I've created a Live Template with IntelliJ IDEA and I'm trying to find and remove a specific String within Velocity through a variable but failed
I tried to set $moduleName variable through $NAME variable -which is giving 'File name'- with RegExp.
I'm removing View string (part of File name) during creating JS file, but failed. Code:
## Input for 'File Name' is FooView**
#set($regex = '/(View)/') ## Try to get 'View' string with regex**
#set($checkRegex = $NAME.matches($regex)) ## Checks if regex finds**
#set($moduleName = $NAME.replaceAll($regex, '')) ## Try to remove 'View' string on $NAME variable**
## So the results;**
$checkRegex ## Returns as FALSE**
$moduleName ## Still returns all input as 'FooView'**
If you want to replace View, put it as is in regex:
#set($regex = 'View')
Related
const Json = ({ data }: any) => <pre>{JSON.stringify(data, null, 4)}</pre>;
let profileName = <Json data={account.name.replace(/\"/g, '')}/>
not used to using regex, but I am trying to remove all instances of ""
When I use that regex with a normal hardcoded string of a name it works, why doesn't it work with this one?
what'up?
The JSON.stringify() automatically put quotes!
Remove it!
I hope to help!
I have variable with "origin/blahbranch" that I want to substring into "blahbranch", how to substring it? I tried with
dev newbranch = (branch1 =~ /.*)[0]
but that left me with
1. / sign included which I don't want
2. the actual git instruction returns error message when embedding the parameter ${newbranch} :
"unexpected char: '''"
Assuming branch1 is string you can use split function
List<String> list = new ArrayList<String>(Arrays.asList(branch1.split("/")));
list.remove(0);
def newbranch = String.join("/", list.toArray(new String[0]))
println newbranch
Very simple solution considering remote always remains origin you can do below
def newbranch = "origin/blahbrachwithslash/blahbranch".replace("origin/","")
println newbranch
I get a variable $response_code with the whole html-code of a website via curl. In this string I want so search via regex for a specific pattern. But this dosn't work, I get no match at all, no matter for what I search. When I write something different in $response_code it works, the array is empty...
Whats wrong with this?
use strict;
use warnings;
use WWW::Curl::Easy;
my $curl = WWW::Curl::Easy->new;
$curl->setopt(CURLOPT_HEADER,1);
$curl->setopt(CURLOPT_URL, 'https://fahrplaner.vbn.de/hafas/stboard.exe/dn?protocol=https:&input=8003760&boardType=dep&time=09$
# A filehandle, reference to a scalar or reference to a typeglob can be used here.
my $response_body;
$curl->setopt(CURLOPT_WRITEDATA,\$response_body);
# Starts the actual request
my $retcode = $curl->perform;
# Looking at the results...
if ($retcode == 0) {
# print("Transfer went ok\n");
my $response_code = $curl->getinfo(CURLINFO_HTTP_CODE);
# judge result and next action based on $response_code
# print("Received response: $response_body\n");
my #test = ($response_code =~ m/ontime/g);
print($test[0]);
}
else {
# Error code, type of error, error message
print("An error happened: $retcode ".$curl->strerror($retcode)." ".$curl->errbuf."\n");
}
So i am currently getting a user input in the form of a URL and parsing it and then printing the other pages that website links to. The package that i am using is:
LWP::Simple
I fetch the link using user input from command line and store it in a variable. I get it using the $ARGV[0].
Then i proceed to make another variable and use the $get on the variable where i store the website.
Then i proceeded to make an array variable and apply the regex on the variable
/\shref="?([^\s>"]+)/gi;
which stored the results of the get function being used on the variable containing the website string. And then i did a foreach loop on the array to print out the results.
However, while it does print links and stuff, it also end up printing just standalone special characters such as / and # if there is nothing after them.
So like if there is something like /blabalbla it prints that. but if there are just standalone special characters such as /, \, or #, it also prints them. Any way i can modify the regex so that if the special characters don't follow a string, they should not print. New at learning perl and not so talented at regex
I can't help you with your specific problem without further information, but in the mean time I suggest that you look at HTML::LinkExtor which was written for this purpose.
Here's an example code its output. It lists only <a> elements that have an href attribute.
use strict;
use warnings;
use 5.010;
use LWP;
use HTML::LinkExtor;
my $ua = LWP::UserAgent->new;
my $resp = $ua->get('http://www.bbc.co.uk/');
my $extor = HTML::LinkExtor->new(undef, $resp->base);
$extor->parse($resp->decoded_content);
for my $link ($extor->links) {
my ($tag, %attr) = #$link;
next unless $tag eq 'a' and $attr{href};
say $attr{href};
}
output
http://m.bbc.co.uk
http://www.bbc.co.uk/
http://www.bbc.co.uk/#h4discoveryzone
http://www.bbc.co.uk/accessibility/
https://ssl.bbc.co.uk/id/status
http://www.bbc.co.uk/news/
http://www.bbc.com/news/
http://www.bbc.co.uk/sport/
http://www.bbc.co.uk/weather/
http://shop.bbc.com/
http://www.bbc.com/earth/
http://www.bbc.com/travel/
http://www.bbc.com/capital/
http://www.bbc.co.uk/iplayer/
http://www.bbc.com/culture/
http://www.bbc.com/autos/
http://www.bbc.com/future/
http://www.bbc.co.uk/tv/
http://www.bbc.co.uk/radio/
http://www.bbc.co.uk/cbbc/
http://www.bbc.co.uk/cbeebies/
http://www.bbc.co.uk/arts/
http://www.bbc.co.uk/ww1/
http://www.bbc.co.uk/food/
http://www.bbc.co.uk/history/
http://www.bbc.co.uk/learning/
http://www.bbc.co.uk/music/
http://www.bbc.co.uk/science/
http://www.bbc.co.uk/nature/
http://www.bbc.com/earth/
http://www.bbc.co.uk/local/
http://www.bbc.co.uk/travel/
http://www.bbc.co.uk/a-z/
http://www.bbc.co.uk/#orb-footer
http://search.bbc.co.uk/search
http://www.bbc.co.uk/privacy/cookies/managing/cookie-settings.html
http://www.bbc.co.uk/locator/default/desktop/en-GB?ptrt=%2F
http://www.bbc.co.uk/#
http://www.bbc.co.uk/#
http://www.bbc.co.uk/weather/2643743?day=0
http://www.bbc.co.uk/weather/2643743?day=0
http://www.bbc.co.uk/weather/2643743?day=1
http://www.bbc.co.uk/weather/2643743?day=1
http://www.bbc.co.uk/weather/2643743?day=2
http://www.bbc.co.uk/weather/2643743?day=2
http://www.bbc.co.uk/locator/default/desktop/en-GB?ptrt=%2F
http://www.bbc.co.uk/weather/2643743
http://www.bbc.co.uk/news/science-environment-30311816
http://www.bbc.co.uk/news/science-environment-30311822
http://www.bbc.co.uk/news/science-environment-30311818
http://www.bbc.co.uk/news/magazine-30282261
http://www.bbc.co.uk/news/science-environment-30311816
http://www.bbc.co.uk/news/uk-politics-30291460
http://www.bbc.co.uk/news/
http://www.bbc.co.uk/news/uk-england-kent-30319549
http://www.bbc.co.uk/news/world-europe-30306106
http://www.bbc.co.uk/news/world-europe-30306992
http://www.bbc.co.uk/news/uk-30306145
http://www.bbc.co.uk/news/local/
http://www.bbc.co.uk/news/england/london/
http://www.bbc.co.uk/news/uk-england-london-30308694
http://www.bbc.co.uk/news/uk-england-london-30315650
http://www.bbc.co.uk/news/uk-england-london-30321504
http://www.bbc.co.uk/sport/live/football/29959148
http://www.bbc.co.uk/sport/0/
http://www.bbc.co.uk/sport/live/snooker/29618359
http://www.bbc.co.uk/sport/football/30204433
http://www.bbc.co.uk/sport/cricket/30308980
http://www.bbc.co.uk/sport/football/30204434
http://www.bbc.co.uk/sport/0/football/
http://www.bbc.co.uk/sport/football/30204459
http://www.bbc.co.uk/sport/football/30204511
http://www.bbc.co.uk/sport/football/28647040
http://www.bbc.co.uk/?dzf=sport
http://www.bbc.co.uk/?dzf=entertainment
http://www.bbc.co.uk/?dzf=bbcnow
http://www.bbc.co.uk/?dzf=entertainment
http://www.bbc.co.uk/?dzf=news
http://www.bbc.co.uk/?dzf=lifestyle
http://www.bbc.co.uk/?dzf=knowledge
http://www.bbc.co.uk/?dzf=sport
http://www.bbc.co.uk/news/
http://www.bbc.com/news/
http://www.bbc.co.uk/sport/
http://www.bbc.co.uk/weather/
http://shop.bbc.com/
http://www.bbc.com/earth/
http://www.bbc.com/travel/
http://www.bbc.com/capital/
http://www.bbc.co.uk/iplayer/
http://www.bbc.com/culture/
http://www.bbc.com/autos/
http://www.bbc.com/future/
http://www.bbc.co.uk/tv/
http://www.bbc.co.uk/radio/
http://www.bbc.co.uk/cbbc/
http://www.bbc.co.uk/cbeebies/
http://www.bbc.co.uk/arts/
http://www.bbc.co.uk/ww1/
http://www.bbc.co.uk/food/
http://www.bbc.co.uk/history/
http://www.bbc.co.uk/learning/
http://www.bbc.co.uk/music/
http://www.bbc.co.uk/science/
http://www.bbc.co.uk/nature/
http://www.bbc.com/earth/
http://www.bbc.co.uk/local/
http://www.bbc.co.uk/travel/
http://www.bbc.co.uk/a-z/
http://www.bbc.co.uk/
http://www.bbc.co.uk/terms/
http://www.bbc.co.uk/aboutthebbc/
http://www.bbc.co.uk/privacy/
http://www.bbc.co.uk/privacy/cookies/about
http://www.bbc.co.uk/accessibility/
http://www.bbc.co.uk/guidance/
http://www.bbc.co.uk/contact/
http://www.bbc.co.uk/bbctrust/
http://www.bbc.co.uk/complaints/
http://www.bbc.co.uk/help/web/links/
For example:
$lang['Select Project'] = 'Select Project OK';
$lang['Project'] = 'Project';
I want to find only the instances of the word 'Project' not contained within the square brackets.
I'm using ColdFusion studio's extended replace utility to do a global replace.
Any suggestions?
Code Sample Follows:
<?php
$lang['Project Message Board'] = 'Project Message Board';
$lang['Project'] = 'Project';
$lang['Post Message'] = 'Post Message';
$lang['To'] = 'To';
$lang['Everyone'] = 'Everyone';
$lang['From'] = 'From';
$lang['Private Messsage'] = 'Private Messsage';
$lang['Note: Only private message to programmer'] = '[ Note: Please enter programmers id for private message with comma separate operator ]';
$lang['Select Project'] = 'Select Project';
$lang['message_validation'] = 'Message';
$lang['You must be logged in as a programmer to post messages on the Project Message Board'] = 'You must be logged in as a programmer to post messages on the Project Message Board';
$lang['Your Message Has Been Posted Successfully'] = 'Your message has been posted successfully';
$lang['You must be logged to post messages on the Project Message Board'] = 'You must be logged to post messages on the Project Message Board';
$lang['You must be post project to invite programmers'] = 'You must be post project to invite programmers';
$lang['You must be logged to invite programmers'] = 'You must be logged to invite programmers';
$lang['There is no open project to Post Mail'] = 'There is no open project to Post Mail';
$lang['You are currently logged in as']='You are currently logged in as';
$lang['Tip']='Tip: You can post programming code by placing it within [code] and [/code] tags.';
$lang['Submit']='Submit';
$lang['Preview']='Preview';
$lang['Hide']='Hide';
$lang['Show']='Show';
$lang['You are currently logged in as']='You are currently logged in as';
A regexp for 'Project' to the right of an equals sign would be:
/=.*Project/
a regexp that also does what you ask for, 'Project' that has no equals sign to its right would be:
/Project[^=]*$/
or a match of your example lines comes to:
/^\$lang['[^']+']\s+=\s+'Project';$/
By placing 'Project' in brackets () you can use that match in a replacement, adding the flag /g finds all occurences in the line.
Edit: Below didn't work because look-behind assertions have to be fixed-length. I am guessing that you want to do this because you want to do a global replace of "Project" with something else. In that case, borrowing rsp's idea of matching a 'Project' that is not followed by an equals sign, this should work:
/Project(?![^=]*\=)/
Here is some example code:
<?php
$str1 = "\$lang['Select Project'] = 'Select Project OK';";
$str2 = "\$lang['Project'] = 'Project';";
$str3 = "\$lang['No Project'] = 'Not Found';";
$str4 = "\$lang['Many Project'] = 'Select Project owner or Project name';";
$regex = '/Project(?![^=]*\=)/';
echo "<pre>\n";
//prints: $lang['Select Project'] = 'Select Assignment OK';
echo preg_replace($regex, 'Assignment', $str1) . "\n";
//prints: $lang['Project'] = 'Assignment';
echo preg_replace($regex, 'Assignment', $str2) . "\n";
//prints: $lang['No Project'] = 'Not Found';
echo preg_replace($regex, 'Assignment', $str3) . "\n";
//prints: $lang['Many Project'] = 'Select Assignment owner or Assignment name';
echo preg_replace($regex, 'Assignment', $str4) . "\n";
This should work:
/(?<=\=.*)Project/
That will match only the word "Project" if it appears after an equals sign. This means you could use it in a substitution too, if you want to replace "Project" on the right-hand-side with something else.
Thx for help. Not sure what is unclear? I just want to find all instances of the word 'Project' but only instances to the right of the equals sign (i.e. not included in square brackets). Hope that helps.
This actually looks like a tricky problem. Consider
[blah blah [yakkity] Project blah] Project [blah blah] [ Project
This is a parsing problem, and I don't know of any way to do it with one regex (but would be glad to learn one!). I'd probably do it procedurally, eliminating the pairs of brackets that did not contain other pairs until there were none left, then matching "Project".
While it's not clear what instances you want to find exactly, this will do:
^.+? = (.+?);
But you might consider using simple string manipulation of your language of choice.
edit
^.+?=.+?(Project).+?;$
will only match lines that have string Project after the equal sign.
[^\[]'[^'\[\]]+'[^\]] seems to accomplish what you want!
This one: [^\[]'[^'\[\]]*Project[^'\[\]]*' will find all strings, not inside of the file that are contained in quotes, and contain the word project.
Another edit: [^\[]'(?<ProjectString>[^'\[\]]*Project[^'\[\]]*)'[^\]]
This one matches the string, and returns it as the group "ProjectString". Any regex library should be able to pull that out sufficiently.