RegEx: Match Within Bounded Groups - regex

I need to match carriage-returns in blocks of text between a pre-determined tag and an indeterminate tag.
In this case, the bounding tags are:
Pre-determined: X-Gmail-Labels:
Indeterminate: (?:^[\w\-]+:) eg: Delivered-To: or ABC123:
Thanks to Wiktor Stribiżew for his answer to this thread, I have a rough idea of the solution I should pursue.
I am unsure of how to apply what I believe is needed: an uncaptured lookahead group for the bounding indeterminate tag.
Plainly stated, I'd like to delete all the carriage-returns in the text associated with the X-Gmail-Labels:. If I can match them, I can delete them!
Initial attempted regex:
(?:\bX-Gmail-Labels:|(?!^)\G)[^\r]*\K\r
Sample data:
From 1604610346950104244#xxx Fri Jun 29 12:34:35 +0000 2018
X-GM-THRID: 1604610346950104244
X-Gmail-Labels: Archived thing,Unread
Delivered-To: joe.schmoe#gmail.com
Received: by 2002:a9f:3005:0:0:0:0:0 with SMTP id h5-v6csp731836uab;
Fri, 29 Jun 2018 05:34:36 -0700 (PDT)
From 1604610346950104244#xxx Fri Jun 29 12:34:35 +0000 2018
X-GM-THRID: 1604610346950104244
X-Gmail-Labels: Also Archived
Day-of-week: Tuesday
Received: by 2002:a9f:3005:0:0:0:0:0 with SMTP id h5-v6csp731836uab;
Fri, 29 Jun 2018 05:34:36 -0700 (PDT)
From 1604610346950104244#xxx Fri Jun 29 12:34:35 +0000 2018
X-GM-THRID: 1604610346950104244
X-Gmail-Labels: Archived
thing,
Unread
Favorite-fruit: bananas
Received: by 2002:a9f:3005:0:0:0:0:0 with SMTP id h5-v6csp731836uab;
Fri, 29 Jun 2018 05:34:36 -0700 (PDT)
From 1604610346950104244#xxx Fri Jun 29 12:34:35 +0000 2018
X-GM-THRID: 1604610346950104244
X-Gmail-Labels: Archived
,Read
ABC123: DoReMe
Received: by 2002:a9f:3005:0:0:0:0:0 with SMTP id h5-v6csp731836uab;
Fri, 29 Jun 2018 05:34:36 -0700 (PDT)
From 1604610346950104244#xxx Fri Jun 29 12:34:35 +0000 2018
X-GM-THRID: 1604610346950104244
X-Gmail-Labels: Archived
thing,Unread
emais
Received: by 2002:a9f:3005:0:0:0:0:0 with SMTP id h5-v6csp731836uab;
Fri, 29 Jun 2018 05:34:36 -0700 (PDT)
(?:^[\w\-]+:)
Above regex applied to data showing indeterminate tag pattern.
(?:\bX-Gmail-Labels:\G)[^\r]*\K\r
Above regex applied to data showing un-end-bounded matches.
Thanks!
-Fitz

Related

AWS cron expression to run every other Monday

I want to schedule a CloudWatch event to run every other Monday and have started with this command:
0 14 ? * 2 *
Currently with the above command, I get a weekly schedule of Monday executions:
Mon, 27 Jul 2020 14:00:00 GMT
Mon, 03 Aug 2020 14:00:00 GMT
Mon, 10 Aug 2020 14:00:00 GMT
Mon, 17 Aug 2020 14:00:00 GMT
Mon, 24 Aug 2020 14:00:00 GMT
Mon, 31 Aug 2020 14:00:00 GMT
Mon, 07 Sep 2020 14:00:00 GMT
Mon, 14 Sep 2020 14:00:00 GMT
Mon, 21 Sep 2020 14:00:00 GMT
Mon, 28 Sep 2020 14:00:00 GMT
However, I would like the schedule to be set to every other Monday, e.g.
Mon, 27 Jul 2020 14:00:00 GMT
Mon, 10 Aug 2020 14:00:00 GMT
Mon, 24 Aug 2020 14:00:00 GMT
Mon, 07 Sep 2020 14:00:00 GMT
Mon, 21 Sep 2020 14:00:00 GMT
I have seen examples with exp and # being used, but I don't think AWS CloudWatch events accept these sort of parameters.

Chris' answer is correct. Currently, there is no way that I could think of to express this as part of CloudWatch Scheduled Events.
However, a workaround could be to set it to every Monday (0 14 ? * 2 *) and trigger a Lambda function that checks whether it's in the on-week or the off-week before triggering the actual target.
Even though this adds some complexity, it would be a viable solution.

You won't be able to do any of the fancier commands (especially those using variables from the command line).
You could do this very basically but would require 2 separate events in order to carry it out:
0 14 ? * 2#1 * - Run on the first Monday of the month.
0 14 ? * 2#3 * - Run on the third Monday of the month.
Unfortunately there is no compatible syntax for scheduled expressions that would allow the concept of every other week, so the above commands occasionally could lead to a 3 week gap.
If you don't care about the Monday you could of course use 0 14 1,15 * * to run on the 1st and 15th of each month (roughly every 2 weeks).
The final option would be to run every Monday, but have the script exit if it is not the every other week, the expression would then just be 0 14 ? * 2 *.
More information about the syntax is available on the Cron Expressions section of the Scheduled Events page.

reset the zoom to the initial in chart.js?

I'm new to chartjs. I applied the extension of this library to enable the zoom. At first it looks great, but as I zoom, I am unable to return to the original point where my bar chart is at the start.
Does anyone know why this happens to me or how can I fix it? thank you very much.
var ctx = document.getElementById("canvas").getContext('2d');
var myChart = new Chart(ctx, {
type: 'bar',
data: {
labels: ["08 Aug 2018 02:42 pm","09 Aug 2018 11:24 am","04 Sep 2018 01:23 pm","04 Sep 2018 01:26 pm","04 Sep 2018 01:31 pm","04 Sep 2018 01:33 pm","04 Sep 2018 01:35 pm","04 Sep 2018 01:36 pm","04 Sep 2018 01:38 pm","04 Sep 2018 01:38 pm","04 Sep 2018 01:40 pm","04 Sep 2018 01:45 pm","04 Sep 2018 01:46 pm","04 Sep 2018 01:49 pm","04 Sep 2018 01:49 pm","04 Sep 2018 01:49 pm","04 Sep 2018 01:53 pm","04 Sep 2018 02:07 pm","04 Sep 2018 02:19 pm","04 Sep 2018 02:19 pm","04 Sep 2018 02:20 pm","04 Sep 2018 02:30 pm","04 Sep 2018 02:31 pm","04 Sep 2018 02:33 pm","05 Sep 2018 09:30 am","05 Sep 2018 09:31 am","08 Aug 2018 02:42 pm","09 Aug 2018 11:24 am","04 Sep 2018 01:23 pm","04 Sep 2018 01:26 pm","04 Sep 2018 01:31 pm","04 Sep 2018 01:33 pm","04 Sep 2018 01:35 pm","04 Sep 2018 01:36 pm","04 Sep 2018 01:38 pm","04 Sep 2018 01:38 pm","04 Sep 2018 01:40 pm","04 Sep 2018 01:45 pm","04 Sep 2018 01:46 pm","04 Sep 2018 01:49 pm","04 Sep 2018 01:49 pm","04 Sep 2018 01:49 pm","04 Sep 2018 01:53 pm","04 Sep 2018 02:07 pm","04 Sep 2018 02:19 pm","04 Sep 2018 02:19 pm","04 Sep 2018 02:20 pm","04 Sep 2018 02:30 pm","04 Sep 2018 02:31 pm","04 Sep 2018 02:33 pm","05 Sep 2018 09:30 am","05 Sep 2018 09:31 am"],
datasets: [{"label":"Estatura (cm)","backgroundColor":"rgba(0, 100, 150, 0.5)","pointBorderColor":"rgba(26,179,148,1)","data":["68.00","69.00","70.00","71.00","72.00","73.00","74.00","75.00","76.00","77.00","78.00","79.00","80.00","81.00","82.00","83.00","84.00","85.00","86.00","87.00","88.00","89.00","90.00","91.00","68.00","69.00","70.00","71.00","72.00","73.00","74.00","75.00","76.00","77.00","78.00","79.00","80.00","81.00","82.00","83.00","84.00","85.00","86.00","87.00","88.00","89.00","90.00","91.00"]}]
},
options: {
legend: {
position: 'top',
},
scales: {
xAxes: [{
ticks: {
autoSkip: true,
maxRotation: 0,
minRotation: 0
}
}]
},
pan: {
enabled: false,
mode: 'xy' // is panning about the y axis neccessary for bar charts?
},
zoom: {
sensitivity:0.5, drag: false, enabled: true, mode: 'x'
}
}
});
this is my code working:
https://jsfiddle.net/ogq5uex6/2/

#yavg Please check bellow screenshot. many labels are duplicated. don't add duplicate label like this. try to add 24 hours time as my answer
I think you expected like this.
var ctx = document.getElementById("canvas").getContext('2d');
var myChart = new Chart(ctx, {
type: 'bar',
data: {
labels:
["08 Aug 2018 14:42","09 Aug 2018 11:24","04 Sep 2018 13:23","04 Sep 2018 13:26","04 Sep 2018 13:31","04 Sep 2018 13:33","04 Sep 2018 13:35","04 Sep 2018 13:36","04 Sep 2018 13:38","04 Sep 2018 13:39","04 Sep 2018 13:40","04 Sep 2018 13:45","04 Sep 2018 13:46","04 Sep 2018 13:49","04 Sep 2018 13:50","04 Sep 2018 13:51","04 Sep 2018 13:53","04 Sep 2018 14:07","04 Sep 2018 14:19","04 Sep 2018 14:20","04 Sep 2018 14:21","04 Sep 2018 14:30","04 Sep 2018 14:31","04 Sep 2018 14:33","05 Sep 2018 09:30","05 Sep 2018 09:31","08 Aug 2018 14:43","09 Aug 2018 11:25","04 Sep 2018 13:22","04 Sep 2018 13:27","04 Sep 2018 13:32","04 Sep 2018 13:34","04 Sep 2018 13:37","04 Sep 2018 13:41","04 Sep 2018 01:40","04 Sep 2018 01:41","04 Sep 2018 01:42","04 Sep 2018 01:45","04 Sep 2018 01:46","04 Sep 2018 01:49","04 Sep 2018 01:50","04 Sep 2018 01:51","04 Sep 2018 01:53","04 Sep 2018 02:07","04 Sep 2018 02:19","04 Sep 2018 02:20","04 Sep 2018 02:22","04 Sep 2018 02:36","04 Sep 2018 02:32","04 Sep 2018 02:35","05 Sep 2018 10:31","05 Sep 2018 10:32"],
datasets: [{"label":"Estatura (cm)","backgroundColor":"rgba(0, 100, 150, 0.5)","pointBorderColor":"rgba(26,179,148,1)","data":["68.00","69.00","70.00","71.00","72.00","73.00","74.00","75.00","76.00","77.00","78.00","79.00","80.00","81.00","82.00","83.00","84.00","85.00","86.00","87.00","88.00","89.00","90.00","91.00","68.00","69.00","70.00","71.00","72.00","73.00","74.00","75.00","76.00","77.00","78.00","79.00","80.00","81.00","82.00","83.00","84.00","85.00","86.00","87.00","88.00","89.00","90.00","91.00"]}]
},
options: {
legend: {
position: 'top',
},
scales: {
xAxes: [{
ticks: {
autoSkip: true,
maxRotation: 0,
minRotation: 0
}
}]
},
pan: {
enabled: false,
mode: 'xy' // is panning about the y axis neccessary for bar charts?
},
zoom: {
sensitivity:0.5, drag: false, enabled: true, mode: 'x'
}
}
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/hammer.js/2.0.8/hammer.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/Chart.js/2.6.0/Chart.min.js"></script>
<script src="https://npmcdn.com/Chart.Zoom.js#0.3.0/Chart.Zoom.min.js"></script>
<canvas id="canvas" height="180"></canvas>
My Codepen Example here

How to grep lines with date formats?

I have a log file that is created from a bash script that uses $(date), so there are dates in such a format:
Fri Apr 24 22:10:39 CEST 2015
The log file looks like this:
Using SCRIPTS_ROOTDIR: /home/gillin/moses/scripts
Using multi-thread GIZA
using gzip
(1) preparing corpus # Fri Apr 24 22:10:39 CEST 2015
Executing: mkdir -p /media/2tb/ccexp/phrase-clustercat-mgiza/work.en-ru/training/corpus
(1.0) selecting factors # Fri Apr 24 22:10:39 CEST 2015
Forking...
(1.2) creating vcb file /media/2tb/ccexp/phrase-clustercat-mgiza/work.en-ru/training/corpus/en.vcb # Fri Apr 24 22:10:39 CEST 2015
(1.1) running mkcls # Fri Apr 24 22:10:39 CEST 2015
/home/gillin/moses/training-tools/mkcls -c50 -n2 -p/media/2tb/ccexp/corpus.exp/train-clean.en -V/media/2tb/ccexp/phrase-clustercat-mgiza/work.en-ru/training/corpus/en.vcb.classes opt
Executing: /home/gillin/moses/training-tools/mkcls -c50 -n2 -p/media/2tb/ccexp/corpus.exp/train-clean.en -V/media/2tb/ccexp/phrase-clustercat-mgiza/work.en-ru/training/corpus/en.vcb.classes opt
(1.1) running mkcls # Fri Apr 24 22:10:39 CEST 2015
/home/gillin/moses/training-tools/mkcls -c50 -n2 -p/media/2tb/ccexp/corpus.exp/train-clean.ru -V/media/2tb/ccexp/phrase-clustercat-mgiza/work.en-ru/training/corpus/ru.vcb.classes opt
Executing: /home/gillin/moses/training-tools/mkcls -c50 -n2 -p/media/2tb/ccexp/corpus.exp/train-clean.ru -V/media/2tb/ccexp/phrase-clustercat-mgiza/work.en-ru/training/corpus/ru.vcb.classes opt
Is there a way such that i can grep all the lines that contain the output of $(date)?
Currently I'm using this regex:
[a-z].*[1-9] [0-2][1-9]:[0-6][0-9]:[0-6][0-9] CEST 2015
And it catches line like
preparing corpus # Fri Apr 24 22:10:39 CEST 2015
But i need the full line:
(1) preparing corpus # Fri Apr 24 22:10:39 CEST 2015
And also the year and time is sort of hard coded. Is there a better regex or unix tool that can extract lines with $(date) outputs?

Try this:
unalias grep
grep --color=never '.*[a-z].*[1-9] [0-2][1-9]:[0-6][0-9]:[0-6][0-9] CEST 2015' file

Boost::gregorian and leap years

I'm writing a code where I use only boost libraries as prerequisites.
I need a class to handle datetime values and operations (add and subtract years, months, hours, etc.), so I picked the gregorian date as an option.
But, when I handle days in leap years, some surprises appear. There is a piece of an example code:
int main()
{
boost::gregorian::date d1(2000,1,1);
boost::gregorian::days ds(118);
boost::gregorian::date d2 = d1 + ds;
std::cout << boost::gregorian::to_iso_extended_string(d1) << std::endl;
std::cout << boost::gregorian::to_iso_extended_string(d2) << std::endl;
return 0;
}
Output:
2000-01-01
2000-04-28 (should be 2000-04-27)
Is there an option for this issue? In the manual page, the boost warning about "lead to unexpected results..."

I think it's correct as it is:
for a in {1..118}; do echo -n "+$a days: "; date --rfc-2822 -d"2000-01-01 +$a days"; done
prints
shows I see no anomalies around the leap date:
+1 days: Sun, 02 Jan 2000 00:00:00 +0100
+2 days: Mon, 03 Jan 2000 00:00:00 +0100
...
+57 days: Sun, 27 Feb 2000 00:00:00 +0100
+58 days: Mon, 28 Feb 2000 00:00:00 +0100
+59 days: Tue, 29 Feb 2000 00:00:00 +0100
+60 days: Wed, 01 Mar 2000 00:00:00 +0100
...
+116 days: Wed, 26 Apr 2000 00:00:00 +0200
+117 days: Thu, 27 Apr 2000 00:00:00 +0200
+118 days: Fri, 28 Apr 2000 00:00:00 +0200

Confusion on grep pattern search

Consider this log file
SN PID Date Status
1 P01 Fri Feb 14 19:32:36 IST 2014 Alive
2 P02 Fri Feb 14 19:32:36 IST 2014 Alive
3 P03 Fri Feb 14 19:32:36 IST 2014 Alive
4 P04 Fri Feb 14 19:32:36 IST 2014 Alive
5 P05 Fri Feb 14 19:32:36 IST 2014 Alive
6 P06 Fri Feb 14 19:32:36 IST 2014 Alive
7 P07 Fri Feb 14 19:32:36 IST 2014 Alive
8 P08 Fri Feb 14 19:32:36 IST 2014 Alive
9 P09 Fri Feb 14 19:32:36 IST 2014 Alive
10 P010 Fri Feb 14 19:32:36 IST 2014 Alive
When i do => grep "P01" File
output is : (as expected)
1 P01 Fri Feb 14 19:32:36 IST 2014 Alive
10 P010 Fri Feb 14 19:32:36 IST 2014 Alive
But when i do => grep " P01 " File (notice the space before and after P01)
I do not get any output!
Question : grep matches pattern in a line, so " P01 " ( with space around ) should match the first PID of P01 as it has spaces around it....but seems that this logic is wrong....what obvious thing i am missing here!!!?

If the log uses tabs not spaces, your grep pattern won't match. I would add word boundaries to the word you want to find:
grep '\<P01\>' file
If you really want to use whitespace in your pattern, use one of:
grep '[[:blank:]]P01[[:blank:]]' file # horizontal whitespace, tabs and spaces
grep -P '\sP01\s' file # using Perl regex