Variable not declared within this scope Array Linear Search - c++

Question

I am trying to make a program in C++ that will search for a desired value in an array of size 10 using a separate search function. Below is the code:
main.cpp
#include <iostream>
#include <array>
using namespace std;
int main()
{
cout << "Welcome to the array linked list program.";
int sanadA[] = {2, 4, 6, 8, 10, 12, 14, 16, 18, 20};
int d = 0;
cin >> d;
while (d =! 0)
{
cout << "Number to be found";
cin >> d;
bool found = seqSearch1(sanadA, 10, d, -1);
cout << found;
}
}
seqSearch1.cpp
#include <iostream>
using namespace std;
bool jw_search (int *list, int size, int key, int*& rec)
{ //Basic sequential search.
bool found = false;
int i;
for(i=0;i<size;i++)
{
if (key == list[i])
{
break;
}
if (i < size)
{
found = true;
rec = &list[i];
}
}
return found;
}
I get the errors:
C:\Users\tevin\Documents\sanad\main.cpp|13|warning: suggest parentheses around assignment used as truth value [-Wparentheses]|
C:\Program Files (x86)\CodeBlocks\MinGW\lib\gcc\mingw32\5.1.0\include\c++\bits\c++0x_warning.h|32|error: #error This file requires compiler and library support for the ISO C++ 2011 standard. This support is currently experimental, and must be enabled with the -std=c++11 or -std=gnu++11 compiler options.|
C:\Users\tevin\Documents\sanad\main.cpp|19|error: 'seqSearch1' was not declared in this scope|
I need help figuring why this happens.

Answer 1

I assume that the error occurs on this line:
bool found = seqSearch1(sanadA, 10, d, -1);
The problem is that you have not declared any function named seqSearch1(). Instead you have a function named jw_search(). So you can change the line to this:
bool found = jw_search(sanadA, 10, d, -1);
But you also need a header file called seqSearch1.h with the following line:
bool jw_search (int *list, int size, int key, int*& rec);
And finally add this line to the top of main.cpp:
#include "seqSearch1.h"
When you compile your code, you will need to include all source files in the command. For example, if you are using g++, you can do something like this:
g++ main.cpp seqSearch1.cpp
To understand how this works, you need to learn about header files and the difference between a function declaration and a function definition. You should also learn about the difference between the compiler and the linker.

Answer 2

Code-Apprentice has the direct answer to your question. If you want the code in multiple files then a declaration of the seqSearch1 function will need to be main.cpp or included via #include directive
The code has multiple problems. I've fixed it up a bit for you and put it in a single file.
#include <iostream>
#include <array>
using namespace std;
bool seqSearch1 (int *list, int size, int key, int& rec)
{//Basic sequential search.
bool found = false;
int i;
for(i=0;i<size;i++)
{
if (key == list[i])
{
found = true;
rec = i;
break;
}
}
return found;
}
int main()
{
cout << "Welcome to the array linked list program." << endl;
int sanadA[] = {2, 4, 6, 8, 10, 12, 14, 16, 18, 20};
int d = -1;
while (d != 0)
{
cout << "Number to be found, 0 to end?";
cin >> d;
if(d == 0) break;
int index = -1;
bool found = seqSearch1(sanadA, 10, d, index);
if(found) cout << "Found" << endl;
else cout << "Not Found" << endl;
}
}
Several issues:
The function was referred to by the wrong name.
The loop structure was a confused.
The fourth argument to seqSearch1 had type confusion.