Constexpr find for array using c++17 - c++

I am trying to write a constexpr find function that will return the index of a std::array containing a certain value. The function below seems to work OK except when the contained type is const char*:
#include <array>
constexpr auto name1() {
return "name1";
}
constexpr auto name2() {
return "name2";
}
template <class X, class V>
constexpr auto find(X& x, V key) {
std::size_t i = 0;
while(i < x.size()) {
if(x[i] == key) return i;
++i;
}
return i;
}
int main() {
constexpr std::array<const char*, 2> x{{name1(), name2()}};
constexpr auto f1 = find(x, name1()); // this compiles
constexpr auto f2 = find(x, name2()); // this doesn't...
}
The weird thing is that find(x, name1()) compiles cleanly but find(x, name2()) fails with the error:
subexpression not valid in a constant expression
if(x[i] == key) return i; `
How can this expression work when used with name1() but fail when used with name2()?
I have also found this answer, but the user builds the array class from scratch and I do not want to do that.

Seems like a compiler bug. Both f1 and f2 should fail to compile in the same way.
The main issue is that it's an assumption that "name1" == "name1" and "name1" != "name2". The standard in fact provides no such guarantees, see [lex.string]/16:
Whether all string literals are distinct (that is, are stored in nonoverlapping objects) and whether successive evaluations of a string-literal yield the same or a different object is unspecified.
Even though the assumption most likely holds, comparing unspecified values inside constexpr is expressly not allowed, see [expr.const]/2.23:
— a relational ([expr.rel]) or equality ([expr.eq]) operator where the result is unspecified;
A workaround (and the right thing to do) would be to not rely on addresses of string literals and instead compare the actual strings. For example:
constexpr bool equals(const char* a, const char* b) {
for (std::size_t i = 0; ; ++i) {
if (a[i] != b[i]) return false;
if (a[i] == 0) break;
}
return true;
}
template <class X, class V>
constexpr auto find(X& x, V key) {
std::size_t i = 0;
while(i < x.size()) {
if(equals(x[i], key)) return i;
++i;
}
return i;
}

Related

How to make a for loop variable const with the exception of the increment statement?

Consider a standard for loop:
for (int i = 0; i < 10; ++i)
{
// do something with i
}
I want to prevent the variable i from being modified in the body of the for loop.
However, I cannot declare i as const as this makes the increment statement invalid. Is there a way to make i a const variable outside of the increment statement?
From c++20, you can use ranges::views::iota like this:
for (int const i : std::views::iota(0, 10))
{
std::cout << i << " "; // ok
i = 42; // error
}
Here's a demo.
From c++11, you can also use the following technique, which uses an IIILE (immediately invoked inline lambda expression):
int x = 0;
for (int i = 0; i < 10; ++i) [&,i] {
std::cout << i << " "; // ok, i is readable
i = 42; // error, i is captured by non-mutable copy
x++; // ok, x is captured by mutable reference
}(); // IIILE
Here's a demo.
Note that [&,i] means that i is captured by non-mutable copy, and everything else is captured by mutable reference. The (); at the end of the loop simply means that the lambda is invoked immediately.
For anyone that likes Cigien's std::views::iota answer but isn't working in C++20 or above, it's rather straightforward to implement a simplified and lightweight version of std::views::iota compatible c++11 or above.
All it requires is:
A basic "LegacyInputIterator" type (something that defines operator++ and operator*) that wraps an integral value (e.g. an int)
Some "range"-like class that has begin() and end() that returns the above iterators. This will allow it to work in range-based for loops
A simplified version of this could be:
#include <iterator>
// This is just a class that wraps an 'int' in an iterator abstraction
// Comparisons compare the underlying value, and 'operator++' just
// increments the underlying int
class counting_iterator
{
public:
// basic iterator boilerplate
using iterator_category = std::input_iterator_tag;
using value_type = int;
using reference = int;
using pointer = int*;
using difference_type = std::ptrdiff_t;
// Constructor / assignment
constexpr explicit counting_iterator(int x) : m_value{x}{}
constexpr counting_iterator(const counting_iterator&) = default;
constexpr counting_iterator& operator=(const counting_iterator&) = default;
// "Dereference" (just returns the underlying value)
constexpr reference operator*() const { return m_value; }
constexpr pointer operator->() const { return &m_value; }
// Advancing iterator (just increments the value)
constexpr counting_iterator& operator++() {
m_value++;
return (*this);
}
constexpr counting_iterator operator++(int) {
const auto copy = (*this);
++(*this);
return copy;
}
// Comparison
constexpr bool operator==(const counting_iterator& other) const noexcept {
return m_value == other.m_value;
}
constexpr bool operator!=(const counting_iterator& other) const noexcept {
return m_value != other.m_value;
}
private:
int m_value;
};
// Just a holder type that defines 'begin' and 'end' for
// range-based iteration. This holds the first and last element
// (start and end of the range)
// The begin iterator is made from the first value, and the
// end iterator is made from the second value.
struct iota_range
{
int first;
int last;
constexpr counting_iterator begin() const { return counting_iterator{first}; }
constexpr counting_iterator end() const { return counting_iterator{last}; }
};
// A simple helper function to return the range
// This function isn't strictly necessary, you could just construct
// the 'iota_range' directly
constexpr iota_range iota(int first, int last)
{
return iota_range{first, last};
}
I've defined the above with constexpr where it's supported, but for earlier versions of C++ like C++11/14, you may need to remove constexpr where it is not legal in those versions to do so.
The above boilerplate enables the following code to work in pre-C++20:
for (int const i : iota(0, 10))
{
std::cout << i << " "; // ok
i = 42; // error
}
Which will generate the same assembly as the C++20 std::views::iota solution and the classic for-loop solution when optimized.
This works with any C++11-compliant compilers (e.g. compilers like gcc-4.9.4) and still produces nearly identical assembly to a basic for-loop counterpart.
Note: The iota helper function is just for feature-parity with the C++20 std::views::iota solution; but realistically, you could also directly construct an iota_range{...} instead of calling iota(...). The former just presents an easy upgrade path if a user wishes to switch to C++20 in the future.
The KISS version...
for (int _i = 0; _i < 10; ++_i) {
const int i = _i;
// use i here
}
If your use case is just to prevent accidental modification of the loop index then this should make such a bug obvious. (If you want to prevent intentional modification, well, good luck...)
Couldn't you just move some or all the content of your for loop in a function that accepts i as a const?
Its less optimal than some solutions proposed, but if possible this is quite simple to do.
Edit: Just an example as I tend to be unclear.
for (int i = 0; i < 10; ++i)
{
looper( i );
}
void looper ( const int v )
{
// do your thing here
}
If you do not have access to c++20, typical makeover using a function
#include <vector>
#include <numeric> // std::iota
std::vector<int> makeRange(const int start, const int end) noexcept
{
std::vector<int> vecRange(end - start);
std::iota(vecRange.begin(), vecRange.end(), start);
return vecRange;
}
now you could
for (const int i : makeRange(0, 10))
{
std::cout << i << " "; // ok
//i = 100; // error
}
(See a Demo)
Update: Inspired from the #Human-Compiler's comment, I was wondering weather the given answers have any difference in the case of performance. It turn out that, except for this approach, for all other approaches surprisingly have same performance (for the range [0, 10)). The std::vector approach is the worst.
(See Online Quick-Bench)
And here is a C++11 version:
for (int const i : {0,1,2,3,4,5,6,7,8,9,10})
{
std::cout << i << " ";
// i = 42; // error
}
Here is live demo
#include <cstdio>
#define protect(var) \
auto &var ## _ref = var; \
const auto &var = var ## _ref
int main()
{
for (int i = 0; i < 10; ++i)
{
{
protect(i);
// do something with i
//
printf("%d\n", i);
i = 42; // error!! remove this and it compiles.
}
}
}
Note: we need to nest the scope because of an astonishing stupidity in the language: the variable declared in the for(...) header is considered to be at the same nesting level as variables declared in the {...} compound statement. This means that, for instance:
for (int i = ...)
{
int i = 42; // error: i redeclared in same scope
}
What? Didn't we just open a curly brace? Moreover, it's inconsistent:
void fun(int i)
{
int i = 42; // OK
}
One simple approach not yet mentioned here that works in any version of C++ is to create a functional wrapper around a range, similar to what std::for_each does to iterators. The user is then responsible for passing in a functional argument as a callback which will be invoked on each iteration.
For example:
// A struct that holds the start and end value of the range
struct numeric_range
{
int start;
int end;
// A simple function that wraps the 'for loop' and calls the function back
template <typename Fn>
void for_each(const Fn& fn) const {
for (auto i = start; i < end; ++i) {
const auto& const_i = i;
fn(const_i); // or fn(std::as_const(i)); in C++17
}
}
};
Where the use would be:
numeric_range{0, 10}.for_each([](const auto& i){
std::cout << i << " "; // ok
//i = 100; // error
});
Anything older than C++11 would be stuck passing a strongly-named function pointer into for_each (similar to std::for_each), but it still works.
Here's a demo
Although this may not be idiomatic for for loops in C++, this approach is quite common in other languages. Functional wrappers are really sleek for their composability in complex statements and can be very ergonomic for use.
This code is also simple to write, understand, and maintain.
template<class T = int, class F>
void while_less(T n, F f, T start = 0){
for(; start < n; ++start)
f(start);
}
int main()
{
int s = 0;
while_less(10, [&](auto i){
s += i;
});
assert(s == 45);
}
maybe call it for_i
No overhead https://godbolt.org/z/e7asGj

Why isn't it a constexpr in this case?

I have a dumb constexpr version of strlen and the compiler accepts it as constexpr in some cases, but in others it does not, here's an example:
template <std::size_t MAX_SIZE>
class FixedString
{
public:
explicit FixedString(const char* str)
{
for(std::size_t i = 0; i < MAX_SIZE; i++)
{
data[i] = str[i];
}
}
char data[MAX_SIZE];
};
constexpr std::size_t constexpr_strlen(const char *str)
{
for(std::size_t i = 0; i < std::numeric_limits<std::size_t>::max(); i++)
{
if(str[i] == '\0')
{
return i;
}
}
return 0;
}
// doesn't compile, compiler says non-type template argument is not a constant expression
auto make_string(const char* str)
{
return FixedString<constexpr_strlen(str)>(str);
}
int main()
{
constexpr bool IS_DEV = true;
// works fine
std::array<int, constexpr_strlen(IS_DEV ? "Development" : "Production")> arr;
// works fine
FixedString<constexpr_strlen(IS_DEV ? "Development" : "Production")> str("Develop");
// doesn't compile, compiler says variable has incomplete type 'void'
auto string = make_string("Not working");
return 1;
}
Why is it that constexpr_strlen is considered constexpr out of the make_string function and in it's not?
For what I can see here, it can be computed at compile time, can't it?
The main problem is that constexpr functions are by definition intended to be callable at compile-time as well as at run-time. Let's start with a simpler example:
constexpr int f(int n) { return n };
int n = 7;
// n could be modified!
f(n); // compiler cannot know which value n has at runtime,
// so the function needs to be executed at runtime as well!
f(7); // well, now right the opposite...
So it's quite simple: The result of a constexpr function is constexpr, too, if and only if all the arguments the function is called with are constexpr themselves (and only then, the function is evaluated at compile-time), otherwise, it will be a runtime value (and the function is evaluated at run-time).
Inside constexpr functions, though, the compiler cannot know if the function is called with constexpr arguments only or not; so function parameters always need to be considered non-constexpr. And here we are...
(Sure, make_string isn't even constexpr, but if constexpr cannot be assumed for parameters of constexpr functions, then even less for normal function parameters...)

C++ std::plus as template parameter

I wanna write a class for a binary indexed array,
which use two non-type default template parameter, op and identity.
And need to check the constraint that op(identity,identity) == identity.
My problem is,
I don't to how to specify op, my current solution does not compile.
‘class std::function<T(T, T)>’ is not a valid type for a template non-type parameter
how to to check op(identity,identity) == identity, currently I cannot verify, since failed on step 1, maybe static_assert?
So currently I use below workaround, but then I cannot specify op, eg, std::multiplies<int>.
Can anyone tell me how to achieve the goal?
#include <vector>
#include <functional>
// template <typename T = int, std::function<T(T,T)> op = std::plus<T>(), const T identity = T()>
template <typename T = int, const T identity = T()> // currently workaround
class BIT { // binary indexed array
const std::function<T(T,T)> op = std::plus<T>(); // currently workaround
public:
BIT(std::vector<T> value) : value(value), prefixSum(value.size() + 1, identity) {
for (size_t i = 1; i < prefixSum.size(); ++i) {
incrementNodeByValue(i, value[i-1]);
}
// print(prefixSum,"prefixSum");
}
T getSum(size_t i) {
auto sum = identity;
while (i) {
sum = op(sum, prefixSum(i));
i = firstSmallerAncestor(i);
}
return sum;
}
void incrementNodeByValue(size_t i, T x) {
while (i < prefixSum.size()) {
prefixSum[i] = op(prefixSum[i], x);
i = firstLargerAncestor(i);
}
}
private:
inline size_t firstLargerAncestor(size_t node) { return node + (node & -node); }
inline size_t firstSmallerAncestor(size_t node) { return node & (node - 1); }
std::vector<T> value;
std::vector<T> prefixSum;
};
int main() {
auto vec = std::vector<int> {5,1,15,11,52,28,0};
auto bit = BIT<>(vec);
}
The use of std::function here is a waste and seems to be the source of your confusion.
Note that templates may only be parameterized on typenames and values of integral types (char, int, long, etc). Here you're attempting to parameterize on a value of a std::function instantiation, which isn't an integral type. That said, you don't actually need to parameterize on a value in this case.
Because your constructor doesn't accept an argument to initialize the op member variable nor is it accessible via the interface, I gather it's safe to assume the operator is known at compile-time, is guaranteed immutable, and default constructible.
As such, I declared the op member to be of a parameter type called operation.
#include <functional>
#include <vector>
template< typename T = int,
typename operation = std::plus<T>,
const T identity = T() >
class BIT {
const operation op = operation();
static_assert( operation()(identity, identity) == identity );
std::vector<T> value;
std::vector<T> prefixSum;
inline size_t firstLargerAncestor(size_t node) { return node + (node & -node); }
inline size_t firstSmallerAncestor(size_t node) { return node & (node - 1); }
public:
BIT(std::vector<T> value) :
value(value),
prefixSum(value.size() + 1, identity) {
for (size_t i = 1; i < prefixSum.size(); ++i) {
incrementNodeByValue(i, value[i-1]);
}
}
T getSum(size_t i) {
auto sum = identity;
while (i) {
sum = op(sum, prefixSum(i));
i = firstSmallerAncestor(i);
}
return sum;
}
void incrementNodeByValue(size_t i, T x) {
while (i < prefixSum.size()) {
prefixSum[i] = op(prefixSum[i], x);
i = firstLargerAncestor(i);
}
}
};
live example
As a note, you'll likely want to define an identity template elsewhere to parameterized on an operation and value types to default the third parameter here. As is, it seems you'll almost always be defining all three parameters during instantiation.

Passing arguments to "array-like" container constructor

Background
I'm working with an embedded platform with the following restrictions:
No heap
No Boost libraries
C++11 is supported
I've dealt with the following problem a few times in the past:
Create an array of class type T, where T has no default constructor
The project only recently added C++11 support, and up until now I've been using ad-hoc solutions every time I had to deal with this. Now that C++11 is available, I thought I'd try to make a more general solution.
Solution Attempt
I copied an example of std::aligned_storage to come up with the framework for my array type. The result looks like this:
#include <type_traits>
template<class T, size_t N>
class Array {
// Provide aligned storage for N objects of type T
typename std::aligned_storage<sizeof(T), alignof(T)>::type data[N];
public:
// Build N objects of type T in the aligned storage using default CTORs
Array()
{
for(auto index = 0; index < N; ++index)
new(data + index) T();
}
const T& operator[](size_t pos) const
{
return *reinterpret_cast<const T*>(data + pos);
}
// Other methods consistent with std::array API go here
};
This is a basic type - Array<T,N> only compiles if T is default-constructible. I'm not very familiar with template parameter packing, but looking at some examples led me to the following:
template<typename ...Args>
Array(Args&&... args)
{
for(auto index = 0; index < N; ++index)
new(data + index) T(args...);
}
This was definitely a step in the right direction. Array<T,N> now compiles if passed arguments matching a constructor of T.
My only remaining problem is constructing an Array<T,N> where different elements in the array have different constructor arguments. I figured I could split this into two cases:
1 - User Specifies Arguments
Here's my stab at the CTOR:
template<typename U>
Array(std::initializer_list<U> initializers)
{
// Need to handle mismatch in size between arg and array
size_t index = 0;
for(auto arg : initializers) {
new(data + index) T(arg);
index++;
}
}
This seems to work fine, aside from needing to handle a dimension mismatch between the array and initializer list, but there are a number of ways to deal with that that aren't important. Here's an example:
struct Foo {
explicit Foo(int i) {}
};
void bar() {
// foos[0] == Foo(0)
// foos[1] == Foo(1)
// ..etc
Array<Foo,10> foos {0, 1, 2, 3, 4, 5, 6, 7, 8, 9};
}
2 - Arguments Follow Pattern
In my previous example, foos is initialized with an incrementing list, similar to std::iota. Ideally I'd like to support something like the following, where range(int) returns SOMETHING that can initialize the array.
// One of these should initialize foos with parameters returned by range(10)
Array<Foo,10> foosA = range(10);
Array<Foo,10> foosB {range(10)};
Array<Foo,10> foosC = {range(10)};
Array<Foo,10> foosD(range(10));
Googling has shown me that std::initializer_list isn't a "normal" container, so I don't think there's any way for me to make range(int) return a std::initializer_list depending on the function parameter.
Again, there are a few options here:
Parameters specified at run-time (function return?)
Parameters specified at compile-time (constexpr function return? templates?)
Questions
Are there any issues with this solution so far?
Does anyone have a suggestion to generate constructor parameters? I can't think of a solution at runtime or compile-time other than hard-coding an std::initializer_list, so any ideas are welcome.
If i understand your problem correctly, I've also stumbled across std::array's total inflexibility regarding element construction in favor of aggregate initialization (and an absense of statically-allocated container with flexible element contruction options). The best approach I came up with was creating a custom array-like container which accepts an iterator to construct it's elements.
This is totally flexible solution:
Works for both fixed-size and dynamic-sized containers
Can pass different or same parameters to element constructors
Can call constructors with one or multiple (tuple piecewise construction) arguments, or even different constructors for different elements (with inversion of control)
For your example it would be like:
const size_t SIZE = 10;
std::array<int, SIZE> params;
for (size_t c = 0; c < SIZE; c++) {
params[c] = c;
}
Array<Foo, SIZE> foos(iterator_construct, &params[0]); //iterator_construct is a special tag to call specific constructor
// also, we are able to pass a pointer as iterator, since it has both increment and dereference operators
Note: you can totally skip parameters array allocation here by using custom iterator class, which calculates it's value from it's position on-the-fly.
For multiple-argument constructor that would be:
const size_t SIZE = 10;
std::array<std::tuple<int, float>, SIZE> params; // will call Foo(int, float)
for (size_t c = 0; c < SIZE; c++) {
params[c] = std::make_tuple(c, 1.0f);
}
Array<Foo, SIZE> foos(iterator_construct, piecewise_construct, &params[0]);
Concrete implementation example is kinda big piece of code, so please let me know if you want more insights into implementation details besides the general idea - I will update my answer then.
I'd use a factory lambda.
The lambda takes a pointer to where to construct and an index, and is responsible for constructing.
This makes copy/move easy to write as well, which is a good sign.
template<class T, std::size_t N>
struct my_array {
T* data() { return (T*)&buffer; }
T const* data() const { return (T const*)&buffer; }
// basic random-access container operations:
T* begin() { return data(); }
T const* begin() const { return data(); }
T* end() { return data()+N; }
T const* end() const { return data()+N; }
T& operator[](std::size_t i){ return *(begin()+i); }
T const& operator[](std::size_t i)const{ return *(begin()+i); }
// useful utility:
bool empty() const { return N!=0; }
T& front() { return *begin(); }
T const& front() const { return *begin(); }
T& back() { return *(end()-1); }
T const& back() const { return *(end()-1); }
std::size_t size() const { return N; }
// construct from function object:
template<class Factory,
typename std::enable_if<!std::is_same<std::decay_t<Factory>, my_array>::value, int> =0
>
my_array( Factory&& factory ) {
std::size_t i = 0;
try {
for(; i < N; ++i) {
factory( (void*)(data()+i), i );
}
} catch(...) {
// throw during construction. Unroll creation, and rethrow:
for(std::size_t j = 0; j < i; ++j) {
(data()+i-j-1)->~T();
}
throw;
}
}
// other constructors, in terms of above naturally:
my_array():
my_array( [](void* ptr, std::size_t) {
new(ptr) T();
} )
{}
my_array(my_array&& o):
my_array( [&](void* ptr, std::size_t i) {
new(ptr) T( std::move(o[i]) );
} )
{}
my_array(my_array const& o):
my_array( [&](void* ptr, std::size_t i) {
new(ptr) T( o[i] );
} )
{}
my_array& operator=(my_array&& o) {
for (std::size_t i = 0; i < N; ++i)
(*this)[i] = std::move(o[i]);
return *this;
}
my_array& operator=(my_array const& o) {
for (std::size_t i = 0; i < N; ++i)
(*this)[i] = o[i];
return *this;
}
private:
using storage = typename std::aligned_storage< sizeof(T)*N, alignof(T) >::type;
storage buffer;
};
it defines my_array(), but that is only compiled if you try to compile it.
Supporting initializer list is relatively easy. Deciding what to do when the il isn't long enough, or too long, is hard. I think you might want:
template<class Fail>
my_array( std::initializer_list<T> il, Fail&& fail ):
my_array( [&](void* ptr, std::size_t i) {
if (i < il.size()) new(ptr) T(il[i]);
else fail(ptr, i);
} )
{}
which requires you pass in a "what to do on fail". We could default to throw by adding:
template<class WhatToThrow>
struct throw_when_called {
template<class...Args>
void operator()(Args&&...)const {
throw WhatToThrow{"when called"};
}
};
struct list_too_short:std::length_error {
list_too_short():std::length_error("list too short") {}
};
template<class Fail=ThrowWhenCalled<list_too_short>>
my_array( std::initializer_list<T> il, Fail&& fail={} ):
my_array( [&](void* ptr, std::size_t i) {
if (i < il.size()) new(ptr) T(il[i]);
else fail(ptr, i);
} )
{}
which if I wrote it right, makes a too-short initializer list cause a meaningful throw message. On your platform, you could just exit(-1) if you don't have exceptions.

How to initialise a floating point array at compile time?

I have found two good approaches to initialise integral arrays at compile times here and here.
Unfortunately, neither can be converted to initialise a float array straightforward; I find that I am not fit enough in template metaprogramming to solve this through trial-and-error.
First let me declare a use-case:
constexpr unsigned int SineLength = 360u;
constexpr unsigned int ArrayLength = SineLength+(SineLength/4u);
constexpr double PI = 3.1415926535;
float array[ArrayLength];
void fillArray(unsigned int length)
{
for(unsigned int i = 0u; i < length; ++i)
array[i] = sin(double(i)*PI/180.*360./double(SineLength));
}
As you can see, as far as the availability of information goes, this array could be declared constexpr.
However, for the first approach linked, the generator function f would have to look like this:
constexpr float f(unsigned int i)
{
return sin(double(i)*PI/180.*360./double(SineLength));
}
And that means that a template argument of type float is needed. Which is not allowed.
Now, the first idea that springs to mind would be to store the float in an int variable - nothing happens to the array indices after their calculation, so pretending that they were of another type than they are (as long as byte-length is equal) is perfectly fine.
But see:
constexpr int f(unsigned int i)
{
float output = sin(double(i)*PI/180.*360./double(SineLength));
return *(int*)&output;
}
is not a valid constexpr, as it contains more than the return statement.
constexpr int f(unsigned int i)
{
return reinterpret_cast<int>(sin(double(i)*PI/180.*360./double(SineLength)));
}
does not work either; even though one might think that reinterpret_cast does exactly what is needed here (namely nothing), it apparently only works on pointers.
Following the second approach, the generator function would look slightly different:
template<size_t index> struct f
{
enum : float{ value = sin(double(index)*PI/180.*360./double(SineLength)) };
};
With what is essentially the same problem: That enum cannot be of type float and the type cannot be masked as int.
Now, even though I have only approached the problem on the path of "pretend the float is an int", I do not actually like that path (aside from it not working). I would much prefer a way that actually handled the float as float (and would just as well handle a double as double), but I see no way to get around the type restriction imposed.
Sadly, there are many questions about this issue, which always refer to integral types, swamping the search for this specialised issue. Similarly, questions about masking one type as the other typically do not consider the restrictions of a constexpr or template parameter environment.
See [1][2][3] and [4][5] etc.
Assuming your actual goal is to have a concise way to initialize an array of floating point numbers and it isn't necessarily spelled float array[N] or double array[N] but rather std::array<float, N> array or std::array<double, N> array this can be done.
The significance of the type of array is that std::array<T, N> can be copied - unlike T[N]. If it can be copied, you can obtain the content of the array from a function call, e.g.:
constexpr std::array<float, ArrayLength> array = fillArray<N>();
How does that help us? Well, when we can call a function taking an integer as an argument, we can use std::make_index_sequence<N> to give use a compile-time sequence of std::size_t from 0 to N-1. If we have that, we can initialize an array easily with a formula based on the index like this:
constexpr double const_sin(double x) { return x * 3.1; } // dummy...
template <std::size_t... I>
constexpr std::array<float, sizeof...(I)> fillArray(std::index_sequence<I...>) {
return std::array<float, sizeof...(I)>{
const_sin(double(I)*M_PI/180.*360./double(SineLength))...
};
}
template <std::size_t N>
constexpr std::array<float, N> fillArray() {
return fillArray(std::make_index_sequence<N>{});
}
Assuming the function used to initialize the array elements is actually a constexpr expression, this approach can generate a constexpr. The function const_sin() which is there just for demonstration purpose does that but it, obviously, doesn't compute a reasonable approximation of sin(x).
The comments indicate that the answer so far doesn't quite explain what's going on. So, let's break it down into digestible parts:
The goal is to produce a constexpr array filled with suitable sequence of values. However, the size of the array should be easily changeable by adjusting just the array size N. That is, conceptually, the objective is to create
constexpr float array[N] = { f(0), f(1), ..., f(N-1) };
Where f() is a suitable function producing a constexpr. For example, f() could be defined as
constexpr float f(int i) {
return const_sin(double(i) * M_PI / 180.0 * 360.0 / double(Length);
}
However, typing in the calls to f(0), f(1), etc. would need to change with every change of N. So, essentially the same as the above declaration should be done but without extra typing.
The first step towards the solution is to replace float[N] by std:array<float, N>: built-in arrays cannot be copied while std::array<float, N> can be copied. That is, the initialization could be delegated to to a function parameterized by N. That is, we'd use
template <std::size_t N>
constexpr std::array<float, N> fillArray() {
// some magic explained below goes here
}
constexpr std::array<float, N> array = fillArray<N>();
Within the function we can't simply loop over the array because the non-const subscript operator isn't a constexpr. Instead, the array needs to be initialized upon creation. If we had a parameter pack std::size_t... I which represented the sequence 0, 1, .., N-1 we could just do
std::array<float, N>{ f(I)... };
as the expansion would effectively become equivalent to typing
std::array<float, N>{ f(0), f(1), .., f(N-1) };
So the question becomes: how to get such a parameter pack? I don't think it can be obtained directly in the function but it can be obtained by calling another function with a suitable parameter.
The using alias std::make_index_sequence<N> is an alias for the type std::index_sequence<0, 1, .., N-1>. The details of the implementation are a bit arcane but std::make_index_sequence<N>, std::index_sequence<...>, and friends are part of C++14 (they were proposed by N3493 based on, e.g., on this answer from me). That is, all we need to do is call an auxiliary function with a parameter of type std::index_sequence<...> and get the parameter pack from there:
template <std::size_t...I>
constexpr std::array<float, sizeof...(I)>
fillArray(std::index_sequence<I...>) {
return std::array<float, sizeof...(I)>{ f(I)... };
}
template <std::size_t N>
constexpr std::array<float, N> fillArray() {
return fillArray(std::make_index_sequence<N>{});
}
The [unnamed] parameter to this function is only used to have the parameter pack std::size_t... I be deduced.
Here's a working example that generates a table of sin values, and that you can easily adapt to logarithm tables by passing a different function object
#include <array> // array
#include <cmath> // sin
#include <cstddef> // size_t
#include <utility> // index_sequence, make_index_sequence
#include <iostream>
namespace detail {
template<class Function, std::size_t... Indices>
constexpr auto make_array_helper(Function f, std::index_sequence<Indices...>)
-> std::array<decltype(f(std::size_t{})), sizeof...(Indices)>
{
return {{ f(Indices)... }};
}
} // namespace detail
template<std::size_t N, class Function>
constexpr auto make_array(Function f)
{
return detail::make_array_helper(f, std::make_index_sequence<N>{});
}
static auto const pi = std::acos(-1);
static auto const make_sin = [](int x) { return std::sin(pi * x / 180.0); };
static auto const sin_table = make_array<360>(make_sin);
int main()
{
for (auto elem : sin_table)
std::cout << elem << "\n";
}
Live Example.
Note that you need to use -stdlib=libc++ because libstdc++ has a pretty inefficient implementation of index_sequence.
Also note that you need a constexpr function object (both pi and std::sin are not constexpr) to initialize the array truly at compile-time rather than at program initialization.
There are a few problems to overcome if you want to initialise a floating point array at compile time:
std::array is a little broken in that the operator[] is not constexpr in the case of a mutable constexpr std::array (I believe this will be fixed in the next release of the standard).
the functions in std::math are not marked constexpr!
I had a similar problem domain recently. I wanted to create an accurate but fast version of sin(x).
I decided to see if it could be done with a constexpr cache with interpolation to get speed without loss of accuracy.
An advantage of making the cache constexpr is that the calculation of sin(x) for a value known at compile-time is that the sin is pre-computed and simply exists in the code as an immediate register load! In the worst case of a runtime argument, it's merely a constant array lookup followed by w weighted average.
This code will need to be compiled with -fconstexpr-steps=2000000 on clang, or the equivalent in windows.
enjoy:
#include <iostream>
#include <cmath>
#include <utility>
#include <cassert>
#include <string>
#include <vector>
namespace cpputil {
// a fully constexpr version of array that allows incomplete
// construction
template<size_t N, class T>
struct array
{
// public constructor defers to internal one for
// conditional handling of missing arguments
constexpr array(std::initializer_list<T> list)
: array(list, std::make_index_sequence<N>())
{
}
constexpr T& operator[](size_t i) noexcept {
assert(i < N);
return _data[i];
}
constexpr const T& operator[](size_t i) const noexcept {
assert(i < N);
return _data[i];
}
constexpr T& at(size_t i) noexcept {
assert(i < N);
return _data[i];
}
constexpr const T& at(size_t i) const noexcept {
assert(i < N);
return _data[i];
}
constexpr T* begin() {
return std::addressof(_data[0]);
}
constexpr const T* begin() const {
return std::addressof(_data[0]);
}
constexpr T* end() {
// todo: maybe use std::addressof and disable compiler warnings
// about array bounds that result
return &_data[N];
}
constexpr const T* end() const {
return &_data[N];
}
constexpr size_t size() const {
return N;
}
private:
T _data[N];
private:
// construct each element from the initialiser list if present
// if not, default-construct
template<size_t...Is>
constexpr array(std::initializer_list<T> list, std::integer_sequence<size_t, Is...>)
: _data {
(
Is >= list.size()
?
T()
:
std::move(*(std::next(list.begin(), Is)))
)...
}
{
}
};
// convenience printer
template<size_t N, class T>
inline std::ostream& operator<<(std::ostream& os, const array<N, T>& a)
{
os << "[";
auto sep = " ";
for (const auto& i : a) {
os << sep << i;
sep = ", ";
}
return os << " ]";
}
}
namespace trig
{
constexpr double pi() {
return M_PI;
}
template<class T>
auto constexpr to_radians(T degs) {
return degs / 180.0 * pi();
}
// compile-time computation of a factorial
constexpr double factorial(size_t x) {
double result = 1.0;
for (int i = 2 ; i <= x ; ++i)
result *= double(i);
return result;
}
// compile-time replacement for std::pow
constexpr double power(double x, size_t n)
{
double result = 1;
while (n--) {
result *= x;
}
return result;
}
// compute a term in a taylor expansion at compile time
constexpr double taylor_term(double x, size_t i)
{
int powers = 1 + (2 * i);
double top = power(x, powers);
double bottom = factorial(powers);
auto term = top / bottom;
if (i % 2 == 1)
term = -term;
return term;
}
// compute the sin(x) using `terms` terms in the taylor expansion
constexpr double taylor_expansion(double x, size_t terms)
{
auto result = x;
for (int term = 1 ; term < terms ; ++term)
{
result += taylor_term(x, term);
}
return result;
}
// compute our interpolatable table as a constexpr
template<size_t N = 1024>
struct sin_table : cpputil::array<N, double>
{
static constexpr size_t cache_size = N;
static constexpr double step_size = (pi() / 2) / cache_size;
static constexpr double _360 = pi() * 2;
static constexpr double _270 = pi() * 1.5;
static constexpr double _180 = pi();
static constexpr double _90 = pi() / 2;
constexpr sin_table()
: cpputil::array<N, double>({})
{
for(int slot = 0 ; slot < cache_size ; ++slot)
{
double val = trig::taylor_expansion(step_size * slot, 20);
(*this)[slot] = val;
}
}
double checked_interp_fw(double rads) const {
size_t slot0 = size_t(rads / step_size);
auto v0 = (slot0 >= this->size()) ? 1.0 : (*this)[slot0];
size_t slot1 = slot0 + 1;
auto v1 = (slot1 >= this->size()) ? 1.0 : (*this)[slot1];
auto ratio = (rads - (slot0 * step_size)) / step_size;
return (v1 * ratio) + (v0 * (1.0-ratio));
}
double interpolate(double rads) const
{
rads = std::fmod(rads, _360);
if (rads < 0)
rads = std::fmod(_360 - rads, _360);
if (rads < _90) {
return checked_interp_fw(rads);
}
else if (rads < _180) {
return checked_interp_fw(_90 - (rads - _90));
}
else if (rads < _270) {
return -checked_interp_fw(rads - _180);
}
else {
return -checked_interp_fw(_90 - (rads - _270));
}
}
};
double sine(double x)
{
if (x < 0) {
return -sine(-x);
}
else {
constexpr sin_table<> table;
return table.interpolate(x);
}
}
}
void check(float degs) {
using namespace std;
cout << "checking : " << degs << endl;
auto mysin = trig::sine(trig::to_radians(degs));
auto stdsin = std::sin(trig::to_radians(degs));
auto error = stdsin - mysin;
cout << "mine=" << mysin << ", std=" << stdsin << ", error=" << error << endl;
cout << endl;
}
auto main() -> int
{
check(0.5);
check(30);
check(45.4);
check(90);
check(151);
check(180);
check(195);
check(89.5);
check(91);
check(270);
check(305);
check(360);
return 0;
}
expected output:
checking : 0.5
mine=0.00872653, std=0.00872654, error=2.15177e-09
checking : 30
mine=0.5, std=0.5, error=1.30766e-07
checking : 45.4
mine=0.712026, std=0.712026, error=2.07233e-07
checking : 90
mine=1, std=1, error=0
checking : 151
mine=0.48481, std=0.48481, error=2.42041e-08
checking : 180
mine=-0, std=1.22465e-16, error=1.22465e-16
checking : 195
mine=-0.258819, std=-0.258819, error=-6.76265e-08
checking : 89.5
mine=0.999962, std=0.999962, error=2.5215e-07
checking : 91
mine=0.999847, std=0.999848, error=2.76519e-07
checking : 270
mine=-1, std=-1, error=0
checking : 305
mine=-0.819152, std=-0.819152, error=-1.66545e-07
checking : 360
mine=0, std=-2.44929e-16, error=-2.44929e-16
I am just keeping this answer for documentation. As the comments say, I was mislead by gcc being permissive. It fails, when f(42) is used e.g. as a template parameter like this:
std::array<int, f(42)> asdf;
sorry, this was not a solution
Separate the calculation of your float and the conversion to an int in two different constexpr functions:
constexpr int floatAsInt(float float_val) {
return *(int*)&float_val;
}
constexpr int f(unsigned int i) {
return floatAsInt(sin(double(i)*PI/180.*360./double(SineLength)));
}