Transform XML - Form a proper record - xslt

Question

I am trying to create an XSLT to transform an XML document and having trouble with identifying the record boundaries. Below is my xml
<?xml version="1.0" encoding="UTF-8"?>
<catalog>
<mheader>
<mid>1</mid>
<mname>mn</mname>
</mheader>
<cheader>
<cid>1</cid>
<cname>cn</cname>
</cheader>
<lheader>
<lid>1</lid>
<lname>ln</lname>
</lheader>
<aheader>
<aid>1</aid>
<aname>an</aname>
</aheader>
<pos>
<pid>1</pid>
<pname>pay</pname>
</pos>
<pos>
<pid>2</pid>
<pname>pay1</pname>
</pos>
<mheader>
<mid>2</mid>
<mname>mh1</mname>
</mheader>
<cheader>
<cid>2</cid>
<cname>ch1</cname>
</cheader>
<lheader>
<lid>2</lid>
<lname>lh1</lname>
</lheader>
<aheader>
<aid>2</aid>
<aname>ah1</aname>
</aheader>
<pos>
<pid>1</pid>
<pname>pay</pname>
</pos>
<pos>
<pid>2</pid>
<pname>pay3</pname>
</pos>
<pos>
<pid>3</pid>
<pname>pay4</pname>
</pos>
</catalog>
I have to transform my xml like the one below
<?xml version="1.0" encoding="UTF-8"?>
<catalog>
<record>
<mheader>
<mid>1</mid>
<mname>mn</mname>
</mheader>
<cheader>
<cid>1</cid>
<cname>cn</cname>
</cheader>
<lheader>
<lid>1</lid>
<lname>ln</lname>
</lheader>
<aheader>
<aid>1</aid>
<aname>an</aname>
</aheader>
<pos>
<pid>1</pid>
<pname>pay</pname>
</pos>
<pos>
<pid>2</pid>
<pname>pay1</pname>
</pos>
</record>
<record>
<mheader>
<mid>2</mid>
<mname>mh1</mname>
</mheader>
<cheader>
<cid>2</cid>
<cname>ch1</cname>
</cheader>
<lheader>
<lid>2</lid>
<lname>lh1</lname>
</lheader>
<aheader>
<aid>2</aid>
<aname>ah1</aname>
</aheader>
<pos>
<pid>1</pid>
<pname>pay</pname>
</pos>
<pos>
<pid>2</pid>
<pname>pay3</pname>
</pos>
<pos>
<pid>3</pid>
<pname>pay4</pname>
</pos>
</record>
</catalog>
A record ideally should start from the tag mheader and ends at the last POS tag.
This is what i have tried till now
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<record>
<xsl:apply-templates select="catalog/mheader"/>
<xsl:apply-templates select="catalog/cheader"/>
<xsl:apply-templates select="catalog/lheader"/>
<xsl:apply-templates select="catalog/aheader"/>
<xsl:apply-templates select="catalog/pos"/>
</record>
</xsl:template>
</xsl:stylesheet>
Any ideas on how to form a proper record here in this case?

Answer 1

<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="catalog">
<xsl:copy>
<xsl:for-each-group select="*" group-starting-with="mheader">
<Record>
<xsl:copy-of select="current-group()"/>
</Record>
</xsl:for-each-group>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Check it.