How to align QTextEdit text - c++

How can I align this text? \t is not good.
What I see (image)
Expected result (image)

I had this problem once in the past. To solve the issue I used monospace font.
To get everything aligned (fixed font width) I used these lines:
// Use "monospaced" font:
// ->insure left column alignment, as for the terminal
//
QFont font("monospace");
font.setPointSize(10);
myQTextEdit->setCurrentFont(font);
from my parent widget containing a QTextEdit child widget.

this line:
QString str = QString("B%1").arg(_ui->lineEdit->text().toInt(), 3, 10, QChar('0'));
lineEdit->text() = 1 , str = B001
lineEdit->text() = 01 , str = B001
lineEdit->text() = 001 , str = B001
lineEdit->text() = 0001 , str = B001
lineEdit->text() = 12 , str = B012
lineEdit->text() = 123 , str = B123
you can adapt it for your use.
Edit based on Hyde Comment
int main(int argc, char **argv)
{
qint32 a,b,c,d,e;
a = -1;b = 1;c = -1;d = 3;
e = (a*b) + (c*d);
QString str = QString("(%1*%2) + (%3*%4) = %5").arg(a, 2, 10, QChar(' '))
.arg(b, 2, 10, QChar(' '))
.arg(c, 2, 10, QChar(' '))
.arg(d, 2, 10, QChar(' '))
.arg(e);
QTextStream(stdout) << str << endl;
a = -1;b = 2;c = -1;d = 4;
e = (a*b) + (c*d);
str = QString("(%1*%2) + (%3*%4) = %5").arg(a, 2, 10, QChar(' '))
.arg(b, 2, 10, QChar(' '))
.arg(c, 2, 10, QChar(' '))
.arg(d, 2, 10, QChar(' '))
.arg(e);
QTextStream(stdout) << str << endl;
return 0;
}
the output is:
(-1 * 1) + (-1 * 3) = -4
(-1 * 2) + (-1 * 4) = -6

Related

How do I return a negative value based on a separate cell?

I have a button that submits information and that works. All the numbers will be positive when entered by clients. The question at hand is:
If A4 = "Sell", cells A16, A18, and A20, return those numbers as negative values instead of positive. If A4 = "Buy", then return as is (positive).
Here's what I currently have. I don't know where to input this IF statement, or even how.
function SubmitBuy() {
var ss = SpreadsheetApp.getActiveSpreadsheet();
var formS = ss.getSheetByName("Front Sheet"); //Data entry sheet
var dataS = ss.getSheetByName("Front Sheet"); //Data Sheet
var values = [[formS.getRange("A2").getValue(),
formS.getRange("A4").getValue(),
formS.getRange("A6").getValue(),
formS.getRange("A8").getValue(),
formS.getRange("A10").getValue(),
formS.getRange("A12").getValue(),
formS.getRange("A16").getValue(),
formS.getRange("A18").getValue(),
formS.getRange("A20").getValue(),
formS.getRange("A28").getValue(), ]];
dataS.getRange(dataS.getLastRow() +1, 3, 1, 10 ).setValues(values);
ClearCells();
}
Get all of Column A's values and manipulate them using Array.map and Set:
function SubmitBuy() {
const ss = SpreadsheetApp.getActiveSpreadsheet();
const frontSheet = ss.getSheetByName('Front Sheet'); //Data entry sheet
const valuesA1A28 = frontSheet.getRange('A1:A28').getValues();
const rowsNeeded = [2, 4, 5, 8, 10, 12, 16, 18, 20];
const criteriaRow = 4;
const rowsToModify = new Set([16, 18, 20]);
const valuesNeeded = [
rowsNeeded.map((thisRow) => {
const thisValue = valuesA1A28[thisRow - 1][0];
if (
rowsToModify.has(thisRow) &&
valuesA1A28[criteriaRow - 1][0] === 'Sell'
)
return -thisValue;
else return thisValue;
}),
];
frontSheet
.getRange(frontSheet.getLastRow() + 1, 3, 1, 10)
.setValues(valuesNeeded);
ClearCells();
}

python tkinter how to organize the rows and columns

Hi I'm trying to build a user interface and having problem with column and row positions. What I expect to see is some distance between buttons and entry widgets since I left two empty column between them. So why are they standing just next to the entry widgets and changing the distances between entry areas? Could anyone give me some help about this?
Here is the code...
from Tkinter import*
HMCC=Tk()
HMCC.title(" GUI v1.0 ")
HMCC.geometry("500x300")
entry_1 = Entry(HMCC)
entry_2 = Entry(HMCC)
entry_3 = Entry(HMCC)
entry_4 = Entry(HMCC)
entry_5 = Entry(HMCC)
entry_6 = Entry(HMCC)
entry_7 = Entry(HMCC)
entry_8 = Entry(HMCC)
entry_1.grid(row=2,column=1)
entry_2.grid(row=3,column=1)
entry_3.grid(row=4,column=1)
entry_4.grid(row=5,column=1)
entry_5.grid(row=6,column=1)
entry_6.grid(row=7,column=1)
entry_7.grid(row=8,column=1)
entry_8.grid(row=9,column=1)
Channel_1 = Label(HMCC, text = "Channel 1 : ")
Channel_2 = Label(HMCC, text = "Channel 2 : ")
Channel_3 = Label(HMCC, text = "Channel 3 : ")
Channel_4 = Label(HMCC, text = "Channel 4 : ")
Channel_5 = Label(HMCC, text = "Channel 5 : ")
Channel_6 = Label(HMCC, text = "Channel 6 : ")
Channel_7 = Label(HMCC, text = "Channel 7 : ")
Channel_8 = Label(HMCC, text = "Channel 8 : ")
Channel_1.grid( row = 2, column = 0, sticky = E)
Channel_2.grid( row = 3, column = 0, sticky = E)
Channel_3.grid( row = 4, column = 0, sticky = E)
Channel_4.grid( row = 5, column = 0, sticky = E)
Channel_5.grid( row = 6, column = 0, sticky = E)
Channel_6.grid( row = 7, column = 0, sticky = E)
Channel_7.grid( row = 8, column = 0, sticky = E)
Channel_8.grid( row = 9, column = 0, sticky = E)
#button1 = Button(text=" START " , fg="red" )
#button2 = Button(text=" PAUSE " , fg="blue" )
#button3 = Button(text=" STOP ", fg="green")
#button4 = Button(text="QUIT" , fg="black",command=HMCC.quit)
#button1.grid( row = 1, column = 3)
#button2.grid( row = 2, column = 3)
#button3.grid( row = 3, column = 3)
#button4.grid( row = 4, column = 3)
HMCC.mainloop()
Current view
Thanks in advance
If there is nothing in column 2, then tkinter will ignore it.
In addition to the comment posted above which contains the answer to your question, you can clean up your code significantly by just using a loop:
num_rows = 8
entries = [None]*num_rows
channels = [None]*num_rows
for i in range(num_rows):
channels[i] = Label(HMCC, text = "Channel {0} : ".format(i+1))
channels[i].grid(row=i+2,column=0,sticky=E)
entries[i] = Entry(HMCC)
entries[i].grid(row=i+2, column=1)
Better yet, use list comprehension:
num_rows = 8
entries = [Entry(HMCC).grid(row=i+2, column=1) for i in range(num_rows)]
channels = [Label(HMCC, text = "Channel {0} : ".format(i)).grid(row=i+2,column=0,sticky=E) for i in range(num_rows)]

change label values when an entry value is changed

My problem at the moment is I am trying to change a label(label 16) to the first value of entry_values[0] which isn't working I have tried passing it in as a variable and many other things, after about an hour of research I couldn't find a solution.I think the main problem is that it sets the label before the code with the entry is run so that it wont change. when I set it to a textvariable it produces an empty string (I think) but when I use just text it puts in a 0 where I expect my number.
def sub_menu(root):
global subpage
subpage = Frame(root)
button5 = Button(subpage, text="Save Generation Data",
command = lambda: save_entries())
button5.grid(row = 1, column = 6, sticky = E)
button6 = Button(subpage, text="Return To Main Page",
command = lambda: switch_page("main"))
button6.grid(row = 0, column = 6, sticky = W)
juveniles_label0 = Label(subpage,text="Juveniles")
adults_label1 = Label(subpage,text="Adults")
seniles_label2 = Label(subpage,text="Seniles")
population_label3 = Label(subpage,text="Population (Thousands)")
survival_rate_label4 = Label(subpage,text="Survival Rate (Between 0 and 1)")
birth_rate_label5 = Label(subpage,text="Birth Rate")
number_of_gens_label6 = Label(subpage,text="Number of Generations")
disease_trigger_label7 = Label(subpage,text="Disease Trigger Point")
global entry0
entry0 = Entry(subpage)
global entry1
entry1 = Entry(subpage)
global entry2
entry2 = Entry(subpage)
global entry3
entry3 = Entry(subpage)
global entry4
entry4 = Entry(subpage)
global entry5
entry5 = Entry(subpage)
global entry6
entry6 = Entry(subpage)
global entry7
entry7 = Entry(subpage)
global entry8
entry8 = Entry(subpage)
juveniles_label0.grid(row = 0, column = 1)
adults_label1.grid(row = 0, column = 2)
seniles_label2.grid(row = 0, column = 3)
population_label3.grid(row = 1, column = 0)
survival_rate_label4.grid(row = 2, column = 0)
birth_rate_label5.grid(row = 3, column = 0)
number_of_gens_label6.grid(row = 3, column = 2)
disease_trigger_label7.grid(row = 4, column = 0)
entry0.grid(row = 1, column = 1)
entry1.grid(row = 1, column = 2)
entry2.grid(row = 1, column = 3)
entry3.grid(row = 2, column = 1)
entry4.grid(row = 2, column = 2)
entry5.grid(row = 2, column = 3)
entry6.grid(row = 3, column = 1)
entry7.grid(row = 3, column = 3)
entry8.grid(row = 4, column = 1)
return subpage
def save_entries(): #entry recieve point
save_page = Frame(root)
""" if e0 < 0:
make a check to check if value is < 0 dont accept and if a value is inputed or not using if type(string_name) == str """
e0 = entry0.get()
if e0 >= 0:
entry_values[0] = (e0)
e1 = entry1.get()
if e0 >= 0:
entry_values[1] = (e1)
e2 = entry2.get()
if e0 >= 0:
entry_values[2] = (e2)
e3 = entry3.get()
if e0 >= 0:
entry_values[3] = (e3)
e4 = entry4.get()
if e0 >= 0:
entry_values[4] = (e4)
e5 = entry5.get()
if e0 >= 0:
entry_values[5] = (e5)
e6 = entry6.get()
if e0 >= 0:
entry_values[6] = (e6)
e7 = entry7.get()
if e0 >= 0:
entry_values[7] = (e7)
e8 = entry8.get()
if e0 >= 0:
entry_values[8] = (e8)
print entry_values
return save_page
def display_values(root):
sub2 = Frame(root)
global entry_values
label8 = Label(sub2, text = "Juveniles")
label9 = Label(sub2, text = "Adults")
label10 = Label(sub2, text = "Seniles")
label11 = Label(sub2, text = "Population(Thousands)")
label12 = Label(sub2, text = "Survival Rate(Between 1 and 0)")
label13 = Label(sub2, text = "Birth Rate")
label14 = Label(sub2, text = "Number of Generations")
label15 = Label(sub2, text = "Disase Trigger Point")
label16 = Label(sub2, text = entry_values[0])
label17 = Label(sub2, textvariable = entry_values[1])
label18 = Label(sub2, textvariable = "")
label19 = Label(sub2, textvariable = "")
label20 = Label(sub2, textvariable = "")
label21 = Label(sub2, textvariable = "")
label22 = Label(sub2, textvariable = "")
label23 = Label(sub2, textvariable = "")
label24 = Label(sub2, textvariable = "")
button7 = Button(sub2, text="Return To Main Page",
command = lambda: switch_page("main"))
label8.grid(row = 0, column = 1)
label9.grid(row = 0, column = 2)
label10.grid(row = 0, column = 3)
label11.grid(row = 1, column = 0)
label12.grid(row = 2, column = 0)
label13.grid(row = 3, column = 0)
label14.grid(row = 3, column = 3)
label15.grid(row = 4, column = 0)
label16.grid(row = 1, column = 1)
label17.grid(row = 1, column = 2)
label18.grid(row = 1, column = 3)
label19.grid(row = 2, column = 1)
label20.grid(row = 2, column = 2)
label21.grid(row = 2, column = 3)
label22.grid(row = 3, column = 1)
label23.grid(row = 3, column = 3)
label24.grid(row = 4, column = 1)
button7.grid(row = 0, column = 0)
return sub2
In order to change the text of a label you can do:
label["text"] = textVar
or
label.config(text=textVar)
So in your above code, when the entry changes, reconfigure the label using one of the above options.

Python 2.7; How to clear an entry in the GUI

I have an example code, here just for BMI index. I would like to clear the input and output fields in the GUI. It seems that i can clear the entries, but the BMI calculation is not being removed (row 79 does not seem to have an effect) (# self.text.delete(0, 'end'))
Thanks
Emin
import math
from Tkinter import *
class Application(Frame):
"""A GUI application with three buttons"""
def __init__(self, master):
"""Initialize the Frame"""
Frame.__init__(self,master)
self.grid()
self.create_widgets()
self.title = Label(self, text = "BMI index calculation")
self.title.grid(row = 0, column = 0, columnspan = 2 , sticky =W)
def create_widgets(self):
"""Create button, text and entry widgets"""
self.name = Label(self, text = "What is your name?")
self.name.grid(row = 1, column = 0, columnspan = 2 , sticky =W)
self.name_io = Entry(self)
self.name_io.grid(row = 1, column =2, sticky = W)
self.age = Label(self, text = "How old are you?")
self.age.grid(row = 2, column = 0, columnspan = 2 , sticky =W)
self.age_io = Entry(self)
self.age_io.grid(row = 2, column =2, sticky = W)
self.height = Label(self, text = "How tall are you?")
self.height.grid(row = 3, column = 0, columnspan = 2 , sticky =W)
self.height_io = Entry(self)
self.height_io.grid(row = 3, column =2, sticky = W)
self.weight = Label(self, text = "How much do you weigh in kg?")
self.weight.grid(row = 4, column = 0, columnspan = 2 , sticky =W)
self.weight_io = Entry(self)
self.weight_io.grid(row = 4, column =2, sticky = W)
self.submit_button = Button(self, text = "Calculate", command = self.reveal)
self.submit_button.grid(row = 5, column = 0, sticky = W)
self.text = Text(self, width = 40, height = 5, wrap = WORD)
self.text.grid(row = 6, column = 0, columnspan = 3, sticky = W)
self.clear_button = Button(self, text = "Clear", command = self.clear_text)
self.clear_button.grid(row = 7, column = 0, sticky = W)
def reveal(self):
"""Display message based on the password typed in"""
content_name = self.name_io.get()
content_age = float(self.age_io.get())
content_height = float(self.height_io.get())
content_weight = float(self.weight_io.get())
BMI = round((content_weight/(content_height/100)**2.),1)
underBMI = 18.5
NormalBMI = 24.9
OverweightBMI = 29.9
ObesityBMI = 30
if BMI <= underBMI:
message = content_name + ", " + "your BMI index is" + " " + str(BMI) + ", " + "you are underweight, so you need to eat!"
elif (BMI > underBMI) and (BMI <= NormalBMI):
message = content_name + ", " + "your BMI index is" + " " + str(BMI) + ", " + "your BMI is Normal"
elif (BMI > NormalBMI) and (BMI <= OverweightBMI):
message = content_name + ", " + "your BMI index is" + " " + str(BMI) + ", " + "you are Overweight - need to exercise!"
elif (BMI > OverweightBMI):
message = content_name + ", " + "your BMI index is" + " " + str(BMI) + ", " + "you are in Obesity"
self.text.insert(0.0, message)
def clear_text(self):
self.name_io.delete(0, 'end')
self.age_io.delete(0, 'end')
self.height_io.delete(0, 'end')
self.weight_io.delete(0, 'end')
# self.text.delete(0, 'end')
root = Tk()
root.title("BMI Index")
root.geometry("600x350")
app = Application(root)
root.mainloop ()
The problem is that you're giving an index that is 0.0. Text widget indexes are a string of the form line.column but you're giving it a floating point number.
The proper index for the first character is the string "1.0".
self.text.delete("1.0", 'end')
Simply
your_entry.delete(0,END)

How to return a list of a single tuple(words,value) from a list of tuples(word, values)?

I need help with a function that can return words that have 3 or more characters that are "evenly" spaced, that is the ord() value for consecutive letters left to right are even (same difference value). This is what I have so far... and the output is this:
test_list2 = ['i', 'made', 'an', 'ace', 'today', 'at', 'tennis...yeaah', 'booi', ':d']
for word in test_list2:
if len(word) >=3:
temp_list = []
for chr1 in word:
if word.index(chr1) != (len(word)-1):
chr2 = word.index(chr1)+1
num = ord(word[chr2]) - ord(chr1)
temp_list.append(num)
temp_tup = (word, temp_list)
final_list.append(temp_tup)
final_list = [('made', [-12, 3, 1]), ('ace', [2, 2]), ('today', [-5, -11, -3, 24]),
('tennis...yeaah', [-15, 9, 0, 0, 10, -69, 0, 0, 0, -20, 9, 0, 0]),
('booi', [13, 0, 0])]
But i need to return only the ones that are evenly spaced ('ace'). The output should be like this,
[('ace',2)]
Assuming that you do not need the final_list with non evenly spaced numbers, then you can keep track of the num to see if it stays the same throughout the word. If you find a different num stop and go to the next word. If num stays the same then add a (word, num) tuple to the final_list:
for word in test_list2:
if len(word) >=3:
all_nums_are_same = True
prev_num = None
for chr1 in word:
if word.index(chr1) != (len(word)-1):
chr2 = word.index(chr1)+1
num = ord(word[chr2]) - ord(chr1)
if not prev_num:
prev_num = num
elif prev_num != num:
# different number is found, we can
# stop and move on to next word
all_nums_are_same = False
break
if all_nums_are_same:
# only add tuple if all numbers we the same
temp_tup = (word, prev_num)
final_list.append(temp_tup)
This yields [('ace',2)] as a result.
I banged this out in Python 3.3, compiles and works on my machine :)
There's a bunch of extra debugging junk in there like print statements, if you want to test it with some more complicated data (example: long blocks of text) for bugs.
I made use of enumerate(), rather than your word.index, not sure which is more pythonic?
import sys
### Define variables
test_list = ['i', 'made', 'an', 'ace', 'today', 'at', 'tennis...yeaah', 'booi', ':d']
proc_check = [('made', [-12, 3, 1]),
('ace', [2, 2]),
('today', [-5, -11, -3, 24]),
('tennis...yeaah', [-15, 9, 0, 0, 10, -69, 0, 0, 0, -20, 9, 0, 0]),
('booi', [13, 0, 0])]
final_check = [('ace', [2,2])]
test_list2 = ['ace', 'ace', 'ace']
proc_check2 = [('ace', [2, 2]),
('poo', [3, 3]),
('ace', [2, 2])]
final_check2 = [('ace', [2,2]),('poo', [2,2]),('ace', [2,2])]
### Function definitions
def wordIsEven(word_list, proc_list_check):
final_list = []
procd_list = []
for word in word_list:
temp_list = []
if len(word) >= 3:
for chr1 in word:
if word.index(chr1) != (len(word)-1):
chr2 = word.index(chr1)+1
num = ord(word[chr2]) - ord(chr1)
temp_list.append(num)
temp_tup = (word, temp_list)
procd_list.append(temp_tup)
errors = False
for i, check in enumerate(procd_list):
if check != proc_list_check[i]:
errors = True
print("Word Eval Fail! " + str(check) + " != " + str(proc_list_check[i]))
if errors == True:
print("List compare failed!" )
else:
print("Lists compare equally!")
for tmp_tup in procd_list:
print("Examining Slice: "+str(tmp_tup[1]))
for i, num in enumerate(tmp_tup[1]):
if i + 1 < len(tmp_tup[1]):
num2 = tmp_tup[1][i+1]
if num == num2:
if num != 0:
print("Got one! " + str(tmp_tup))
final_list.append(tmp_tup)
return final_list
### Code execution
my_list = wordIsEven(test_list2, proc_check2)
my_check = final_check2
print("Printing Final list:")
for i, item in enumerate(my_list):
tempStr = str(item)
if item != my_check[i]:
tempStr += " doesn't match check data..." + str(my_check[i])
print(tempStr)
sys.exit()