Is there a way to get the current date in ballerina?
As I was browsing through some code examples I came across the syntax to get the current time. Shown below is how to get the current date in Ballerina:
Note: first you have to import the time package given below for this to work.
import ballerina/time;
Then put the following lines of code:
time: Time currentTime = time:[currentTime][2]();
string customTimeString = currentTime.format("dd-MM-yyyy");
This will give the following output:
08-07-2018
This is work for ballerina 0.991 and 1.0 first you have to import the time package
Then it will give the current date if you want to get in a format it will included the code
import ballerina/time;
To get current time
time:Time time = time:currentTime();
string standardTimeString = time:toString(time);
io:println("Current system time in ISO format: ", standardTimeString);
To format the time
string|error customTimeString = time:format(time, "yyyy-MM-dd-E");
if (customTimeString is string) {
io:println("Current system time in custom format: ", customTimeString);
}
y -Years
M -months
d -date
E -day
h -hour
m -Minuit
s -seconds
For Swan Lake Update 3 they seem to have removed the time:currentTime() function.
It seems they have replaced it with time:utcNow().
According to the ballerina documentation,
"The time:Utc is the tuple representation of the UTC. The UTC represents the number of seconds from a specified epoch. Here, the epoch is the UNIX epoch of 1970-01-01T00:00:00Z."
So you can convert this above tuple representation to RFC 3339 timestamp by using,
time:Utc currTime = time:utcNow();
string date = time:utcToString(currTime);
io:println(date);
Then you will get a result like below,
2023-01-14T17:04:15.639510400Z
Using ballerina time library you can convert to other different representations as well.
Related
I am using following code to get current time in python.
import datetime
now = datetime.datetime.now()
message_sent_time = now.strftime("%I:%M %p")
It returns time as
06:58 PM
However, I would like to get output as
6:58 PM
i.e. single digit time when time is before 10. How can I achieve it?
You can get a single-digit hour using %-I:
>>> message_sent_time = now.strftime("%-I:%M %p")
>>> print(message_sent_time)
7:07 PM
Full strftime formatting reference: http://strftime.org/
I'm trying to investigate the Python time striptime method to decompose a time represented as 11:49:57.74. The standard %H, %M, %S are able to decompose the hour , minute , second. However, since the data is a string ( which is taken in python pandas column as datatype object, the Milliseconds after the decimal second is left uninterpreted. Hence, I get an error. Could someone please advise how to parse the example so that the seconds and microseconds are correctly interpreted from the time string ?
I would then use them to find the time delta between two time stamps.
I don't know if I had correctly understood your question.
So, to convert that string time to datetime and calculate the timedelta between two times you need to do as follow:
timedelta = str() #declare an empty string where save the timedelta
my_string = '11:49:57.74' # first example time
another_example_time = '13:49:57.74' #second example time, invented by me for the example
first_time = datetime.strptime(my_string, "%H:%M:%S.%f") # extract the first time
second_time = datetime.strptime(another_example_time , "%H:%M:%S.%f") # extract the second time
#calculate the time delta
if(first_time > second_time):
timedelta = first_time - second_time
else:
timedelta = second_time - first_time
print "The timedelta between %s and %s is: %s" % (first_time, second_time, timedelta)
Here obviusly you don't have any date, so the datetime library as default use 1900-01-01 as you can see in the result of the print:
The timedelta between 1900-01-01 11:49:57.740000 and 1900-01-01 13:49:57.740000 is: 2:00:00
I hope this solution is what you need. Next time provide a little bit more information please, or share an example with the code that you have tried to write.
I have converted some sensor data into CSV format. The data contains a timestamp attribute that is divided into two parts as follows:
measurement_timestamp_begin:
seconds: 3733032665
fractions: 3056174174
I need to convert this into standard UNIX timestamp format. I saw several posts for doing the conversion but each method receives a single argument. I don't understand the fraction part. Does it mean seconds.fraction? e.g. 3733032665.3056174174.
Following code converts above mentioned timestamp format to standard UNIX timestamp format.
#!/usr/bin/env python
import datetime, time
unix_epoch = datetime.date(*time.gmtime(0)[0:3])
ntp_epoch = datetime.date(1900, 1, 1)
ntp_delta = (unix_epoch - ntp_epoch).days * 24 * 3600
def ntp_to_unix_time(date):
return (date - ntp_delta)
print datetime.datetime.fromtimestamp(int(ntp_to_unix_time(3733032665.3056174174))).strftime('%Y-%m-%d %H:%M:%S')
13:20:06.037
13:20:06.038
13:20:06.039
I want to read the timestamps from a file using python and compare the difference between adjacent values. Below is the code I used for this.
h, m, s = str(diff).split(':')
v,w = str(s).split('.')
I tried to split the diff in to hours,minutes and seconds using split(':'). In s, there is seconds and milliseconds value. When I try to run the second line of code, I get the error:" ValueError: need more than 1 value to unpack".
If you would like to convert string records from a file then You should try:
--put here Your code, that retrieves time records from file--
format = '%H:%M:%S.%f'
time_string = '09:54:11.001'
time = datetime.strptime(time_string, format)
This function does the job with displaying time, as You wanted to:
strftime("%H:%M:%S.%f", *put your time variable here*)
And this code snippet shows how to get a difference between two dates in Your format:
time1 = '09:54:11.001'
time2 = '10:32:43.837'
format = '%H:%M:%S.%f'
difference = datetime.strptime(time2, format) - datetime.strptime(time1, format)
You can read more about time functions in Python docs: https://docs.python.org/2/library/time.html
Regards.
I've tried to convert datetime string into datetime of an SArray (uses C++ booster library), but it does not seem to understand the %p format specifier. http://www.boost.org/doc/libs/1_43_0/doc/html/date_time/date_time_io.html
This documentation says specifiers marked with ! do not currently work for input.
Does that mean that you cannot parse anything with pm or PM?
I was able to get the string-to-datetime conversion to work by making two small changes:
Use %I for the hour on a 12-hour clock (%H is for a 24 hour clock).
Use %P (upper case) for the AM/PM flag.
Here's what works for me:
sf = gl.SFrame({'date': ['2015-11-06 02:12:42 pm',
'2015-11-05 03:43:11 pm']})
sf['date2'] = sf['date'].str_to_datetime('%Y-%m-%d %I:%M:%S %p')