I've got a use case where I have multiple Ingredient that can be linked to a Recipe through the Django admin. Now I have around a hundred ingredients which makes it very difficult to select the ingredients in the following UI.
Is there a way to add a search field or something similar to the django admin for easier selection?
You have few choices.
1. filter_horizontal
With filter_horizontal, you can use horizontal m2m ui in admin. I prefer this way using m2m in admin.
class YourAdmin(admin.ModelAdmin):
filter_horizontal = ('m2m_field',)
...
And the result will be...
2. raw_id_fields docs
You can use raw_id_fields for using pop-up modal with your m2m fields.
It's bit useful when you have lots of m2m field. Also, it's easy to filter which m2m obj to add.
class YourAdmin(admin.ModelAdmin):
raw_id_fiedls = ('m2m_field',)
...
I suppose you want to filter over ingredients and select it one by one on admin UI
You can use django forms builtin CheckboxSelectMultiple
widget in place of SelectMultiple to make selection easy
from django import forms
from django.contrib import admin
class RecipeForm(forms.ModelForm):
class Meta(object):
model = Recipe
widgets = {
'Ingredient': forms.CheckboxSelectMultiple,
}
class RecipeAdmin(admin.ModelAdmin):
form = RecipeForm
admin.site.register(Recipe, RecipeAdmin)
Alternatively, you can use django-better-filter-widget
package if you want a search input on choices, Refer Github repo for
installation
It is a custom widget, created by overriding SelectMultiple widget of
django forms
from django import forms
from django.contrib import admin
from better_filter_widget import BetterFilterWidget
class RecipeForm(forms.ModelForm):
class Meta(object):
model = Recipe
widgets = {
'Ingredient': BetterFilterWidget(),
}
class RecipeAdmin(admin.ModelAdmin):
form = RecipeForm
admin.site.register(Recipe, RecipeAdmin)
Related
I am building an app in Django.
I found there is a very easy way to integrate a widget into django admin that allows the admin to filter model objects by fields values. That is achieved by including the line
list_filter = ['field_to_filter_by_its_values']
into the class mymodelAdmin(ImportExportModelAdmin) in admin.py, as shown below
class target_area_history_dataAdmin(ImportExportModelAdmin):
resource_class = target_area_history_dataResource
list_filter = ['Target_area_input_data__Name']
admin.site.register(target_area_history_data, target_area_history_dataAdmin)
Now, instead of integrate a widget to filter my model objects by that field, is there a way to integrate a widget to sort my model objects by that field?
Note: I am using Django Import-Export in my model.
I'll suggest you use django-treebeard. This allows you to view tree nodes hierarchically in the administration interface, with interface features dependent upon the tree algorithm used.
# admin.py
from django.contrib import admin
from treebeard.admin import TreeAdmin
from .models import Category
class CategoryAdmin(TreeAdmin):
list_display = ("title", "created", "modified",)
list_filter = ("created",)
admin.site.register(Category, CategoryAdmin)
What's cool about this is that you can not only sort (by clicking the header row) but also drag things around, as shown in this image.
I recommend you using the grapelli admin interface that allows what you need and a bit more. here you have the grapelli project page and the https://github.com/sehmaschine/django-grappelli.
It's a well documented package and is plug and play for what you need. It also gives a fresh face to Django Admin and is compatible with Django import/export package.
I want to show select box options as raido buttons in Django Admin change model view. I don't want to write custom model forms. I'm looking for a way to render some select boxes as radio buttons while keeping auto generated model forms of the Django admin. I'm using django v 1.11.
Assuming my_field is the field, we want to be rendered as Radio Button
# admin.py
from django.contrib import admin
from django import forms
from .models import MyModel
class MyModelAdminForm(forms.ModelForm):
class Meta:
model = MyModel
exclude = ()
widgets = {'my_field': forms.RadioSelect}
class MyModelAdmin(admin.ModelAdmin):
form = MyModelAdminForm
admin.site.register(MyModel, MyModelAdmin)
I have two models, Product and Category and ManytoMany field in Product.
The Category appear as key on ProductCreate View.
I need to customize the widget and field for Categories.
I checked in Django source Fields and Widgets but I don't see a reference(class) for ManyToMany.
To what type of Field and Widget ManyToMany relationship corresponds(I presume is Charfield as save or SelectField)? Where I can find the code ? (an example to customize field/widget in this case)
A model ManyToManyField is represented as a MultipleChoiceField and the default widget is SelectMultiple But, we can customise it.
You can find it in below references.
[1]https://docs.djangoproject.com/en/dev/topics/forms/modelforms/#field-types
[2]https://docs.djangoproject.com/en/dev/ref/forms/widgets/#setting-arguments-for-widgets
from django import forms
from . import models
class ProductForm(forms.ModelForm):
class Meta:
model = models.Post
fields = [<fields-for-your-product-form>]
categories = forms.ModelMultipleChoiceField(
queryset=models.Category.objects.all(),
widget=forms.CheckboxSelectMultiple
)
This will render checkboxes in your form but you can substitute it with your preferred widget.
I've done something similiar where I was adding tags to blog posts. I wrote a tutorial for it- goes into more detail: https://ctrlzblog.com/how-to-add-tags-to-your-blog-a-django-manytomanyfield-example/
I have registered some models to display in the admin area, but I would like for some fields to be hidden.
As an example, I have a TeachingClasses model with a BooleanField named 'Status' that is set to True or False depending if the class is open or not. But that is set somewhere else in the app. There is no need to have that field displayed in the admin area when someone wants to create a new class to attend.
As such, is there a way to hide that field in the admin area?
I have tried adding this to the app admin.py file but it did nothing
from django.contrib import admin
class MyModelAdmin(admin.ModelAdmin):
class TeachingClasses:
exclude = ('Status',)
but it's not working?
Any clue if this is the right way?
My model:
class TeachingClasses(models.Model):
name = models.Charfield('Class Name',max_lenght=64)
[...]
status = models.BooleanField('Status',default=True)
What you did is not the correct syntax, you need:
class TeachingClassesAdmin(admin.ModelAdmin):
exclude = ('status',)
admin.site.register(TeachingClasses, TeachingClassesAdmin)
Django doc about how to use exclude.
In the admin.py:
class TeachingClassesAdmin(admin.ModelAdmin):
list_display = ('name',) # plus any other fields you'd like to display
admin.site.register(TeachingClasses, TeachingClassesAdmin)`
I'm working in a form with a m2m field. I want that this field looks like the horizontal interface of the django admin site... ¿how i can do it?
thanks...
You need to use the FilteredSelectMultiple widget
from django.contrib.admin.widgets import FilteredSelectMultiple
from django import forms
from .models import Person
class PersonForm(forms.ModelForm):
some_field = forms.ModelMultipleChoiceField(Person.objects.all(), widget=FilteredSelectMultiple("Person", False, attrs={'rows':'2'}))
class Meta:
model = Person
You will also need to include the Javascript and CSS used in the admin. Here's an example