I cannot find any suitable example on how to inject an app.context object into a Loopback 4 controller being in a separate file
This inline example from the documentation works fine
import {inject} from '#loopback/context';
import {Application} from '#loopback/core';
const app = new Application();
app.bind('defaultName').to('John');
export class HelloController {
constructor(#inject('defaultName') private name: string) {}
greet(name?: string) {
return `Hello ${name || this.name}`;
}
}
but I cannot find a way to obtain the same having my controller in a separate file.
I am trying to do something like this:
export class PingController {
constructor(#inject(app.name) private name: string)
app.name being a simple binding in my app-context.
Solution was quite simple.
Since all context values on app level is available throughout the application, no reference to app is required.
I just needed to replace (app.name) with ('name') in the constructor injection.
Related
I want to use http://tabulator.info/ with ember. I don't understand the documentation nor can I find any guides on configuration for ember. How can I start by creating a simple table?
Looking at the examples on the site, http://tabulator.info/, it seems that tabulator only needs an element to work (and some config).
So, our end goal is going to be to use a modifier with the ability to pass the tabulator config to it.
So, this is what we'll end up with:
<div {{tabulator someConfig}}></div>
Now, unfortunately, it looks like tabulator only accepts an id in its constructor. so we'll need to dynamically add that in to appears tabulator.
First thing you'll want to do is install https://github.com/ember-modifier/ember-modifier (be sure to read the docs as this is fun stuff)
Then, create a file in your app, app/modifiers/tabulator.js
and use these contents:
import Modifier from 'ember-modifier';
import Tabulator from 'tabulator';
import { guidFor } from '#ember/object/internals';
export default class TabulatorModifier extends Modifier {
id = guidFor(this);
get config() {
return this.args.positional[0];
}
didInstall() {
this.element.id = this.id;
let config = th
this.tabulator = new Tabulator(`#${this.id}`, this.config);
}
}
And then maybe in a component or controller or something, you'd have something like:
export default class MyComponent extends Component {
get myConfig() {
return { ... };
}
}
<div {{tabulator this.myConfig}}></div>
and that should be it.
You'll want to import the CSS in your app.css
I tried to altered route it didn't work in my custom module. it is taking the altered path from contributed module. then i tried to extend the routesubscriber.php from extended module but its still didn't work.
I have cleared cache, rebuild routes, and tried to adjust weight for my custom module giving it highest weight. But still didn't work.
If anyone call help with this issue, it will be great help.
this is MyAppsRouteSubscriber.php
<?php
namespace Drupal\MyApps\Routing;
use Drupal\MyApps\Entity\ListBuilder\DeveloperAppListBuilder;
use Drupal\Core\Routing\RouteSubscriberBase;
use Symfony\Component\Routing\RouteCollection;
use Drupal\apigee_kickstart_enhancement\Routing\RouteSubscriber;
/**
* Custom MyAppsRouteSubscriber for MyApps.
*/
class MyAppsRouteSubscriber extends RouteSubscriber
{
protected function alterRoutes(RouteCollection $collection)
{
// Override the controller for the Apigee Kickstart Enhancement.
/** #var \Drupal\Core\Entity\EntityTypeInterface $app_entity_type */
foreach (\Drupal::service('apigee_kickstart.enhancer')->getAppEntityTypes() as $entity_type_id => $app_entity_type) {
if ($route = $collection->get("entity.$entity_type_id.collection_by_" . str_replace('_app', '', $entity_type_id))) {
if ($entity_type_id == 'team_app') {
$route->setDefault('_controller', TeamAppListBuilder::class . '::render');
} else {
$route->setDefault('_controller', DeveloperAppListBuilder::class . '::render');
}
}
}
}
}
and i have DeveloperAppListBuilder.php
<?php
namespace Drupal\MyApps\Entity\ListBuilder;
use Drupal\apigee_edge\Entity\DeveloperAppRouteProvider;
use Drupal\apigee_edge\Entity\ListBuilder\DeveloperAppListBuilderForDeveloper;
/**
* Renders the Apps list as a list of entity views instead of a table.
*/
class DeveloperAppListBuilder extends DeveloperAppListBuilderForDeveloper
{
/**
* {#inheritdoc}
*/
public function render()
{
//code here
}
}
First make sure your module is following the details outlined in Naming and placing your Drupal 8 module - Name your module:
It must contain only lower-case letters and underscores.
The namespace in your details indicates it is using upper camel case instead of snake cases.
Also ensure your route subscriber has a relevant my_app.services.yml services YAML file and tag it with event_subscriber or it won't be registered:
services:
my_app.route_subscriber:
class: Drupal\my_app\Routing\MyAppsRouteSubscriber
tags:
- { name: event_subscriber }
Make sure your module is enabled or it won't be working either. Debug through it to see where it still fails.
I'm using ML.NET in an ASP.NET Core application, and I am using the following code in Startup:
var builder = services.AddPredictionEnginePool<Foo, Bar>();
if (File.Exists("model.zip"))
{
builder.FromFile(String.Empty, "model.zip", true);
}
If model.zip doesn't exist, I create it later in the middleware. How do I add it to the PredictionEnginePool that is injected?
There are no options to load a model via PredictionEnginePool, and instantiating or injecting a PredictionEnginePoolBuilder isn't an option as it requires IServiceCollection (so must be configured during Startup.ConfigureServices).
The only option I can see at the moment is to set a flag if the file doesn't exist at startup, and then restart the service after model.zip is created in the middleware later on (using IApplicationLifetime.StopApplication), but I really don't like this as an option.
PredictionEnginePool is designed in such a way that you can write your own ModelLoader implementation. Out of the box, Microsoft.Extensions.ML has 2 loaders, File and Uri. When those don't meet your needs, you can drop down and write your own.
See https://github.com/dotnet/machinelearning-samples/pull/560 which changes one of the dotnet/machine-learning samples to use an "in-memory" model loader, it doesn't get the model from a file or a Uri. You can follow the same pattern and write whatever code you need to get your model.
public class InMemoryModelLoader : ModelLoader
{
private readonly ITransformer _model;
public InMemoryModelLoader(ITransformer model)
{
_model = model;
}
public override ITransformer GetModel() => _model;
public override IChangeToken GetReloadToken() =>
// This IChangeToken will never notify a change.
new CancellationChangeToken(CancellationToken.None);
}
And then in Startup.cs
services.AddPredictionEnginePool<ImageInputData, ImageLabelPredictions>();
services.AddOptions<PredictionEnginePoolOptions<ImageInputData, ImageLabelPredictions>>()
.Configure(options =>
{
options.ModelLoader = new InMemoryModelLoader(_mlnetModel);
});
As the title states, is it possible to have a unit test for a controller, and mock a tag lib?
As it stands, I have a User controller. Many of the actions use the
g.message(code: 'something.something')
call to set a message on the page.
#TestFor(UserController)
#Mock(User)
#TestMixin(GroovyPageUnitTestMixin)
class UserControllerSpec extends Specification
{
UserService userServiceMock = Mock(UserService)
def setup()
{
controller.userService = userServiceMock
}
def cleanup()
{
}
void "test manageDevice"()
{
given:
def g = mockTagLib(FormTagLib)
when:
controller.manageDevice()
then:
model.pageTitle == 'message.device'
}
With that code I'm trying to hit the controller action but because of the g.message, it's failing with an error saying that it can't set a value to null. Pretty much because it doesn't see the "g.message"
I'm a little unsure if my unit test needs written differently, or if I'm just missing something.
Any help would be great!
EDIT:
Some updates using messageSource:
void "test manageDevice"()
{
given:
messageSource.addMessage 'user.devices', request.locale, 'Manage Devices'
when:
controller.manageDevices()
then:
assertEquals model.pageTitle == 'user.devices', controller.flash.message
}
It seems to still be complaining because it doesn't have context of the "g" namespace on the controller. I'll note as well, I don't have context of 'addMessage' from messageSource. Not sure why, it should be there.
In the same controller, and many others, the only taglib we use in the controller scope is 'g' for the 'g.message' set in each action. The only other call that's being done, is one using the 'g' for a call like 'g.fixRedisIssue'
You can make a unit test for a controller with a mocked TagLib by including the necessary TagLib classes in the value of the grails.test.mixin.Mock annotation on the Spec class. For example, if you have the following TagLib:
(based on code in Grails documentation)
package org.grails.samples
class SimpleTagLib {
static namespace = 'g'
def hello = { attrs, body ->
out << "Hello ${attrs.name ?: 'World'}"
}
}
And you have the following controller:
package org.grails.samples
class SimpleController {
def flashHello() {
flash.message = g.hello()
}
}
You could test it with the following specification:
package org.grails.samples
import grails.test.mixin.Mock
import grails.test.mixin.TestFor
import spock.lang.Specification
#TestFor(SimpleController)
#Mock(SimpleTagLib)
class SimpleControllerSpec extends Specification {
void 'test flashHello'() {
when:
controller.flashHello()
then:
flash.message == 'Hello World'
}
}
If you have multiple classes to mock, you can specify them in an array argument to #Mock. So you can add any necessary tag libraries to UserControllerSpec by changing #Mock(User) to something like #Mock([User, FormTagLib, YourFixRedisIssueTagLib]). However, I'd be surprised if you actually did need to add FormTagLib because in my Grails testing it seems to be included by default.
As some further advice, some of the code you posted doesn't make any sense. Specifically:
assertEquals model.pageTitle == 'user.devices', controller.flash.message
Decide specifically what you want to test for and focus on writing the simplest code possible for that.
Also, based on your description of what's happening, I think that you're getting thrown off because your IDE is not properly integrated with Grails to see the g context.
Instead of returning the message text to the view from the controller, why not return the message code instead? For example, if you have something like this in your view:
<p>${flash.message}</p>
You can replace it with this:
<p><g:message code="${flash.code}" /></p>
And then set the code in the controller:
flash.code = "user.devices"
Then you'll be able to test the controller methods painlessly :)
How can I in Laravel 5 make global variable which will be available in all Blade templates?
Option 1:
You can use view::share() like so:
<?php namespace App\Http\Controllers;
use View;
//You can create a BaseController:
class BaseController extends Controller {
public $variable1 = "I am Data";
public function __construct() {
$variable2 = "I am Data 2";
View::share ( 'variable1', $this->variable1 );
View::share ( 'variable2', $variable2 );
View::share ( 'variable3', 'I am Data 3' );
View::share ( 'variable4', ['name'=>'Franky','address'=>'Mars'] );
}
}
class HomeController extends BaseController {
//if you have a constructor in other controllers you need call constructor of parent controller (i.e. BaseController) like so:
public function __construct(){
parent::__construct();
}
public function Index(){
//All variable will be available in views
return view('home');
}
}
Option 2:
Use a composer:
Create a composer file at app\Composers\HomeComposer.php
NB: create app\Composers if it does not exists
<?php namespace App\Composers;
class HomeComposer
{
public function compose($view)
{
//Add your variables
$view->with('variable1', 'I am Data')
->with('variable2', 'I am Data 2');
}
}
Then you can attached the composer to any view by doing this
<?php namespace App\Http\Controllers;
use View;
class HomeController extends Controller{
public function __construct(){
View::composers([
'App\Composers\HomeComposer' => ['home'] //attaches HomeComposer to home.blade.php
]);
}
public function Index(){
return view('home');
}
}
Option 3:
Add Composer to a Service Provider, In Laravel 5 I prefer having my composer in App\Providers\ViewServiceProvider
Create a composer file at app\Composers\HomeComposer.php
Add HomeComposer to App\Providers\ViewServiceProvider
<?php
namespace App\Providers;
use Illuminate\Support\ServiceProvider;
use View;
use App\Composers\HomeComposer;
use Illuminate\Support\Facades\Blade;
class ViewServiceProvider extends ServiceProvider
{
/**
* Register any application services.
*
* #return void
*/
public function register()
{
//
}
/**
* Bootstrap any application services.
*
* #return void
*/
public function boot()
{
//add to all views
view()->composer('*', HomeComposer::class);
//add to only home view
//view()->composer('home', HomeComposer::class);
}
}
Create a new Service Provider as suggested in here
Add your new Service Provider to the configuration file (config/app.php).
In the boot method of your new Service Provider use:
View::share( 'something_cool', 'this is a cool shared variable' );
Now you are ready to use $something_cool in all of your views.
Hope this helps.
Searching for solution of the same problem and found the best solution in Laravel documentation. Just use View::share in AppServiceProvider like this:
View::share('key', 'value');
Details here.
You can do this with view composers. View composers are executed when a template is loaded. You can pass in a Closure with additional functionality for that view. With view composers you can use wildcards. To make a view composer for every view just use a *.
View::composer('*', function($view)
{
$view->with('variable','Test value');
});
You can also do this without a closure as you can see in the docs.
View::composer('*', 'App\Http\ViewComposers\ProfileComposer');
The profile composer class must have a compose method.
View composers are executed when a view is rendered. Laravel has also view creators. These are executed when a view is instantiated.
You can also choose to use a BaseController with a setupLayout method. Then every view which you will load is loaded through the setupLayout method which adds some additional data. However, by using view composers you're pretty sure that the code is executed. But with the BaseController approach you've more flexibility because you can skip the loading of the extra data.
EDIT: As mentioned by Nic Gutierrez you can also use view share.
Also, you can do this in the Route.php file:
view()->share('variableName', $variable);
I would rather use middleware with the view() facade helper. (Laravel 5.x)
Middleware is easier to mantain and does not make a mess in the controllers class tree.
Steps
Create the Middleware
/app/Http/Middleware/TimezoneReset.php
To create a middleware you can run php artisan make:middleware GlobalTimeConfig
share() the data you need shared
<?php
namespace App\Http\Middleware;
use Closure;
class GlobalTimeConfig
{
/**
* Handle an incoming request.
*
* #param \Illuminate\Http\Request $request
* #param \Closure $next
* #return mixed
*/
public function handle($request, Closure $next)
{
$time_settings = [
'company_timezone' => 'UTC',
'company_date_format' => 'Y-m-d H:i:s',
'display_time' => true,
];
view()->share('time_settings', $time_settings);
return $next($request);
}
}
Register the newly created middleware
Add the middleware to your middleware route group as per example below
/app/Http/Kernel.php
protected $middlewareGroups = [
'web' => [
\App\Http\Middleware\GlobalTimeConfig::class,
\App\Http\Middleware\EncryptCookies::class,
\Illuminate\Cookie\Middleware\AddQueuedCookiesToResponse::class,
\Illuminate\Session\Middleware\StartSession::class,
// \Illuminate\Session\Middleware\AuthenticateSession::class,
\Illuminate\View\Middleware\ShareErrorsFromSession::class,
\App\Http\Middleware\VerifyCsrfToken::class,
\Illuminate\Routing\Middleware\SubstituteBindings::class,
],
'api' => [
'throttle:60,1',
'bindings',
],
];
Access data from templates
Access the data from any template with the given key in the View::share() method call
eg.:
Company timezone: {{ $time_settings['company_timezone'] }}
EDIT:
Nic Gutierrez's Service Provider answer might be a better (or the best) solution.
and you can give array not just View::share('key', 'value');
can put array like View::share(['key'=>'value','key'=>'value'])
You can add in Controller.php file:
use App\Category;
And then:
class Controller extends BaseController {
public function __construct() {
$categories = Category::All();
\View::share('categories', $categories);
}
}
you can flash it into the session, you can define it in the .env file (static vars)