How to get a model by modelname in django template - django

Question

I have model LandingSnippet that contains attribute ...model = CharField()..., and it is related to context keyword (for example cars in context below)
I have next code in my view
def GeneratedLanding(request):
snippets = LandingSnippet.objects.all().filter(view_on=True).order_by('order')
context = {
'snippets':snippets,
...
'cars':Car.objects.all(), # this is cars
...
return render(request,'qlanding/generateindex.html',{'context':context})
how i can get querySet cars that is in context by keyword cars as a string
for example
{{context}}
prints
{'snippets': <QuerySet [<LandingSnippet: Snippet1Title>, <LandingSnippet: 2 - about - Лучшая служба развозки детей>]>, 'services': <QuerySet []>, 'cars': <QuerySet []>, 'faqs': <QuerySet []>}
and
{{snippet.model}}
prints
cars
QUESTION:
How can i get the {{ context.cars }} ? I think something like context[snippet.model] where snippet.model='cars'
i want push it inside another template when include
{% if snippet.module %}
{% with "qlanding/snippets/module/"|add:snippet.module|add:".html" as path %}
{% include path with model=context[snippet.model] %} # But this is incorect while rendering
{% endwith %}
{% endif %}

Answer 1

you can write a simple template tag like this:
first in your app directory create a directory named templatetags this directory must contains an empty file named __init__.py
create a file with any name in this directory. for example load_from_context
write these code on this file
from django import template
register = template.Library()
#register.tag(name="GetFromContext")
def get_from_context(parser, token):
bits = token.split_contents()
node_list = parser.parse(('endGetFromContext',))
variable = bits[1]
return GetFromContextNode(node_list, variable)
class GetFromContextNode(template.Node):
def __init__(self, node_list, variable):
self.node_list = node_list
self.variable = variable
def render(self, context):
variable_value = template.Variable(self.variable).resolve(context)
with context.push():
context['model'] = context.get(variable_value)
return self.node_list.render(context)
then in your template you can use it like this
{% load load_from_context %}
{# any code in your template #}
{% GetFromContext snippet.model %}
{% include path %}
{% endGetFromContext %}

Answer 2

#vorujack , I get the same error still. but based on your solution I got next.
from Django import template
register = template.Library()
#register.simple_tag
def get_model_from_context(context,model_name):
return context[model_name]
and how I used in view
{% get_model_from_context context=context model_name=snippet.model as model %}
{% include "qlanding/snippets/module/"|add:snippet.module|add:".html" with model=model %}
many thanks for #vorujack