Apparent mixed-mode arithmetic from a Fortran intrinsic function - fortran

What I'm doing is very straightforward. Here are the relevant declarations:
USE, INTRINSIC :: ISO_Fortran_env, dp=>REAL64 !modern DOUBLE PRECISION
REAL(dp), PARAMETER :: G_H2_alpha = 1.57D+04, G_H2_beta = 5.3D+03, G_H2_gamma = 4.5D+03
REAL(dp) :: E_total_alpha, E_total_beta, E_total_gamma, P_H2_sed
Usage:
P_H2_sed = G_H2_alpha * E_total_alpha + G_H2_beta * E_total_beta * G_H2_gamma * E_total_gamma
where E_total_alpha, E_total_beta, and E_total_gamma are just running dp totals inside various loops. I ask for the nearest integer NINT(P_H2_sed) and get -2147483648, which looks like mixed-mode arithmetic. The float P_H2_sed returns 2529548272025.4888, so I would expect NINT to return 2529548272026. I didn't think it was possible to get this kind of result from an intrinsic function. I haven't seen this since my days with the old F77 compiler. I'm doing something bad, but what is the question.

NINT, by default, returns an integer with default type parameter, that usually is equivalent to int32.
An integer of this kind cannot represent a number as high as 2529548272026. The maximum representable number is 2^31-1, that is 2147483647. The result you are getting is similar to that, but is the lowest representable number, -2147483648 (equivalent o all 32 bits set to 1).
To get a result of other kind from NINT, pass an optional parameter named kind, like this: NINT(P_H2_sed, kind=int64).

Related

Maximum value of 64 bit floating point number for overflow detection

I have a seemingly simple problem: I want to detect whether a floating point addition in Fortran will overflow by doing something like the following:
real*8 :: a, b, c
a = ! some value
b = ! some value
if (b > DOUBLE_MAX - a) then
! handle overflow
else
c = a + b
The problem is that I don't know what DOUBLE_MAX should be. I'm aware of how floating point numbers are represented according to IEEE 754 but the largest value representable by a double precision floating point number seems to be too large for a variable of type real*8 (i.e. if I try to assign 1.7976931348623157e+308 to such a variable gfortran complains). C and C++ have predefined constants/generic functions for this purpose but I couldn't find a Fortran equivalent.
Note: I'm aware that real*8 is not really part of the standard but there seems to be no other way to reliably specify that a floating point number should use the double precision format.
Something like this?
real(REAL64) function func( a, b )
use, intrinsic :: iso_fortran_env, only: REAL64, INT64
use, intrinsic :: ieee_arithmetic, only: ieee_value, ieee_set_flag, IEEE_OVERFLOW, IEEE_QUIET_NAN
implicit none
real(REAL64), intent(in) :: a, b
real(REAL64), parameter :: MAX64 = huge(0.0_REAL64)
if ( b > MAX64-a ) then
! Set IEEE_OVERFLOW flag and return NaN
call ieee_set_flag(IEEE_OVERFLOW,.true.)
func = ieee_value(func,IEEE_QUIET_NAN)
else
func = a + b
end if
return
end function func
All I could find for intrinsic ieee_exceptions module is:
https://github.com/gcc-mirror/gcc/blob/master/libgfortran/ieee/ieee_exceptions.F90
For setting NaN value see post.
There are likely better ways to detect overflow, but the precise answer to your question is to use the huge function. HUGE(a) returns the largest possible number representable by the type a.

Function type does not match the function definition

I am new to Fortran, writing some practice code with a function that returns Farenheit from Celsius
program Console1
implicit none
real, parameter :: ikind = selected_real_kind(p=15)
real (kind = ikind):: c,f,o,faren
print *, "enter a temperature in degrees celsius"
read *, c
write(*,10) "farenheit =", faren(c)
10 format(a,f10.8)
end program Console1
function faren(c)
real, parameter :: ikind = selected_real_kind(p=15)
real (kind = ikind):: c,f
faren = (9/5)*c + 32
end function faren
I get an error #7977 : The type of the function reference does not match the type of the function definition.
So with that if i change function faren(c) to real function faren(c)
I get the same error, but the types are the same?
Am i missing something? Do I have to define the function in the main program?
There are several issues in addition to the structural/code arrangement ones already noted.
First, KIND is an integer, so you want to change
real, parameter :: ikind = selected_real_kind(p=15)
to
integer, parameter :: ikind = selected_real_kind(p=15)
Ideally, you want to define that in only one place (i.e. in a module) and reference it from both your main program and the function, but the code should be fine as it is for test purposes.
A second issue that often trips up newcomers to Fortran (and Python2) is that real numbers and integers are distinct types and are not generally interchangeable.
faren = (9/5)*c + 32
simplifies to
faren = (1)*c + 32
because integer division has an integer result; 9/5 = 1
Fortran is picky about numerical values (that's sort of the whole point of the language) so what you probably want is:
faren = (9.0 / 5.0) * c + 32.0
Or more precisely, if faren is defined with a specific precision of ikind,
faren = (real(9.0,ikind) / real_(5.0,ikind)) * c + real(32.0,ikind)
or
faren = (9.0_ikind / 5.0_ikind) * c + 32.0_ikind
This syntax tends to make people's heads explode. Welcome to modern fortran ;)
The last issue deals with the horrors of Fortran I/O. From a design standpoint, you need to know what results the user expects and make sure the output format can display them. The legitimate range of input values for c is -273.15 (give or take) to some upper bound which relies on the use case for the code. If you're dealing with cooking temperatures, you probably won't exceed 400.0; if you're doing fusion research, you could be going much higher. Are 8 figures past the decimal useful or believable? In this case, we're just testing the code so we may not need a lot of precision in the output; you'll want to change the output format to something like:
10 format(a,es10.2)
or
10 format(a,g16.8)
You need to ensure the total field width (the number before the dot) can contain the decimal part (the number after the dot) along with the integer part of the number, plus the space needed to show sign and exponent. For scientific notation, four characters are eaten by mantissa sign, decimal point, 'E' and exponent sign. It may be safer just starting out to use an output format of *; it's frustrating to fight with numerics and formatting simultaneously.
That is a good effort and simple start to work through the nuance, so a good question.
Personally I would use reals for the math, rather the 9/5, and use a module. In this example you could pass in a real or a double to C2Faren and the interface/procedure will sort out whether to use the real or the double version. Then you have a few options in case you want different precision.
You could also use the ISO_C_BINDING if you do mixed language...
MODULE MyTEMPS
PRIVATE
DOUBLE PRECISION, PARAMETER :: C2F_ScaleFact = 1.8D0
DOUBLE PRECISION, PARAMETER :: F2C_ScaleFact = /(1.0D0 / 1.8D0)/
DOUBLE PRECISION, PARAMETER :: F2C_Offset = 32.0D0
PUBLIC Faren2C
INTERFACE C2Faren
MODULE PROCEDURE C2Faren_Real, C2Faren_DBL
END INTERFACE
CONTAINS
!========= REAL VERISON =========
REAL FUNCTION C2Faren_Real(c)
IMPLICIT NONE
real, INTENT(IN ) :: c
C2Faren_Real = ( C*F2C_ScaleFact ) + F2C_Offset
RETURN
END FUNCTION C2Faren_Real
!========= DOUBLE VERSION =========
DOUBLE PRECISION FUNCTION C2Faren_DBL(c)
IMPLICIT NONE
DOUBLE PRECISION , INTENT(IN ) :: c
C2Faren_DBL = ( C*F2C_ScaleFact ) + F2C_Offset
RETURN
END FUNCTION C2Faren_DBL
!========= REAL VERSION (Faren to Centigrade) =========
REAL FUNCTION faren2C(Faren)
IMPLICIT NONE
REAL, INTENT(IN ) :: Faren
faren2C = (faren - F2C_Offset) / F2C_ScaleFact
RETURN
END FUNCTION faren2C
END MODULE MyTEMPS
Then your program uses the module via USE n the second line...
program Console1
USE MyTEMPS !<== Here
implicit none
real :: c, f
DOUBLE PRECISION :: Dc, Df ! No way to get Df to C or DC in the module (yet)!
print *, "enter a temperature in degrees celsius"
read *, c
write(*,10) "farenheit =", C2faren(c)
10 format(a,f10.6)
Dc = C
write(*,12) "farenheit =", C2faren(Dc)
12 format("DBL:",A,f10.6)
F = Dc
write(*,14) "Centigrade =", faren2C(F)
14 format("DBL:",A,f10.6)
end program Console1
So/and the main advantage of the module is when you end up wanting to use this stuff in a variety of programs and test and sort out the module once... Usually people put this sort of stuff (lots of modules) in a library, when the module(s) have lot of functions.
You could also put just the real, parameter :: ikind = selected_real_kind(p=15) into a module and use that in both the program and the function and you would be there. You were real close, and it mostly a matter of style and utility.
For Intel Fortran you can use REAL(KIND=4) and REAL(KIND=8)... Which I do, but that is not portable to gfortran, so it is probably a better habit to use the ISO_C_BINDING or just use REAL and DOUBLE PRECISION.
Modules are great but if you have a very simple code another way to work is to put the subroutines and functions in your main program. The trick is to put them after the word contains:
program xxx
stuff
contains
subroutine yyy
function zzz
end program xxx
In this way the functions can see into the contents of the main program so you don't have to re-declare your parameters and you are likely to get more meaningful error messages.
Since you are new I have a great resource I learned a lot from to share:
http://www.uv.es/dogarcar/man/IntrFortran90.pdf

How to cast a real as a specific KIND?

I have multiple kinds I am using in Fortran and would like to add a real valued number where the real number is cast as that kind.
For example, something like:
program illsum
implicit none
#if defined(USE_SINGLE)
integer, parameter :: rkind = selected_real_kind(6,37)
#elif defined(USE_DOUBLE)
integer, parameter :: rkind = selected_real_kind(15,307)
#elif defined(USE_QUAD)
integer, parameter :: rkind = selected_real_kind(33, 4931)
#endif
integer :: Nmax = 100
integer :: i
real(kind = rkind) :: mysum = 0.0
do i = 1,Nmax
mysum = mysum + kind(rkind, 1.0)/kind(rkind, i)
enddo
end program illsum
So I want to make sure that 1.0 and the real valued expression of i are expressed as the proper kind that I have chosen before performing the division and addition.
How can I cast 1.0 as rkind?
To convert a numeric value to a real value then there is the real intrinsic function. Further, this takes a second argument which determines the kind value of the result. So, for your named constant rkind
real(i, rkind) ! Returns a real valued i of kind rkind
real(1.0, rkind) ! Returns a real valued 1 of kind rkind
which I think is what you are meaning with kind(rkind, 1.0). kind itself, however, is an intrinsic which returns the kind value of a numeric object.
However, there are other things to note.
First, the literal constant 1._rkind (note the . in there, could be clearer with 1.0_rkind) which is of kind rkind and value approximating 1.
There's no comparable expression i_rkind, though, so the conversion above would be necessary for a real result of kind rkind with value approximating i.
That said, for you example there is no need to do such casting of the integer value. Under the rules of Fortran the expression 1._rkind/i involves that implicit conversion of i and is equivalent to 1._rkind/real(i,rkind) (and real(1.0, rkind)/real(i,rkind)).

fortran: compilation in 64-bit system producing 32-bit integer overflow error [duplicate]

Fortran is completely new for me, can anybody help me to solve the follwing problem? I want to find out all the integer kind numbers and the largest and the smallest value for each kind number on my pc. I have code listed below:
program intkind
implicit none
integer :: n=1
integer :: integer_range =1
do while(integer_range /= -1)
print*, "kind_number ", selected_int_kind(n)
call rang(integer_range)
n = n *2
integer_range = selected_int_kind(n)
end do
contains
subroutine rang(largest)
integer largest
print*, huge(largest)
end subroutine
end
The integer kind numbers what I get are : 1,2,4,8.
Why is each largest integer for each kind number the same: 2147483647? And is there a intrinsic function for the smallest integer?
How can I keep the integer kind number when the subroutine rang is called? I think it is the key to the largest integer.
Your subroutine:
subroutine rang(largest)
integer :: largest
print *, huge(largest)
end subroutine
takes as input a default-sized integer, and prints the largest possible value that will fit in that default-sized integer. It will always return huge(default integer) which is, on most systems, huge(4-byte-integer), or 2147483647. huge considers only the variable type; it doesn't interpret the variable in any way. The only way you could do what you're trying to do above is with parameterized derived types, which are new enough that support for it in compilers is still a little spotty.
If you want to take a look at ranges of different KINDs of INTEGERs, you'll have to use different variables:
program integerkinds
use iso_fortran_env
implicit none
integer :: i
integer(kind=int8) :: i8
integer(kind=int16) :: i16
integer(kind=int32) :: i32
integer(kind=int64) :: i64
integer(kind=selected_int_kind(6)) :: j6
integer(kind=selected_int_kind(15)):: j15
print *,'Default:'
print *, huge(i)
print *,'Int8:'
print *, huge(i8)
print *,'Int16:'
print *, huge(i16)
print *,'Int32:'
print *, huge(i32)
print *,'Int64:'
print *, huge(i64)
print *,''
print *,'Selected Integer Kind 6:'
print *, huge(j6)
print *,'Selected Integer Kind 15:'
print *, huge(j15)
end program integerkinds
Running gives:
$ ./intkinds
Default:
2147483647
Int8:
127
Int16:
32767
Int32:
2147483647
Int64:
9223372036854775807
Selected Integer Kind 6:
2147483647
Selected Integer Kind 15:
9223372036854775807
Purely as an addendum, or alternate perspective, Fortran variables are defined in terms of the number of bytes of memory allocated to the var. Indeed, all comparable compilers define vars in terms of bytes allocated, otherwise it would be very difficult for the system to allocate/store in memory, and very very difficult to perform arithmetic etc without such.
For some, like me, it is easier to see what is going on by using a slightly older notation (rather than the "kind konfusion". In particular, very many compilers provide a direct 1:1 correspondence between Kind and bytes/var, which then makes calculation of largest/smallest Integer fairly straightforward (some compiler use a non-linear or non-direct correspondence). Though be sure to take note of the portability assistance at the end. For example
Integer(1) :: Int1 ! corresponds to a 1 byte integer
Integer(2) :: Int1 ! corresponds to a 2 byte integer
Integer(4) :: Int1 ! corresponds to a 4 byte integer
Integer(8) :: Int1 ! corresponds to an 8 byte integer
Similar notation applies to other Fortran types (Real, Logical, etc). All var types have a default number of bytes allocated if the "size" is not specified.
The maximum number of bytes for a particular type also depends on compiler and system (e.g. Integer(16) is not available on all systems, etc).
A byte is 8 bits, so a single byte should be able to accommodate the largest value of 2^8 = 256 if numbering from 1, or = 255, when starting from 0.
However, in Fortran, (almost all) numeric vars are "signed". That means somewhere in the bit representation one bit is required to track whether the number is a +ve number or a -ve number. So in this example, the max would be 2^7, since one bit is "lost/reserved" for the "sign" information. Thus, the values possible for a signed 1-byte integer are -127:+128 (notice the Abs(limits) sum to 255, since "0" takes up one place, for a total of 256 "things", as it should be).
A similar rule applies for all such vars, with simply the exponent "n", in 2^n, varying based on the number of bytes. For example, an Integer(8) var has 8 bytes, or 64 bits, with 1 bit lost/reserved for sign information, so the largest possible value would be 2^63 = 9223372036854775808, if numbering from 1, or = 4611686018427387904 when starting from 0.
The standard Integer data model would be generalised as:
IntNum = s * Sum[ w(k) * 2 ^ (k-1), k=1:(NumBytes*8)-1],
where s = "sign" (+/-1), w(k) is either 1 or 0 for the kth bit value.
One need not use explicit numbers or env vars in the type declarations; user defined compile time constants (i.e. Parameters) are permitted. For example
Integer, Parameter :: DP = Kind(1.0d0) ! a standard Double Precision/8-byte declaration
Integer, Parameter :: I4B = 4 ! NOTICE, here the "Integer" bit has not been explicitly "sized", so defaults to "Integer(4)"
!
Real(DP) :: ADoublePrecReal ! an 8-byte Real (approx 15 decimal places with exp +/- approx 300, see Real data model)
!
Integer(I4B) :: AStandardInt ! a 4-byte integer.
Since the Parameter statement can be in another Module accessible via Use etc, it is a simple matter to recompile large complex code for alternate definitions of "precision" desired. For example, if DP is edited to Kind(1.0), then everywhere that declaration is applied will become "single precision" Real.
The Fortran intrinsic functions Huge(), Tiny() etc help to determine what is possible on a given system.
Much more can be accomplished with Fortran "bit" intrinsics, and other tools/methods.

Fortran: the largest and the smallest integer

Fortran is completely new for me, can anybody help me to solve the follwing problem? I want to find out all the integer kind numbers and the largest and the smallest value for each kind number on my pc. I have code listed below:
program intkind
implicit none
integer :: n=1
integer :: integer_range =1
do while(integer_range /= -1)
print*, "kind_number ", selected_int_kind(n)
call rang(integer_range)
n = n *2
integer_range = selected_int_kind(n)
end do
contains
subroutine rang(largest)
integer largest
print*, huge(largest)
end subroutine
end
The integer kind numbers what I get are : 1,2,4,8.
Why is each largest integer for each kind number the same: 2147483647? And is there a intrinsic function for the smallest integer?
How can I keep the integer kind number when the subroutine rang is called? I think it is the key to the largest integer.
Your subroutine:
subroutine rang(largest)
integer :: largest
print *, huge(largest)
end subroutine
takes as input a default-sized integer, and prints the largest possible value that will fit in that default-sized integer. It will always return huge(default integer) which is, on most systems, huge(4-byte-integer), or 2147483647. huge considers only the variable type; it doesn't interpret the variable in any way. The only way you could do what you're trying to do above is with parameterized derived types, which are new enough that support for it in compilers is still a little spotty.
If you want to take a look at ranges of different KINDs of INTEGERs, you'll have to use different variables:
program integerkinds
use iso_fortran_env
implicit none
integer :: i
integer(kind=int8) :: i8
integer(kind=int16) :: i16
integer(kind=int32) :: i32
integer(kind=int64) :: i64
integer(kind=selected_int_kind(6)) :: j6
integer(kind=selected_int_kind(15)):: j15
print *,'Default:'
print *, huge(i)
print *,'Int8:'
print *, huge(i8)
print *,'Int16:'
print *, huge(i16)
print *,'Int32:'
print *, huge(i32)
print *,'Int64:'
print *, huge(i64)
print *,''
print *,'Selected Integer Kind 6:'
print *, huge(j6)
print *,'Selected Integer Kind 15:'
print *, huge(j15)
end program integerkinds
Running gives:
$ ./intkinds
Default:
2147483647
Int8:
127
Int16:
32767
Int32:
2147483647
Int64:
9223372036854775807
Selected Integer Kind 6:
2147483647
Selected Integer Kind 15:
9223372036854775807
Purely as an addendum, or alternate perspective, Fortran variables are defined in terms of the number of bytes of memory allocated to the var. Indeed, all comparable compilers define vars in terms of bytes allocated, otherwise it would be very difficult for the system to allocate/store in memory, and very very difficult to perform arithmetic etc without such.
For some, like me, it is easier to see what is going on by using a slightly older notation (rather than the "kind konfusion". In particular, very many compilers provide a direct 1:1 correspondence between Kind and bytes/var, which then makes calculation of largest/smallest Integer fairly straightforward (some compiler use a non-linear or non-direct correspondence). Though be sure to take note of the portability assistance at the end. For example
Integer(1) :: Int1 ! corresponds to a 1 byte integer
Integer(2) :: Int1 ! corresponds to a 2 byte integer
Integer(4) :: Int1 ! corresponds to a 4 byte integer
Integer(8) :: Int1 ! corresponds to an 8 byte integer
Similar notation applies to other Fortran types (Real, Logical, etc). All var types have a default number of bytes allocated if the "size" is not specified.
The maximum number of bytes for a particular type also depends on compiler and system (e.g. Integer(16) is not available on all systems, etc).
A byte is 8 bits, so a single byte should be able to accommodate the largest value of 2^8 = 256 if numbering from 1, or = 255, when starting from 0.
However, in Fortran, (almost all) numeric vars are "signed". That means somewhere in the bit representation one bit is required to track whether the number is a +ve number or a -ve number. So in this example, the max would be 2^7, since one bit is "lost/reserved" for the "sign" information. Thus, the values possible for a signed 1-byte integer are -127:+128 (notice the Abs(limits) sum to 255, since "0" takes up one place, for a total of 256 "things", as it should be).
A similar rule applies for all such vars, with simply the exponent "n", in 2^n, varying based on the number of bytes. For example, an Integer(8) var has 8 bytes, or 64 bits, with 1 bit lost/reserved for sign information, so the largest possible value would be 2^63 = 9223372036854775808, if numbering from 1, or = 4611686018427387904 when starting from 0.
The standard Integer data model would be generalised as:
IntNum = s * Sum[ w(k) * 2 ^ (k-1), k=1:(NumBytes*8)-1],
where s = "sign" (+/-1), w(k) is either 1 or 0 for the kth bit value.
One need not use explicit numbers or env vars in the type declarations; user defined compile time constants (i.e. Parameters) are permitted. For example
Integer, Parameter :: DP = Kind(1.0d0) ! a standard Double Precision/8-byte declaration
Integer, Parameter :: I4B = 4 ! NOTICE, here the "Integer" bit has not been explicitly "sized", so defaults to "Integer(4)"
!
Real(DP) :: ADoublePrecReal ! an 8-byte Real (approx 15 decimal places with exp +/- approx 300, see Real data model)
!
Integer(I4B) :: AStandardInt ! a 4-byte integer.
Since the Parameter statement can be in another Module accessible via Use etc, it is a simple matter to recompile large complex code for alternate definitions of "precision" desired. For example, if DP is edited to Kind(1.0), then everywhere that declaration is applied will become "single precision" Real.
The Fortran intrinsic functions Huge(), Tiny() etc help to determine what is possible on a given system.
Much more can be accomplished with Fortran "bit" intrinsics, and other tools/methods.