0] }
END {
for (domA in doms) {
hasSubDom = 0
for (domB in doms) {
if ( index(domA,domB ".") == 1 ) {
hasSubDom = 1
}
}
if ( !hasSubDom ) {
print domA
}
}
}
$ rev file | awk -f tst.awk | rev
bbc.co.uk
dailymail.co.uk
amazon.co.uk
kaffnet.com
test.com
$ rev file | sort |
awk -F'.' 'index($0,prev FS)!=1{ print; prev=$1 FS $2 }' |
rev
bbc.co.uk
test.com
The above just implements the algorithm you described in your question. It reverses the chars on each line and then sorts the result just like you were already doing, then if the previous line was foo.bar.stuff then prev is foo.bar and so if the current line is foo.bar.otherstuff then the call to index WILL find that foo.bar. (note the . at the end - adding that last . to the comparison is important so that foo.bar doesn't falsely match foo.barristers.wig) DOES occur at the start (index position 1) of the current line and so we will NOT print that line and prev will remain as is. If, on the other hand the current line is my.sharona.song then prev (foo.bar) DOES NOT occur at the start of that line and so that line IS printed and prev gets set to my.sharona. Finally it just reverses the chars on each output line back to their original order.

You can test a dynamic regex inside awk if you build a variable with the ~ operator
awk 'NR==1{a=$0} NR>1{if(length(a)>0){regex="^"a;if($0~regex){print a}}a=$0}'
Example (using tac and rev to facilitate the reversion)
The problem with your method is that you need at least 2 lines for the domain because you only display the previous line, but what if you did not have a previous line? Maybe that is not an issue for you if your domains always come with at least 2 lines.

For what it's worth, here is a version that works without requiring reversing and sorting the input.
awk -F. 'BEGIN {
SLDs = "co.uk,gov.uk,add.others" # general-use second-level domains we recognize
split(SLDs, slds, /,/);
for (i in slds) slds[slds[i]] = 1
}
/./ {
tld = $(NF-1) "." $(NF)
if (NF > 2 && tld in slds) tld = $(NF-2) "." tld
lines[NR] = $0
tlds[NR] = tld
if (tld == $0) existing_tlds[tld] = 1
}
END {
for (i = 1; i <= length(lines); i++) {
line = lines[i]; tld = tlds[i]
if (!(tld in existing_tlds) || tld == line) print(line)
}
}' input_file
This goes through the file and builds an array of existing TLDs. In the END block it prints a line only when it is a TLD itself or its TLD does not exist in said array.
When input_file is
1234.f.dsfsd.test.com
abc.test.com
amazon.co.uk
bbc.co.uk
bbc.test.com
sub.test.bbc.co.uk
test.amazon.co.uk
test.bbc.co.uk
test.com
it prints
amazon.co.uk
bbc.co.uk
test.com

Related

Bash - Extract a column from a tsv file whose header matches a given pattern

I've got a tab-delimited file called dataTypeA.txt. It looks something like this:
Probe_ID GSM24652 GSM24653 GSM24654 GSM24655 GSM24656 GSM24657
1007_s_at 1149.82818866431 1156.14191288693 743.515922643437 1219.55564561635 1291.68030259557 1110.83793199643
1053_at 253.507372571459 150.907554200493 181.107054946649 99.0610660103702 147.953428467212 178.841519788697
117_at 157.176825094869 147.807257232552 162.11169957066 248.732378039521 176.808414979907 112.885784025819
121_at 1629.87514240262 1458.34809770171 1397.36209234134 1601.83045996129 1777.53949459116 1256.89054921471
1255_g_at 91.9622298972477 29.644137111864 61.3949774595639 41.2554576367652 78.4403716513328 66.5624213750532
1294_at 313.633291641829 305.907304474766 218.567756319376 335.301256439494 337.349552407502 316.760658896597
1316_at 195.799277107983 163.176402437481 111.887056644528 194.008323756222 211.992656497053 135.013920706472
1320_at 34.5168433158599 19.7928225262233 21.7147425051394 25.3213322300348 22.4410631949167 29.6960283168278
1405_i_at 74.938724593443 24.1084307838881 24.8088845994911 113.28326338746 74.6406975005947 70.016519414531
1431_at 88.5010900723741 21.0652011409692 84.8954961447585 110.017339630928 84.1264201735067 49.8556999547353
1438_at 26.0276274326623 45.5977459152141 31.8633816890024 38.568939176828 43.7048363737468 28.5759163094148
1487_at 1936.80799770498 2049.19167519573 1902.85054762899 2079.84030768241 2088.91036902825 1879.84684705068
1494_f_at 358.11266607978 271.309665853292 340.738488775022 477.953251687206 388.441738062896 329.43505750512
1598_g_at 2908.90515715761 4319.04621682741 2405.62061966298 3450.85255814957 2573.97860992156 2791.38660060659
160020_at 416.089910909237 327.353902186303 385.030831004533 385.199279534446 256.512900212781 217.754025190117
1729_at 43.1079499314469 114.654670657195 133.191500889286 86.4106614983387 122.099426341898 218.536976034472
177_at 75.9653827137444 27.4348937420347 16.5837374743166 50.6758325717831 58.7568500760629 18.8061888366161
1773_at 31.1717741953018 158.225161489953 161.976679771553 139.173486349393 218.572194156366 103.916119454
179_at 1613.72113870554 1563.35465407698 1725.1817757679 1694.82209331327 1535.8108561345 1650.09670894426
Let's say I have a variable col="GSM24655". I want to extract the column from dataTypeA.txt that corresponds to this column name.
Additionally, I'd like to put this in a function, where I can just give it a file (i.e. dataTypeA.txt), and a column (i.e. GSM24655), and it'll return that column.
I'm not very proficient in Bash, so I've been having some trouble with this. I'd appreciate the help.
Below script using awk can be used to achieve the objective.
col="GSM24655";
awk -v column_val="$col" '{ if (NR==1) {val=-1; for(i=1;i<=NF;i++) { if ($i == column_val) {val=i;}}} if(val != -1) print $val} ' dataTypeA.txt
Working: Initially, value of col is passed to awk script using -v column_val="$col" . Then the column number is find out. (when NR==1, i.e the first row, it iterates through all the fields (for(i=1;i<=NF;i++), awk variable NF contains the number of columns) and then compare the value of column_val (if ($i == column_val)), when a match is found the corresponding column number is found and stored ( val=i )). After that, from next row onwards, the values in that column is printed (print $val).
If you copy the below code into a file called say find_column.sh, you can call sh find_column.sh GSM24655 dataTypeA.txt to display the column having value of first parameter (GSM24655) in the file named second parameter (dataTypeA.txt). $1 and $2 are positional parameters. The lines column=$1 and file=$2 will assign the input values to the variables.
column=$1;
file=$2;
awk -v column_val="$column" '{ if (NR==1) {val=-1; for(i=1;i<=NF;i++) { if ($i == column_val) {val=i;}}} if(val != -1) print $val} ' $file
I would use the following, it is quick and easy.
In your script, you get the name of the file, let's say $1, and word, $2.
Then, in my for each I am using the whole header, but you can just add a head -1 $1, and in the IF, the $2, this is going to output column name.
c=0;
for each in `echo "Probe_ID GSM24652 GSM24653 GSM24654 GSM24655 GSM24656 GSM24657"`;do if [[ $each == "Probe_ID" ]];then
echo $c;
col=$c;
else c=$(( c + 1 ));
fi;
done
Right after this, you just do a cat $1| cut -d$'\t' -f$col

Finding Lines between two characters and separate them in notepad ++

I have a huge text file in the following pattern
####
Some Question 1
answer 1
####
####
Some Question 2
answer 2
some answer 2
another answer 2
####
####
Some Question 3
answer 3
some answer 3
####
in my project I need to:
1. find lines between two characters and I already did it by (####)(.+?)(####)
2. put a question mark at the end of the first line after ####
3. put a slash before the second line and before third line
to have a result like this
Some Question 1 ? answer1
Some Question 2 ? answer 2 / some answer 2 / another answer 2
Some Question 3 ? answer 3 / some answer 3
as I mentioned I already marked the text and made 3 groups \1 & 3 #### \2 the in-between lines, how can I separate those lines and make the desired changes ?
I recommend you to do this job outside of notepad, using a script launched from the command line interface.
If you have awk installed on your system, write the following script, say script.awk:
#!/usr/bin/awk -f
/^####$/ { if (q != "") {
print q a
}
q = "";
a = "";
next
}
# other lines
{ if (q == "") {
q = $0 " ? "
} else {
if (a == "") {
a = $0;
next
} else {
a = a " / " $0 ;
next
}
}
}
Assuming your input is in file input.txt, you can run this script from the command line issuing:
./script.awk input.txt
or:
awk -f script.awk input.txt
I assume you can work in a Unix-like environment.

Finding columns with only white space in a text file and replace them with a unique separator

I have a file like this:
aaa b b ccc 345
ddd fgt f u 3456
e r der der 5 674
As you can see the only way that we can separate the columns is by finding columns that have only one or more spaces. How can we identify these columns and replace them with a unique separator like ,.
aaa,b b,ccc,345
ddd,fgt,f u,3456
e r,der,der,5 674
Note:
If we find all continuous columns with one or more white spaces (nothing else) and replace them with , (all the column) the problem will be solved.
Better explanation of the question by josifoski :
Per block of matrix characters, if all are 'space' then all block should be replaced vertically with one , on every line.
$ cat tst.awk
BEGIN{ FS=OFS=""; ARGV[ARGC]=ARGV[ARGC-1]; ARGC++ }
NR==FNR {
for (i=1;i<=NF;i++) {
if ($i == " ") {
space[i]
}
else {
nonSpace[i]
}
}
next
}
FNR==1 {
for (i in nonSpace) {
delete space[i]
}
}
{
for (i in space) {
$i = ","
}
gsub(/,+/,",")
print
}
$ awk -f tst.awk file
aaa,b b,ccc,345
ddd,fgt,f u,3456
e r,der,der,5 674
Another in awk
awk 'BEGIN{OFS=FS=""} # Sets field separator to nothing so each character is a field
FNR==NR{for(i=1;i<=NF;i++)a[i]+=$i!=" ";next} #Increments array with key as character
#position based on whether a space is in that position.
#Skips all further commands for first file.
{ # In second file(same file but second time)
for(i=1;i<=NF;i++) #Loops through fields
if(!a[i]){ #If field is set
$i="," #Change field to ","
x=i #Set x to field number
while(!a[++x]){ # Whilst incrementing x and it is not set
$x="" # Change field to nothing
i=x # Set i to x so it doesnt do those fields again
}
}
}1' test{,} #PRint and use the same file twice
Since you have also tagged this r, here is a possible solution using the R package readr. It looks like you want to read a fix width file and convert it to a comma-seperated file. You can use read_fwf to read the fix width file and write_csv to write the comma-seperated file.
# required package
require(readr)
# read data
df <- read_fwf(path_to_input, fwf_empty(path_to_input))
# write data
write_csv(df, path = path_to_output, col_names = FALSE)

AWK - Search for a pattern-add it as a variable-search for next line that isn't a variable & print it + variable

I have a given file:
application_1.pp
application_2.pp
#application_2_version => '1.0.0.1-r1',
application_2_version => '1.0.0.2-r3',
application_3.pp
#application_3_version => '2.0.0.1-r4',
application_3_version => '2.0.0.2-r7',
application_4.pp
application_5.pp
#application_5_version => '3.0.0.1-r8',
application_5_version => '3.0.0.2-r9',
I would like to be able to read this file and search for the string
".pp"
When that string is found, it adds that line into a variable and stores it.
It then reads the next line of the file. If it encounters a line preceded by a # it ignores it and moves onto the next line.
If it comes across a line that does not contain ".pp" and doesn't start with # it should print out that line next to a the last stored variable in a new file.
The output would look like this:
application_1.pp
application_2.pp application_2_version => '1.0.0.2-r3',
application_3.pp application_3_version => '2.0.0.2-r7',
application_4.pp
application_5.pp application_5_version => '3.0.0.2-r9',
I would like to achieve this with awk. If somebody knows how to do this and it is a simple solution i would be happy if they could share it with me. If it is more complex, it would be helpful to know what in awk I need to understand in order to know how to do this (arrays, variables, etc). Can it even be achieved with awk or is another tool necessary?
Thanks,
I'd say
awk '/\.pp/ { if(NR != 1) print line; line = $0; next } NF != 0 && substr($1, 1, 1) != "#" { line = line $0 } END { print line }' filename
This works as follows:
/\.pp/ { # if a line contains ".pp"
if(NR != 1) { # unless we just started
print line # print the last assembled line
}
line = $0 # and remember this new one
next # and we're done here.
}
NF != 0 && substr($1, 1, 1) != "#" { # otherwise, unless the line is empty
# or a comment
line = line $0 # append it to the line we're building
}
END { # in the end,
print line # print the last line.
}
You can use sed:
#n
/\.pp/{
h
:loop
n
/[^#]application.*version/{
H
g
s/\n[[:space:]]*/\t/
p
b
}
/\.pp/{
x
p
}
b loop
}
If you save this as s.sed and run
sed -f s.sed file
You will get this output
application_1.pp
application_2.pp application_2_version => '1.0.0.2-r3',
application_3.pp application_3_version => '2.0.0.2-r7',
application_4.pp
application_5.pp application_5_version => '3.0.0.2-r9',
Explanation
The #n supresses normal output.
Once we match the /\.pp/, we store that line into the hold space with h, and start the loop.
We go to the next line with n
If it matches /[^#]application.*version/, meaning it doesn't start with a #, then we append the line to the hold space with H, then copy the hold space to the pattern space with g, and substitute the newline and any subsequent whitespace for a tab. Finally we print with p, and skip to the end of the script with b
If it matches /\.pp/, then we swap the pattern and hold spaces with x, and print with p.

Replace several occurences of the same character in a different way in AWK

I want to replace several characters in a csv file depending on the characters around them using AWK.
For example in this line:
"Example One; example one; EXAMPLE ONE; E. EXAMPLE One"
I would like to replace all capital "E"'s with "EE" if they are within a word that uses only capitals and with "Ee" if they are in a word with upper and lower case letters or in an abbreviation (like the E., it's an adress file so there are no cases where this could also be the end of a sentence) so it should look like this:
"Eexample One; example one; EEXAMPLEE ONEE; Ee. EEXAMPLEE One"
Now what I have tried is this:
{if ($0 ~/E[A-Z]+/)
$0 = gensub(/E/,"EE","g",$0)
else if ($0 ~/[A-Z]E/)
$0 = gensub(/E/,"EE","g",$0)
else
$0 = gensub(/E/,"Ee","g",$0)
}
This works fine in most cases, but for lines (or fieds for that matter) that contain several "E"'s where I'd want one to be replaced as a "Ee" and one as a "EE" like in "E. EXAMPLE One", it matches the E in "EXAMPLE" and just replaces all "E"'s in that line with "EE".
Is there a better way to do this? Can I maybe somehow use if within gensub?
ps: Hope this makes sense, I just started learning the basics of programming!
$ cat tst.awk
{
head = ""
tail = $0
while ( match(tail,/[[:alpha:]]+\.?/) ) {
tgt = substr(tail,RSTART,RLENGTH)
add = (tgt ~ /^[[:upper:]]+$/ ? "E" : "e")
gsub(/E/,"&"add,tgt)
head = head substr(tail,1,RSTART-1) tgt
tail = substr(tail,RSTART+RLENGTH)
}
print head tail
}
$ awk -f tst.awk file
Eexample One; example one; EEXAMPLEE ONEE; Ee. EEXAMPLEE One
It's not clear though how you distinguish a string of letters followed by a period as an abbreviation or just the end of a sentence.